Why Factor a Likelihood by Event Type?
When a subject can experience one of several competing terminal events, each event type has its own intensity while the subject remains at risk. The observed path records both how long the subject remained event-free and which type of event occurred, if any. A likelihood built from type-specific intensities makes both contributions explicit.
The resulting expression is a product over event types. That is an algebraic factorization, not an assertion that the event types are independent. All types share the same risk process: an event of any type ends follow-up for a terminal competing-risks outcome. The type-specific intensities may also depend on common covariates, shared parameters, or the observed history.
Assume event types are mutually exclusive for a subject: at most one type can occur at any instant, and the first event of any type ends the at-risk period. Conditional on the observed history, the probability of one type-\(k\) event in a short interval of width \(dt\) is \(\lambda_k(t\mid\mathcal{F}_{t-};\theta)dt+o(dt)\); the probability of no event of any type is \(1-\sum_k\lambda_k(t\mid\mathcal{F}_{t-};\theta)dt+o(dt)\). These statements require finite integrated intensities over the observation period and intensities predictable from the history just before each time.
The Joint Path Likelihood
For an observed path through time \(\tau\), let \(dN_k(t)\) denote the increment in the type-\(k\) count at time \(t\). Multiplying the conditional contributions from event times and event-free time gives the path likelihood, up to a factor that does not depend on \(\theta\):
Equivalently, the exponential term is a product of type-specific terms, so the likelihood can be written as
The product over event times supplies a factor for every observed event, while the integrated intensities account for the absence of events over the full at-risk time. With \(\lambda_k=Y\alpha_k\), where \(\alpha_k\) is the event-type rate while at risk, the integral automatically stops contributing after the subject leaves the risk set. For terminal competing risks, an event of any type makes \(Y=0\), so all types share the same stopping time.
Why the Formula Holds
A short-interval argument shows how the event and no-event contributions combine. Suppose there is no event in an interval \([t,t+dt)\). Its conditional likelihood contribution is \(1-\sum_k\lambda_k(t)dt+o(dt)\). If instead a type-\(j\) event occurs, its contribution is \(\lambda_j(t)dt+o(dt)\). Across intervals with no event, multiplying the no-event contributions and taking the limit gives the exponential of minus the integrated total intensity. At each observed event time, the appropriate type-specific intensity supplies the event factor.
At a type-\(j\) event time \(t\), the event contribution is \(\lambda_j(t)dt\); in a continuous-time path density, the interval-width terms are part of the reference measure, leaving the factor \(\lambda_j(t)\). Multiplying these event factors by the event-free contribution yields the displayed likelihood. This argument presumes a simple process with no simultaneous jumps of distinct types. If simultaneous events can occur, their joint mechanism needs its own intensity or event contribution; the formula above does not describe it.
Worked Event-Time Likelihoods
Worked Example: One Type-1 Event at Day 5
Consider one hypothetical subject followed from day 0 until the first event or censoring. While at risk, the constant type-1 intensity is \(0.08\) per day and the type-2 intensity is \(0.12\) per day. A type-1 event occurs on day 5. Assume the intensities are correctly specified and the event time is observed exactly.
The subject is at risk for 5 days, so the integrated total intensity is \((0.08+0.12)(5)=1.00\). The event factor is the type-1 intensity, \(0.08\) per day. Thus the joint event-time density is
The two type-specific factors give the same result: \(L_1=0.08e^{-0.08(5)}=0.05363\) per day and \(L_2=e^{-0.12(5)}=0.5488\); hence \(L_1L_2=0.02943\) per day (rounding aside). The type-2 factor is an event-free contribution, not an observed type-2 event.
Worked Example: Constant Rates with Shared Risk Exposure
In a hypothetical cohort, each subject is followed until a first event or censoring. Suppose the type-1 and type-2 intensities are constant at \(0.10\) and \(0.05\) per person-day while at risk. The observed paths contain 2 type-1 events, 1 type-2 event, and 20 total person-days at risk. Treat the event times and risk histories as observed, and omit factors that do not depend on these rates.
The type-specific likelihood factors are \(L_1=(0.10)^2e^{-0.10(20)}\) and \(L_2=(0.05)e^{-0.05(20)}\). Their product is
The exposure is 20 person-days for each type: the same subjects were at risk for either event type until an event or censoring. The exponential term therefore reflects the total rate of all competing events over that shared exposure. The likelihood is a path likelihood with event-time factors suppressed only when they do not depend on the constant rates; it is not a probability for the count totals alone.
Worked Example: Mutually Exclusive Outcomes Are Not Independent
Suppose, hypothetically, that a subject has constant type-1 and type-2 rates of \(0.10\) and \(0.20\) per day and is observed for one day. Either first event ends follow-up. The probability of a type-\(k\) event during that day is the probability of any event, \(1-e^{-0.30}\), multiplied by the type-\(k\) fraction of the total rate:
The probability of observing both types as the first event by day 1 is zero. If the two event indicators were independent, that probability would be the product of their marginal probabilities, \(0.08639(0.1728)=0.01493\), which is positive. Thus the observed competing outcomes are not independent, even though their path likelihood has a product form.
Assumptions, Censoring, and Diagnostics
The likelihood is appropriate when the recorded event types are exhaustive for the outcomes being modeled, event times and types are observed accurately, and the stated intensities describe the conditional event rates given the available history. The at-risk process must be defined consistently and be predictable. For right-censored paths, follow-up contributes event-free exposure through the censoring time. Censoring can be omitted from the event likelihood when its mechanism is independent of future event occurrence conditional on the modeled history, or when a separate censoring model is handled appropriately. Informative censoring requires additional modeling or a valid adjustment; simply stopping the integral at censoring does not remove the bias.
Useful checks include verifying that each observed event has exactly one type, that every event occurs while the subject is at risk, and that the recorded risk time ends at the first competing event for terminal outcomes. Compare observed event counts with the fitted type-specific intensity contributions, and inspect whether fitted rates vary systematically with time or recorded covariates in ways the model does not capture. Zero fitted intensity at an observed event makes the likelihood zero, signaling a model-data incompatibility. Unmodeled dependence through shared latent factors can also make a conditional-intensity specification inadequate; dependence should be represented through the history or an appropriate joint model rather than dismissed because the expression factors.
| Approach | What it contributes | Important distinction |
|---|---|---|
| Joint path likelihood from intensities | Uses event-type factors and total event-free exposure | Allows each intensity to depend on history; factorization is algebraic |
| Separate type-specific likelihoods | Can be a convenient way to display the product | Cannot generally be treated as independent fits when factors share risk time, history, or parameters |
| Likelihood for counts alone | Uses event totals without necessarily retaining event-time detail | Requires accounting for the distribution of event times and risk histories that were not retained |
A common mistake is to interpret \(\prod_k L_k(\theta)\) as evidence that the competing event processes are independent, or to give each type a separate risk period that continues after another type has occurred. The correction is to use one shared at-risk history, stop risk time at the first terminal event, and interpret the product as the factorization of a single joint path likelihood. Independence assumptions, if needed for a different model or sampling design, must be justified separately.
Check Your Understanding
Answer each question, then compare with the solutions below.
- For two competing types with constant intensities \(0.04\) and \(0.06\) per day, a type-2 event occurs at day 3. Write the event-time likelihood and calculate it.
- Why does a product of type-specific likelihood factors not imply that the competing event types are independent?
- A subject is censored at day 8 without an event. With constant type-specific intensities \(0.03\) and \(0.02\) per day, what event-free contribution enters the likelihood?
- Name two assumptions or data features that would make the displayed terminal competing-risks likelihood inappropriate without modification.
Solutions. (1) The event-time factor is the type-2 rate, multiplied by survival free of either event through day 3: \(L=0.06e^{-(0.04+0.06)(3)}=0.06e^{-0.30}=0.04445\) per day. (2) The product follows from splitting the summed integrated intensity into a sum of type-specific integrals. The types share risk time, and the event indicators are mutually exclusive; the factors may also share parameters or depend on common history. (3) No event factor occurs, so the contribution is \(e^{-(0.03+0.02)(8)}=e^{-0.40}=0.6703\), provided censoring is ignorable for the event likelihood under the stated model. (4) Examples include simultaneous jumps of distinct types, informative censoring not accounted for by the model, unrecorded event types, or a risk indicator that remains active after a terminal event.