Why Follow-Up Can Create an Association
A study may begin with two factors that are independent in the source population, yet find that they are associated among participants who remain under observation. This can happen because inclusion in the observed follow-up sample depends on both factors. The association in that selected sample need not reflect a relationship between the factors in the original population.
For example, suppose both access to care and a participant’s health status affect whether a scheduled visit is observed. Among those with an observed visit, participants with less access may be disproportionately those whose health status made attendance more likely. Conditioning on having an observed visit can therefore connect the two causes, even if they were independent before selection. This is a consequence of selection, not evidence that one factor caused the other.
The causal diagram for the basic mechanism is small:
Here \(A\) and \(B\) are factors in the source population, and \(R=1\) indicates that a person is retained in follow-up (or otherwise selected for the analysis). The arrowheads meet at \(R\), making \(R\) a collider on this path. The path between \(A\) and \(B\) is blocked before conditioning on \(R\), but conditioning on \(R=1\) can open it.
Deriving the Induced Association
Let \(A\) and \(B\) be binary, and suppose they are independent in the source population. Write \(r_{ab}=P(R=1\mid A=a,B=b)\), for \(a,b\in\{0,1\}\). Assume these four probabilities are positive. The selection probability may depend on both factors, and no particular functional form is required.
Because \(A\) and \(B\) are independent before selection, their source-population joint probabilities factor into their marginal probabilities. In the selected group, Bayes’ rule gives a joint probability proportional to the source probability multiplied by the chance of selection:
For binary variables, the odds ratio summarizes their association. When the selected cell probabilities are substituted into the odds ratio, the source-population marginal probabilities and the common normalizing factor cancel:
Thus, even though the source-population odds ratio is 1, the selected-sample odds ratio is determined by the pattern of selection probabilities. If \(r_{11}r_{00}<r_{10}r_{01}\), the selected association is negative; if \(r_{11}r_{00}>r_{10}r_{01}\), it is positive. Equality means the selected odds ratio remains 1.
This result also supplies a short justification for a common intuition about selection. If the probability of selection follows an additive pattern, \(r_{ab}=a_0+b_0a+c_0b\), then
When both factors increase selection probability (\(b_0>0\) and \(c_0>0\)), this difference is negative, so the selected-sample odds ratio is below 1. Informally, among selected people, having one factor can partly make up for not having the other. This direction is not universal: a sufficiently strong interaction in the selection probabilities can change it.
Worked Example: Selection Produces a Negative Association
Consider a hypothetical source population in which \(A\) and \(B\) are independent, each with probability \(0.5\) of being present. Suppose the probability of continued follow-up is \(0.20\) when neither is present, \(0.80\) when exactly one is present, and \(0.90\) when both are present. These probabilities are assumed to describe selection, not a causal effect of \(A\) on \(B\).
The selection probabilities are \(r_{00}=0.20\), \(r_{10}=0.80\), \(r_{01}=0.80\), and \(r_{11}=0.90\). Each source-population cell has probability \(0.25\). Multiplying each cell probability by its selection probability gives selected joint masses of \(0.050\), \(0.200\), \(0.200\), and \(0.225\), respectively. Their sum is \(0.675=P(R=1)\).
Dividing each mass by \(0.675\), the selected probabilities for \((A,B)=(0,0),(1,0),(0,1),(1,1)\) are \(2/27\), \(8/27\), \(8/27\), and \(9/27\). The selected odds ratio is
The source odds ratio was 1 because \(A\) and \(B\) were independent. Among those retained, the odds ratio is about 0.281, indicating a negative association. Selection has created the association; these calculations do not imply that \(A\) prevents \(B\), or that either factor causes the other.
How the Selection Mechanism Controls the Direction
The sign of the induced association depends on all four selection probabilities, not just on whether each factor predicts follow-up. In particular, the way the joint presence of both factors affects selection matters. The next examples use hypothetical probabilities to show why it is important to calculate rather than assume a direction.
Worked Example: An Additive Selection Rule
Suppose \(A\) and \(B\) are independent and each has source-population probability \(0.5\). Let the selection probability be \(r_{ab}=0.20+0.30a+0.30b\). The four probabilities are \(0.20, 0.50, 0.50,\) and \(0.80\); all are valid probabilities, and each factor increases selection probability at either level of the other factor.
The four selected masses, before normalization, are the source cell probabilities \(0.25\) multiplied by these selection probabilities: \(0.050, 0.125, 0.125,\) and \(0.200\). Their sum is \(0.500\). Thus the selected cell probabilities are \(0.10, 0.25, 0.25,\) and \(0.40\).
The selected odds ratio is
The selected marginal probability of either factor is \(0.25+0.40=0.65\). The covariance in the selected group is therefore \(0.40-(0.65)(0.65)=-0.0225\), also confirming negative dependence. In the source population the covariance was 0. The calculation agrees with the additive-rule derivation: both factors raise selection probability, producing a negative selected association in this example.
Worked Example: A Selection Interaction Reverses the Direction
Now suppose \(A\) and \(B\) are again independent with source probabilities \(0.5\), but use selection probabilities \(r_{00}=0.20\), \(r_{10}=0.40\), \(r_{01}=0.40\), and \(r_{11}=0.90\). Both factors increase selection probability whether or not the other factor is present. However, their joint presence raises selection probability more than an additive rule would predict.
The selected masses are \(0.050, 0.100, 0.100,\) and \(0.225\), which sum to \(0.475\). The selected cell probabilities are \(2/19,4/19,4/19,\) and \(9/19\). Therefore,
Here the induced association is positive, not negative. For an additional check, each selected marginal probability is \(13/19\), while \(P(A=1,B=1\mid R=1)=9/19\). The selected covariance is \(9/19-(13/19)^2=2/361\), which is positive. The result illustrates why “conditioning on a collider always creates a negative association” is not a valid rule. The direction follows from the selection probabilities, including their interaction.
Interpreting the Result in Follow-Up Data
In a longitudinal study, \(R=1\) might indicate that a biomarker measurement is available at a particular visit. The factors \(A\) and \(B\) could represent distinct determinants of being observed, such as access to care and health status. If the analysis uses only people with a measurement, it conditions on the common effect \(R\). A relationship between the determinants in that subset may then arise even if they were independent in the source population.
The same logic applies when selection is defined by being event-free and observable at a visit. The event-free observation indicator can be affected by multiple causes. Restricting the analysis to that indicator’s selected value can connect those causes. The key question is not whether a variable is called “dropout,” “attendance,” or “eligibility,” but whether analysis conditions on a common effect of factors that may otherwise be unrelated.
The calculation above has clear assumptions. The source-population independence of \(A\) and \(B\) is needed for the simple odds-ratio formula; if they are already associated, their source association also contributes to the selected association. The \(r_{ab}\) values must correspond to the selection event being analyzed, and the relevant cells must have positive probability to define the odds ratio. The diagram represents causal assumptions; observed data alone do not establish that its arrows or source independence are correct.
Diagnostics, Alternatives, and Limitations
Collider bias is a warning about a design or analysis restriction, not a pattern that can always be diagnosed from a single selected data set. Useful checks include comparing measured characteristics between people retained and not retained, examining whether candidate causes of follow-up predict observation, and checking whether the analysis conditions on an event or visit indicator influenced by multiple variables. These checks can flag plausible selection mechanisms, but they cannot prove independence in the source population or rule out unmeasured causes.
The main alternatives address different questions:
- Analyze the full eligible cohort where possible. Avoiding an unnecessary restriction on follow-up can prevent this particular collider path from being opened, though missing outcomes may still require handling.
- Model selection or use inverse-probability weighting. When important predictors of selection are measured, a suitable model for observation probabilities can support analyses that reweight observed participants toward the target population. This requires adequate measurement, a correctly specified selection model, and positivity: every relevant covariate pattern must have a nonzero chance of being observed. It does not automatically remove bias from unmeasured selection factors.
- Use a joint model when the scientific problem calls for it. A joint modeling approach can represent dependence between longitudinal measurements and event or observation processes under explicit assumptions. It does not make selection assumptions unnecessary, and its conclusions still depend on the adequacy of the specified model.
These approaches are not interchangeable cures. A complete-case analysis conditions directly on availability; weighting relies on measured predictors and a selection model; joint modeling represents dependence through its chosen structure. Each targets a different way of addressing incomplete or selected follow-up, and each can fail if its assumptions are implausible.
A further limitation is that the simple derivation concerns two binary factors and a binary selection indicator. With continuous factors, multiple visits, or selection depending on time-varying history, the induced association may be more complex. The basic lesson still applies: selection can alter relationships, and the direction and size cannot be inferred from the word “collider” alone.
Common Pitfall
A common mistake is to say, “\(A\) and \(B\) are independent in the cohort, so they will still be independent among participants with observed follow-up.” That reasoning ignores that selection probabilities can vary jointly with \(A\) and \(B\). The correction is to distinguish the source population from the selected analysis sample and, when the factors are binary, inspect \(r_{11}r_{00}\) relative to \(r_{10}r_{01}\). A second mistake is to assume that the resulting association is necessarily negative. The interaction example shows that it can be positive. Neither direction, by itself, establishes a causal effect between the factors.
Check Your Understanding
Answer each question using the distinction between the source population and the selected group. Solutions follow.
- If \(A\) and \(B\) are independent before selection and \(r_{00}=0.3\), \(r_{10}=0.6\), \(r_{01}=0.6\), and \(r_{11}=0.9\), what is the selected-sample odds ratio?
- What does a selected-sample odds ratio below 1 say, and what does it not establish?
- Can both \(A\) and \(B\) increase the chance of follow-up while their selected association is positive? Briefly explain.
- Name two assumptions or conditions required for the simple selection-odds-ratio calculation.
Solutions. 1. The odds ratio is \((0.9)(0.3)/[(0.6)(0.6)]=0.27/0.36=0.750\), so selection induces a negative association under the stated source independence. 2. It indicates that \(A\) and \(B\) are negatively associated among selected people on the odds-ratio scale; it does not show that either causes or prevents the other. 3. Yes. A strong joint effect on selection can make \(r_{11}r_{00}>r_{10}r_{01}\), giving a selected odds ratio above 1 even when each factor raises selection probability. 4. The factors must be independent in the source population for this formula to describe the selected odds ratio by selection probabilities alone, and the relevant cell probabilities must be positive. The selection probabilities must also describe the actual selection event being conditioned on.