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Endogeneity and Control Functions · Tutorial 238 of 952

Probit With An Endogenous Continuous Regressor

Learn to derive and interpret a probit control function for a continuous endogenous regressor, and to quantify how accounting for endogeneity changes probability predictions and effects.

Advanced 8 min read

What You'll Learn

  • Derive the control-function term from the conditional distribution of jointly normal errors.
  • Specify the first-stage and binary-outcome equations and the conditions they require.
  • Interpret the residual coefficient as conditional dependence on the first-stage disturbance.
  • Calculate fitted probabilities with and without the residual term.
  • Distinguish a structural probability effect from a derivative along the observed first-stage relationship.
  • Recognize why ordinary probit standard errors do not account for an estimated residual.

Why a Continuous Endogenous Regressor Changes Probit

A binary outcome is often modeled with a probit equation, but the usual probit interpretation relies on the included regressors being conditionally unrelated to the outcome disturbance. If a continuous regressor is endogenous, its values contain information about that disturbance. A probit equation that omits this dependence can therefore give misleading conditional probabilities and probability effects.

A control-function approach makes the dependence explicit. It models the endogenous regressor using an instrument and exogenous covariates, then includes the first-stage residual in the probit index. Under joint normality, this residual is a sufficient control for the dependence in the model described below. This is a distributional result, not a general recipe that works regardless of the error assumptions.

Definition: Let \(Y\) be a binary outcome, \(D\) a continuous endogenous regressor, \(X\) a vector of exogenous covariates, and \(Z\) an excluded instrument. A recursive probit control-function model specifies a first stage for \(D\), a latent-index equation for \(Y\), and a probit probability conditional on the first-stage residual.

Model and Conditional-Normal Derivation

Write the first stage and latent outcome equation as

$$ D = m(X,Z) + V,\qquad Y^* = X'\beta + \delta D + U,\qquad Y = \mathbf{1}\{Y^*>0\}. $$

Here \(m(X,Z)\) is the conditional mean of \(D\) given the exogenous variables and instrument, \(V\) is the first-stage disturbance, and \(U\) is the outcome disturbance. The outcome is observed as \(Y=1\) when the latent index \(Y^*\) is positive. Assume that, conditional on \(X,Z\), \(U\) and \(V\) have mean zero, are jointly normal, and have constant variances and covariance. In particular, \(\operatorname{Var}(V)=\sigma_v^2>0\) and \(\operatorname{Cov}(U,V)=\sigma_{uv}\). Also assume \(\tau^2=\sigma_u^2-\sigma_{uv}^2/\sigma_v^2>0\), so the conditional variance of \(U\) given \(V\) is positive. The instrument is relevant for \(D\), is independent of the structural outcome disturbance conditional on \(X\), and is excluded from the structural outcome equation.

For jointly normal disturbances, the conditional mean of \(U\) given \(V=v\) is linear in \(v\). Define \(\kappa=\sigma_{uv}/\sigma_v^2\). Then

$$ U = \kappa V + E,\qquad E=U-\kappa V,\qquad E\mid V \sim N(0,\tau^2),\qquad \tau^2=\sigma_u^2-\frac{\sigma_{uv}^2}{\sigma_v^2}. $$

The conditional variance formula follows by subtracting the variance explained by the linear projection of \(U\) on \(V\). Joint normality also makes \(E\) independent of \(V\); under the stated conditional model, its conditional distribution does not depend on \(X,Z,V\). Substituting \(V=D-m(X,Z)\) into the outcome equation gives

$$ P(Y=1\mid X,D,Z) = \Phi\!\left( \frac{X'\beta+\delta D+\kappa[D-m(X,Z)]}{\tau} \right). $$

A probit model normalizes the scale of its latent disturbance. Thus the coefficients estimated in the conditional probit are the scale-normalized coefficients \(b=\beta/\tau\), \(\theta=\delta/\tau\), and \(\rho=\kappa/\tau\), rather than the unscaled latent-equation coefficients. In practice, estimate the first stage, form the residual \(\hat V=D-\hat m(X,Z)\), and estimate a probit with \(X,D,\hat V\) as regressors. Its index is \(X'b+\theta D+\rho\hat V\).

Worked Examples

Worked Example: Forming a First-Stage Residual and Outcome Index

Suppose a hypothetical first stage, with one covariate \(X\) and instrument \(Z\), is \(\hat m(X,Z)=2+0.6Z+0.3X\). For an observation with \(X=1\), \(Z=2\), and \(D=4.1\), calculate the residual. Suppose the estimated probit index is \(-0.2+0.5X+0.4D+0.3\hat V\).

The fitted value is \(2+0.6(2)+0.3(1)=3.5\). Therefore \(\hat V=4.1-3.5=0.6\). Substituting the observed values into the outcome index gives

$$ -0.2+0.5(1)+0.4(4.1)+0.3(0.6) =-0.2+0.5+1.64+0.18=2.12. $$

The fitted conditional probability is \(\Phi(2.12)\), approximately \(0.9830\). The residual is not a replacement value for \(D\): both \(D\) and its first-stage residual enter the outcome index. This calculation illustrates the plug-in procedure; it does not establish that the instrument or distributional assumptions hold.

Worked Example: How the Residual Changes a Probability Prediction

Consider a hypothetical observation for which the probit index excluding the residual term is \(0.65\), and the estimated residual contribution is \(0.20\). Compare the probit probability that omits this contribution with the control-function probability.

Without the residual, the probability is \(\Phi(0.65)\approx0.7421539\). Including the residual gives an index of \(0.65+0.20=0.85\), so the probability is \(\Phi(0.85)\approx0.8023375\). The change, calculated from the unrounded probabilities, is

$$ \Phi(0.85)-\Phi(0.65) \approx 0.8023375-0.7421539 =0.0601836 \approx 0.0602. $$

Thus, for this hypothetical covariate pattern, including the residual increases the fitted conditional probability by about \(0.0602\), or \(6.02\) percentage points. This is a comparison of two model predictions, not a causal effect of changing the residual. The residual term also changes the point at which the normal density is evaluated, so it can change a probability effect even when the coefficient on \(D\) is unchanged.

Worked Example: Comparing Probability Effects

Suppose the coefficient on \(D\) in a hypothetical control-function probit is \(\theta=0.8\). At the same covariate values as in the previous example, the index is \(0.85\) when the residual is included and \(0.65\) when it is omitted. Calculate the local structural probability effect of a one-unit increase in \(D\), holding the control value fixed, at each index.

For a probit index \(\eta\), the derivative with respect to \(D\), holding \(X\) and the control value fixed, is \(\theta\phi(\eta)\), where \(\phi\) is the standard normal density. With the residual included,

$$ 0.8\phi(0.85)\approx 0.8(0.2780)=0.2224. $$

Without the residual contribution, the corresponding calculation is

$$ 0.8\phi(0.65)\approx 0.8(0.3230)=0.2584. $$

At these values, the local effect is about \(0.0360\) probability units smaller when the residual is included. Equivalently, the local effects are about \(22.24\) and \(25.84\) percentage points per unit of \(D\), respectively. These are local derivatives, not constant changes in probability for every one-unit increase. They describe the structural response holding the control value fixed. If \(D\) changes along the first-stage relationship with \(X,Z\) fixed, then \(V=D-m(X,Z)\) changes too; differentiating that conditional prediction includes the residual term's coefficient as well.

Interpreting the Residual Coefficient

The coefficient \(\rho\) on the first-stage residual captures conditional dependence between the outcome disturbance and the part of \(D\) not predicted by \(X,Z\), on the probit's normalized latent scale. Its sign indicates the direction of that dependence under this model. A positive \(\rho\) means that, conditional on the included covariates and \(D\), larger first-stage residuals are associated with a higher latent outcome index. A negative \(\rho\) indicates the opposite direction.

The residual coefficient is not a probability-point effect, and it is not the effect of the instrument on the outcome. Nor is it, by itself, proof of endogeneity: its interpretation depends on the joint-normal control-function specification and valid instruments. The coefficient \(\theta\) is the normalized structural coefficient on \(D\); the probability effect at a given index also depends on the normal density at that index.

Worked Example: From Error Covariance to a Residual Contribution

Suppose a hypothetical model has \(\operatorname{Var}(V)=0.64\), \(\operatorname{Cov}(U,V)=0.36\), and \(\operatorname{Var}(U)=1\). Compute the raw conditional-mean coefficient \(\kappa\), the conditional variance \(\tau^2\), and the residual contribution to the normalized probit index when \(V=0.4\).

First,

$$ \kappa=\frac{0.36}{0.64}=0.5625,\qquad \tau^2=1-\frac{0.36^2}{0.64} =1-\frac{0.1296}{0.64} =0.7975. $$

Thus \(\tau=\sqrt{0.7975}\approx0.8930\). The raw conditional mean contribution is \(\kappa V=0.5625(0.4)=0.2250\). On the normalized probit index, the contribution is

$$ \rho V=\frac{\kappa}{\tau}V =\frac{0.5625}{0.8930}(0.4) \approx0.2520. $$

The positive contribution reflects the positive covariance in this hypothetical example. The normalized coefficient is not simply the covariance ratio: dividing by \(\tau\) is necessary because the conditional probit index has unit latent-error scale.

Conditions, Estimation, and Common Pitfalls

The control-function probit requires more than a first-stage regression. Its interpretation depends on a correctly specified conditional mean for \(D\), instrument relevance, and an exclusion restriction: \(Z\) affects \(Y\) through \(D\), not directly through the structural outcome equation. The instrument must also be exogenous with respect to the structural outcome disturbance, conditional on \(X\). The derivation above additionally uses joint normality and constant conditional variances and covariance. If these assumptions fail, the residual need not capture the relevant dependence, and a linear residual term may be misspecified.

In estimation, the first-stage residual is estimated, not observed. Inference must therefore account for that estimation; treating \(\hat V\) as fixed in an ordinary second-stage probit generally gives incorrect standard errors. Use an inference method appropriate for estimated control functions, such as a suitable stacked-estimation variance calculation or bootstrap procedure. This issue affects uncertainty estimates even when the fitted two-step coefficients are the quantities of interest.

  • Wrong: “The residual coefficient is the change in the probability for a one-unit increase in the residual.” Correction: It is a coefficient on the normalized latent index; probability changes depend on the index through \(\phi(\eta)\).
  • Wrong: “Adding the residual makes the coefficient on \(D\) itself a probability effect.” Correction: A local probability effect also requires evaluating the normal density at the relevant index.
  • Wrong: “A significant residual coefficient proves that the instrument is valid.” Correction: The residual coefficient concerns conditional dependence under the model; instrument validity requires separate substantive and statistical justification.
  • Wrong: “The control function works because any first-stage residual removes endogeneity.” Correction: The scalar residual has this role here because of the specified conditional-normal structure and first stage.
Key takeaway: Under a valid, relevant excluded instrument and the stated joint-normal assumptions, the first-stage residual represents the part of the endogenous regressor associated with the outcome disturbance. Including it gives a conditional probit model whose probability effects depend both on the coefficient for the continuous regressor and on the residual-adjusted index.

Check Your Understanding

Work through these questions using the model assumptions stated above.

  1. Why does joint normality imply that the conditional mean of \(U\) given \(V\) is linear in \(V\)?
  2. What does the sign of the residual coefficient indicate, and why is it not itself a probability effect?
  3. If the first-stage residual contribution raises a probit index, must the local probability effect of \(D\) increase? Explain using the normal density.
  4. State the instrument exclusion restriction in words and explain why first-stage relevance alone is insufficient.
  5. Why must inference account for the fact that the first-stage residual is estimated?
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