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Fitting MSMs for Survival Outcomes · Tutorial 196 of 501

Interval Width Effects in Pooled Logistic Survival MSMs

Learn how interval width changes the treatment coefficient in a pooled logistic survival MSM, and how to diagnose and interpret that dependence.

Advanced 11 min read

What You'll Learn

  • Derive the event probability and odds for an interval under a continuous-time hazard.
  • Relate interval-specific odds ratios to a continuous-time hazard ratio.
  • Calculate how unequal or split intervals change a pooled-logistic treatment coefficient.
  • Identify when a constant treatment coefficient is incompatible with the assumed hazard model.
  • Diagnose interval-width sensitivity and distinguish it from changes in cumulative risk.
  • Compare pooled logistic estimates with continuous-time Cox-model estimates.

Why Interval Width Matters

A pooled logistic survival MSM models whether an event occurs within each interval among individuals still at risk at its start. Its treatment coefficient therefore describes an interval odds ratio, not automatically a continuous-time hazard ratio. The distinction matters whenever interval widths differ, or when the same follow-up is divided into different numbers of intervals: even if the underlying treatment effect on the hazard is constant, the interval odds ratio can change with interval width.

We derive this dependence for a simple continuous-time model, then examine what it implies for model specification and interpretation. The calculations also show why a coefficient can change when intervals are regrouped even though the underlying event process and cumulative risks have not changed.

From a Continuous-Time Hazard to an Interval Odds Ratio

Let interval \(j\) run from \(c_{j-1}\) to \(c_j\), with width \(\Delta_j=c_j-c_{j-1}\). Let \(Y_{ij}=1\) indicate that individual \(i\) experiences the event in that interval, conditional on being event-free and at risk at \(c_{j-1}\). For treatment level \(a\), write the cumulative hazard over the interval as \(H_{aj}=\int_{c_{j-1}}^{c_j}\lambda_a(t)\,dt\). Assume a continuous event time, no competing event, and a hazard \(\lambda_a(t)\) that correctly describes the event process under treatment level \(a\). The event probability in the interval is \(p_{aj}=1-\exp(-H_{aj})\).

Definition: The interval event odds under treatment \(a\) in interval \(j\) are \(p_{aj}/(1-p_{aj})\). The interval odds ratio comparing treatment levels 1 and 0 is \(\{p_{1j}/(1-p_{1j})\}/\{p_{0j}/(1-p_{0j})\}\). It is conditional on being at risk at the interval’s start.

The hazard-to-risk relationship gives a direct expression for these odds. Since \(1-p_{aj}=\exp(-H_{aj})\), the odds equal \(\{\;1-\exp(-H_{aj})\;\}/\exp(-H_{aj})=\exp(H_{aj})-1\). Thus the interval odds depend on the cumulative hazard in that interval, and so generally depend on its width.

$$ \frac{p_{aj}}{1-p_{aj}}=\exp(H_{aj})-1, \qquad \operatorname{OR}_j= \frac{\exp(H_{1j})-1}{\exp(H_{0j})-1}. $$

Suppose treatment has a constant proportional effect on the continuous-time hazard: \(\lambda_1(t)=r\lambda_0(t)\), where \(r>0\) is the hazard ratio. Then \(H_{1j}=rH_{0j}\), and \(\operatorname{OR}_j=\{\exp(rH_{0j})-1\}/\{\exp(H_{0j})-1\}\). This is not generally \(r\). The interval odds ratio is a function of the baseline cumulative hazard in the interval, which usually grows as the interval becomes wider.

Result: Under proportional hazards with ratio \(r\), as \(H_{0j}\) approaches zero, the interval odds ratio approaches \(r\). For \(H_{0j}>0\), it is greater than \(r\) when \(r>1\), and less than \(r\) when \(0<r<1\).

To verify the small-interval limit, put \(x=H_{0j}\). The Taylor expansion \(\exp(x)-1=x+O(x^2)\) gives \(\{\exp(rx)-1\}/\{\exp(x)-1\}=\{rx+O(x^2)\}/\{x+O(x^2)\}\), which tends to \(r\) as \(x\) decreases to zero. For the strict comparison at positive \(x\), the function \(f(s)=\exp(sx)-1\) is strictly convex, with \(f(0)=0\). If \(r>1\), strict convexity implies \(f(1)<f(r)/r\), so \(f(r)/f(1)>r\). If \(0<r<1\), it implies \(f(r)<rf(1)\), so \(f(r)/f(1)<r\). These are the claimed comparisons. \(\square\)

What a Pooled Logistic MSM Estimates

With baseline treatment \(A_i\), a pooled logistic MSM with interval-specific intercepts and a common treatment coefficient has the form \(\operatorname{logit}P(Y_{ij}=1\mid R_{ij}=1,A_i)=\alpha_j+\beta A_i\), where \(R_{ij}=1\) indicates that individual \(i\) is at risk at the start of interval \(j\). In an MSM, treatment and, when needed, censoring weights are used to represent the target pseudo-population. A causal interpretation requires the relevant consistency, exchangeability, and positivity assumptions, adequate handling of censoring, and appropriate weights; the weighted outcome model must also represent the target interval risks adequately.

Under a continuous-time proportional-hazards process, the interval-specific log odds ratio implied by the process is \(\beta_j=\log\{\{\exp(rH_{0j})-1\}/\{\exp(H_{0j})-1\}\}\). A common \(\beta\) is therefore generally not the exact interval-specific effect when the \(H_{0j}\) differ. If that common-effect model is fitted anyway, its estimate is a compromise determined by the interval-specific risks, risk sets, weights, and the fitted model. It is not, in general, a fixed transformation of the continuous-time hazard ratio.

Worked Example: The Same Hazard Ratio in Short and Long Intervals

Suppose the untreated hazard is constant at \(0.10\) per time unit and the treated hazard is constant at \(0.20\), so the continuous-time hazard ratio is \(r=2\). For an interval of width 1, the untreated cumulative hazard is \(0.10\) and the treated cumulative hazard is \(0.20\). The risks are \(1-\exp(-0.10)\approx0.09516\) and \(1-\exp(-0.20)\approx0.18127\). The odds ratio is \((\exp(0.20)-1)/(\exp(0.10)-1)=\exp(0.10)+1\approx2.10517\).

For an interval of width 3, the cumulative hazards are \(0.30\) and \(0.60\). The odds ratio becomes \((\exp(0.60)-1)/(\exp(0.30)-1)=\exp(0.30)+1\approx2.34986\). The equality follows by factoring \(\exp(0.60)-1=(\exp(0.30)-1)(\exp(0.30)+1)\). The hazard ratio remains 2 in both calculations, but the interval odds ratio is larger in the wider interval.

Worked Consequences of Unequal and Split Intervals

Worked Example: Unequal Intervals and an Interval Odds Ratio

Suppose the baseline cumulative hazard in one interval is \(0.10\), and treatment multiplies the hazard by 3. The interval odds ratio is \((\exp(0.30)-1)/(\exp(0.10)-1)\). Because \(0.30=3(0.10)\), factor the numerator to obtain \((\exp(0.30)-1)/(\exp(0.10)-1)=\exp(0.20)+\exp(0.10)+1\). Using \(\exp(0.20)\approx1.22140\) and \(\exp(0.10)\approx1.10517\), the result is \(1.22140+1.10517+1=3.32657\), approximately \(3.327\), not 3.

This interval has a nonzero baseline cumulative hazard, so the interval odds ratio is above the hazard ratio of 3. If another interval has a different cumulative baseline hazard, its odds ratio will generally differ as well, even though the continuous-time hazard ratio remains 3.

Worked Example: Splitting an Interval Changes the Coefficient

Return to constant hazards \(0.10\) without treatment and \(0.20\) with treatment over a total follow-up of 2 time units. If follow-up is represented as one interval of width 2, the interval odds ratio is \((\exp(0.40)-1)/(\exp(0.20)-1)=\exp(0.20)+1\approx2.22140\).

Now split the same follow-up into two intervals of width 1. In each interval, conditional on being event-free at its start, the odds ratio is \((\exp(0.20)-1)/(\exp(0.10)-1)=\exp(0.10)+1\approx2.10517\). The two interval-specific odds ratios agree with each other, but they do not equal the one-interval odds ratio.

The cumulative risks over the full follow-up are unchanged by this bookkeeping choice. Without treatment, the risk by time 2 is \(1-\exp(-0.20)\approx0.18127\); with treatment it is \(1-\exp(-0.40)\approx0.32968\). Thus regrouping intervals changes the pooled-logistic treatment coefficient while leaving the continuous-time process and full-period risks unchanged.

Model Checks, Alternatives, and Limitations

When intervals are unequal, or when baseline event rates vary substantially over time, inspect whether the model’s treatment effect is plausibly constant on the interval log-odds scale. A useful diagnostic is to fit or examine treatment-by-interval terms and compare the interval-specific estimates with their uncertainty. Large systematic differences, especially differences associated with interval width or baseline event frequency, can indicate that a common pooled-logistic coefficient is an inadequate summary. Also check whether conclusions change when a scientifically defensible alternative interval partition is used. This is a sensitivity check, not a guarantee that one partition is correct.

The main alternatives answer somewhat different questions. A continuous-time Cox model targets a hazard-ratio description on the continuous-time scale and does not define its treatment coefficient through chosen event intervals. A pooled logistic model is useful when the discrete interval risk is itself the target or when the analysis is naturally organized in discrete time. In either case, adequate weighting, risk-set construction, and uncertainty estimation remain necessary. The introductory material on the continuous-time limit of pooled logistic models explains why short intervals can make the logistic and hazard comparisons numerically close; that approximation does not make them identical for finite intervals.

Common pitfall: “The hazard ratio is constant, so one common pooled-logistic treatment coefficient must represent it in every interval.” This reasoning confuses hazard ratios with interval odds ratios. Under proportional hazards, the latter depend on interval cumulative hazard. Use interval-specific treatment effects when supported by the data and scientific aim, use sufficiently fine intervals when appropriate, or choose a continuous-time model if that matches the target. A robust variance estimate does not repair a misspecified mean model.

Interval width is not merely a formatting choice if the fitted coefficient is interpreted as an interval odds ratio. Coarsening combines event-free time and events into wider intervals, while fine partitioning creates smaller interval risks and odds ratios closer to hazard ratios. Both choices can be reasonable, but the interpretation must match the interval definition. Unequal intervals deserve particular care: a common treatment coefficient may obscure genuine width-related differences, while a single reported coefficient can be sensitive to how the follow-up has been partitioned.

Check Your Understanding

Answer each question, then compare with the worked solutions below.

  1. Under a constant baseline hazard of \(0.05\) per time unit and hazard ratio 2, what is the interval odds ratio for a width of 1? Show the calculation.
  2. For a proportional hazard ratio \(r=0.5\) and positive interval cumulative baseline hazard, is the interval odds ratio above or below 0.5? Explain.
  3. Why can splitting one follow-up interval into shorter intervals change a pooled-logistic treatment coefficient without changing full-period risk?
  4. Name two checks that can reveal problems with a common treatment coefficient across unequal intervals.

Solutions. (1) Here \(H_0=0.05\), so the odds ratio is \((\exp(0.10)-1)/(\exp(0.05)-1)=\exp(0.05)+1\approx2.05127\), which is greater than the hazard ratio 2. (2) It is below 0.5: strict convexity of \(f(s)=\exp(sH_0)-1\), with \(f(0)=0\), gives \(f(0.5)<0.5f(1)\), so \(f(0.5)/f(1)<0.5\). (3) Each interval odds ratio depends on the cumulative hazard within that interval, whereas full-period survival depends on the cumulative hazard over the whole follow-up. Partitioning changes the former but not the latter. (4) Examine treatment-by-interval estimates for systematic differences, and assess sensitivity to a scientifically defensible alternative interval partition. Either can flag incompatibility between a common log-odds effect and the observed interval pattern.

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