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Phase 2 Single-Arm Monitoring · Tutorial 609 of 696

Worked Single-Arm Monitoring Design Case

Work through a complete hypothetical monitoring design, from its terminal response rule and interim boundaries to the decisions made as trial outcomes accumulate.

Intermediate 10 min read

What You'll Learn

  • Specify a terminal success rule for a single-arm binary-response trial.
  • Calculate the predictive probability of meeting that rule at a scheduled interim look.
  • Apply paired efficacy and futility cutoffs without confusing predictive probability with posterior probability about the response rate.
  • Trace trial decisions across complete-cohort interim looks and the final analysis.
  • Identify assumptions and practical checks needed when applying the design.

From a Terminal Rule to Interim Decisions

A single-arm phase 2 trial may have a clear final criterion for success but still need a plan for what to do before all participants have outcomes. Predictive monitoring connects those decisions: at each scheduled look, it asks how likely the trial is to satisfy its prespecified terminal success rule if enrollment and follow-up continue as planned. A very low probability can support stopping for futility; a sufficiently high probability can support stopping early for efficacy.

This worked case uses a deliberately small hypothetical trial so that every probability can be checked by hand. Six participants have fully observed binary response outcomes, with looks after participants 2 and 4. The numbers illustrate the mechanics, not a recommended clinical design. In practice, sample size, timing, prior distribution, terminal criterion, and stopping cutoffs require design justification appropriate to the trial.

Definition: Let \(X_N\) be the number of responses among \(N\) participants. A terminal success rule specifies which final data outcomes count as success. At an interim look with \(n\) observed outcomes and \(x\) responses, the predictive probability of terminal success is the posterior predictive probability that the final data will satisfy that rule, conditional on the interim data and the specified model.

Design Specification and Assumptions

Suppose each participant has a binary outcome, response or no response, and outcomes are modeled as conditionally independent Bernoulli observations with a common response probability \(p\). Assign \(p\) the prespecified prior distribution \(\operatorname{Beta}(1,1)\). After observing \(x\) responses among \(n\) participants, the posterior distribution is \(\operatorname{Beta}(x+1,n-x+1)\). This simple prior is used to make the arithmetic transparent; choosing it does not establish that it is appropriate for a real trial.

The maximum sample size is \(N=6\), and the trial's terminal success rule is \(X_6\geq 3\). Interim analyses occur only after complete cohorts of two participants: at \(n=2\) and \(n=4\). At each interim look, stop for early efficacy if the predictive probability is at least 0.90, stop for futility if it is at most 0.15, and otherwise continue. These cutoffs are prespecified design inputs for this example. They are not universal thresholds.

The calculation assumes outcomes are available and correctly classified at each look; there are no pending outcomes, delayed assessments, or changes to the sample size or analysis plan. It also assumes the response model and prior remain the specified ones at each look. If these conditions do not hold, the calculation may not describe the actual decision problem. Pending outcomes, for example, require an explicit plan for how they enter the analysis rather than silently treating them as failures or successes.

For a look at \(n\), let \(m=N-n\) be the number of participants remaining and \(Y\) their future response count. Given the observed data, \(Y\) has a beta-binomial posterior predictive distribution. The predictive probability for this design is \(P(x+Y\geq 3\mid x,n)\). In particular, the probability integrates uncertainty about \(p\); it is not simply the posterior probability that \(p\) exceeds a fixed value.

$$ P(Y=y\mid x,n) = \binom{m}{y} \frac{B(x+1+y,\ n-x+1+m-y)} {B(x+1,\ n-x+1)}, \qquad y=0,\ldots,m. $$

Here \(B(\cdot,\cdot)\) is the beta function. The predictive probability is found by summing this distribution over future counts that meet the terminal rule:

$$ \operatorname{PP}(x,n) = P(X_6\geq 3\mid x,n) = \sum_{y=\max(0,\,3-x)}^{m}P(Y=y\mid x,n). $$

If \(3-x>m\), the sum has no eligible future counts and the predictive probability is zero: even responses from every remaining participant could not satisfy the terminal rule. If \(x\geq 3\), the terminal count criterion is already met, so this probability is one.

Worked Example: The First Interim Look

Worked Example: The First Interim Look

At \(n=2\), four participants remain. Calculate the predictive probability of terminal success for each possible response count, then apply the paired boundaries.

If \(x=0\), the posterior is \(\operatorname{Beta}(1,3)\). Terminal success requires at least three responses among the four remaining participants. The beta-binomial probabilities for \(Y=3\) and \(Y=4\) are \(3/35\) and \(1/35\), respectively. Therefore:

$$ \operatorname{PP}(0,2) =P(Y\geq 3\mid x=0,n=2) =\frac{3}{35}+\frac{1}{35} =\frac{4}{35} =0.1143. $$

Since \(0.1143\leq 0.15\), the rule stops for futility. This does not mean success is mathematically impossible; it means the prespecified predictive-probability criterion for stopping is met.

If \(x=1\), the posterior is \(\operatorname{Beta}(2,2)\), and at least two of the four remaining participants must respond. The predictive probabilities of two, three, and four future responses are \(9/35\), \(8/35\), and \(5/35\). Thus:

$$ \operatorname{PP}(1,2) =P(Y\geq 2\mid x=1,n=2) =\frac{9+8+5}{35} =\frac{22}{35} =0.6286. $$

This value is above the futility cutoff and below the efficacy cutoff, so the decision is to continue.

If \(x=2\), the posterior is \(\operatorname{Beta}(3,1)\). At least one of the four remaining participants must respond. The probability of no future responses is \(1/35\), giving:

$$ \operatorname{PP}(2,2) =1-P(Y=0\mid x=2,n=2) =1-\frac{1}{35} =\frac{34}{35} =0.9714. $$

Because \(0.9714\geq 0.90\), the rule stops for early efficacy. The three possible counts therefore produce a futility decision at zero responses, continuation at one, and early efficacy at two.

Worked Example: Applying Both Boundaries at the Second Look

Worked Example: Applying Both Boundaries at the Second Look

At \(n=4\), two participants remain. For \(x=1\), the posterior is \(\operatorname{Beta}(2,4)\). The terminal rule requires both remaining participants to respond. The probability of two responses is:

$$ \operatorname{PP}(1,4) =P(Y=2\mid x=1,n=4) =\frac{2\cdot 3}{6\cdot 7} =\frac{1}{7} =0.1429. $$

Since \(0.1429\leq 0.15\), this count meets the futility boundary. For \(x=2\), the posterior is \(\operatorname{Beta}(3,3)\), and at least one of the two remaining participants must respond. The chance of zero future responses is \((3\cdot4)/(6\cdot7)=2/7\), so:

$$ \operatorname{PP}(2,4) =1-\frac{3\cdot4}{6\cdot7} =1-\frac{2}{7} =\frac{5}{7} =0.7143. $$

This lies between the two cutoffs, so the trial continues. With \(x=3\), the terminal count criterion has already been reached, and \(\operatorname{PP}(3,4)=1\); the efficacy boundary is met. Counts above three likewise have predictive probability one. If \(x=0\), even two additional responses would produce only two total responses, so \(\operatorname{PP}(0,4)=0\) and the futility criterion is met.

Thus, at this look, zero or one response leads to stopping for futility, two leads to continuation, and three or more leads to stopping for efficacy. Only counts reachable after continuation from the first look can occur in the actual trial; listing the other counts clarifies the rule's behavior.

Worked Example: Tracing a Trial Through to Its Final Outcome

Worked Example: Tracing a Trial Through to Its Final Outcome

Consider a hypothetical sequence in which the first cohort has one response among two participants. The first-look calculation gives \(\operatorname{PP}(1,2)=22/35=0.6286\), so the trial continues.

Suppose the next two participants also include one response. The cumulative data are now \(x=2\) responses among \(n=4\). The second-look predictive probability is \(\operatorname{PP}(2,4)=5/7=0.7143\), which again meets neither stopping boundary. The trial continues to the maximum sample size.

Suppose the last two participants include one response. The final total is \(X_6=3\), so the terminal success rule \(X_6\geq3\) is met. This final classification follows directly from the prespecified rule; no participants remain, so there is no future-outcome predictive probability to calculate.

If instead the final two participants had no responses, the total would be \(X_6=2\), and the trial would not meet the terminal rule. The interim decision to continue is not a prediction that success is certain; it allows the trial to collect the remaining outcomes when neither stopping criterion has been met.

Why the Calculation Works, and What to Check

The beta-binomial calculation follows from averaging the future binomial response distribution over the posterior uncertainty in \(p\). Conditional on a particular \(p\), \(Y\) has a binomial distribution with \(m\) trials and response probability \(p\). After observing \(x\) responses and \(n-x\) nonresponses, the posterior density for \(p\) is beta with parameters \(a=x+1\) and \(b=n-x+1\). Integrating the conditional probability over that density gives the predictive probability:

$$ P(Y=y\mid x,n) = \int_0^1 \binom{m}{y}p^y(1-p)^{m-y} \frac{p^{a-1}(1-p)^{b-1}}{B(a,b)} \,dp = \binom{m}{y}\frac{B(a+y,b+m-y)}{B(a,b)}. $$

The integral is the beta-function identity applied to the product of the binomial likelihood and posterior density. Summing over the future counts compatible with the terminal rule yields the probability used at the look. The posterior distribution reflects uncertainty about \(p\); the predictive distribution additionally accounts for the randomness of the remaining participants' outcomes.

Several checks help catch implementation or interpretation errors:

  • Check the remaining sample size. At each look, \(m=N-n\). The future count must range from zero through \(m\), not through the original maximum sample size.
  • Check the terminal event. For the rule \(X_6\geq3\), the required future count is \(Y\geq3-x\). A coding error in this threshold can reverse a decision.
  • Check impossible and guaranteed outcomes. If \(x+m<3\), terminal success is impossible and the probability is zero. If \(x\geq3\), it is guaranteed by the count rule and the probability is one.
  • Check the probability distribution. The predictive probabilities over all \(y=0,\ldots,m\) should sum to one, up to numerical rounding.
  • Check the schedule and data status. Use only outcomes available under the prespecified look plan. If outcomes are pending or assessments are delayed, an analysis that treats them as observed can misstate the information available.

As the observed response count increases, the terminal threshold can become easier to reach because fewer additional responses are required and the posterior for \(p\) changes. Separately, fewer participants remaining reduce the available opportunities for future responses and can eventually make success impossible. These are distinct effects; with the current response count and terminal threshold fixed, simply reducing the number of remaining participants cannot make the threshold easier to reach.

Interpreting Boundaries and Comparing Approaches

The efficacy and futility cutoffs form a paired decision rule: a predictive probability at or above the efficacy cutoff triggers early efficacy, one at or below the futility cutoff triggers futility, and a value between them leads to continuation. These are boundaries on the probability of a future terminal event under the specified model. They are not, by themselves, frequentist type I error or power guarantees, and they are not posterior probabilities that a null hypothesis is true or false.

A fixed-sample analysis waits until the maximum sample size and applies the terminal rule once. It is simpler to operate but cannot stop early under this monitoring plan. Predictive monitoring can reduce exposure or resource use when evidence is already compelling in either direction, but its decisions depend on the prior, response model, terminal rule, look schedule, and cutoffs. Those design choices should be evaluated together, including the probability of each stopping decision under plausible response rates.

A different Bayesian decision rule might assess a posterior probability about \(p\) directly, for example whether \(p\) exceeds a clinically relevant benchmark. That is a different target from the probability of satisfying a finite-sample terminal count rule. The two probabilities answer different questions and need not lead to the same decision. This case uses the predictive target because it was specified as the design's stopping quantity.

The simple model also has limitations. A common response probability may be inadequate when outcomes vary by site, dose, subgroup, or calendar time. A prior that is poorly aligned with the clinical context can affect interim predictive probabilities, especially with little data. Changes in eligibility, follow-up, response assessment, or accrual can undermine the assumptions used to calculate the future distribution. Sensitivity analyses and design simulations can expose some of these concerns, but no calculation removes the need to define the target and assumptions carefully.

Key takeaway: A monitoring decision is obtained by combining three prespecified ingredients: the terminal success event, the predictive model for future outcomes, and paired efficacy and futility cutoffs. Keep those ingredients distinct, calculate from the data available at each scheduled look, and interpret the resulting probability as a chance of meeting the terminal rule under the specified model.

Check Your Understanding

Use the hypothetical design in this tutorial: \(N=6\), terminal success if \(X_6\geq3\), looks at \(n=2\) and \(n=4\), efficacy cutoff 0.90, futility cutoff 0.15, and prior \(\operatorname{Beta}(1,1)\).

  1. At the first look, what decision follows from \(x=1\)?
  2. At the second look, what is the predictive probability and decision for \(x=1\)?
  3. At the second look, why is the predictive probability zero when \(x=0\)?
  4. If the trial reaches \(n=4\) with \(x=2\) and then observes one response among the final two participants, what is the terminal classification?
  5. Explain why the predictive probability is not the posterior probability that the response rate exceeds a benchmark.

Solutions. (1) \(\operatorname{PP}(1,2)=22/35=0.6286\), between 0.15 and 0.90, so continue. (2) \(\operatorname{PP}(1,4)=1/7=0.1429\), at or below 0.15, so stop for futility. (3) With zero responses observed and only two participants remaining, even two more responses give \(X_6=2<3\), so terminal success is impossible. (4) The final count is three, so the terminal success rule is met. (5) The predictive probability concerns future data and the event \(X_6\geq3\), integrating over the posterior for \(p\); a posterior probability about whether \(p\) exceeds a benchmark concerns the parameter itself and is a different quantity.

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