Tutorials › Joint Modeling of Longitudinal and Time-to-Event Data › Current-Value Association with Noisy Measurements

Association Structures · Tutorial 174 of 697

Current-Value Association with Noisy Measurements

Learn how measurement noise affects current-value hazard associations, and why joint models link the hazard to a latent marker trajectory rather than a raw observation.

Advanced 11 min read

What You'll Learn

  • Distinguish an observed marker measurement from the latent current marker value in a joint model.
  • State the measurement and hazard submodels that define a current-value association.
  • Calculate how substituting a noisy observation can change a hazard comparison.
  • Explain why a fitted latent value is not necessarily known without uncertainty.
  • Compare latent-trajectory links with raw-measurement and last-observation substitutions.
  • Identify model checks and assumptions relevant to measurement noise.

Why the Current Value Is Not the Latest Observation

A longitudinal marker is usually measured intermittently, and each recorded value contains both information about the subject’s underlying trajectory and measurement noise. A current-value association is meant to connect the event hazard to the subject’s underlying marker level at time \(t\), not to the accidental upward or downward error in one measurement. The distinction matters especially when measurements are sparse, imprecise, or taken at times that do not coincide with the event-risk time of interest.

The introductory material on current-value links defines the association through the marker value at the time the hazard is evaluated. Here the central issue is what that value represents. In a joint model, the hazard uses the latent trajectory specified by the longitudinal model. The observed marker informs estimation of that trajectory, but it is not itself the hazard covariate.

Definition: Let \(Y_{ij}\) be subject \(i\)'s observed marker at measurement time \(t_{ij}\), and let \(m_i(t)\) be that subject's latent, error-free marker value at time \(t\). A current-value association links the event hazard to \(m_i(t)\). Under a common measurement model, \(Y_{ij}=m_i(t_{ij})+\epsilon_{ij}\), where \(\epsilon_{ij}\) is measurement error. Thus \(Y_{ij}\) is an imperfect observation of \(m_i(t_{ij})\), not a substitute for the latent value.

Measurement and Hazard Models

A standard linear mixed longitudinal submodel can be written as

$$ Y_{ij}=m_i(t_{ij})+\epsilon_{ij}, \qquad m_i(t)=\mathbf{x}_i(t)^\top\boldsymbol{\beta} +\mathbf{z}_i(t)^\top\mathbf{b}_i. $$

Here \(\mathbf{x}_i(t)\) and \(\mathbf{z}_i(t)\) are specified covariate vectors, \(\boldsymbol{\beta}\) is a vector of fixed effects, and \(\mathbf{b}_i\) is a vector of subject-specific random effects. A common assumption is that \(\epsilon_{ij}\) has mean zero and variance \(\sigma_\epsilon^2\), is independent across measurements conditional on the random effects, and is independent of the random effects. The random effects describe between-subject trajectory variation; the errors describe measurement-level variation around each trajectory.

For a current-value link, a typical conditional hazard model is

$$ h_i(t\mid \mathbf{b}_i,\mathbf{w}_i) = h_0(t)\exp\!\left\{ \boldsymbol{\gamma}^{\top}\mathbf{w}_i+\alpha m_i(t) \right\}. $$

The hazard is conditional on the subject-specific trajectory, represented through \(\mathbf{b}_i\), and on the included covariates \(\mathbf{w}_i\). The baseline hazard is \(h_0(t)\), and \(\alpha\) is the current-value association parameter. If the marker is measured in units \(U\), then \(\alpha\) has units \(U^{-1}\), so that \(\alpha m_i(t)\) is dimensionless. A hazard ratio for two otherwise comparable subjects whose latent marker values differ by \(\Delta\) at time \(t\) is \(\exp(\alpha\Delta)\).

These models require more than a convenient formula. The longitudinal mean and random-effects structure must adequately describe the marker trajectories; the measurement-error distribution and variance must be reasonable; and the hazard model must correctly specify how the latent trajectory and other covariates relate to event risk. The usual shared-random-effects formulation also assumes that, conditional on the modeled random effects and covariates, the longitudinal measurement errors do not carry additional information about the event process. If measurement timing or measurement error itself is related to event risk in ways not represented in the model, the stated conditional interpretation may fail.

Worked Example: A Noisy Measurement Reverses a Comparison

Suppose two hypothetical subjects have the same values of all other hazard covariates. At a particular time, the model-estimated latent marker values are 10 and 12 units. Let \(\alpha=0.30\) per marker unit. Suppose the observed measurements at that time are 13 and 10 units, respectively. For this illustration, take the latent values as the values specified by the model and treat the measurement discrepancies as errors: \(13-10=3\) and \(10-12=-2\).

Using the latent values. The second subject's latent value exceeds the first subject's by \(12-10=2\) units. The hazard ratio is

$$ \exp\{\alpha(12-10)\} =\exp(0.30\times 2) =\exp(0.60) \approx 1.822. $$

Under the specified hazard model, the subject with latent marker value 12 has an estimated instantaneous hazard 1.822 times that of the subject with latent value 10, at that time and holding the other modeled covariates fixed.

Substituting the observed measurements instead. The observed difference is \(10-13=-3\), which has the opposite sign. The resulting plug-in comparison would be

$$ \exp\{0.30(10-13)\} =\exp(-0.90) \approx 0.4066. $$

That calculation would suggest a lower hazard for the subject whose latent marker is actually higher. It is not a different estimate of the same model parameter; it is a different, noise-contaminated covariate comparison. The example checks the arithmetic directly and shows why a single measurement error can overwhelm the latent difference.

Why Replacing the Latent Value Changes the Model

Suppose for a moment that a measurement is taken exactly at time \(t\), with \(Y_i(t)=m_i(t)+\epsilon_i(t)\). Replacing \(m_i(t)\) by \(Y_i(t)\) changes the hazard multiplier from \(\exp\{\alpha m_i(t)\}\) to \(\exp\{\alpha[m_i(t)+\epsilon_i(t)]\}\). The ratio of the substituted multiplier to the intended multiplier is therefore

$$ \frac{\exp\{\alpha Y_i(t)\}}{\exp\{\alpha m_i(t)\}} =\exp\{\alpha\epsilon_i(t)\}. $$

Unless \(\alpha=0\) or the measurement error is exactly zero, this ratio varies with the error. Thus a raw measurement injects a random, subject- and occasion-specific perturbation directly into the hazard. If errors are normal with mean zero and variance \(\sigma_\epsilon^2\), the expected substituted multiplier conditional on \(m_i(t)\) is

$$ E\!\left[\exp\{\alpha Y_i(t)\}\mid m_i(t)\right] = \exp\{\alpha m_i(t)\} \exp\!\left(\frac{\alpha^2\sigma_\epsilon^2}{2}\right). $$

This follows from the moment-generating function of a normal random variable: for \(\epsilon\sim N(0,\sigma_\epsilon^2)\), \(E[\exp(\alpha\epsilon)]=\exp(\alpha^2\sigma_\epsilon^2/2)\). The extra factor shows that even mean-zero error need not average out after exponentiation. This calculation is a justification for avoiding the substitution; it is not a general formula for the bias in an estimated association parameter. In a fitted survival model, risk sets, event times, covariates, and latent-trajectory uncertainty all affect estimation, so the direction and amount of coefficient bias are not determined by this factor alone.

Worked Example: Quantifying the Exponentiation Effect

Consider a hypothetical subject with latent marker value \(m_i(t)=6\) units, association parameter \(\alpha=0.40\) per unit, and measurement-error standard deviation \(\sigma_\epsilon=1.5\) units. The intended marker-related hazard multiplier is

$$ \exp(0.40\times 6)=\exp(2.4)\approx 11.02. $$

If a noisy observation is substituted, its conditional expected marker-related multiplier is

$$ \exp\!\left(0.40\times 6+ \frac{0.40^2\times 1.5^2}{2}\right) = \exp(2.4+0.18) = \exp(2.58) \approx 13.20. $$

The difference arises because exponentiating a noisy value is nonlinear: the positive and negative errors do not cancel on the multiplier scale. The assumed normal error distribution and variance are used in this calculation; if those assumptions do not hold, this particular expected-multiplier formula need not apply. Even when they do hold, the result describes the expected plug-in multiplier, not a universal correction to the fitted hazard ratio.

Model-Estimated Does Not Mean Known Exactly

The latent value \(m_i(t)\) is not directly observed. It is defined by the longitudinal model and estimated using the available repeated measurements, covariates, and—in a joint analysis—the event information through the shared model. The joint likelihood accounts for the fact that a subject's random effects are unknown rather than treating a noisy measurement as the true trajectory. In the hazard submodel, \(m_i(t)\) is the model-defined value; it is not replaced by a preliminary point prediction and then treated as error-free.

A subject-specific fitted trajectory can be useful for displaying or summarizing results, but a point prediction does not remove uncertainty about the trajectory. For example, a subject with few noisy measurements may have a predicted value pulled toward the population trajectory, with substantial remaining uncertainty. Joint estimation propagates latent-effect uncertainty through the model; a two-stage procedure that first predicts a marker value and then fits a survival model as if that prediction were known can understate uncertainty and can produce different estimates.

Worked Example: Shrinkage From Noisy Repeated Measurements

Consider a deliberately simple hypothetical random-intercept model. Each subject has a constant latent marker \(m_i=5+b_i\), where \(b_i\sim N(0,1)\). Two measurements are taken, with independent errors \(\epsilon_{ij}\sim N(0,4)\), so the measurement-error standard deviation is 2 units. The observed values are 8 and 6. This calculation uses only the longitudinal model to illustrate how repeated noisy measurements inform a latent value; a full joint model can also use event information.

The residuals from the population mean of 5 are \(8-5=3\) and \(6-5=1\). Under the normal random-intercept model, the conditional distribution of \(b_i\) given these observations has variance

$$ \left(\frac{1}{1}+\frac{2}{4}\right)^{-1} = \left(1.5\right)^{-1} = 0.6667, $$

and mean

$$ 0.6667\left(\frac{3+1}{4}\right) = 0.6667. $$

The resulting conditional mean marker value is \(5+0.6667=5.667\) units. By contrast, the latest observed value is 6 and the first is 8. Neither observation alone is the model's estimated latent value; both are noisy evidence, combined with the population distribution. The conditional standard deviation for \(b_i\) is \(\sqrt{0.6667}\approx0.8165\), so even the fitted value is uncertain.

If \(\alpha=0.50\) per unit, the hazard multiplier evaluated at the conditional mean marker is \(\exp(0.50\times5.667)\approx17.02\), relative to the same baseline and other covariates. Using the latest raw value instead gives \(\exp(0.50\times6)=20.09\). These are different plug-in calculations. Neither should be confused with a fully uncertainty-integrated hazard prediction; this example demonstrates the estimation of a latent value, not a substitute for joint-model inference.

Alternatives, Diagnostics, and Limits

The main alternatives differ in what they treat as the hazard covariate. Their consequences are not interchangeable.

ApproachHazard covariateMain concern
Latent current-value linkModel-defined \(m_i(t)\)Depends on adequate longitudinal and hazard models; accounts for measurement error through the joint model.
Raw observed valueA recorded \(Y_{ij}\)Injects measurement error and may not be available at the hazard time.
Last observation carried forwardThe most recent recorded \(Y_{ij}\), held fixed after its measurement timeCombines measurement noise with an assumption that the marker remains constant until another observation.
Two-stage predicted valueA fitted marker estimate entered into a separate event modelMay fail to propagate uncertainty in the estimated trajectory into survival inference.

Several checks help assess whether the latent-value link is credible. Examine whether the longitudinal model describes the observed trajectories, including systematic residual patterns, changes in variability over time, and unusually influential observations. Compare the estimated measurement-error variation with the variation in fitted trajectories: when error is large relative to between-subject trajectory differences, individual latent values will be weakly determined. Check whether the assumed error distribution and independence structure are plausible. Finally, assess whether the specified time pattern and hazard association are adequate; a good measurement model cannot compensate for a misspecified hazard model.

The approach has important limitations. The latent marker is only as credible as the model used to define it. A misspecified mean trajectory, random-effects distribution, measurement-error structure, or hazard link can yield misleading estimates. If the timing or frequency of measurements depends on unmodeled health changes or event risk, treating observation times as ignorable may also be inappropriate. Sparse measurements can make the trajectory between visits—and especially near or after the last visit—highly uncertain. The latent-value formulation avoids equating a noisy observation with the marker, but it does not make the unobserved marker directly known.

A Common Mistake

Common pitfall: “The latest measurement is the best available value, so I can insert it into the hazard and treat it as the current marker.” The latest measurement may be a useful piece of evidence, but it includes measurement error and may have occurred before the hazard time. The correction is to define the hazard association through the model's latent \(m_i(t)\), estimate that trajectory using the longitudinal and event data under stated assumptions, and retain its uncertainty in inference.

The practical distinction is not between using data and ignoring data. The observed measurements are essential: they inform the trajectory parameters and subject-specific effects. The distinction is between using measurements as evidence about the latent marker and declaring one noisy measurement to be the marker itself.

Check Your Understanding

Answer each question, then compare with the short solutions below.

  1. If two otherwise comparable subjects have latent marker values differing by 1.5 units and \(\alpha=0.20\) per unit, what is the hazard ratio for the subject with the higher value?
  2. Why can mean-zero measurement error still alter the expected hazard multiplier when a noisy measurement is substituted?
  3. In a current-value joint model, does the hazard use the latest observed \(Y_{ij}\) or the latent \(m_i(t)\)? What role do the observations play?
  4. Name one assumption about the measurement errors and one diagnostic that can help assess the longitudinal model.

Solutions. (1) The ratio is \(\exp(0.20\times1.5)=\exp(0.30)\approx1.350\); under the model, the higher latent value corresponds to a hazard 1.350 times as large, holding other modeled covariates fixed. (2) Exponentiation is nonlinear: for normal error, \(E[\exp(\alpha\epsilon)]=\exp(\alpha^2\sigma_\epsilon^2/2)\), which generally exceeds 1 when \(\alpha\ne0\) and \(\sigma_\epsilon^2>0\). (3) The hazard uses \(m_i(t)\); the observed values inform estimation of the latent trajectory. (4) For example, errors may be assumed independent across measurements conditional on random effects; residual plots can reveal systematic patterns or changing variability that challenge the longitudinal model.

Clinical Biostats