Why Plot Posterior Results Against the Discount?
A power-prior analysis uses a fixed discount \(a\) to control how much historical information contributes to the current analysis, with \(0\leq a\leq1\). A result reported at only one value of \(a\) can hide how sensitive that result is to the borrowing choice. A plot makes this dependence visible: it can show whether a posterior mean shifts gradually, whether uncertainty contracts, and whether a clinically relevant posterior probability crosses a decision threshold.
The horizontal axis represents the chosen discount, not time, a patient characteristic, or a quantity estimated from the trial. Each point is the result of a separate posterior calculation conditional on that fixed value of \(a\). The resulting curve is therefore a sensitivity display, not a posterior distribution for the discount.
A useful plot states the estimand or parameter, its units, the discount range, the prior and likelihood model, and whether each interval is a credible interval conditional on that fixed discount. It should also identify any clinical threshold used in a decision-probability curve. These details let the reader distinguish a change caused by the discount from a change caused by redefining the model or summary.
Constructing a Posterior Mean and Interval Curve
Consider a continuous control outcome with current and historical sample means \(\bar{x}_c\) and \(\bar{x}_h\). Suppose the two sample means have known sampling variances \(\sigma_c^2/n_c\) and \(\sigma_h^2/n_h\), respectively. Assume conditional normal sampling, a common parameter \(\theta\) for the current and historical controls, and a normal prior \(\theta\sim N(\mu_0,\tau_0^2)\). Under a power prior, the historical likelihood is raised to a fixed power \(a\). This model assumes that the historical and current data measure the same endpoint on the same scale and that the common-parameter assumption is reasonable; those assumptions are not established merely by making a plot.
Write the prior precision as \(P_0=1/\tau_0^2\), the current-data precision as \(P_c=n_c/\sigma_c^2\), and the historical-data precision as \(P_h=n_h/\sigma_h^2\). The current and historical precision-weighted means are \(B_0=P_0\mu_0\), \(B_c=P_c\bar{x}_c\), and \(B_h=P_h\bar{x}_h\). Completing the square in the normal prior times the current likelihood and the power-weighted historical likelihood gives posterior precision \(P(a)=P_0+P_c+aP_h\). The posterior mean is the precision-weighted sum of the prior mean and the two data means, divided by that precision:
Thus a central \(100(1-\gamma)\%\) credible interval at each fixed \(a\) is \(m(a)\pm z_{1-\gamma/2}/\sqrt{P(a)}\), where \(z_{1-\gamma/2}\) is the corresponding standard-normal quantile. Plotting the lower and upper endpoints around the mean displays both location and posterior uncertainty. The interval has its stated posterior coverage conditional on the model and fixed discount; it is not a frequentist confidence interval, nor does it assign a probability to \(a\).
Worked Example: Plotting a Posterior Mean and 95% Credible Interval
Suppose a hypothetical blood-pressure analysis measures mean systolic pressure in mmHg. The prior is \(N(150,25)\), where 25 is the prior variance in \(\text{mmHg}^2\). The current control group has \(n_c=17\), mean \(150\) mmHg, and known individual-level variance \(80\ \text{mmHg}^2\). The historical group has \(n_h=32\), mean \(145\) mmHg, and the same known variance. Assume the two groups can be represented by the stated common-mean normal model. Calculate plot values at \(a=0,0.5,1\).
The prior precision is \(P_0=1/25=0.04\ \text{mmHg}^{-2}\). The current precision is \(P_c=17/80=0.2125\ \text{mmHg}^{-2}\), and the historical precision is \(P_h=32/80=0.4\ \text{mmHg}^{-2}\). The corresponding weighted means are \(B_0=0.04(150)=6\), \(B_c=0.2125(150)=31.875\), and \(B_h=0.4(145)=58\), in consistent precision-weighted units.
At \(a=0\), the historical data contribute no precision. The posterior precision is \(0.04+0.2125=0.2525\), and the numerator of the posterior mean is \(6+31.875=37.875\). Therefore \(m(0)=37.875/0.2525=150.0\) mmHg and the posterior standard deviation is \(\sqrt{1/0.2525}=1.990\) mmHg. The 95% interval is \(150.0\pm1.96(1.990)=(146.1,153.9)\) mmHg.
At \(a=0.5\), the precision is \(0.04+0.2125+0.5(0.4)=0.4525\), and the numerator is \(6+31.875+0.5(58)=66.875\). The posterior mean is \(66.875/0.4525=147.7901\) mmHg, and the standard deviation is \(\sqrt{1/0.4525}=1.4866\) mmHg. The 95% interval is \(147.7901\pm1.96(1.4866)\), or approximately \((144.9,150.7)\) mmHg.
At \(a=1\), the precision is \(0.04+0.2125+0.4=0.6525\), and the numerator is \(6+31.875+58=95.875\). The posterior mean is \(95.875/0.6525=146.9349\) mmHg, and the standard deviation is \(\sqrt{1/0.6525}=1.2380\) mmHg. The 95% interval is \(146.9349\pm1.96(1.2380)\), which rounds to \((144.5,149.4)\) mmHg.
A plot would connect these means across a grid of discounts and draw the lower and upper interval endpoints as bounds. Here the mean moves downward as historical borrowing increases, while the interval becomes narrower because posterior precision increases. The interval endpoints need not both move in the same direction: the mean shift and the change in uncertainty act together.
What the Curves Can—and Cannot—Show
The mean curve has a simple form in the normal model. Let \(B=B_0+B_c\) and \(C=P_0+P_c\), so \(m(a)=(B+aB_h)/(C+aP_h)\). Differentiating gives:
Because the denominator is positive, the sign of the derivative is determined by the constant numerator \(B_hC-P_hB\). The mean is therefore monotone in \(a\) under this particular model, or constant if that numerator is zero. In the example, \(B=37.875\), \(C=0.2525\), \(B_h=58\), and \(P_h=0.4\), so \(B_hC-P_hB=58(0.2525)-0.4(37.875)=-0.505\). The posterior mean decreases throughout the discount range. This conclusion is specific to the stated conjugate model; do not assume every posterior summary in every model must be monotone.
A second useful curve is a posterior probability tied to a clinical question. For example, if lower systolic pressure is favorable, a decision-maker might examine \(P(\theta<148\text{ mmHg}\mid\text{data},a)\). Under the normal model, this is the standard-normal cumulative distribution function evaluated at \((148-m(a))/\sqrt{1/P(a)}\). The threshold must be justified clinically and expressed in the parameter’s units. A probability curve reports posterior support for that event, conditional on the model and the selected discount; it does not by itself determine the trial’s decision rule.
Worked Example: Plotting a Decision-Relevant Probability
Use the hypothetical blood-pressure analysis above and examine the event \(\theta<148\) mmHg. At \(a=0\), the standardized threshold is \((148-150.0)/1.990=-1.005\), so the posterior probability is approximately \(\Phi(-1.005)=0.157\). At \(a=0.5\), use the unrounded posterior values: \((148-147.7901)/1.4866=0.1412\), giving \(\Phi(0.1412)\approx0.5562\). At \(a=1\), the standardized threshold is \((148-146.9349)/1.2380=0.8605\), giving \(\Phi(0.8605)\approx0.805\).
Plotting these three values at their respective discounts shows that the probability of a mean below 148 mmHg rises substantially as borrowing increases in this example. The curve is not evidence that the treatment caused a reduction, and it is not the probability that a null hypothesis is true. It describes posterior probability for a parameter event under the specified model and fixed discount.
Binary Outcomes: The Same Plotting Principle
For a binary control outcome, suppose the current data contain \(y_c\) responses among \(n_c\) participants, and the historical data contain \(y_h\) responses among \(n_h\) participants. Assume conditionally independent Bernoulli observations with a common response probability \(p\), and use a \(\operatorname{Beta}(\alpha_0,\beta_0)\) prior. With a fixed power-prior discount, the posterior is \(\operatorname{Beta}(\alpha_0+y_c+ay_h,\ \beta_0+n_c-y_c+a(n_h-y_h))\). The model again requires that a common response probability be appropriate for the current and historical controls.
Worked Example: Plotting a Beta-Binomial Posterior Mean
In hypothetical data, suppose 12 of 20 current controls and 70 of 100 historical controls respond. Let the prior be \(\operatorname{Beta}(1,1)\). The posterior mean at discount \(a\) is:
At \(a=0\), the posterior is \(\operatorname{Beta}(13,9)\), with mean \(13/(13+9)=0.5909\). At \(a=0.5\), it is \(\operatorname{Beta}(48,24)\), with mean \(48/72=0.6667\). At \(a=1\), it is \(\operatorname{Beta}(83,39)\), with mean \(83/122=0.6803\). These values give three points on the posterior-mean curve, with response probability on the vertical axis.
For an interval plot, calculate the chosen lower and upper beta quantiles at each discount. For example, a central 95% interval uses the 0.025 and 0.975 quantiles of the corresponding beta posterior. The bounds must be recalculated at each \(a\); holding the interval width fixed while changing only its center would not represent these posterior distributions.
Building a Reliable Discount Plot
In practice, calculate posterior summaries over a sufficiently fine grid from 0 to 1, including both endpoints and any values that are scientifically prespecified. A grid can be dense enough to reveal curvature without implying more precision than the model or data warrant. For every grid value, keep the likelihood, prior, endpoint, analysis population, and summary definition unchanged; vary only the fixed discount. A multi-step workflow helps prevent accidental changes in the analysis:
Name the parameter, outcome model, prior, fixed-discount range, and clinical threshold if a probability curve will be shown.
For every grid value, obtain the posterior mean or median, the interval endpoints, and any decision-relevant posterior probability from the same model.
Label the discount axis, parameter or probability axis, units, interval level, and threshold. Show the full discount range or clearly state any restricted range.
Verify endpoint calculations and selected grid values independently, then describe the direction and practical size of changes without treating the curve as a probability distribution over discounts.
A table of selected fixed-discount results is a useful alternative when only a few values are of interest, and it can be easier to read exact numbers from a table than from a graph. A plot is usually better for seeing the overall pattern and possible threshold crossings. Neither replaces model diagnostics or justification of the historical data. A fixed-discount plot also differs from an analysis that assigns a distribution to the discount and averages over it: the former displays conditional results separately, rather than combining them.
Diagnostics, Failure Modes, and Limitations
Check that the plotted means and interval endpoints reproduce direct calculations at selected discounts, especially \(a=0\), \(a=1\), and any clinically emphasized value. Confirm that \(a=0\) removes the historical likelihood contribution and that \(a=1\) corresponds to full power-prior weighting under the chosen model. For simulated or numerically integrated posteriors, check Monte Carlo error or numerical accuracy at every grid point; a jagged curve may be numerical noise rather than a real feature.
- Misleading axis limits. A narrow vertical range can exaggerate a small mean change. Show a scale that supports a clinically meaningful comparison.
- Unclear interval display. Label the interval level and state that it is conditional on the fixed discount. Do not call it a probability that the parameter lies within the realized interval.
- Mixing summaries. A posterior mean curve and a probability curve answer different questions. Label the vertical axis so readers do not mistake one for the other.
- Unjustified common model. Smooth curves do not demonstrate that historical and current data are comparable. Differences in endpoint, population, or data quality can undermine the likelihood assumptions.
- Overinterpreting threshold crossings. A curve crossing a decision threshold marks a change in the displayed posterior probability, not a universal decision rule. The threshold and action rule require clinical and design justification.
A discount plot is conditional on the model and the fixed values selected for display. It cannot repair bias in historical data, establish transportability, or show that borrowing is justified. It is also not a causal analysis. Interpret it alongside the rationale for selecting and discounting historical information, and report the fixed-discount results needed to make the display auditable.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions.
- In a fixed-discount plot, what does one point at \(a=0.4\) represent?
- In the hypothetical blood-pressure example, why does the posterior mean decrease as \(a\) increases?
- What does a 95% credible interval shown at a particular discount mean?
- Why is a posterior probability curve for \(\theta<148\) mmHg not itself a decision rule?
- Name two checks that can help detect a misleading or incorrectly computed discount plot.
Solutions. 1. It is the specified posterior summary calculated conditional on setting the historical-data discount to 0.4, with the rest of the model held fixed. 2. The historical mean is below the current mean and prior mean in this example, so increasing its precision-weighted contribution pulls the posterior mean downward; algebraically, the derivative numerator is \(-0.505\), and its denominator is positive. 3. Conditional on the stated model and fixed discount, the posterior probability that the parameter lies in the calculated interval is 0.95. It does not describe the probability that \(a\) is correct. 4. A decision also requires a justified threshold and an action rule; the curve only reports posterior probability for the specified parameter event. 5. Examples include verifying the \(a=0\) and \(a=1\) limits, recomputing selected grid values independently, checking numerical error, and confirming that axes, units, and interval levels are clearly labeled.