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Information Fraction, Sample Size and Events · Tutorial 82 of 699

Information Across Strata

Combine information across independent strata to quantify overall precision for a common treatment contrast and identify which strata contribute most.

Intermediate 10 min read

What You'll Learn

  • State the assumptions that make stratum-specific information additive.
  • Derive the information-weighted estimate of a common treatment contrast.
  • Calculate total information and each stratum’s share of precision.
  • Distinguish an overall information fraction from a stratum’s share of total information.
  • Recognize when heterogeneity or a mismatch in effect scales makes pooling misleading.
  • Check how stratified information compares with an unstratified analysis.

Why Information Must Be Combined Across Strata

A stratified trial may divide participants by site, region, disease severity, or another baseline characteristic. Each stratum can provide its own estimate of the treatment contrast, with its own precision. To describe the precision of a common treatment effect, the stratum-specific information must be combined in a way that reflects how precisely each contrast was estimated.

The central result is simple: under independence and a common treatment contrast, information adds across strata. A stratum with more information receives more weight in the combined estimate and contributes a larger share of the total precision. Its share is not generally the same as its share of enrollment.

Definition: Suppose there are \(K\) independent strata. In stratum \(s\), let \(\hat{\theta}_s\) estimate the same treatment contrast \(\theta\), and let \(I_s\) denote the information for that estimate. When \(\operatorname{Var}(\hat{\theta}_s)=1/I_s\), the total information is \(I_{\text{total}}=\sum_{s=1}^{K} I_s\). The information contribution of stratum \(s\) is \(I_s\), and its share of total information is \(I_s/I_{\text{total}}\).

Information is on the scale of inverse variance. If the contrast is measured in outcome points, for example, information is measured in inverse squared points. A larger information value means a smaller variance and therefore greater precision. Stratum shares are dimensionless proportions that add to one.

Assumptions and the Combining Formula

The basic calculation uses a common-effect model for the contrast. Specifically, each \(\hat{\theta}_s\) is an unbiased estimate of the same \(\theta\), and the estimates from different strata are independent. For the exact normal calculation below, assume \(\hat{\theta}_s\sim N(\theta,1/I_s)\), with each \(I_s\) known and positive. In large-sample applications, the same formulas are often used with estimated variances as an approximation, provided the estimates are sufficiently well behaved.

The stratum outcomes themselves need not have the same baseline means or distributions. What must be common for this calculation is the treatment contrast being estimated, on the stated effect scale. For example, a common difference in mean outcome is different from a common ratio of means; one must define the contrast before combining information.

$$ \hat{\theta}_{\text{comb}} = \frac{\sum_{s=1}^{K} I_s\hat{\theta}_s}{\sum_{s=1}^{K} I_s}, \qquad \operatorname{Var}(\hat{\theta}_{\text{comb}}) = \frac{1}{\sum_{s=1}^{K} I_s}. $$

Thus the combined estimate is an information-weighted average, not necessarily an average weighted by stratum sample size. Its standard error is \(SE(\hat{\theta}_{\text{comb}})=1/\sqrt{I_{\text{total}}}\). This formula does not say that stratum estimates are identical; it gives the precision-weighted estimate of their stipulated common contrast.

Why the Information Adds

A short likelihood argument shows why the weights and total information take this form. Under the normal model, the log likelihood for \(\theta\), apart from a constant, is the sum of the independent stratum log likelihoods:

$$ \ell(\theta) = -\frac{1}{2}\sum_{s=1}^{K}I_s(\hat{\theta}_s-\theta)^2. $$

Differentiate with respect to \(\theta\). The score is \(\sum_s I_s(\hat{\theta}_s-\theta)\). Setting it equal to zero gives \(\hat{\theta}_{\text{comb}}=\sum_s I_s\hat{\theta}_s/\sum_s I_s\). The second derivative of the log likelihood is \(-\sum_s I_s\), so the information in the joint likelihood is \(I_{\text{total}}=\sum_s I_s\). Independently, the variance of the weighted estimate is

$$ \operatorname{Var}(\hat{\theta}_{\text{comb}}) = \frac{\sum_{s=1}^{K} I_s^2(1/I_s)} {(\sum_{s=1}^{K}I_s)^2} = \frac{1}{\sum_{s=1}^{K}I_s}. $$

The variance calculation uses independence: covariance terms between distinct stratum estimates are zero. If participants or measurements connect strata, or if the estimates are otherwise correlated, simply adding the stratum information may not be justified.

Worked Example: Combining Two Stratum Estimates

Suppose a hypothetical trial estimates a common treatment difference in outcome points in two independent strata. In stratum A, the estimate is \(2.4\) points with variance \(5.0\) points squared. In stratum B, it is \(1.2\) points with variance \(7.2\) points squared. Treat these variances as known for this calculation.

The information values are the reciprocals of the variances:

$$ I_A=\frac{1}{5.0}=0.2000, \qquad I_B=\frac{1}{7.2}=0.1389 \quad\text{inverse points squared}. $$

The total information is \(0.2000+0.1389=0.3389\) inverse points squared. The combined estimate is

$$ \hat{\theta}_{\text{comb}} = \frac{(0.2000)(2.4)+(0.1389)(1.2)}{0.3389} = \frac{0.6467}{0.3389} = 1.908\text{ points}. $$

The standard error is \(1/\sqrt{0.3389}=1.718\) points. Stratum A contributes \(0.2000/0.3389=0.5902\), or \(59.02\%\), of total information; stratum B contributes \(40.98\%\). The estimate is closer to stratum A’s estimate because A is more precise. This calculation is meaningful as an estimate of a common contrast only if the common-effect assumption is appropriate.

Calculating Information From Group Sizes

For a difference in means between two independent treatment groups within stratum \(s\), suppose outcomes have a common variance \(\sigma_s^2\) in that stratum, and the treatment and control sample sizes are \(n_{Ts}\) and \(n_{Cs}\). The variance of the estimated difference is \(\sigma_s^2(1/n_{Ts}+1/n_{Cs})\). Therefore its information is

$$ I_s = \frac{1}{\sigma_s^2(1/n_{Ts}+1/n_{Cs})} = \frac{n_{Ts}n_{Cs}}{\sigma_s^2(n_{Ts}+n_{Cs})}. $$

This expression shows why enrollment alone does not determine information. The allocation between treatment and control matters, and a stratum with more variable outcomes can contribute less precision even when it has many participants. The formula assumes independent observations within each treatment group, the stated variance model, and a well-defined mean difference in every included stratum.

Worked Example: Comparing Contributions Across Three Strata

Consider a hypothetical trial with independent observations and a mean-difference contrast. Assume a common within-stratum outcome variance in each stratum, but allow that variance to differ between strata. Planned values are shown below.

StratumTreatment nControl nOutcome standard deviation
Urban50508 points
Rural406010 points
Remote204015 points

For urban participants, \(\sigma^2=8^2=64\) points squared, so

$$ I_{\text{urban}} = \frac{1}{64(1/50+1/50)} = \frac{1}{2.56} = 0.3906\text{ inverse points squared}. $$

For the rural stratum, \(\sigma^2=100\), giving

$$ I_{\text{rural}} = \frac{1}{100(1/40+1/60)} = \frac{1}{4.1667} = 0.2400\text{ inverse points squared}. $$

For the remote stratum, \(\sigma^2=225\), and

$$ I_{\text{remote}} = \frac{1}{225(1/20+1/40)} = \frac{1}{16.875} = 0.05926\text{ inverse points squared}. $$

Adding gives \(I_{\text{total}}=0.3906+0.2400+0.05926=0.6899\) inverse points squared. The shares are \(0.3906/0.6899=56.62\%\) urban, \(34.79\%\) rural, and \(8.59\%\) remote. The total standard error is \(1/\sqrt{0.6899}=1.204\) points. Although the remote stratum has 60 participants, its high outcome variability and allocation produce a relatively small information contribution.

Information Shares at an Interim Analysis

At an interim analysis, it is useful to distinguish each stratum’s information from its share of the total information. If information in stratum \(s\) has reached \(I_s(t)\) at a particular analysis and its planned final value is \(I_s(F)\), its within-stratum progress is \(I_s(t)/I_s(F)\). The overall information fraction is instead the ratio of the summed current information to the summed planned final information:

$$ \frac{I_{\text{total}}(t)}{I_{\text{total}}(F)} = \frac{\sum_s I_s(t)}{\sum_s I_s(F)}. $$

This is a weighted combination of the strata’s progress, with planned information \(I_s(F)\) providing the weights. It is not generally the simple average of the within-stratum progress values, nor is it the fraction of all participants enrolled. The distinction matters when strata accrue at different rates or have different planned contributions.

Worked Example: Unequal Progress Across Strata

Suppose a hypothetical trial has planned final information of 100, 60, and 40 inverse-variance units in strata 1, 2, and 3, respectively. At an interim analysis, the corresponding information values are 50, 15, and 32 units. Assume the information calculations use the same contrast and scale at both times.

The within-stratum progress values are \(50/100=0.50\), \(15/60=0.25\), and \(32/40=0.80\). Current total information is \(50+15+32=97\) units, and planned final total information is \(100+60+40=200\) units. Therefore the overall information fraction is \(97/200=0.485\), or \(48.50\%\).

At the interim, the strata’s shares of current information are \(50/97=51.55\%\), \(15/97=15.46\%\), and \(32/97=32.99\%\). These shares answer which strata currently supply the precision; they are not the same quantities as the strata’s progress toward their own final information. For instance, stratum 3 is \(80\%\) complete but contributes about \(33\%\) of current information.

Interpretation, Diagnostics, and Alternatives

A useful diagnostic is to calculate both the absolute information values and their shares. A very small share may arise from small enrollment, an unfavorable treatment-control allocation, high variance, or a combination of these. Check whether the planned allocation and variance assumptions match the design. At an interim, compare observed information by stratum with planned values; substantial departures can reveal that the overall information target is being reached through a different mix of strata than expected.

Also check that every stratum estimate targets the same contrast on the same scale. For example, differences in means cannot be combined by this formula with log-odds ratios merely because both are treatment effects. A common numerical value can have a different interpretation on different effect scales. If treatment effects genuinely differ across strata, the information-weighted average is not automatically a universal common effect: it is a weighted summary whose weights depend on the information distribution.

The main alternative is to report separate stratum-specific estimates rather than impose a common contrast. That preserves evidence about differences across strata but does not yield the same single precision-weighted summary. An unstratified analysis is another alternative, but pooling raw outcomes without accounting for strata can mix treatment effects with differences in stratum composition or baseline outcome levels. Which analysis is appropriate depends on the estimand and design, not merely on which calculation is easiest.

ApproachWhat it summarizesKey caution
Information-weighted common contrastOne contrast, weighted by stratum precisionRequires a defensible common-effect interpretation and compatible information calculations
Separate stratum estimatesA contrast within each stratumIndividual estimates may be imprecise; they do not by themselves provide one common-effect estimate
Unstratified analysisA contrast in the pooled sampleMay not account for stratum structure or target the same contrast

The additive formula is limited to information calculations that respect the model and independence assumptions. If stratum estimates are correlated, the variance of their weighted combination includes covariance terms; the simple reciprocal of summed information need not hold. Likewise, if the effect is not common, a single weighted estimate may conceal clinically important variation. Information shares describe precision contribution, not the scientific importance of a stratum or the treatment effect’s size there.

Common Mistake

  • Wrong reasoning: “Stratum A has twice as many participants as stratum B, so it must contribute twice as much information.”
  • Correction: Information depends on the variance of the contrast, not enrollment alone. For a two-group mean difference, \(I_s=1/\{\sigma_s^2(1/n_{Ts}+1/n_{Cs})\}\); allocation and outcome variability both affect the result.
  • Wrong reasoning: “The overall interim information fraction is the average of the strata’s interim fractions.”
  • Correction: Weight each within-stratum progress value by its planned final information, or directly divide summed interim information by summed final information.
Key takeaway: When independent strata estimate the same treatment contrast, their information adds. The combined estimate weights each stratum by its information, and \(I_s/\sum_j I_j\) quantifies that stratum’s share of total precision. Neither enrollment share nor within-stratum progress alone gives that contribution.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions.

  1. Two independent strata estimate a common contrast. Their variances are 4 and 12. What is the total information, and what share comes from the first stratum?
  2. Why can a stratum with more participants contribute less information than a smaller stratum?
  3. Planned final information is 80 units in stratum A and 20 units in stratum B. At interim, the values are 40 and 10. What is the overall information fraction? Is it necessarily the enrollment fraction?
  4. Name two conditions needed for the simple information-addition formula.
  5. What is the interpretation concern if treatment contrasts differ materially across strata?

Solutions. (1) The information values are \(1/4=0.25\) and \(1/12=0.08333\), so total information is \(0.3333\); the first stratum’s share is \(0.25/0.3333=75.00\%\). (2) Its variance may be larger because of greater outcome variability or a less efficient treatment-control allocation. (3) The fraction is \((40+10)/(80+20)=0.50\). It is not necessarily the enrollment fraction, because enrollment and information need not grow in the same proportions. (4) The stratum estimates must be independent, and they must estimate the same contrast with valid information values. (5) The combined estimate may no longer represent one common treatment effect; it is a precision-weighted summary that can obscure variation.

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