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Weak Instruments and Identification · Tutorial 202 of 952

Identified Sets When First-Stage Strength Is Zero

See how zero first-stage strength leaves every admissible coefficient observationally compatible when the reduced form is also zero, and when the resulting set is empty instead.

Advanced 10 min read

What You'll Learn

  • Express the structural coefficient’s restrictions through the first-stage and reduced-form coefficients.
  • Characterize the identified set when all first-stage coefficients are zero.
  • Distinguish an unrestricted identified set from one bounded by parameter restrictions.
  • Recognize when reduced-form and first-stage coefficients are incompatible with the maintained model.
  • Explain why a zero first stage does not imply a zero structural effect or point identification.

Why Zero First-Stage Strength Changes the Identification Question

Instrumental variables use variation in an instrument that predicts the endogenous regressor to learn about a structural coefficient. When the population first-stage coefficient is zero, that source of variation is absent. The central question is then not how to calculate a ratio of reduced-form to first-stage coefficients, but which structural values remain consistent with the population reduced forms and the maintained assumptions.

The answer depends on both reduced forms. If the instrument has no population association with the endogenous regressor and also has no population association with the outcome, the reduced forms impose no restriction on the structural coefficient. If the first stage is zero but the outcome reduced form is nonzero, the two cannot be reconciled with the usual linear instrumental-variables model and its exclusion restriction. Parameter-space restrictions can limit the set of compatible coefficients, but they do not create identification from the instrument.

Reduced Forms and the Identified Set

Consider a scalar endogenous regressor \(D\), an outcome \(Y\), and a vector of \(K\) instruments \(Z\). Assume variables have been centered and any included exogenous controls have been partialled out. Write the structural equation and the two population reduced forms as

$$ Y=\beta D+U,\qquad D=Z'\boldsymbol{\pi}+V,\qquad Y=Z'\boldsymbol{\delta}+\varepsilon. $$

Here \(\beta\) is the structural coefficient of interest, \(\boldsymbol{\pi}\) is the \(K\)-vector of first-stage coefficients, and \(\boldsymbol{\delta}\) is the \(K\)-vector of reduced-form coefficients for the outcome. The errors \(V\) and \(\varepsilon\) are the population linear-projection residuals, so they are orthogonal to the instruments. The structural error is \(U=Y-\beta D\).

The maintained instrumental-variables assumptions relevant to the argument are that the structural equation holds and the instruments are excluded from it: \(E[ZU]=\boldsymbol{0}\). Instruments must also have enough independent variation for the stated reduced-form coefficient vectors to be defined. This tutorial characterizes the population set implied by these restrictions; it does not treat sample estimates as if they were population coefficients.

Definition: Given a maintained model and an admissible parameter space \(\mathcal{B}\), the identified set for \(\beta\) is the set of all values in \(\mathcal{B}\) that are consistent with the population observable implications of the model. A singleton set means point identification; a set with multiple values means the parameter is not point identified; an empty set means the maintained model and population implications are incompatible.

The key population implication comes from substituting the first stage into the structural equation. Since \(Y=\beta D+U\), its instrument-related component is \(\beta Z'\boldsymbol{\pi}\), while the exclusion restriction prevents \(U\) from contributing an instrument-related component. Therefore the reduced-form coefficients must satisfy

$$ \boldsymbol{\delta}=\beta\boldsymbol{\pi}. $$

This is a vector equality: every instrument’s outcome reduced-form coefficient must equal its first-stage coefficient multiplied by the same structural coefficient. Consequently, the identified set based on these reduced-form restrictions is

$$ \mathcal{I}(\beta) = \left\{b\in\mathcal{B}:\boldsymbol{\delta}=b\boldsymbol{\pi}\right\}. $$

What Happens When the First Stage Is Zero?

Zero first-stage strength means that every component of the population first-stage vector is zero: \(\boldsymbol{\pi}=\boldsymbol{0}\). It does not merely mean that one instrument has a zero coefficient while another predicts \(D\). Substituting the zero vector into the reduced-form restriction gives

$$ \boldsymbol{\delta} = \beta\boldsymbol{0} = \boldsymbol{0} \quad\text{for every } \beta. $$

There are two cases. If the outcome reduced-form vector is also zero, every value allowed by \(\mathcal{B}\) satisfies the reduced-form restriction. If the outcome reduced-form vector is not zero, no value of \(\beta\) can satisfy it. Thus the set is not automatically all real numbers: it is all of the admissible parameter space in the compatible case, and empty in the incompatible case.

$$ \mathcal{I}(\beta)= \begin{cases} \mathcal{B}, & \boldsymbol{\pi}=\boldsymbol{0}\ \text{and}\ \boldsymbol{\delta}=\boldsymbol{0},\\ \varnothing, & \boldsymbol{\pi}=\boldsymbol{0}\ \text{and}\ \boldsymbol{\delta}\ne\boldsymbol{0}. \end{cases} $$

The result can be justified directly from the definition. In the first case, for any \(b\in\mathcal{B}\), \(b\boldsymbol{\pi}=b\boldsymbol{0}=\boldsymbol{0}=\boldsymbol{\delta}\); hence every admissible value belongs to the set. In the second case, for every \(b\), \(b\boldsymbol{\pi}=\boldsymbol{0}\), which cannot equal a nonzero \(\boldsymbol{\delta}\); hence no admissible value belongs to the set. This argument establishes the characterization without dividing by a first-stage coefficient.

Worked Example: An Unrestricted Coefficient With Zero Reduced Forms

Suppose a hypothetical population has one instrument, with first-stage coefficient \(\pi=0\) and outcome reduced-form coefficient \(\delta=0\). Let the structural parameter space be unrestricted, \(\mathcal{B}=\mathbb{R}\). Find the identified set.

For one instrument, the restriction is \(\delta=\beta\pi\). Substituting the hypothetical population coefficients gives

$$ 0=\beta(0)=0. $$

This equality holds for every real \(\beta\). Therefore \(\mathcal{I}(\beta)=\mathbb{R}\). The structural coefficient is not point identified: the reduced forms do not distinguish, for example, \(\beta=-2\), \(\beta=0\), and \(\beta=4\). In particular, \(\delta=0\) does not imply \(\beta=0\); the product is zero because the first-stage coefficient is zero.

Bounded and Otherwise Restricted Parameter Spaces

The identified set is defined relative to the admissible space \(\mathcal{B}\), which may contain substantive restrictions on \(\beta\). A bounded parameter space can make the set bounded even though the instruments provide no information that selects one coefficient over another. The bound comes from the maintained restriction, not from the zero-strength instrument.

Worked Example: A Bounded Parameter Space

Suppose the hypothetical population reduced forms again have \(\pi=0\) and \(\delta=0\), but substantive knowledge restricts the coefficient to \(\mathcal{B}=[-1.5,2]\), measured as outcome units per unit of \(D\). Determine the identified set.

The compatibility equation is

$$ \delta=\beta\pi \quad\Longrightarrow\quad 0=\beta(0)=0. $$

Thus every \(\beta\) in the admissible interval satisfies the restriction, and values outside that interval are excluded by the parameter-space assumption. The identified set is \(\mathcal{I}(\beta)=[-1.5,2]\) outcome units per unit of \(D\). This is a bounded set, but it is not a point: the reduced forms have not narrowed the allowed interval at all.

More generally, if \(\mathcal{B}\) is any specified set, including a union of intervals or a discrete set, zero first-stage strength with zero outcome reduced forms gives \(\mathcal{I}(\beta)=\mathcal{B}\). The shape of the identified set in this case is inherited entirely from the admissible parameter space.

Boundedness should not be confused with identification. A narrow admissible range may be useful in an application, but unless the population restrictions reduce it to one value, the structural coefficient remains set identified. Nor does a parameter restriction repair a conflict between the two reduced forms: if \(\boldsymbol{\pi}=\boldsymbol{0}\) and \(\boldsymbol{\delta}\ne\boldsymbol{0}\), restricting \(\beta\) to a bounded interval still leaves the identified set empty.

Worked Example: Nonzero Outcome Reduced Form and an Empty Set

Consider a hypothetical model with two instruments. Let \(\boldsymbol{\pi}=(0,0)'\), let \(\boldsymbol{\delta}=(0,0.12)'\), and suppose \(\mathcal{B}=[-3,3]\). The second reduced-form coefficient is measured in outcome units per unit of the second instrument. Determine whether any admissible coefficient satisfies the model.

For every \(\beta\in[-3,3]\), multiplication gives

$$ \beta\boldsymbol{\pi} = \beta \begin{pmatrix} 0\\ 0 \end{pmatrix} = \begin{pmatrix} 0\\ 0 \end{pmatrix}. $$

The required equality would be \((0,0.12)'=(0,0)'\), which is false because \(0.12\ne0\). Therefore \(\mathcal{I}(\beta)=\varnothing\), even under the bounded parameter restriction. Under the maintained linear equations and exclusion restriction, the hypothetical population coefficients cannot jointly hold. An empty set flags incompatibility with those maintained restrictions; it does not indicate that \(\beta\) is some particular value outside the interval.

Interpretation and Practical Importance

When first-stage strength is zero and both reduced forms are zero, the data implications used here are consistent with every admissible structural coefficient. There is no valid ratio \(\delta/\pi\): it would be \(0/0\), which is undefined and does not determine a value. When the outcome reduced form is nonzero, a nonzero numerator divided by a zero first-stage coefficient is also not a meaningful estimate of \(\beta\); the population restrictions instead conflict.

These are statements about population identification. In an empirical analysis, estimated first-stage and reduced-form coefficients are random and need not equal zero exactly. A small estimated first stage is not by itself proof that the population first stage is exactly zero, and plugging noisy estimates into a ratio does not answer the population set-identification question. Weak-instrument-robust inference addresses uncertainty in settings where conventional ratio-based inference can be unreliable; the population characterization here explains the limiting identification problem when strength is exactly zero.

The vector formulation also clarifies what “zero strength” means with several instruments. All first-stage coefficients must be zero for the result above to apply. If at least one component of \(\boldsymbol{\pi}\) is nonzero, the equation \(\boldsymbol{\delta}=\beta\boldsymbol{\pi}\) can restrict \(\beta\); the zero-strength case is specifically the case where no component supplies that restriction.

Common Pitfall

  • Wrong reasoning: “The instrument has no effect on \(D\), so the structural effect \(\beta\) must be zero.” This confuses the first-stage coefficient, which describes how the instrument predicts \(D\), with the structural coefficient describing how \(D\) relates to \(Y\).
  • Correction: Use \(\boldsymbol{\delta}=\beta\boldsymbol{\pi}\). When \(\boldsymbol{\pi}=\boldsymbol{0}\) and \(\boldsymbol{\delta}=\boldsymbol{0}\), every admissible \(\beta\) satisfies the restriction. When \(\boldsymbol{\delta}\ne\boldsymbol{0}\), no \(\beta\) does. Neither case identifies \(\beta=0\).
  • Another error: Calling a bounded admissible interval a point estimate. A bounded identified set can still contain many values; state its endpoints and the assumptions that impose them.
Key takeaway: With zero population first-stage coefficients, the reduced-form restriction becomes \(\boldsymbol{\delta}=\boldsymbol{0}\), independent of \(\beta\). If that restriction holds, the identified set is exactly the admissible parameter space; if it fails, the set is empty.

Check Your Understanding

Use the population restriction \(\boldsymbol{\delta}=\beta\boldsymbol{\pi}\) and state any parameter-space assumption needed.

  1. With one instrument, \(\pi=0\), \(\delta=0\), and \(\mathcal{B}=\mathbb{R}\), what is the identified set? Is \(\beta\) point identified?
  2. If the same reduced forms hold but \(\mathcal{B}=[0,5]\), what determines the endpoints of the identified set?
  3. With two instruments, \(\boldsymbol{\pi}=(0,0)'\) and \(\boldsymbol{\delta}=(0,0.03)'\), can any structural coefficient satisfy the reduced-form restriction?
  4. Why is \(\delta/\pi\) not a valid way to identify \(\beta\) when \(\delta=\pi=0\)?
  5. With multiple instruments, does one zero first-stage coefficient establish the zero-strength case used in this tutorial? Explain.
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