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Stagewise Boundaries and Familywise Error · Tutorial 179 of 499

Unequal Information Increments Across Stages

Learn how unequal information increments determine cross-stage and cross-arm dependence, and how to calibrate boundaries that control familywise type I error.

Advanced 12 min read

What You'll Learn

  • Express each stagewise statistic as a standardized cumulative score.
  • Derive cross-stage and cross-arm covariances from information increments.
  • Distinguish unequal information increments from equal information fractions.
  • Calibrate multivariate-normal boundaries using the correct covariance matrix.
  • Construct conservative familywise-valid boundaries with an explicit error budget.
  • Diagnose when a canonical joint model or a chosen calibration is not justified.

Why Unequal Information Increments Matter

In a multi-arm, multi-stage trial, an interim statistic summarizes the evidence accumulated so far. Its dependence on later statistics is determined by how much information was added between looks. If stages contribute unequal increments, treating the looks as equally spaced can give the wrong joint distribution, even when the marginal statistic at each look is correctly standardized. Since boundary calibration depends on the probability of crossing at least one boundary, this can distort familywise type I error.

The key calculation is to build cumulative statistics from stage-specific score increments and then derive their covariance. The resulting covariance matrix—not the labels “first,” “second,” or “final” look by themselves—is the input to a multivariate-normal calibration. The earlier material on multivariate-normal calibration provides the general calibration framework; here the focus is how unequal information increments determine its dependence structure.

Score Increments and the Joint Distribution

Let \(i=1,\ldots,J\) index treatment comparisons and \(k=1,\ldots,K\) index stages. For comparison \(i\), let \(\Delta I_{ik}>0\) be the information added at stage \(k\), and let \(I_{ik}=\sum_{r=1}^{k}\Delta I_{ir}\) be cumulative information. Write \(Y_{ik}\) for the stage-\(k\) score increment, on a scale for which its variance is the information increment under the null. The cumulative standardized statistic is

$$ Z_{ik}=\frac{\sum_{r=1}^{k}Y_{ir}}{\sqrt{I_{ik}}}. $$

For the canonical joint model used here, assume the increments have mean zero under the relevant null hypotheses, are jointly multivariate normal, and are independent across stages. Within stage \(r\), let \(\operatorname{Cov}(Y_{ir},Y_{jr})=C_{ij,r}\), with \(C_{ii,r}=\Delta I_{ir}\). These assumptions describe a fixed, prespecified information plan and score process; if the analysis or data collection changes the joint law, the covariance must be justified for that design rather than borrowed unchanged.

Definition: Under the stage-independent increment model, the covariance between two standardized statistics is $$ \operatorname{Cov}(Z_{ik},Z_{j\ell})= \frac{\sum_{r=1}^{\min(k,\ell)}C_{ij,r}} {\sqrt{I_{ik}I_{j\ell}}}. $$ The sum stops at the earlier look because later-stage increments are independent of the earlier cumulative score.

In particular, for a single arm comparison, \(C_{ii,r}=\Delta I_{ir}\), so \(\operatorname{Corr}(Z_{ik},Z_{i\ell})=\sqrt{I_{ik}/I_{i\ell}}\) when \(k<\ell\). The correlation is therefore the square root of the earlier information divided by the later information, not necessarily the square root of the look-number ratio. Across comparisons, the covariances \(C_{ij,r}\) reflect shared data and design features such as a common control group. They should come from the specified score covariance model.

Justifying the Covariance Formula

The formula follows directly by expanding the covariance of the two cumulative sums. If \(k\leq \ell\), then the first statistic contains increments \(1,\ldots,k\), while the second contains increments \(1,\ldots,\ell\). Stage independence makes every covariance between distinct stages zero. The only contributions are the matching stages through \(k\):

$$ \begin{aligned} \operatorname{Cov}(Z_{ik},Z_{j\ell}) &=\frac{1}{\sqrt{I_{ik}I_{j\ell}}} \operatorname{Cov}\left(\sum_{r=1}^{k}Y_{ir},\sum_{s=1}^{\ell}Y_{js}\right)\\ &=\frac{1}{\sqrt{I_{ik}I_{j\ell}}} \sum_{r=1}^{k}\operatorname{Cov}(Y_{ir},Y_{jr})\\ &=\frac{\sum_{r=1}^{k}C_{ij,r}}{\sqrt{I_{ik}I_{j\ell}}}. \end{aligned} $$

The same result with \(\min(k,\ell)\) applies when the order of the looks is reversed. Since the increments are jointly normal and the statistics are linear combinations of them, the full vector of \(Z\)-statistics is multivariate normal under the model. This derivation also supplies a practical diagnostic: a proposed covariance matrix should be symmetric, have unit diagonal, and be positive semidefinite. A failure indicates an arithmetic error or an incompatible increment-covariance specification.

Worked Example: Building the Covariance Matrix With Unequal Increments

Suppose there are two treatment comparisons and two stages. Their information increments are \((40,60)\) and \((25,75)\), respectively. Assume that within each stage the increment correlation between comparisons is \(0.30\), so \(C_{12,r}=0.30\sqrt{\Delta I_{1r}\Delta I_{2r}}\). Calculate selected correlations and state what the unequal information implies.

The cumulative information values are \(I_{11}=40\), \(I_{12}=100\), \(I_{21}=25\), and \(I_{22}=100\). For comparison 1, the correlation between its first- and second-stage cumulative statistics is \(\sqrt{40/100}=0.6325\). For comparison 2 it is \(\sqrt{25/100}=0.5000\). These are different because the first stage contributes different fractions of the two comparisons’ total information.

The first-stage cross-comparison covariance of the increments is \(C_{12,1}=0.30\sqrt{40\cdot25}=9.4868\). Thus the correlation between the first-look statistics is \(9.4868/\sqrt{40\cdot25}=0.3000\), as specified. Between comparison 1 at the first look and comparison 2 at the second look, only the first-stage increment is shared: \(\operatorname{Cov}(Z_{11},Z_{22})=9.4868/\sqrt{40\cdot100}=0.1500\).

At the second stage, \(C_{12,2}=0.30\sqrt{60\cdot75}=20.1246\). Therefore the correlation between the two final statistics is \((9.4868+20.1246)/\sqrt{100\cdot100}=0.2961\). The reduction from \(0.30\) is due to the differing stage-specific information patterns; the final covariance is obtained by summing increment covariances before standardizing.

From the Joint Law to Familywise-Valid Boundaries

Suppose each hypothesis is tested in the upper direction, with rejection at look \(k\) for comparison \(i\) if \(Z_{ik}\geq b_{ik}\). Under a specified intersection null, define the crossing event as the event that at least one true-null statistic crosses its boundary. A multivariate-normal calibration chooses the boundaries so that the probability of this event is at most \(\alpha\). In integral form, for a set \(S\) of hypotheses treated as true, the calibration condition is

$$ P_{H_S}\left(\bigcup_{i\in S}\bigcup_{k=1}^{K} \{Z_{ik}\geq b_{ik}\}\right)\leq \alpha, $$

where the probability is computed using the joint null distribution for the statistics in \(S\). Equality is often used when calibrating a common boundary or a prespecified family of boundaries, but a conservative inequality is also valid. For strong familywise control, this condition must hold for every possible set of true null hypotheses, or be combined with a valid closed-testing procedure. Calibrating only under the complete null is not automatically enough: its validity for partial-null configurations requires an additional property, such as the appropriate subset-pivotal joint distribution.

The calibration is a numerical probability calculation. With a fixed covariance matrix, the probability of no crossing is the multivariate-normal probability of the rectangle \(Z_{ik}<b_{ik}\) for all included looks and comparisons; crossing probability is one minus that rectangle probability. Recursive probability calculation or numerical multivariate-normal integration can evaluate it. Unequal increments enter through the covariance matrix, so replacing that matrix by one based on equal information fractions changes the probability being calibrated.

Worked Example: A Guaranteed Boundary by Bonferroni Allocation

Consider two one-sided comparisons observed at two looks, with familywise level \(\alpha=0.05\). The information increments are unequal as in the preceding example. Construct a simple boundary that controls the familywise error without needing to numerically integrate the joint distribution.

Allocate \(\alpha_{ik}=0.05/4=0.0125\) to each of the four comparison-look tests, and use the common critical value \(c=\Phi^{-1}(1-0.0125)\). Since \(\Phi^{-1}(0.9875)\approx2.241\), set \(b_{ik}=2.241\) at all four looks. Under each true null, the corresponding one-sided marginal crossing probability is \(0.0125\), provided the statistic has the stated standard normal null distribution.

For any configuration of true nulls, the probability of at least one false rejection is no larger than the sum of the marginal crossing probabilities for those true-null tests. Even if all four hypotheses are true, \(P(\text{at least one false rejection})\leq4(0.0125)=0.0500\). For a smaller true subset, the sum is smaller. This is therefore strongly familywise-valid under the marginal null assumptions, regardless of the correlations or unequal information increments. It may be conservative because it does not use the joint dependence to reduce the boundary.

A less conservative alternative is to use the derived covariance matrix and solve the multivariate crossing-probability condition for a prespecified boundary pattern. That calculation can exploit the dependence, but its guarantee relies on the covariance model and on validity for the relevant true-null subsets. The Bonferroni construction is a useful benchmark when checking a numerical calibration.

Allocation, Diagnostics, and Limits

A boundary need not be constant across looks. One can allocate error over comparison-look pairs, use prespecified stagewise spending, or numerically calibrate a joint boundary pattern. Whatever choice is made, the allocation or calibration rule should be fixed as part of the design and should account for all opportunities to reject a true null. In particular, using a nominal level \(\alpha\) separately at every look does not control the familywise error at \(\alpha\).

Before using a calibrated boundary, check the assumptions and the calculation:

  • Confirm that \(\Delta I_{ik}>0\), that cumulative information is updated by summation, and that every statistic is standardized by the square root of its own cumulative information.
  • Check that increment covariances are appropriate for the design and that the resulting joint covariance matrix is symmetric and positive semidefinite.
  • Verify that the marginal null distributions used by the calibration are standard normal, or use a justified alternative distribution and calibration method.
  • Recompute crossing probabilities with the final boundary values and check the error budget, including the relevant true-null subsets.

A common mistake is to set the correlation between looks to \(\sqrt{k/\ell}\) merely because one statistic is from look \(k\) and the other from look \(\ell\). That expression is appropriate only when information increments are equal across those looks for the comparison in question. In the worked example, the actual within-comparison correlations are \(0.6325\) and \(0.5000\), not a common value obtained from look numbers. A second mistake is to infer strong control from a complete-null calibration alone. The correction is to establish the necessary subset validity or use a procedure that controls error for every relevant intersection.

The canonical calculation has limits. Stage independence and a correct score covariance model are substantive assumptions, not consequences of unequal information arithmetic. If increments are dependent across stages, the numerator of the covariance must include the nonzero cross-stage covariances as well. If information is altered using interim data, or the null distribution changes under alternative configurations, a fixed covariance calibration may not be valid without further justification. The central lesson remains: boundaries are only as reliable as the joint distribution used to calibrate them.

Check Your Understanding

Answer each question using the increment model above. Solutions are included after the questions.

  1. A comparison has information increments 36 and 64. What is the correlation between its first- and second-look standardized statistics?
  2. For two comparisons, suppose the first-stage increment covariance is 12, and their cumulative information at the second look is 64 and 100. What is the covariance between the first-look statistic for comparison 1 and the second-look statistic for comparison 2, if the first-look information for comparison 1 is 36?
  3. Why does allocating \(\alpha/4\) to each of four one-sided tests control familywise error at level \(\alpha\), without requiring independent statistics?
  4. What additional issue must be addressed before a complete-null multivariate calibration can be claimed to provide strong familywise control?

Solutions. (1) The correlation is \(\sqrt{36/(36+64)}=\sqrt{0.36}=0.6000\). (2) The covariance is \(12/\sqrt{36\cdot100}=12/60=0.2000\), because only the shared first-stage increment contributes. (3) The union bound gives a probability of any false rejection no greater than the sum of the marginal probabilities, at most \(4(\alpha/4)=\alpha\), regardless of dependence. (4) One must justify validity for every possible true-null subset, for example through an appropriate subset-pivotality condition or closed testing; the complete-null result alone does not guarantee it.

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