Why the Baseline Hazard Matters
A joint model links a longitudinal marker to an event process, but the marker association does not by itself describe how event risk changes over time. That time pattern is supplied by the baseline hazard. Together, the baseline hazard and the marker-linked component determine the subject-specific hazard at each time. Understanding their distinct roles is essential for interpreting conditional survival and for checking that a fitted model represents plausible event risk.
Use \(i\) to index subjects, \(t\) for time, and \(b_i\) for subject \(i\)'s shared random effects. Write \(m_i(t)\) for the subject-specific latent marker value at time \(t\), as defined by the longitudinal submodel. The event hazard conditional on \(b_i\) is
Here \(h_0(t)\) is the baseline hazard and \(\alpha\) is the current-value association parameter. This form assumes that, conditional on the shared random effects and the latent marker history represented by \(m_i(t)\), the marker modifies the hazard multiplicatively. Other terms may be included in a fuller model, but this tutorial focuses on the baseline and current-value components.
The baseline is therefore a reference hazard curve, not a constant event probability and not necessarily a constant hazard. If time is measured in years, for example, \(h_0(t)\) has units of inverse years. The exponent must be dimensionless, so \(\alpha\) has units reciprocal to those of the marker. When \(m_i(t)=0\), the multiplier is one and the conditional hazard equals \(h_0(t)\). When \(m_i(t)\) is positive, the hazard is multiplied by \(\exp\{\alpha m_i(t)\}\); a negative value of \(\alpha\) reverses the direction of that association.
From Hazard to Conditional Survival
A hazard describes an instantaneous rate among subjects who have remained event-free up to the time in question. It is not itself a probability. To obtain a probability of surviving through an interval, the hazard must be accumulated over time. Conditional on \(b_i\), define the cumulative hazard through time \(t\) by
The integration variable is \(u\), because the hazard and latent marker can change throughout the interval. The conditional survival function is
This relationship follows from the definition of hazard. Over a short interval of length \(dt\), conditional survival changes approximately by a factor \(1-h_i(t\mid b_i)dt\). Thus \(dS_i(t\mid b_i)/dt=-h_i(t\mid b_i)S_i(t\mid b_i)\). Dividing by survival and integrating from 0 to \(t\), with \(S_i(0\mid b_i)=1\), gives \(\log S_i(t\mid b_i)=-\int_0^t h_i(u\mid b_i)\,du\), and exponentiating gives the stated result.
The cumulative hazard is dimensionless, as required by the exponential. The conditional probability of an event by \(t\), for a subject event-free at time 0, is \(1-S_i(t\mid b_i)\). For an interval beginning at \(s\), the event probability conditional on being event-free at \(s\) is \(1-\exp\{-[H_i(t\mid b_i)-H_i(s\mid b_i)]\}\), for \(t>s\). Both quantities depend on the hazard over the full relevant interval, not just its value at the endpoint.
Worked Example: A Constant Baseline and Marker Value
Suppose, hypothetically, that time is measured in years, the baseline hazard is \(h_0(t)=0.020\) per year over the interval of interest, and a subject has latent marker value \(m_i(t)=2\) marker units throughout three years. Let \(\alpha=0.5\) per marker unit. Compute the conditional hazard, survival, and event probability at three years.
The marker multiplier is \(\exp(0.5\times2)=\exp(1)=2.7183\). Therefore the subject-specific hazard is
Because this hazard is constant over the three-year interval, the cumulative hazard is \(H_i(3\mid b_i)=0.05437\times3=0.1631\). Hence
Under these specified model values, the subject has about 0.8495 conditional probability of remaining event-free through three years and 0.1505 conditional probability of experiencing the event by then. The baseline hazard alone would imply survival \(\exp(-0.020\times3)=0.9418\); the lower survival in the example follows from the positive marker-linked multiplier. These are model-based conditional quantities, not estimates of a population-average risk.
A Changing Baseline and a Changing Marker
When either component varies with time, the cumulative hazard generally requires integration of their product. In particular, it is usually incorrect to multiply the cumulative baseline hazard by the marker multiplier evaluated at the final time. That shortcut would ignore the marker values and baseline levels at earlier times. Numerical integration is one way to evaluate the required integral when no convenient closed form is available.
Worked Example: Numerical Integration Over Time
Consider a hypothetical subject followed for four months. Let \(t\) denote the numerical time in months, let the latent marker rise at one marker unit per month so that \(m_i(t)=t\), and set \(\alpha=0.2\log(2)\) per marker unit. Suppose the baseline hazard is \(h_0(t)=0.010+0.002t\) per month, where the coefficient of \(t\) has units of inverse months squared. Then the integrand for cumulative hazard is
Use Simpson's rule with spacing one month, which is valid here because there are four equal subintervals. The integrand values at months 0, 1, 2, 3, and 4 are approximately \(0.01000\), \(0.01378\), \(0.01847\), \(0.02425\), and \(0.03134\), respectively. Simpson's rule gives
The cumulative hazard is dimensionless: the integrand is per month and the integration is over months. The conditional survival and event probability by month 4 are therefore
Thus the model gives about 0.9261 conditional probability of remaining event-free through month 4 and about 0.0739 conditional probability of an event by then. The approximation depends on the stated time grid and numerical integration rule; a finer grid or a more accurate integration method can be used when needed.
The integral also explains why the baseline and marker components cannot usually be separated into two independent cumulative terms. In general,
The right-hand side is valid only in special cases, such as when \(m_i(u)\) is constant throughout the interval. Otherwise, the multiplier changes inside the integral and must be evaluated along the latent trajectory.
Instantaneous Association Is Not a Risk Ratio
At a fixed time, comparing two subjects under the same baseline hazard isolates the marker-linked hazard ratio. For subjects \(i\) and \(j\), conditional on their respective random effects,
This is a ratio of instantaneous hazards at time \(t\), not a ratio of event probabilities over a follow-up period. Cumulative probabilities also depend on how the baseline and each subject's marker value evolve over the entire interval.
Worked Example: Hazard Ratio Versus Event Probability
Suppose, hypothetically, that \(h_0(t)=0.030\) per year for five years and that two subjects have constant latent marker values \(m_A(t)=1\) and \(m_B(t)=0\). Let \(\alpha=\log(1.5)\) per marker unit. The hazard for subject A is \(0.030\exp\{\log(1.5)\}=0.0450\) per year, while the hazard for subject B is \(0.030\) per year. Their instantaneous hazard ratio is \(0.0450/0.030=1.5\).
Since each hazard is constant in this example, the five-year cumulative hazards are \(0.0450\times5=0.225\) for A and \(0.030\times5=0.150\) for B. The corresponding conditional event probabilities are
The event-probability ratio is approximately \(0.2015/0.1393=1.446\), not 1.5. The value 1.5 is the instantaneous hazard ratio under the model; it does not directly give the ratio of five-year event probabilities.
Conditional and Population-Level Interpretation
The hazard formula above is conditional on the shared random effects. Those effects connect the longitudinal and event submodels: they help determine the latent marker trajectory and therefore the marker-linked hazard. A subject-specific conditional survival is consequently not the same as survival averaged across the population. If \(G(b)\) denotes the random-effects distribution, the population survival at \(t\) is
In general, this is not \(\exp\{-\int h_i(t\mid b)\,dG(b)\,dt\}\), nor is it obtained by simply inserting an average marker trajectory into the conditional formula. The exponential and averaging operation do not generally commute. Interpretation should therefore specify whether a reported quantity is conditional on random effects or averaged over their distribution.
Assumptions, Diagnostics, and Alternatives
The baseline-hazard representation relies on several conditions. The baseline must be nonnegative and integrable over the time intervals used, so that cumulative hazards are finite there. The multiplicative association assumes that the marker changes the hazard through the stated exponential factor; in particular, a one-unit marker difference gives the same hazard ratio \(\exp(\alpha)\) at each time, conditional on other modeled quantities. The latent marker trajectory must be defined on the times at which its value enters the event model. The shared-random-effects formulation also requires that the conditional event model be interpreted given those random effects and the modeled latent history.
Useful checks follow directly from the structure of the model:
- Check the baseline scale and units. A hazard stated per month cannot be integrated against time measured in years without converting units.
- Check nonnegativity and cumulative monotonicity. A baseline hazard should not be negative, and a computed cumulative hazard should not decrease as time advances.
- Inspect the implied time pattern. A baseline that is too restrictive may fail to represent changing event risk when the marker is at its reference value. Compare fitted and observed event patterns over time using appropriate model diagnostics.
- Check the marker contribution. Confirm the marker scale and the direction and size of \(\alpha\). A unit change in a rescaled marker changes the numerical value and interpretation of \(\alpha\).
- Check integration accuracy. When the integrand changes quickly, a coarse grid can distort cumulative hazards and survival probabilities. Recalculate with a finer grid and compare results.
A common mistake is to call \(h_0(t)\) the subject's event probability at time \(t\), or to report \(\exp(\alpha)\) as the event-probability ratio. The correction is that \(h_0(t)\) is a reference rate, and \(\exp(\alpha)\) is the conditional hazard ratio for a one-unit difference in latent marker value at a fixed time. Probabilities require integrating the subject-specific hazard over an interval and converting cumulative hazard to survival or event probability.
Baseline-hazard choices trade assumptions against flexibility. A fully specified parametric baseline gives a compact form but commits to a particular time pattern. A semiparametric approach leaves the baseline less restricted while estimating the association, and flexible estimated curves can represent more varied patterns but may require careful smoothing or numerical calculations. These approaches do not change the basic relationship \(h_i(t\mid b_i)=h_0(t)\exp\{\alpha m_i(t)\}\); they differ in how \(h_0(t)\) is represented and estimated. No baseline choice compensates for a misspecified marker association, an unsuitable time scale, or inadequate event information.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions below.
- If \(h_0(t)\) is measured per year, what are the units of \(H_i(t\mid b_i)\)?
- At a fixed time, two subjects have latent marker values differing by two units. What is their conditional hazard ratio if \(\alpha=0.3\) per marker unit?
- Why is it generally incorrect to calculate cumulative hazard by multiplying cumulative baseline hazard by the marker multiplier at the end of follow-up?
- What distinguishes conditional survival given random effects from population-average survival?
Solutions. (1) Cumulative hazard is dimensionless because a hazard in inverse years is integrated over years. (2) The ratio is \(\exp(0.3\times2)=\exp(0.6)=1.822\), assuming the subjects share the same baseline hazard at that time. (3) The marker multiplier may vary over time, so the correct calculation is \(\int_0^t h_0(u)\exp\{\alpha m_i(u)\}\,du\), not the cumulative baseline multiplied by the endpoint value. (4) Conditional survival fixes the subject's random effects; population-average survival averages the conditional survival over their distribution, and in general cannot be obtained by substituting an average random effect into the conditional formula.