Why Treatment Labels Can Be Too Broad
A treatment variable often records a category such as “treated” or “received the drug.” But that label may hide what was actually done: the dose, timing, duration, route, or method of delivery. If those differences can change an outcome, “treated” does not by itself describe one intervention with one potential outcome. The difficulty is not merely imprecise data recording. It is that the causal question may not yet specify what action is being compared.
The earlier material on consistency for longitudinal treatment strategies expresses the basic requirement: for a person whose observed treatment history matches a specified strategy, the observed outcome equals the potential outcome under that strategy. When a strategy is recorded only as a broad treatment label, we must ask whether its hidden versions can legitimately be treated as the same intervention.
The phrase “for an outcome” matters. Two delivery methods might produce the same value of one outcome but different values of another. Whether versions can be grouped is therefore a substantive, outcome-specific judgment, not a rule that can be settled from the treatment variable’s name alone.
Consistency When Versions Are Recorded
Suppose one decision is observed as a pair \((A,V)\). The version-specific consistency condition is \(Y=Y^{A,V}\): the observed outcome equals the potential outcome under the treatment level and version actually received. If a longitudinal history records both levels and versions, the corresponding condition is \(Y=Y^{\bar A,\bar V}\). This says what consistency means for fully specified observed treatment; it does not assert that the data identify any potential-outcome mean.
For a broad level \(a\) with possible versions in a set \(\mathcal V_a\), a single potential outcome \(Y^a\) is coherent only when the version-specific potential outcomes agree, at least almost surely, across the versions that the broad level is intended to include. If they do agree, write their common value as \(Y^a\). If they do not, the level-specific label alone leaves multiple possible outcomes and does not define one version-free potential outcome.
To justify the result, first suppose the version-specific outcomes agree. Choose one version \(v_0\in\mathcal V_a\) and set \(Y^a=Y^{a,v_0}\). For every \(v\in\mathcal V_a\), the assumed equality gives \(Y^{a,v}=Y^{a,v_0}=Y^a\) almost surely. In the other direction, if \(Y^{a,v}=Y^a\) and \(Y^{a,v'}=Y^a\) almost surely, then \(Y^{a,v}=Y^{a,v'}\) almost surely by transitivity of almost-sure equality. Thus a version-free outcome is not an additional observed quantity: it is a coherent summary only when the version-specific outcomes support it. \(\square\)
Three Ways a Broad Label Can Hide an Intervention
Worked Example: A Drug Label That Hides the Dose
Suppose \(A=1\) means “received the drug,” but the label combines doses of 2 mg and 10 mg. Let their potential-outcome means be \(E[Y^{1,2\text{mg}}]=8\) and \(E[Y^{1,10\text{mg}}]=5\), in a setting where higher outcomes are preferable. These values differ, so the broad label does not have a single version-free mean unless the intervention also specifies how dose is chosen.
For a policy that assigns 2 mg with probability \(0.75\) and 10 mg with probability \(0.25\), independently of the potential outcomes, the policy mean is \(0.75(8)+0.25(5)=6+1.25=7.25\). If instead the probabilities are \(0.25\) and \(0.75\), the mean is \(0.25(8)+0.75(5)=2+3.75=5.75\).
Both policies use the recorded label \(A=1\), but their means differ by \(1.5\). “The mean outcome if treated” is therefore not determined by the label alone. It could refer to either dose policy, or to another specified policy.
Worked Example: Timing Is Part of the Treatment
Consider an intervention recorded as “start therapy during the first week.” It includes starting on day 1 and starting on day 7. Suppose the potential outcome is symptom score on day 14, with lower values better. For a particular patient, let \(Y^{a,\text{day 1}}=3\) and \(Y^{a,\text{day 7}}=7\). These are different outcomes under two versions of the same broad label.
If a study records only \(A=a\), it cannot say which of these two potential outcomes corresponds to an intervention that says only “start during the first week.” To make the intervention unambiguous, specify a start day, define a timing rule (for example, start on the first day symptoms exceed a stated threshold), or state a probability distribution over start days. Each option defines a different intervention question.
The calculation is not an adjustment for timing. It is a check on what the treatment intervention means: the broad label contains potential outcomes that need not coincide.
Worked Example: Delivery Route and a Stochastic Version Policy
Suppose a treatment level includes oral and intravenous delivery. Their version-specific potential-outcome means are 10 and 6. Define a policy \(G\) that selects oral delivery with probability \(0.4\) and intravenous delivery with probability \(0.6\), independently of the vector of potential outcomes. Its mean is \(0.4(10)+0.6(6)=4+3.6=7.6\).
A policy that reverses the probabilities has mean \(0.6(10)+0.4(6)=6+2.4=8.4\). Thus even if the broad treatment label is consistently recorded, it does not determine which policy mean is intended. A policy that specifies the version distribution does.
Means Under a Policy That Selects Versions
A broad treatment level need not be discarded merely because its versions have different effects. Instead, the intervention can explicitly select among versions. Let \(G\) denote a random version drawn according to probabilities \(g(v)\), where \(\sum_{v\in\mathcal V_a}g(v)=1\), and define \(Y^{a,G}=Y^{a,V}\) when \(G=V\). Assume the version draw is independent of the potential-outcome vector \(\{Y^{a,v}:v\in\mathcal V_a\}\). This independence describes the policy’s randomization; it is not a claim about how versions were assigned in observational data.
For a finite set, partition according to the selected version. Independence gives \(P(G=v\mid \{Y^{a,u}\}_u)=g(v)\). Consequently, \(E[Y^{a,G}]=\sum_v E[\mathbf 1(G=v)Y^{a,v}]\). For each term, independence implies \(E[\mathbf 1(G=v)Y^{a,v}]=g(v)E[Y^{a,v}]\). The finite sum yields the stated identity; finiteness of each absolute expectation ensures each term is integrable.
For a countable set, the same partition gives a sum of expectations. The condition \(\sum_v g(v)E[|Y^{a,v}|]<\infty\) implies \(E[\sum_v\mathbf 1(G=v)|Y^{a,v}|]=\sum_v g(v)E[|Y^{a,v}|]<\infty\), by Tonelli’s theorem for nonnegative terms. Hence the selected outcome is integrable, and the sum of signed expectations can be interchanged with expectation by absolute integrability. This proves the identity and ensures its value is finite. Without this condition, finite expectations for each individual version do not by themselves guarantee a finite policy mean. \(\square\)
A specified version policy is an alternative to demanding that all versions have identical effects. The two approaches answer different questions: version-free consistency treats the versions as equivalent for the outcome, whereas a policy mean averages over versions with stated probabilities. A fixed version is another option, as is refining the treatment variable so that substantively distinct versions are separate levels.
Diagnostics, Common Mistakes, and Limits
When reviewing a treatment definition, list the features that can vary within each recorded level. For a medication, check dose, schedule, duration, and route. For a procedure, check timing, provider, and relevant implementation details. Ask whether these differences are part of the intended intervention, whether the potential outcome is plausibly unchanged across them, or whether a rule for selecting versions should be specified. In data, examine whether versions are actually recorded and whether treatment labels combine visibly different protocols. These checks diagnose ambiguity; they do not prove that unrecorded versions have no effect.
- Common mistake: assuming the treatment name is the intervention. The reasoning “everyone received the drug, so consistency gives one \(Y^1\)” fails if “received the drug” combines doses with different potential outcomes. The correction is to specify a version or policy, or defend the claim that the included versions have the same potential outcome.
- Common mistake: confusing version ambiguity with confounding. Defining a dose policy does not establish that people receiving that dose are comparable to people not receiving it. A precise intervention and assumptions for causal identification are separate requirements.
- Diagnostic warning: versions are unmeasured. If dose or timing is absent from the data, it may be impossible to check whether the recorded category combines versions. A broad label can remain ambiguous even when the data contain no visible evidence of differences.
The main alternatives each have limits. Refining categories clarifies the intervention only when the relevant version information is measured and the resulting categories are meaningful. Specifying a stochastic policy makes version selection explicit, but its mean still depends on the chosen probabilities. Treating all versions as equivalent can simplify the estimand, but requires substantive justification and may fail for one outcome even if it is plausible for another. None of these choices, by itself, supplies the assumptions needed to identify the causal effect from observed data.
Check Your Understanding
Answer each question, then compare your reasoning with the solutions.
- A treatment label includes two doses with version-specific potential outcomes that differ for some individuals. Can one common potential outcome represent both doses? What would make the intervention precise?
- A policy selects versions \(v_1\) and \(v_2\) with probabilities \(0.2\) and \(0.8\), and their potential-outcome means are 9 and 4. Calculate the policy mean under the independence and integrability conditions stated above.
- Why does observing \(Y=Y^{A,V}\) not imply that \(Y=Y^A\) for a treatment label that omits \(V\)?
- For a countably infinite version set, why is finite \(E[|Y^{a,v}|]\) for every version not sufficient to guarantee a finite policy mean?
- A protocol says “deliver treatment within 48 hours” but does not specify how the delivery time is selected. Give two ways to make the causal intervention more precise.
Solutions. (1) No, not if the two version-specific potential outcomes differ with positive probability. Specify a dose, or state a policy for selecting doses. (2) The mean is \(0.2(9)+0.8(4)=1.8+3.2=5\). (3) The observed equality refers to the actual pair \((A,V)\); it does not establish that potential outcomes are equal across versions hidden inside \(A\). (4) The weighted absolute expectations may have an infinite sum, so the expected absolute outcome under the policy may be infinite even though each version-specific expectation is finite. (5) Specify a particular delivery time, or define a timing rule or probability distribution over times.