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Instrumental Variable Assumptions and Estimands · Tutorial 498 of 972

Proof That the Wald Ratio Identifies Complier LATE

See why the Wald ratio isolates the average treatment effect among compliers, and why it need not equal the population average treatment effect.

Intermediate 10 min read

What You'll Learn

  • State the binary-instrument assumptions needed for the Wald identification result.
  • Connect observed assignment contrasts to contrasts in potential outcomes.
  • Use monotonicity to show that only compliers contribute to the two contrasts.
  • Derive the Wald ratio as the average treatment effect among compliers.
  • Explain why the result remains valid when everyone is a complier.
  • Distinguish the complier effect from the population average treatment effect.

Why the Wald Ratio Has a Specific Target

An instrument changes treatment take-up for some individuals but not necessarily for everyone. The Wald ratio divides the difference in mean outcomes across instrument assignments by the difference in treatment rates across those assignments. The ratio is therefore not automatically the average treatment effect for the whole population. Under the instrumental-variable assumptions, it identifies an average effect for the individuals whose treatment is changed by the instrument: the compliers.

The key to the result is to examine the two assignment contrasts at the level of potential outcomes. Independence lets us interpret the observed contrasts as contrasts in potential assignment outcomes. Exclusion removes any direct effect of assignment on the outcome. Monotonicity then implies that individuals whose treatment does not change contribute zero to both contrasts. Relevance ensures that the remaining group has positive probability, so the ratio is defined.

Setup and Assumptions

Let \(Z\) be a binary instrument, with values 0 and 1, and let \(D\) be a binary treatment. For each individual, \(D(z)\) is the treatment that would be received under instrument value \(z\), and \(Y(d)\) is the outcome that would be observed under treatment value \(d\). Assume these potential outcomes are well-defined, that one individual's assignment does not affect another individual's outcome, and that observed treatment and outcome satisfy consistency: \(D=D(Z)\) and, under exclusion, \(Y=Y(D)\).

Assumptions for the Wald identification result:

Independence: \(Z\) is independent of the joint vector \(\{Y(0),Y(1),D(0),D(1)\}\). Both instrument values occur with positive probability, so the observed assignment-specific means are defined.

Exclusion: The instrument affects the outcome only through treatment. In potential-outcome notation, the outcome under assignment \(z\) and treatment \(d\) is \(Y(d)\), with no additional dependence on \(z\).

Monotonicity: \(D(1)\geq D(0)\) for every individual. Thus assignment to \(Z=1\) does not make anyone less likely to receive treatment than assignment to \(Z=0\).

Relevance: The population treatment-rate contrast \(E[D\mid Z=1]-E[D\mid Z=0]\) is nonzero.

The four assumptions play different roles. Independence connects assignment-specific observed means to potential outcomes. Exclusion specifies which potential outcome is observed when treatment is set. Monotonicity rules out individuals who would take treatment under \(Z=0\) but not under \(Z=1\). Relevance rules out a zero denominator. For the identification result, these assumptions concern the population; sample contrasts are estimates of the population contrasts, not the assumptions themselves.

Definition: An individual is a complier if \(D(1)=1\) and \(D(0)=0\). Write \(C\) for the event that an individual is a complier. The complier average treatment effect, or complier LATE, is \(E[Y(1)-Y(0)\mid C]\), provided \(P(C)>0\). The population average treatment effect is \(E[Y(1)-Y(0)]\).

With binary \(Z\) and \(D\), monotonicity leaves three possible treatment-response types: compliers, who take treatment only under \(Z=1\); always-takers, who take it under either assignment; and never-takers, who take it under neither assignment. Relevance does not say that everyone complies. It says that the assignment changes treatment take-up for a positive proportion of the population.

From Assignment Contrasts to Potential Outcomes

Define the population reduced-form assignment contrast and the first-stage treatment contrast as

$$ \Delta_Y=E[Y\mid Z=1]-E[Y\mid Z=0], \qquad \Delta_D=E[D\mid Z=1]-E[D\mid Z=0]. $$

By consistency and exclusion, an individual assigned \(Z=z\) has observed treatment \(D(z)\) and observed outcome \(Y(D(z))\). Independence makes the distribution of the potential variables the same across the two assignment groups. Consequently, the assignment-specific observed means equal the corresponding population means of potential assignment outcomes:

$$ \Delta_Y=E[Y(D(1))]-E[Y(D(0))], \qquad \Delta_D=E[D(1)]-E[D(0)]. $$

These equalities do not claim that the same person is observed under both assignments. They use the independence assumption to identify each assignment group's observed mean with a mean of potential outcomes in the population.

Proof: Only Compliers Contribute

Let \(I_C\) equal 1 for a complier and 0 otherwise. Under monotonicity, \(D(1)-D(0)\) is 1 for a complier and 0 for an always-taker or never-taker. Thus \(D(1)-D(0)=I_C\) for every individual. For the outcome contrast, if treatment does not change, the outcome under the two assignments is the same under exclusion. If treatment changes, monotonicity says the individual is a complier, and the outcome difference is \(Y(1)-Y(0)\). In one identity covering all cases,

$$ Y(D(1))-Y(D(0))=I_C\{Y(1)-Y(0)\}. $$

Taking expectations gives the two central expressions:

$$ \Delta_D=E[I_C]=P(C), \qquad \Delta_Y=E[I_C\{Y(1)-Y(0)\}]. $$

Relevance says \(\Delta_D\ne 0\). Since monotonicity implies \(\Delta_D=P(C)\geq 0\), relevance therefore gives \(P(C)>0\). For any integrable variable \(A\), the indicator identity \(E[I_C A]=P(C)E[A\mid C]\) holds when \(P(C)>0\). Apply it to \(A=Y(1)-Y(0)\). The result is

$$ \frac{\Delta_Y}{\Delta_D} = \frac{E[I_C\{Y(1)-Y(0)\}]}{P(C)} = E[Y(1)-Y(0)\mid C]. $$
Theorem: Under relevance, independence, exclusion, and monotonicity, the Wald ratio \[ \frac{E[Y\mid Z=1]-E[Y\mid Z=0]} {E[D\mid Z=1]-E[D\mid Z=0]} \] identifies \(E[Y(1)-Y(0)\mid C]\), the average treatment effect among compliers.

This proof also covers the case \(P(C)=1\). Then \(I_C=1\) for every individual, the first stage is 1, and the outcome contrast is \(E[Y(1)-Y(0)]\). The Wald ratio is the average treatment effect among compliers because the entire population consists of compliers. No conditional expectation given a zero-probability noncomplier group is needed anywhere in the derivation.

Worked Example: A Mixed Population and a Different Population ATE

Consider a hypothetical population with 30% never-takers, 20% always-takers, and 50% compliers. Suppose the average potential outcomes \(Y(0),Y(1)\) are respectively \((4,5)\) for never-takers, \((7,9)\) for always-takers, and \((6,8.4)\) for compliers. Assume assignment is independent of these potential quantities, exclusion holds, and no one is a defier. These choices make the assumptions explicit: treatment type is determined by the stated response type, and assignment itself has no outcome path beyond treatment.

Under \(Z=0\), never-takers and compliers receive treatment 0, while always-takers receive treatment 1. Therefore,

$$ E[Y\mid Z=0]=0.30(4)+0.20(9)+0.50(6) =1.20+1.80+3.00=6.00. $$

Under \(Z=1\), the compliers receive treatment 1, as do the always-takers; never-takers remain untreated. Hence,

$$ E[Y\mid Z=1]=0.30(4)+0.20(9)+0.50(8.4) =1.20+1.80+4.20=7.20. $$

The treatment rate is 0.20 under \(Z=0\) and 0.70 under \(Z=1\), so relevance holds. The Wald ratio is

$$ \frac{7.20-6.00}{0.70-0.20} = \frac{1.20}{0.50} =2.40. $$

The complier treatment effect is \(8.4-6.0=2.4\), matching the ratio. But the population average treatment effect is

$$ 0.30(5-4)+0.20(9-7)+0.50(8.4-6) =0.30+0.40+1.20=1.90. $$

Thus the Wald ratio is 2.40 outcome units per treatment, not the population ATE of 1.90 outcome units per treatment. The noncompliers affect the population ATE, but under the stated assumptions they contribute nothing to the assignment contrasts.

Worked Example: Everyone Is a Complier

In a hypothetical population, suppose every individual has \(D(0)=0\) and \(D(1)=1\), and assignment is independent of potential outcomes. Suppose the population mean of \(Y(0)\) is 10 points and the population mean of \(Y(1)\) is 13 points. Exclusion holds, and monotonicity holds because \(D(1)\geq D(0)\) for everyone. The first stage is \(1-0=1\), so relevance holds.

The assignment contrast is the outcome contrast between treatment states:

$$ \Delta_Y=13-10=3\text{ points}, \qquad \Delta_D=1-0=1. $$

Therefore the Wald ratio is \(3/1=3\) points per treatment. Since every individual is a complier, the complier average treatment effect is also the population average treatment effect, 3 points. This boundary case is included in the theorem: the proof needs positive complier probability, not a separate noncomplier group.

Worked Example: Heterogeneous Effects Among Compliers

Consider another hypothetical population: 25% always-takers, 25% never-takers, and 50% compliers. Assume independence, exclusion, and monotonicity. Among compliers, 40% have a treatment effect of 1 outcome unit and 60% have an effect of 4 outcome units. Let all compliers have \(Y(0)=5\), so their \(Y(1)\) values are 6 and 9 in those two subgroups. Let never-takers have \(Y(0)=2\), and let always-takers have \(Y(1)=10\). Relevance holds because the first stage is the 50% complier proportion.

The average treated outcome for compliers is \(0.40(6)+0.60(9)=2.4+5.4=7.8\). Thus the assignment-specific outcome means are

$$ E[Y\mid Z=0]=0.25(10)+0.25(2)+0.50(5) =2.5+0.5+2.5=5.5, $$
$$ E[Y\mid Z=1]=0.25(10)+0.25(2)+0.50(7.8) =2.5+0.5+3.9=6.9. $$

The Wald ratio is \((6.9-5.5)/(0.50)=1.4/0.50=2.8\) outcome units per treatment. Directly averaging the heterogeneous effects among compliers gives \(0.40(1)+0.60(4)=0.4+2.4=2.8\), as required. The theorem does not require every complier to have the same treatment effect; the ratio targets their average.

Interpretation and a Common Mistake

The result is an identification statement: under the assumptions, the population ratio of assignment contrasts equals a particular causal estimand. It does not say that the Wald ratio equals the ATE in every population. The ATE averages effects over compliers and noncompliers, while this ratio weights only individuals whose treatment status responds to the instrument. Those two averages coincide in special cases, such as when everyone complies or when the groups' average effects happen to be equal, but neither equality follows from the IV assumptions alone.

A common mistake is to reason, “The instrument is relevant and independent, so the Wald ratio is the treatment effect for everyone.” The correction is that relevance says only that treatment rates differ by assignment, while independence makes the assignment contrast interpretable. Exclusion and monotonicity then yield the complier-specific result; none of these assumptions requires the complier effect to equal the effects for always-takers or never-takers.

1
Translate observed contrasts.
Use consistency, exclusion, and independence to express the outcome and treatment contrasts through \(D(1),D(0)\) and \(Y(d)\).
2
Apply monotonicity.
The treatment difference \(D(1)-D(0)\) is one for compliers and zero for everyone else; the outcome difference is the complier treatment effect and zero for everyone else.
3
Divide by the first stage.
Relevance makes the complier proportion positive, so the outcome contrast divided by that proportion is the average treatment effect among compliers.

The target population is instrument-specific: it consists of those who would change treatment status under the two instrument values being compared. This is why the causal interpretation must name compliers rather than silently generalizing to the full population. The next step in using the result is to calculate assignment contrasts from a concrete compliance-type distribution while keeping that target clear.

Check Your Understanding

Use the assumptions and proof to answer these questions.

  1. Which assumption ensures that the observed outcome contrast can be written as a contrast in potential assignment outcomes?
  2. Under monotonicity, what values can \(D(1)-D(0)\) take for compliers and noncompliers?
  3. Why does relevance combined with monotonicity imply that \(P(C)>0\)?
  4. If everyone is a complier, what does the Wald ratio identify, and why does the proof still apply?
  5. In what respect can the Wald ratio differ from the population ATE even when all four IV assumptions hold?
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