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Local Influence · Tutorial 151 of 499

Normal Curvature of the Likelihood Displacement

You will derive the likelihood-displacement curvature matrix and learn how its largest curvature summarizes the most sensitive unit-length perturbation direction.

Advanced 12 min read

What You'll Learn

  • Define the likelihood displacement as the gain from refitting at the same perturbed likelihood.
  • Derive the normal-curvature matrix from the observed information and mixed likelihood derivatives.
  • Interpret directional curvature and its maximum over unit perturbations.
  • Calculate curvature matrices for hypothetical selection-likelihood perturbations.
  • Diagnose sign, scaling, and numerical problems in local-curvature calculations.
  • Compare normal curvature with other local and casewise influence summaries.

Why Normal Curvature Matters

A selection-model likelihood can respond differently to small changes in different aspects of the analysis: subject weights, covariates in a selection equation, or other specified perturbations. A local quadratic approximation summarizes that response near the unperturbed analysis. The normal curvature measures how quickly the likelihood displacement grows as the perturbation moves away from its baseline. Its largest value over unit-length perturbations gives a concise measure of the most sensitive local direction.

The derivation is useful because curvature depends on two ingredients with distinct roles: the likelihood's local information about the parameters and the way the perturbation changes the score. This tutorial derives their combination and states carefully which likelihood difference is being approximated. The earlier material on likelihood displacement and its local quadratic approximation motivates the quantity; the focus here is its curvature matrix and interpretation.

Setup and Definition

Let \(\ell(\theta;\omega)\) be a twice continuously differentiable log likelihood for a selection model, where \(\theta\) is a \(p\)-dimensional parameter vector and \(\omega\) is a \(q\)-dimensional perturbation vector. The unperturbed value is \(\omega_0\), and \(\hat{\theta}\) is an interior local maximizer of \(\ell(\theta;\omega_0)\). Thus the baseline score is zero. Assume the observed information matrix at this fit is positive definite:

$$ J=-\left.\frac{\partial^2\ell(\theta;\omega)} {\partial\theta\,\partial\theta'}\right|_{(\hat{\theta},\omega_0)}. $$

The mixed derivative matrix describes how the score changes with the perturbation:

$$ \Delta=\left.\frac{\partial^2\ell(\theta;\omega)} {\partial\theta\,\partial\omega'}\right|_{(\hat{\theta},\omega_0)}. $$

For \(\omega\) near \(\omega_0\), let \(\hat{\theta}(\omega)\) denote the local maximizer that continues from \(\hat{\theta}\). We use the positive refitting gain as the likelihood displacement:

$$ LD(\omega)=2\{\ell(\hat{\theta}(\omega);\omega) -\ell(\hat{\theta};\omega)\}. $$

Both likelihood values in this definition use the same perturbed likelihood. The first is evaluated at its refitted maximizer and the second at the baseline parameter. This makes the displacement nonnegative when the refitted point maximizes that perturbed likelihood over the parameter region being compared.

Definition: The normal-curvature matrix for this likelihood displacement is \(C=2\Delta'J^{-1}\Delta\). For a unit perturbation direction \(a\), its normal curvature is \(a'Ca\), and locally \(LD(\omega_0+ta)=\tfrac12t^2a'Ca+o(t^2)\) as \(t\) tends to zero.

Deriving the Curvature Matrix

The derivation uses the score equation for the perturbed fit. Write \(a=\omega-\omega_0\) and \(d=\hat{\theta}(\omega)-\hat{\theta}\). Differentiability and the implicit function theorem give a local smooth solution to the score equation when \(J\) is nonsingular. Expanding that equation around the baseline gives

$$ 0=\ell_\theta(\hat{\theta}+d;\omega_0+a) =-Jd+\Delta a+o(\|d\|+\|a\|). $$

Since \(J\) is invertible, this first implies \(d=O(\|a\|)\), and then

$$ d=J^{-1}\Delta a+o(\|a\|). $$

Now compare the two parameter values under the same perturbed likelihood. At the baseline parameter, the perturbed score is \(\ell_\theta(\hat{\theta};\omega_0+a)=\Delta a+o(\|a\|)\), because the score at \((\hat{\theta},\omega_0)\) is zero. Taylor expansion in the parameter gives

$$ \ell(\hat{\theta}+d;\omega_0+a)-\ell(\hat{\theta};\omega_0+a) =(\Delta a)'d-\frac12d'Jd+o(\|a\|^2). $$

Substituting \(d=J^{-1}\Delta a+o(\|a\|)\), and using the symmetry of \(J\), yields the local improvement:

$$ \ell(\hat{\theta}(\omega_0+a);\omega_0+a) -\ell(\hat{\theta};\omega_0+a) =\frac12a'\Delta'J^{-1}\Delta a+o(\|a\|^2). $$

Multiplication by two gives \(LD(\omega_0+a)=a'\Delta'J^{-1}\Delta a+o(\|a\|^2)\), or equivalently the definition's \(\tfrac12a'Ca\) form. The factor of two in \(C\) therefore corresponds to defining curvature as the second derivative of displacement along a direction.

This result also explains the matrix's key properties. Since \(J\) is positive definite, \(J^{-1}\) is positive definite, so \(a'Ca=2(\Delta a)'J^{-1}(\Delta a)\geq 0\). Thus \(C\) is positive semidefinite. If \(\Delta a=0\), the perturbation direction has zero curvature to this order: it produces no first-order score change, although higher-order effects are not ruled out.

Worked Curvature Calculations

Worked Example: A Two-Parameter Likelihood and Two Perturbations

Suppose a hypothetical selection-model fit has two parameters and two perturbation coordinates. At the baseline fit, let \(J=\begin{pmatrix}4&1\\1&3\end{pmatrix}\) and \(\Delta=\begin{pmatrix}1&0\\0&2\end{pmatrix}\). Assume the fit is an interior local maximum and these matrices are the derivatives at that fit. The determinant of \(J\) is \(4(3)-1(1)=11>0\); its leading diagonal entry is positive, so \(J\) is positive definite.

First invert the information matrix:

$$ J^{-1}=\frac{1}{11} \begin{pmatrix}3&-1\\-1&4\end{pmatrix} = \begin{pmatrix}0.2727&-0.09091\\-0.09091&0.3636\end{pmatrix}. $$

Then \(\Delta'J^{-1}\Delta=\frac{1}{11}\begin{pmatrix}3&-2\\-2&16\end{pmatrix}\), so

$$ C=2\Delta'J^{-1}\Delta =\frac{2}{11}\begin{pmatrix}3&-2\\-2&16\end{pmatrix} = \begin{pmatrix}0.5455&-0.3636\\-0.3636&2.909\end{pmatrix}. $$

For the unit direction \(a=(1,0)'\), the curvature is \(a'Ca=0.5455\); for \(a=(0,1)'\), it is \(2.909\). In the second direction, the local displacement for a perturbation of size \(t\) is approximately \(\tfrac12(2.909)t^2=1.455t^2\). This comparison indicates greater local sensitivity along the second coordinate, but does not by itself say whether the underlying model is misspecified.

Worked Example: A Perturbation With Redundant Directions

Consider a hypothetical one-parameter selection likelihood with \(J=5\) and three perturbation coordinates whose mixed derivatives are \(\Delta=(1,2,-1)\). The information is positive, so the local maximum has positive curvature in the parameter direction. Direct multiplication gives

$$ C=2\Delta'J^{-1}\Delta =\frac{2}{5} \begin{pmatrix} 1&2&-1\\ 2&4&-2\\ -1&-2&1 \end{pmatrix}. $$

For the unit direction \(a=(1,0,0)'\), \(a'Ca=2/5=0.4\). For \(b=(0,1,0)'\), \(b'Cb=8/5=1.6\). In the unit direction \(v=(1,0,1)'/\sqrt{2}\), \(\Delta v=(1-1)/\sqrt{2}=0\), so \(v'Cv=0\). The perturbation changes in this last combination cancel in the first-order score. This rank-deficient curvature matrix does not uniquely distinguish all three perturbation coordinates; redundant directions should be considered when interpreting a diagnostic.

Worked Example: Checking the Displacement Convention

Let the hypothetical log likelihood be \(\ell(\theta;\omega)=-\tfrac12(\theta-\omega)^2\), with scalar parameter and perturbation, and baseline \(\hat{\theta}=\omega_0=0\). Then \(J=1\), \(\Delta=1\), and the perturbed maximizer is \(\hat{\theta}(\omega)=\omega\). Under the positive refitting-gain definition,

$$ LD(\omega)=2\{\ell(\omega;\omega)-\ell(0;\omega)\} =2\{0-(-\omega^2/2)\}=\omega^2. $$

The curvature matrix is the scalar \(C=2\), and \(\tfrac12 C\omega^2=\omega^2\), as required. In contrast, comparing \(\ell(\hat{\theta};\omega_0)\) with \(\ell(\hat{\theta}(\omega);\omega)\) gives zero in this example: it mixes likelihoods at different perturbations and does not yield the refitting-gain curvature formula. Reversing the order of the two likelihood values evaluated at the same perturbed \(\omega\) gives the negative of the gain, not a nonnegative displacement.

Largest Curvature and Interpretation

For any unit vector \(a\), the directional curvature is the quadratic form \(a'Ca\). The largest possible value over all unit directions is the largest eigenvalue of the symmetric matrix \(C\); a direction attaining it is a locally most sensitive unit perturbation direction. This characterization follows from the Rayleigh-quotient result for symmetric matrices. It is a local statement: it compares perturbations using the specified coordinate scale and approximation near \(\omega_0\), not arbitrary finite changes.

A large maximum curvature means that some small unit-length perturbation can produce relatively large likelihood displacement, to second order. It does not establish that the perturbation is plausible, that the model is wrong, or that a particular treatment-effect contrast changes substantially. Curvature summarizes refitting of the full parameter vector; a target-specific assessment requires a different diagnostic.

The units and scaling of \(\omega\) matter. If one coordinate is measured in days and another in years, a unit Euclidean perturbation treats those numerical units as comparable, which may be scientifically inappropriate. Rescaling coordinates changes \(C\) and its largest curvature. Use a defensible perturbation scale, such as prespecified comparable changes, before interpreting the maximum.

Assumptions, Diagnostics, and Alternatives

The derivation relies on a smooth likelihood near the baseline, an interior stationary fit, and nonsingular positive-definite observed information. It also assumes that the perturbed local maximizer continues smoothly from the baseline one. In selection models, numerical instability, weak identification, boundary estimates, or multiple competing maxima can undermine these conditions. The curvature then describes, at best, one local branch and should not be treated as a global summary.

Useful checks include verifying that the fitted score is close to zero, checking that \(J\) is symmetric and positive definite, and confirming that the perturbation derivatives use the same parameter and perturbation scales as the likelihood. A numerical check compares directly refitted displacements at small \(t\) with \(\tfrac12 t^2a'Ca\); the ratio should approach one as \(t\) decreases when the approximation is working. Large discrepancies, a ratio that does not stabilize, or branch changes in the optimizer may indicate derivative errors, an overly large perturbation, or failure of local regularity.

Normal curvature complements rather than replaces other influence approaches. Exact case deletion assesses a finite change to the observed data contribution, while a first-order case-deletion approximation targets that particular removal. Weighted-likelihood perturbations provide a chosen coordinate system for subject influence; normal curvature summarizes their joint local response over directions. Likelihood-based sensitivity curves can instead track a specified treatment effect as a sensitivity parameter varies. These methods answer different questions, and a large normal curvature should be followed by inspection of the corresponding perturbation scale and practical consequences.

Common Pitfalls and Limitations

  • Mixing perturbation values in the likelihood difference. The baseline fit evaluated at \(\omega_0\) and the perturbed fit evaluated at \(\omega\) include direct changes to the likelihood. Their difference is not the refitting gain derived here.
  • Reversing the sign. The positive gain is the perturbed maximum minus the baseline parameter's likelihood under that same perturbation. Reversing the order produces a nonpositive quantity.
  • Dropping the factor of two. With the convention \(LD=2\) times the gain, the matrix is \(C=2\Delta'J^{-1}\Delta\), and the expansion is \(\tfrac12a'Ca\).
  • Ignoring units. A largest curvature is meaningful only relative to the perturbation coordinates and their scaling.
  • Overinterpreting local evidence. Small-perturbation curvature does not guarantee accurate predictions for large changes or diagnose causal effects.
Key takeaway: Under smoothness, an interior fit, and positive-definite observed information, the positive same-perturbation refitting gain has normal-curvature matrix \(C=2\Delta'J^{-1}\Delta\). Its largest curvature identifies the most sensitive unit direction on the chosen perturbation scale.

Check Your Understanding

Answer each question, then check the concise solutions below.

  1. State the definition of \(J\) and \(\Delta\), including where they are evaluated.
  2. If \(J=4\) and \(\Delta=3\) in a scalar problem, calculate \(C\).
  3. For the scalar likelihood in the convention example, what does the positive refitting-gain displacement equal?
  4. Why can a large maximum curvature be misleading if perturbation coordinates have very different units?
  5. Name two conditions needed for the local derivation and give one diagnostic check.

Solutions. (1) \(J\) is the negative parameter Hessian and \(\Delta\) is the parameter-by-perturbation mixed derivative, both evaluated at \((\hat{\theta},\omega_0)\). (2) \(C=2\Delta^2/J=2(9)/4=4.5\). (3) It is \(\omega^2\), because the perturbed maximum has log likelihood zero and the baseline parameter has log likelihood \(-\omega^2/2\) under that same perturbation. (4) Unit length then combines changes that may not be comparable in practical size; rescaling changes the curvature. (5) Conditions include differentiability, an interior stationary fit, positive-definite information, and a smoothly continuing local maximum. A useful check is to compare small-step refitted displacements with the quadratic approximation along a selected direction.

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