Why Serial Correlation Changes the State
A dynamic choice model is memoryless when its state contains enough information to determine the distribution of future payoffs and states, conditional on the current state and action. If payoff shocks persist over time, the observed state alone may not contain that information. A shock realized today can both affect today's decision and predict tomorrow's payoff shock. The choices observed in the past can therefore matter for predicting future choices, even after conditioning on the currently observed state.
The modeling response is to include the relevant current shock in the state. The resulting state may be partly latent to the econometrician, but it can still be the correct state for the decision-maker's dynamic problem. This is a structural modeling step, not merely a correction to a standard error or a different choice-probability formula.
A Choice Model With Persistent Payoff Shocks
Let \(x_t\) denote the observed state at time \(t\), \(a_t\) the chosen action, and \(z_t\) a vector of payoff shocks. The vector can have one component for each action, so that \(z_{a,t}\) is the persistent shock associated with action \(a\). A simple utility specification is
The key feature is that \(z_t\) evolves over time rather than being redrawn independently each period. For example, it may follow a vector autoregression of the form
where \(\eta_{t+1}\) is a new innovation. In a scalar version, a common specification is \(|\rho|<1\) and \(\eta_{t+1}\sim N(0,\sigma_\eta^2)\), independent across time. A positive \(\rho\) means a high current shock tends to predict a high next-period shock. The model must also specify how the observed state evolves, for example through a transition probability \(P(x_{t+1}\mid x_t,a_t)\).
For the formulation below, suppose the decision-maker observes \(z_t\) when choosing. The econometrician may not observe it. Suppose also that the observed-state transition and shock transition together have a specified conditional distribution given the current state and action. If they are conditionally independent, their joint transition distribution factors into \(P(x_{t+1}\mid x_t,a_t)\) and \(Q(z_{t+1}\mid z_t,x_t,a_t,x_{t+1})\). If they are not independent, the model must specify the joint distribution directly.
The decision-maker's state is then \(s_t=(x_t,z_t)\). The observed component alone may still follow a Markov transition, but it is not generally a sufficient state for the choice problem: knowing \(x_t\) does not reveal the current persistent shock or the distribution of the next one.
Worked Example: Same Observed State, Different Future Choice Probabilities
Consider two actions. Action 1 has utility \(d+z_t\), action 0 has utility zero, and \(d=-0.2\). The shock follows \(z_{t+1}=0.7z_t+\eta_{t+1}\), where \(\eta_{t+1}\sim N(0,0.5^2)\). There is no additional choice noise, so action 1 is chosen next period exactly when \(d+z_{t+1}>0\), or \(z_{t+1}>0.2\).
Suppose the observed state \(x_t\) is the same in two cases, but the current shock differs. When \(z_t=0.4\), the next shock has mean \(0.7(0.4)=0.28\) and standard deviation \(0.5\). Therefore,
When \(z_t=-0.4\), the next shock has mean \(0.7(-0.4)=-0.28\), so
Thus the same observed \(x_t\) is compatible with substantially different next-period choice probabilities. The calculation conditions on \(z_t\), not just \(x_t\); omitting the shock discards information that predicts future payoffs.
Augmenting the State and Writing the Bellman Equation
Let \(V(x,z)\) be the value to a decision-maker who begins a period with observed state \(x\) and persistent shock \(z\). For a finite action set \(\mathcal A\), let \(u(x,a,z)\) be current deterministic utility, and let \(\beta\in(0,1)\) be the discount factor. Write \(Q(dx',dz'\mid x,z,a)\) for the joint transition distribution of next period's observed state and shock. With no additional transitory choice shocks, the Bellman equation is
The integral is an expectation over both next-period components. If they are conditionally independent under the model, this expectation can instead be written as a sum or integral over \(x'\), followed by one over \(z'\), using their separate transition distributions. If there are also independent, transitory choice shocks \(\varepsilon_t\), they enter the current payoff but not the persistent state; the Bellman equation then takes the expectation over \(\varepsilon_t\) of the maximum over actions.
The important change is not the discounting or the maximization. It is the conditioning information in the continuation value: the distribution of \(z'\) depends on \(z\), so the value is a function of both \(x\) and \(z\). In a model with choice-specific persistent shocks, choices compare both current shock realizations and continuation values that depend on those realizations.
The result follows directly from the definition of a Markov-sufficient state. Current utility is determined by \((x_t,z_t,a_t)\), so earlier history provides no further information about the current payoff once those variables are known. By assumption, the distribution of the next state \((x_{t+1},z_{t+1})\) is also determined by \((x_t,z_t,a_t)\). Applying the same argument at each future date, the conditional distribution of future payoffs and states is determined by the current augmented state and future actions, not by the earlier path. Thus the Bellman problem can be written using \((x_t,z_t)\) rather than the full history. This justification requires the stated transition condition; adding a shock variable is not sufficient if the shock transition still depends on omitted history.
Worked Example: Comparing Actions With Shock-Dependent Continuation Values
Consider a two-state persistent shock \(z\in\{-1,+1\}\). It remains at its current value with probability \(0.8\) and switches with probability \(0.2\). There are two actions, \(A\) and \(B\), and \(\beta=0.9\). For illustration, suppose that the expected continuation values conditional on the next shock are as follows. These values may arise from the next observed state and subsequent choices.
| Action | Continuation value if \(z'=+1\) | Continuation value if \(z'=-1\) |
|---|---|---|
| A | 4 | 1 |
| B | 2 | 3 |
At \(z=+1\), the probability that \(z'=+1\) is \(0.8\). The expected continuation value for \(A\) is \(0.8(4)+0.2(1)=3.4\); for \(B\), it is \(0.8(2)+0.2(3)=2.2\). Suppose current utilities at \(z=+1\) are \(u(A)=1\) and \(u(B)=1.5\). The action values are
Thus \(A\) is preferred at \(z=+1\). At \(z=-1\), the probability that \(z'=+1\) is \(0.2\). The expected continuation values are \(0.2(4)+0.8(1)=1.6\) for \(A\) and \(0.2(2)+0.8(3)=2.8\) for \(B\). If current utilities are \(u(A)=0.2\) and \(u(B)=1\), then
Now \(B\) is preferred. The action comparison depends on the current shock because it predicts the next shock, which changes the continuation values. A formulation that conditions only on \(x\) cannot represent this comparison unless it also tracks the relevant distribution of \(z\).
What the Econometrician Observes
State augmentation describes the decision-maker's problem; it does not assert that the econometrician observes the added state. If \(z_t\) is latent, the econometrician must account for it when relating the model to observed choices. In general, the probability of a future choice conditional on the observed state alone averages over the possible current shocks. The distribution used for that average can depend on the observed history, because past choices provide information about persistent shocks.
This distinction matters for likelihood construction and for conditional choice probabilities. A probability conditional on \((x_t,z_t)\) is not generally the same object as a probability conditional only on \(x_t\). When \(z_t\) is unobserved, the latter is a mixture over the shock's conditional distribution given the information available to the econometrician. Treating that mixture as a fixed probability depending only on \(x_t\) can be wrong if the mixture weights change with history.
Worked Example: Past Choices Update the Latent Shock Distribution
Suppose a latent shock has two values, \(H\) and \(L\), with probability \(0.5\) each before observing a choice. It follows a Markov transition with probability \(0.8\) of remaining in its current value. A choice indicator \(y_t\) has probability \(0.9\) of being 1 in state \(H\) and \(0.2\) in state \(L\). These choice probabilities represent the model's choice behavior conditional on the latent state.
After observing \(y_t=1\), Bayes' rule gives
The predicted probability of \(H\) next period is therefore
The next choice probability, conditional on the observed history \(y_t=1\), is
Without the observed past choice, the initial probability of \(H\) remains \(0.5\), giving a next-choice probability of \(0.9(0.5)+0.2(0.5)=0.55\). The difference arises because the earlier choice changes the econometrician's distribution over the current latent state, and persistence carries that information forward. The decision-maker's augmented state is the realized shock; for the econometrician, the relevant conditioning information may instead include a history-dependent distribution over that shock.
Scope and Modeling Conditions
Several distinctions prevent common specification errors. A persistent payoff shock is not the same as a fixed latent type. A type is typically constant over the modeled horizon, whereas a serially correlated shock changes according to a transition law. Nor is it the same as a transitory shock that is independently redrawn each period: a transitory shock does not, by itself, predict future payoffs. A model can contain both a persistent component \(z_t\) and a transitory component \(\varepsilon_t\), but their roles and distributions should be specified separately.
The Markov formulation also relies on an information assumption. The Bellman equation above treats the decision-maker as observing \(z_t\). If the decision-maker does not observe the shock and instead learns about it from signals, then the decision-maker's information or beliefs may need to be represented in the state. Similarly, if the shock transition depends on omitted history, adding \(z_t\) alone will not restore the Markov property. The model must include enough information to make current payoffs and transition distributions history-independent conditional on the state and action.
Common Mistake: Averaging Away Persistence
A tempting but generally incorrect argument is: “The shock is unobserved, so average it out and solve a model with state \(x_t\) only.” Averaging is not automatically invalid, but the averaging distribution must be correct for the information being conditioned on. If the conditional distribution of \(z_t\) changes with past choices and the shock predicts future shocks, then a single average based only on \(x_t\) loses relevant information. The resulting continuation values and choice probabilities can be misspecified.
The correction is to specify the persistent shock's transition law, include its current realization in the decision-maker's state, and derive the Bellman equation over the augmented state. If the shock is latent to the econometrician, the model's observed-data probabilities must then account for the distribution of that state given the observed history. The shock can be integrated out only with the appropriate conditional distribution, not by assuming that history no longer matters.
Check Your Understanding
Try these questions before moving on.
- In what sense can \(x_t\) remain Markov while still being insufficient as the state for a dynamic choice problem with persistent payoff shocks?
- For \(z_{t+1}=\rho z_t+\eta_{t+1}\), explain why the distribution of \(z_{t+1}\) generally depends on \(z_t\) when \(\rho\ne 0\).
- What conditional transition distribution must be specified for the augmented state \((x_t,z_t)\) to be Markov-sufficient?
- Why can two histories ending at the same observed \(x_t\) imply different probabilities of a future choice when \(z_t\) is latent?
- How does a persistent payoff shock differ from a fixed latent type and from an independently redrawn transitory shock?