Tutorials › Econometrics (Graduate) › Continuous Instruments and Local IV

Instrumental Variables in Causal Analysis · Tutorial 860 of 952

Continuous Instruments and Local IV

Learn when a derivative ratio for a continuous instrument identifies the treatment effect at a particular level of latent resistance.

Advanced 10 min read

What You'll Learn

  • State the conditional independence, exclusion, and monotone treatment-selection conditions for local IV.
  • Express the conditional outcome mean as an integral over latent treatment resistance.
  • Derive the local IV derivative ratio and identify the effect it represents.
  • Distinguish monotone take-up in response to the instrument from monotone treatment response in outcomes.
  • Explain why the derivative ratio is local and why a finite Wald ratio generally averages effects.
  • Recognize when the local IV estimand is undefined or its interpretation is unsupported.

From Instrument Changes to Local Effects

A binary instrument can compare outcome and treatment changes between two instrument values. A continuously varying instrument allows a different question: what treatment effect is associated with a small change in the instrument around a particular value? Under suitable assumptions, the ratio of the resulting outcome slope to the treatment-probability slope identifies the effect for individuals at a specific margin of treatment take-up.

That interpretation is stronger than saying that the instrument predicts treatment, and more local than an average treatment effect. The key is a model in which instrument values move a common threshold for treatment take-up. The location of that threshold determines which latent-resistance group is marginal at each instrument value.

Definition: Let \(Z\) be a continuous instrument, \(X\) observed covariates, \(D\in\{0,1\}\) treatment, and \(Y\) the outcome. Write \(Y(d)\) for the potential outcome under treatment status \(d\), and \(D(z)\) for treatment status under instrument value \(z\). A local IV effect at \(z\) and \(x\) is the effect for individuals at the latent treatment-resistance threshold induced by \(z\), when that threshold is identified by the instrument's local changes in treatment probability and outcome.

Assumptions and the Threshold Model

The argument uses potential outcomes and a scalar latent resistance \(U\), normalized to be uniformly distributed on \([0,1]\) conditional on \(X=x\). The treatment-selection model is \(D=1\{U\leq p(Z,x)\}\), where \(p(z,x)=P(D=1\mid Z=z,X=x)\). Thus \(p(z,x)\) is both the treatment probability at \(z,x\) and the threshold in the resistance scale. Individuals with lower \(U\) are more inclined to take treatment.

  • Conditional independence: \(Z\) is independent of \((Y(0),Y(1),U)\) conditional on \(X\). This excludes confounding of instrument variation by the potential outcomes or latent resistance, given the covariates.
  • Exclusion: the instrument affects the observed outcome only through treatment; the outcome under treatment status \(d\) is \(Y(d)\), not a separate function of \(Z\).
  • Monotone treatment selection: treatment follows the threshold rule \(D=1\{U\leq p(Z,X)\}\). As the instrument changes, it shifts the threshold rather than causing some people to move into treatment while others move out in an unrestricted way.
  • Regularity and relevance: the conditional means exist, \(p(z,x)\) is differentiable at the value considered, and its derivative with respect to \(z\) is nonzero. The treatment probability must respond locally to the instrument.

Here, monotonicity concerns how treatment take-up responds to the instrument. It is not the separate outcome restriction sometimes called monotone treatment response, \(Y(1)\geq Y(0)\). That outcome restriction is not required for the derivative-ratio result. If it is imposed as an additional assumption, it implies nonnegative individual treatment effects, but it is conceptually distinct from monotone treatment selection.

Define \(m_d(u,x)=E[Y(d)\mid U=u,X=x]\) and \(\Delta(u,x)=m_1(u,x)-m_0(u,x)\). The quantity \(\Delta(u,x)\) is the mean treatment effect at resistance level \(u\), conditional on \(X=x\). It need not be constant across \(u\); that heterogeneity is precisely why a local effect can differ from a population average.

Deriving the Local IV Ratio

For a fixed \(x\), write \(g(z,x)=E[Y\mid Z=z,X=x]\). Conditional independence and exclusion let us calculate this mean by integrating the potential-outcome means over the resistance values assigned to each treatment status. People with \(U\leq p(z,x)\) receive treatment; those with \(U>p(z,x)\) do not. Since \(U\mid X=x\) is uniform,

$$ g(z,x)=\int_0^{p(z,x)}m_1(u,x)\,du +\int_{p(z,x)}^1m_0(u,x)\,du. $$

Rearranging this expression is important. It gives a term that does not depend on the instrument and a single integral with a moving upper endpoint:

$$ g(z,x)=\int_0^1m_0(u,x)\,du +\int_0^{p(z,x)}\Delta(u,x)\,du. $$

Suppose \(\Delta(u,x)\) is continuous at \(u=p(z,x)\). The fundamental theorem of calculus and the chain rule then give the outcome-mean derivative. The treatment mean is \(E[D\mid Z=z,X=x]=p(z,x)\), so its derivative is the first-stage slope.

$$ \frac{\partial g(z,x)}{\partial z} =\Delta(p(z,x),x)\frac{\partial p(z,x)}{\partial z}, \qquad \frac{\partial E[D\mid Z=z,X=x]}{\partial z} =\frac{\partial p(z,x)}{\partial z}. $$

When the first-stage slope is nonzero, division cancels the instrument-induced change in the threshold:

$$ \frac{\partial E[Y\mid Z=z,X=x]/\partial z} {\partial E[D\mid Z=z,X=x]/\partial z} =\Delta(p(z,x),x). $$

This is the local IV estimand. It identifies the conditional mean treatment effect at the resistance threshold \(u=p(z,x)\), not necessarily the effect for every individual who changes treatment over a broad interval of instrument values.

Key result: Under conditional independence, exclusion, the threshold treatment-selection model, differentiability of \(p(z,x)\), continuity of \(\Delta(u,x)\) at \(p(z,x)\), and a nonzero first-stage derivative, the local derivative ratio equals \(\Delta(p(z,x),x)\). The outcome-mean derivative is justified by differentiating the combined expression with \(\Delta\), not by requiring separate derivatives of the two integrals involving \(m_0\) and \(m_1\).

Worked Example: A Linear Treatment-Probability Curve

Consider a hypothetical setting with no covariates, where \(z\) ranges from 0 to 6 and \(p(z)=0.2+0.1z\). Suppose the conditional untreated outcome mean at every resistance level is \(m_0(u)=10\), while the treatment-effect curve is \(\Delta(u)=2+4u\). These functions imply the treated-outcome mean \(m_1(u)=12+4u\). Assume the instrument is conditionally independent of the potential outcomes and resistance, affects outcomes only through treatment, and treatment follows the stated threshold rule. The probability is between 0.2 and 0.8 over the specified instrument range, and the first-stage slope is nonzero.

At \(z=3\), the threshold is \(p(3)=0.2+0.1(3)=0.5\). The outcome mean is

$$ g(z)=\int_0^1 10\,du+\int_0^{p(z)}(2+4u)\,du =10+2p(z)+2p(z)^2. $$

Differentiating with respect to \(z\) gives \(g'(z)=(2+4p(z))p'(z)\). At \(z=3\), \(p'(z)=0.1\), so \(g'(3)=(2+4(0.5))(0.1)=0.4\) outcome units per instrument unit. The treatment-probability derivative is \(p'(3)=0.1\) probability points per instrument unit. Therefore,

$$ \frac{g'(3)}{p'(3)}=\frac{0.4}{0.1}=4 \quad\text{outcome units per treatment}. $$

This equals \(\Delta(0.5)=2+4(0.5)=4\): the mean effect at the resistance level made marginal by \(z=3\).

Regularity: Differentiate the Combined Mean

The derivation does not require \(m_0\) and \(m_1\) to be individually continuous at the threshold. It requires continuity of their difference \(\Delta\) there, so the combined integral has a derivative. This distinction matters: separate moving-endpoint integrals can each have a corner even when their sum is differentiable.

Worked Example: A Discontinuous Baseline Mean

For a hypothetical instrument ranging over values that give \(p(z)=0.4+0.1z\), let \(m_0(u)=5+2\,1\{u>0.5\}\) and \(m_1(u)=m_0(u)+(1+u)\). Thus \(m_0\) and \(m_1\) jump at \(u=0.5\), but \(\Delta(u)=1+u\) is continuous. Assume the same conditional independence, exclusion, and threshold-selection conditions as above. At \(z=1\), \(p(1)=0.5\).

The fixed baseline integral is \(\int_0^1m_0(u)\,du=5+2(0.5)=6\), and the treatment-effect integral up to the threshold is \(\int_0^{0.5}(1+u)\,du=0.5+0.125=0.625\). Hence \(g(1)=6.625\). Differentiating the combined representation gives

$$ g'(1)=\Delta(0.5)p'(1)=(1+0.5)(0.1)=0.15. $$

The treatment-probability derivative is \(0.1\), so the ratio is \(0.15/0.1=1.5\) outcome units per treatment. This equals \(\Delta(0.5)=1.5\). No derivative of either separate integral at its corner is needed.

Local Slopes and Finite Instrument Changes

A derivative ratio uses an infinitesimal instrument change at a particular \(z\). A finite comparison between \(z_0\) and \(z_1\) generally has a different interpretation. Under the same threshold model, if \(p(z_1,x)>p(z_0,x)\), the finite outcome change is the integral of \(\Delta(u,x)\) over the resistance interval between the two thresholds. Dividing by the treatment-probability change averages those effects over that interval. It equals the local effect at one endpoint only under additional conditions, such as a constant treatment effect over the interval.

Worked Example: A Finite Wald Ratio Averages Local Effects

Suppose, hypothetically, \(p(z)=0.2+0.1z\), \(m_0(u)=0\), and \(\Delta(u)=1+4u\). Assume conditional independence, exclusion, and threshold selection hold, and consider \(z_0=1\) and \(z_1=5\). The thresholds are \(p(z_0)=0.3\) and \(p(z_1)=0.7\), so the first-stage difference is \(0.7-0.3=0.4\).

Here the conditional outcome mean is \(g(z)=\int_0^{p(z)}(1+4u)\,du=p(z)+2p(z)^2\). Thus \(g(z_0)=0.3+2(0.3)^2=0.48\), and \(g(z_1)=0.7+2(0.7)^2=1.68\). The finite Wald ratio is

$$ \frac{g(z_1)-g(z_0)}{p(z_1)-p(z_0)} =\frac{1.68-0.48}{0.7-0.3} =\frac{1.20}{0.40}=3. $$

This is the average of \(1+4u\) over \(u\in[0.3,0.7]\), not the local effect at \(z_0\), which is \(\Delta(0.3)=2.2\), or at \(z_1\), which is \(\Delta(0.7)=3.8\). The distinction is between an interval average and a point-specific effect.

Interpretation, Scope, and Common Pitfalls

The local IV result is useful when treatment effects vary with latent resistance: it explains what a continuous instrument's local outcome slope, relative to its local first-stage slope, can identify. It does not by itself identify the average treatment effect, and it does not establish that the effect is representative of people whose resistance levels lie elsewhere. With covariates, the result is conditional on \(X=x\); combining results across covariate values requires a separately specified aggregation.

  • Calling the ratio an ATE. The ratio identifies \(\Delta(p(z,x),x)\), a local mean effect at a threshold, rather than an average over the full population.
  • Using a finite Wald ratio as a derivative ratio. A finite instrument contrast generally averages effects across the threshold interval it traverses.
  • Ignoring a weak local first stage. If \(\partial p(z,x)/\partial z=0\), the derivative ratio is undefined. If it is near zero, estimation can be unstable even when the population ratio is mathematically defined.
  • Assuming an instrument is valid because it is continuous. A continuum of instrument values does not establish conditional independence or exclusion; these remain substantive assumptions.
  • Differentiating the two moving-endpoint integrals separately. Their derivatives may fail to exist when the component means are discontinuous. Rewrite the outcome mean using the fixed baseline integral and the continuous difference \(\Delta\) before applying the chain rule.

The identification statement is about population conditional means and their derivatives. Estimating those derivatives from data requires additional statistical choices, such as how to smooth the conditional means and how to quantify uncertainty. Those choices do not replace the causal assumptions or change the target estimand.

Check Your Understanding

Use the assumptions and definitions above to answer these questions.

  1. What does the local IV derivative ratio identify at instrument value \(z\) and covariate value \(x\)?
  2. Why is continuity of \(\Delta(u,x)\) at the threshold sufficient for the outcome-mean derivative used in the derivation, even if \(m_0\) is discontinuous there?
  3. In the threshold model, what does a zero derivative of the treatment probability imply for the local derivative ratio?
  4. How does a finite Wald ratio differ from the local IV derivative ratio when treatment effects vary with resistance?
  5. Is the condition \(Y(1)\geq Y(0)\) required for the derivative-ratio result? Explain how it differs from monotone treatment selection.
Clinical Biostats