Why Check the Canonical Model?
Group sequential calculations rely on a joint model for statistics at several analysis looks. The canonical model represents the score accumulated by each look as a sum of stage increments whose variances are measured by information. Its usefulness depends on more than the marginal distribution at each look: the increments must also have the appropriate means, variances, and dependence structure. A statistic can look approximately standard normal at every look while the joint model is still wrong.
The key diagnostic objects are therefore the score increments, not just the cumulative \(Z\) statistics. The earlier material on score statistics and asymptotically independent score increments motivates this representation. Here the emphasis is on the assumptions it requires and on what simulated or observed increments can tell us about them.
This is a model for the joint behavior of the sequential statistics, not a claim that every finite-sample score is exactly normal. It is commonly justified as an approximation in regular models. The information increments must be positive, and the score and information must be calculated under a correctly specified likelihood or a suitable valid approximation. The stages should contribute non-overlapping data increments; otherwise, the score increments can share data and be dependent. The stated distribution also assumes that the information scale is correctly calibrated.
The compact form above treats the information increments as fixed at the analysis schedule. If information is random or the schedule changes in response to accumulating data, an unconditional fixed-schedule canonical model does not follow automatically. A suitable conditional model may still be possible, but it needs its own justification. Similarly, nuisance-parameter estimation, model misspecification, clustering, or temporal dependence can affect the score variance or the dependence among increments.
What the Increment Assumptions Imply
Under the model, cumulative scores are sums of increments. Thus \(U_k=\sum_{j=1}^k\Delta U_j\), and cumulative information is \(I_k=\sum_{j=1}^k\Delta I_j\). Independence gives a direct way to derive the covariance structure of cumulative statistics.
This derivation also clarifies what to inspect. If standardized increments show serial dependence, unusual variance, or a systematic change in their mean, the assumed joint distribution may not describe the data well. Checking only the marginal mean and variance of each cumulative \(Z_k\) can miss such departures because cumulative statistics combine information from earlier stages.
Diagnostics for Simulated and Observed Increments
A diagnostic starts by putting increments on a comparable scale. Under \(H_0\), calculate \(Q_k=\Delta U_k/\sqrt{\Delta I_k}\). Under a specified alternative, the model gives \(E(Q_k)=\theta\sqrt{\Delta I_k}\), so a residual-style quantity is \(Q_k-\theta\sqrt{\Delta I_k}\). Examine whether these quantities are centered as expected, have roughly unit variance across repeated realizations, and are not systematically dependent across stages. Plots against look number, information increment, calendar time, and relevant design features can expose patterns that a single summary conceals.
Simulation is especially useful because many independent replicate trials can be generated under a specified model and analysis plan. For each replicate, calculate all stage score and information increments using the same method intended for the analysis. Compare empirical means, variances, correlations, and distributional shapes with their canonical targets. Observed data offer only one path through the sequence, so they can suggest a problem but provide much weaker evidence about repeated-sampling behavior.
Worked Example: Standardizing Simulated Null Increments
Suppose a hypothetical simulation under \(H_0\) produces three independent stage increments with information values \(\Delta I=(25,36,39)\) and observed score increments \(\Delta U=(4,-5,7)\). These are one simulated path, not estimates of the repeated-simulation distribution.
Calculate each standardized increment: $$ Q_1=\frac{4}{\sqrt{25}}=0.800,\qquad Q_2=\frac{-5}{\sqrt{36}}=-0.8333,\qquad Q_3=\frac{7}{\sqrt{39}}\approx1.121. $$
The individual values are not expected to be zero; under the null, each is a draw from \(N(0,1)\). Their cumulative scores are \(U_1=4\), \(U_2=4-5=-1\), and \(U_3=4-5+7=6\), while cumulative information is \(I_1=25\), \(I_2=61\), and \(I_3=100\). Thus the cumulative statistics are $$ Z_1=\frac{4}{5}=0.800,\qquad Z_2=\frac{-1}{\sqrt{61}}\approx-0.128,\qquad Z_3=\frac{6}{10}=0.600. $$
These three cumulative values are not three independent standard-normal draws. For example, the canonical model implies \(\operatorname{Corr}(Z_1,Z_3)=\sqrt{25/100}=0.500\). One simulated path cannot establish whether that correlation or the increment distribution is correct; many replicates are needed to assess those repeated-simulation properties.
For observed data, the same calculations can be informative, but interpretation requires care. Under a nonzero effect, standardized increments need not be centered at zero. If the purpose is to inspect departures from a specified alternative, compare them with the model’s expected drift as well as its variance. Substituting an effect estimate computed from the same increments can induce dependence among the resulting residuals; such residuals are exploratory, not independent null draws.
Worked Example: Inspecting Observed Increments Under the Null
Consider a hypothetical study with three non-overlapping stages. Suppose its score increments are \(\Delta U=(1.6,7.5,-1.5)\) and its corresponding information increments are \(\Delta I=(16,25,9)\). Assume the null is the diagnostic reference and that the score and information were computed from the prespecified model.
The null-standardized increments are $$ Q_1=\frac{1.6}{\sqrt{16}}=0.400,\qquad Q_2=\frac{7.5}{\sqrt{25}}=1.500,\qquad Q_3=\frac{-1.5}{\sqrt{9}}=-0.500. $$
The cumulative scores are \(1.6\), \(9.1\), and \(7.6\); the cumulative information values are \(16\), \(41\), and \(50\). The cumulative statistics are therefore \(Z_1=1.6/4=0.400\), \(Z_2=9.1/\sqrt{41}\approx1.421\), and \(Z_3=7.6/\sqrt{50}\approx1.075\). The second stage contributes the largest positive standardized increment, while the third contributes a negative increment.
Nothing in this single path establishes a violation: values such as \(1.500\) and \(-0.500\) are plausible draws under \(N(0,1)\). The pattern is a reason to inspect stage-specific data, score construction, and repeated-simulation behavior if available, not a basis for declaring the canonical model false. Nor does the observed pattern alone establish that an effect changed over time.
Using Replicate Simulations to Diagnose Departures
A stronger diagnostic compares the empirical behavior of increments across many simulated replicates. For each stage, estimate the mean and variance of \(Q_k\) across replicates, and estimate correlations between different stages. Under the null canonical model, the target means are zero, variances are one, and correlations between distinct increments are zero. These are reference values, not exact finite-simulation requirements: Monte Carlo estimates fluctuate, especially when the number of replicates is small.
The following hypothetical results illustrate how to interpret a discrepancy. Assume 5,000 simulated null trials with three planned increments. The empirical variance of the first standardized increment is 1.44, its empirical correlation with the second is 0.38, and the corresponding correlation between the second and third is 0.02. A variance of 1.44 suggests that the first-stage score may be more variable than its stated information predicts. The correlation of 0.38 suggests dependence between the first two increments. The near-zero later correlation is consistent with independence for that pair, but does not cancel the first discrepancy.
Worked Example: Locating a Simulated Dependence Problem
Suppose the 5,000-replicate diagnostic summary above was computed from standardized null increments. To express the size of the first-stage variance departure, compare the empirical variance with the canonical target: $$ \frac{1.44}{1}=1.44. $$ The empirical variance is 44% above the target. The empirical correlation of 0.38 is also materially different from the target of zero in this hypothetical summary. These discrepancies point to a need to inspect how stage-one information was calculated and whether the first two stages actually use non-overlapping data.
The summary does not by itself identify the cause. Shared participants, an omitted source of clustering, a coding error, or an incorrect variance model could produce related symptoms. Repeat the check after verifying score construction and the simulation design; then use additional stage-specific summaries to locate the source. A numerical difference from its target is a diagnostic signal, not a universal pass-or-fail threshold.
Comparison, Failure Modes, and Limits
Increment diagnostics complement, rather than replace, checks of the cumulative covariance matrix. A covariance check asks whether the joint covariance of the \(Z\) statistics matches the canonical pattern. Increment checks help localize why it may not: dependence between adjacent increments, incorrect variance at one stage, or a mean pattern inconsistent with the reference effect. Comparing the two views is useful because cumulative statistics can hide where a departure entered the sequence.
Simulation and observed-data diagnostics have different strengths. Simulation can assess repeated-sampling behavior under an explicitly specified model and schedule, but it cannot reveal misspecification that was omitted from the simulation. Observed increments reflect the actual data path, but one path cannot reliably estimate repeated-sampling variances or correlations. Neither approach turns model checking into proof that assumptions hold.
Several practical departures deserve attention:
- Overlapping or reused data: stage increments may share observations, creating dependence not represented by the model.
- Information miscalibration: an incorrect variance model can make standardized increments too variable or too concentrated.
- Unmodeled heterogeneity or clustering: dependence among individuals can alter both the score variance and the cross-stage relationship.
- Changing data collection or analysis: a shift in measurement, eligibility, or score calculation can create a stage pattern.
- Adaptive timing or random information: a fixed-schedule joint distribution may not apply without an appropriate conditional argument.
A common mistake is to say, “Every cumulative \(Z_k\) looks approximately standard normal, so the canonical model is validated.” That reasoning checks only marginal behavior. The correction is to inspect the joint structure, especially the score increments: the canonical model requires the specified variance and mean at each increment and independence across increments, not merely standard-normal-looking cumulative statistics.
Diagnostics are also limited by the number of stages and replicates, the quality of the score and information calculations, and the sensitivity of the chosen summaries. A small correlation estimate does not prove independence, and a large one may be unstable if based on few replicates. Graphs and numerical summaries should be interpreted alongside knowledge of the data-generating process and analysis implementation. If a material departure remains, the response is to investigate and justify a more suitable model or analysis, not to assume that the canonical approximation remains valid unchanged.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions.
- Under the null, a stage has \(\Delta I=49\) and \(\Delta U=-7\). Find its standardized increment and state its model distribution.
- Why are cumulative \(Z\) statistics generally not independent under the canonical model?
- In repeated null simulations, the standardized increments have variances near one but a correlation of 0.30 between stages one and two. Which assumption is in question?
- Why is one observed standardized increment of 2.1 not sufficient to establish a model failure?
- Name one way a simulation diagnostic could appear reassuring even though the real study’s canonical model is wrong.
Solutions. (1) \(Q=-7/\sqrt{49}=-1\), and under the null its model distribution is \(N(0,1)\). (2) Cumulative scores share earlier increments, so for \(j\leq k\), \(\operatorname{Cov}(U_j,U_k)=I_j\), giving \(\operatorname{Corr}(Z_j,Z_k)=\sqrt{I_j/I_k}\). (3) Independence of the score increments is in question; the nonzero empirical correlation warrants investigation. (4) A single draw can be far from zero by chance under \(N(0,1)\); it does not estimate the repeated-sampling distribution. (5) The simulation may omit a real feature, such as clustering or shared observations, so it can reproduce the assumed model while failing to represent the study.