Why the Mix of Instruments Matters
With one valid binary instrument and a binary treatment, the Wald ratio can identify a local average treatment effect for units whose treatment changes with the instrument, under the familiar exclusion, independence, and monotonicity assumptions. With several instruments and heterogeneous treatment effects, two-stage least squares (2SLS) need not target one common local effect. Its population coefficient can instead combine instrument-specific local effects, and the coefficients in that combination need not behave like probabilities.
The key issue is that 2SLS uses the joint covariance structure of the instruments. If instruments are correlated, the contribution assigned to one instrument depends not only on its own first-stage effect but also on how it covaries with the other instruments. This tutorial derives a useful weighted-average representation under explicit conditions and shows how a negative weight can arise even when every instrument shifts treatment in the same direction.
Setup and Conditions for Local Effects
Let \(Z=(Z_1,\ldots,Z_K)'\) be a vector of binary instruments, \(D\) a binary treatment, and \(Y\) an outcome. Include an intercept in the 2SLS regression, and define \(\Sigma=\operatorname{Cov}(Z,Z)\). Assume the instrument vector is jointly independent of the potential treatments \(D(z)\) and potential outcomes \(Y(d)\), has full support over its binary combinations, and affects the outcome only through treatment: \(Y=Y(D(Z))\). For each instrument component, assume monotonicity: changing \(Z_j\) from 0 to 1 while holding \(Z_{-j}\) fixed never lowers anyone’s treatment, so \(D(1,z_{-j})\ge D(0,z_{-j})\).
These assumptions alone do not ensure that every marginal Wald ratio is an instrument-specific local effect. A transparent sufficient condition is that the conditional mean treatment and reduced-form outcome are additive in the instruments:
Here \(\pi_j\) and \(\gamma_j\) are the respective changes in conditional mean treatment and outcome when \(Z_j\) changes from 0 to 1, holding the other components fixed. Additivity means these changes do not depend on the values of the other instruments. If \(\pi_j>0\), the ratio \(\theta_j=\gamma_j/\pi_j\) is a local average treatment effect for the units whose treatment is changed by component \(j\), averaged over the distribution of the other instrument components. To see why, under exclusion the outcome change for a unit whose treatment switches is \(Y(1)-Y(0)\); units whose treatment does not switch contribute zero. Monotonicity rules out treatment decreases, so dividing the average outcome change by the average treatment change averages treatment effects among the switchers.
The additive-mean condition is a sufficient condition for the particular representation developed here, not a universal property of instrumental-variable models. Without appropriate conditions, ratios of reduced-form to first-stage coefficients need not be local average treatment effects.
Deriving the 2SLS Weighted Average
Under the additive conditional-mean model, \(\pi\) and \(\gamma\) are the population linear-projection coefficient vectors of \(D\) and \(Y\) on the centered instrument vector. The first-stage fitted value, apart from its intercept, is \(\widehat D=\pi'(Z-E[Z])\). The population 2SLS coefficient is the regression slope of \(Y\) on this fitted value, with an intercept. Its denominator can be written as the covariance between fitted treatment and actual treatment, and its numerator as the covariance between fitted treatment and the outcome.
For the numerator, \(\operatorname{Cov}(\widehat D,Y)=\pi'\operatorname{Cov}(Z,Y)=\pi'\Sigma\gamma\); the second equality follows from \(\operatorname{Cov}(Z,Y)=\Sigma\gamma\). The same reasoning gives \(\operatorname{Cov}(\widehat D,D)=\pi'\operatorname{Cov}(Z,D)=\pi'\Sigma\pi\). Now write each component of \(\gamma\) as \(\gamma_j=\pi_j\theta_j\). Then:
The weights sum to one because \(\sum_j\pi_j(\Sigma\pi)_j=\pi'\Sigma\pi\). If \(\Sigma\) is positive definite and \(\pi\ne 0\), the denominator is positive. But that does not make every numerator positive: \((\Sigma\pi)_j\) can be negative even when \(\pi_j>0\). Thus the weights sum to one but may include negative values or exceed one. They are not necessarily proportions of the population or shares of a group of compliers.
Worked Example: Independent Instruments Give Positive Weights
Suppose two binary instruments are independent, each has probability 0.5 of being 1, and the additive first-stage coefficients are \(\pi_1=0.1\) and \(\pi_2=0.2\). Suppose the instrument-specific local effects are \(\theta_1=2\) and \(\theta_2=5\) outcome units per treatment unit. Independence gives \(\Sigma=0.25I\), where \(I\) is the two-by-two identity matrix.
The weights are proportional to the squared first-stage coefficients, since the common variance factor 0.25 cancels:
They sum to \(1\), and the weighted effect is \(0.2(2)+0.8(5)=0.4+4=4.4\) outcome units per treatment unit. These positive weights arise from the diagonal covariance matrix; they do not establish that positive weights are guaranteed with correlated instruments.
How Correlation Can Produce a Negative Weight
For two instruments, write their covariance matrix as \(\Sigma=\begin{pmatrix}\sigma_1^2&\sigma_{12}\\\sigma_{12}&\sigma_2^2\end{pmatrix}\). Then \((\Sigma\pi)_1=\sigma_1^2\pi_1+\sigma_{12}\pi_2\). Even if both first-stage coefficients are positive, a sufficiently negative covariance \(\sigma_{12}\) can make this expression negative. The instrument’s own positive first-stage shift is then offset, in the fitted-value covariance, by its negative association with the other instrument.
Worked Example: A Negative Weight with Positive First Stages
Consider two binary instruments with marginal probabilities 0.5 and correlation \(-0.6\). Their covariance matrix is \(\Sigma=0.25\begin{pmatrix}1&-0.6\\-0.6&1\end{pmatrix}\). Assume the additive first-stage coefficients are \(\pi=(0.1,0.2)'\), both positive, and the instrument-specific local effects are \(\theta_1=2\) and \(\theta_2=5\). Thus \(\gamma=(0.2,1.0)'\). The negative correlation is feasible for binary variables with these marginal probabilities: the probability that both instruments equal 1 is 0.10, and all four instrument combinations have positive probability.
First calculate the covariance-weighted first-stage vector:
The denominator is \(\pi'\Sigma\pi=0.1(-0.005)+0.2(0.035)=0.0065\), which is positive. Therefore,
The weights sum to \(1\), but the first is negative and the second exceeds \(1\). The weighted effect is \((-1/13)(2)+(14/13)(5)=68/13\approx5.231\) outcome units per treatment unit. As a check using the covariance formula, \(\Sigma\gamma=(-0.1,0.22)'\), so \(\pi'\Sigma\gamma=0.1(-0.1)+0.2(0.22)=0.034\), and \(0.034/0.0065\approx5.231\). This is not a convex average bounded between 2 and 5; that is precisely what a negative weight permits.
A Local-Effect Calculation with Heterogeneity Across Strata
The additive-mean condition is not the only way a weighted local-effect interpretation can arise. For example, if binary instruments are independent, the marginal change associated with one component averages its controlled changes over the distribution of the other components. With componentwise monotonicity, the resulting reduced-form-to-first-stage ratio is a local effect, even if the controlled changes differ across strata. When instruments are independent, their covariance matrix is diagonal, so the corresponding 2SLS weights are nonnegative.
Worked Example: Averaging Stratum-Specific Complier Effects
Suppose \(Z_1\) and \(Z_2\) are independent binary instruments, each with probability 0.5 of being 1. Under a hypothetical potential-outcome model satisfying independence, exclusion, and componentwise monotonicity, changing \(Z_1\) from 0 to 1 changes mean treatment by 0.1 when \(Z_2=0\) and by 0.3 when \(Z_2=1\). The corresponding mean outcome changes are 0.2 and 0.9 outcome units. Changing \(Z_2\) from 0 to 1 changes mean treatment by 0.1 when \(Z_1=0\) and by 0.3 when \(Z_1=1\). The corresponding mean outcome changes are 0.4 and 1.1 outcome units.
Because \(Z_2\) is independent of \(Z_1\), the average first-stage change for \(Z_1\) is \(\pi_1=0.5(0.1)+0.5(0.3)=0.2\). Its average reduced-form change is \(\gamma_1=0.5(0.2)+0.5(0.9)=0.55\). Thus \(\theta_1=0.55/0.2=2.75\) outcome units per treatment unit. Equivalently, the stratum-specific local effects are \(0.2/0.1=2\) and \(0.9/0.3=3\), combined in proportion to their first-stage changes: \((0.1(2)+0.3(3))/(0.1+0.3)=1.1/0.4=2.75\).
For \(Z_2\), \(\pi_2=0.5(0.1)+0.5(0.3)=0.2\), \(\gamma_2=0.5(0.4)+0.5(1.1)=0.75\), and \(\theta_2=0.75/0.2=3.75\). Its stratum-specific local effects are \(0.4/0.1=4\) and \(1.1/0.3=11/3\), combined in proportion to their first-stage changes: \((0.1(4)+0.3(11/3))/(0.1+0.3)=1.5/0.4=3.75\). Independence gives \(\Sigma=0.25I\), so the weights are \(w_1=0.2^2/(0.2^2+0.2^2)=0.5\) and \(w_2=0.2^2/(0.2^2+0.2^2)=0.5\). The 2SLS coefficient is \(0.5(2.75)+0.5(3.75)=1.375+1.875=3.25\) outcome units per treatment unit. This calculation illustrates how a local effect can itself average over instrument strata before 2SLS combines instrument-specific effects.
Interpretation and a Common Pitfall
The weighted-average formula describes the population 2SLS coefficient under the stated model and identification conditions. It does not show that 2SLS always equals the average treatment effect for the population, nor that every instrument-specific ratio is a local effect under minimal instrumental-variable assumptions. The target depends on the instruments’ first stages, their covariance structure, and the assumptions that make the component ratios causal.
A common mistake is to see weights that sum to one and conclude that they must be nonnegative shares, so that 2SLS must lie between the instrument-specific effects. The sum-to-one identity does not imply nonnegativity. In the correlated-instrument example, the weights \(-1/13\) and \(14/13\) sum to one but yield a coefficient greater than both local effects. The correction is to inspect the actual weight formula, including \(\Sigma\), before interpreting the 2SLS coefficient as an average. A negative weight is an algebraic feature of the projection; it is not a negative proportion of people.
In applications, weak first stages create an additional concern: even when the population representation is valid, estimation and inference can be unstable if the instruments predict treatment poorly. The weighted-average derivation is about the estimand and does not remove the need to assess instrument strength or justify the validity assumptions.
Check Your Understanding
Use the definitions and formulas above to answer these questions.
- What assumptions make \(\gamma_j/\pi_j\) an instrument-specific local effect in the additive conditional-mean setup?
- Why do the 2SLS weights sum to one, and why does that fact not guarantee that each weight is nonnegative?
- For two instruments, describe how a negative covariance can make \((\Sigma\pi)_1\) negative even when both first-stage coefficients are positive.
- With independent instruments and first-stage coefficients 0.1 and 0.3, calculate the two 2SLS weights when both instruments have the same variance.
- Does a weighted-average representation establish that the 2SLS coefficient is the population average treatment effect? Explain why or why not.