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IV Assumptions and Local Average Treatment Effects · Tutorial 473 of 699

A Worked Wald Calculation From an Encouragement Trial

You will calculate the treatment and outcome contrasts in an encouragement trial, form their Wald ratio, and identify the assumptions needed to interpret it as a complier effect.

Advanced 10 min read

What You'll Learn

  • Calculate the first-stage treatment contrast from randomized assignment groups.
  • Calculate the reduced-form outcome contrast using the same groups.
  • Divide the contrasts to obtain the Wald estimate with the correct units.
  • Explain why the ratio identifies a local average treatment effect for compliers under IV assumptions.
  • Distinguish the Wald estimate from the intention-to-treat effect and an as-treated comparison.
  • Recognize weak first stages and assumption violations that undermine interpretation.

From an Encouragement Table to a Wald Estimate

In an encouragement trial, assignment changes how likely people are to receive a treatment, but it does not determine treatment receipt for everyone. The randomized assignment can therefore be used as an instrument for treatment receipt. A basic calculation compares the outcome difference between assignment groups with the difference in treatment receipt between those same groups. The resulting ratio is the Wald estimate.

The calculation has two distinct contrasts. The outcome contrast measures the effect of assignment on the outcome, often called the reduced-form or intention-to-treat contrast. The treatment contrast measures how much assignment changed treatment receipt, called the first stage. Dividing the first by the second puts the outcome contrast on the scale of treatment receipt.

Definition: Let \(Z=1\) denote assignment to encouragement and \(Z=0\) denote assignment to control; let \(D=1\) denote receipt of treatment and \(D=0\) no receipt; and let \(Y\) be the outcome. The first-stage contrast is \(\Delta_D=E[D\mid Z=1]-E[D\mid Z=0]\). The reduced-form outcome contrast is \(\Delta_Y=E[Y\mid Z=1]-E[Y\mid Z=0]\). When \(\Delta_D\ne 0\), the Wald ratio is \(\Delta_Y/\Delta_D\).

In a sample, use the observed mean treatment receipt and outcome in each assignment group: \(\widehat{\Delta}_D=\bar{D}_{Z=1}-\bar{D}_{Z=0}\) and \(\widehat{\Delta}_Y=\bar{Y}_{Z=1}-\bar{Y}_{Z=0}\). The sample Wald estimate is \(\widehat{\Delta}_Y/\widehat{\Delta}_D\). For binary \(D\), each group’s mean \(D\) is its treatment-receipt proportion. Keep the assignment groups as the basis for both contrasts; comparing people by treatment actually received is a different, generally confounded comparison.

Why the Ratio Can Represent a Complier Effect

The ratio has a causal interpretation only under assumptions. Write \(D(z)\) for the treatment receipt a person would have under assignment \(z\), and \(Y(d)\) for the outcome that person would have under treatment status \(d\). The relevant assumptions are that assignment is independent of these potential outcomes and potential treatment receipts (as supplied by valid randomization); assignment affects the outcome only through treatment receipt (the exclusion restriction); treatment receipt and outcomes are consistent with the defined interventions, with no interference between participants; and there are no defiers, so \(D(1)\ge D(0)\) for every person. There must also be a nonzero first stage: the encouragement changes treatment receipt for some people.

The principal compliance types are defined by \((D(1),D(0))\): compliers are \((1,0)\), always-takers are \((1,1)\), never-takers are \((0,0)\), and defiers are \((0,1)\). Under monotonicity, defiers are absent. Random assignment makes the assignment-group contrasts identify the corresponding expectations over the randomized population. Exclusion means assignment itself does not change \(Y\), apart from any change caused by treatment receipt.

$$ \begin{aligned} \Delta_D &= E[D(1)-D(0)]\\ &= P(\text{complier}),\\[4pt] \Delta_Y &= E[Y(D(1))-Y(D(0))]\\ &= P(\text{complier})\,E[Y(1)-Y(0)\mid \text{complier}]. \end{aligned} $$

The first equality for \(\Delta_D\) follows because random assignment identifies the mean difference in potential treatment receipt, and because, without defiers, \(D(1)-D(0)\) is one for compliers and zero for everyone else. For the outcome contrast, exclusion and consistency allow the observed outcome under assignment \(z\) to be written as \(Y(D(z))\). Compliers contribute \(Y(1)-Y(0)\) to the difference across assignments. Always-takers receive treatment either way, and never-takers receive no treatment either way, so both types contribute zero. Averaging therefore gives the second line. Dividing the two contrasts yields:

$$ \frac{\Delta_Y}{\Delta_D} =E[Y(1)-Y(0)\mid \text{complier}]. $$

This is the local average treatment effect (LATE) for compliers: their average causal effect of treatment, not automatically the average treatment effect for everyone. The derivation explains why the denominator matters. The outcome contrast is diluted because only some participants change treatment receipt when encouraged; dividing by the size of that change rescales the contrast to the complier group.

Worked Example: A Randomized Offer and a Symptom Score

In a hypothetical trial, 100 participants are randomly assigned an offer of a treatment and 100 are assigned control. The outcome is a symptom score at follow-up, measured in points; lower scores indicate fewer symptoms. The table reports treatment receipt and mean outcome by randomized assignment.

AssignmentParticipantsReceived treatmentMean symptom score
Offer (\(Z=1\))100706.4 points
Control (\(Z=0\))100207.0 points

The treatment-receipt proportions are \(70/100=0.70\) and \(20/100=0.20\), so the first stage is \(\widehat{\Delta}_D=0.70-0.20=0.50\). The reduced-form outcome contrast is \(\widehat{\Delta}_Y=6.4-7.0=-0.6\) points. Thus:

$$ \widehat{\text{Wald}} =\frac{-0.6\text{ points}}{0.50} =-1.2\text{ symptom-score points per treatment recipient}. $$

If the IV assumptions hold, this estimates an average reduction of 1.2 symptom-score points from treatment among compliers. The numerator alone says that assignment to the offer lowered the mean score by 0.6 points; the ratio is not that assignment effect. The table is consistent with a first stage, but it cannot establish exclusion or monotonicity. Those assumptions require design knowledge and substantive justification, not just this arithmetic.

Calculating Carefully From Counts and Totals

When the table gives counts and outcome totals rather than means, first calculate a mean within each randomized assignment group. Do not calculate an outcome mean among treatment recipients and compare it with one among nonrecipients: those groups are formed after assignment and can differ in ways that affect the outcome.

Worked Example: Unequal Assignment-Group Sizes

Suppose a hypothetical trial randomly assigns 120 people to a treatment offer and 80 to control. The outcome is a continuous functioning score in points. In the offer group, 84 people receive treatment and the outcome total is 756 points. In control, 24 receive treatment and the outcome total is 448 points.

The first-stage contrast is the difference in receipt proportions: \[ \widehat{\Delta}_D=\frac{84}{120}-\frac{24}{80}=0.70-0.30=0.40. \] The unequal group sizes do not change the calculation: each group’s count is divided by its own size.

The assignment-group outcome means are \(756/120=6.30\) points and \(448/80=5.60\) points. Therefore \(\widehat{\Delta}_Y=6.30-5.60=0.70\) points, and:

$$ \widehat{\text{Wald}} =\frac{0.70\text{ points}}{0.40} =1.75\text{ points per treatment recipient}. $$

Under the IV assumptions, the estimate is a 1.75-point average increase in the functioning score caused by treatment among compliers. Randomization supports independence if assignment was implemented as specified. The table shows a nonzero sample first stage, but does not by itself verify exclusion, monotonicity, consistency, or no interference.

Diagnostics, Uncertainty, and What the Table Cannot Show

Before interpreting a Wald ratio, check the calculation and the design. Confirm that the rows are randomized assignment groups, that the receipt rates use each row’s correct denominator, and that the outcome means use the same assignment groups. Check the direction and units of both contrasts. If assignment increases receipt, \(\widehat{\Delta}_D\) should be positive under the chosen coding; the Wald estimate’s sign should then match the outcome contrast. A small denominator deserves particular attention: even a modest outcome difference can produce a very large ratio.

A nonzero first stage is necessary, but a weak first stage makes the ratio unstable. Sampling variation in a denominator near zero can produce a highly variable estimate and unreliable conventional confidence intervals. A large Wald estimate in that setting is not, by itself, evidence of a large treatment effect. Report the first-stage and reduced-form contrasts alongside the ratio, and assess uncertainty using methods appropriate for an instrumental-variables ratio; do not treat the point calculation as a complete inferential analysis.

The assumptions also have different evidential status. Randomization can support instrument independence, and the observed treatment rates show whether assignment changed receipt in the sample. But a table cannot demonstrate that the offer has no direct effect on the outcome, that no one is a defier, or that treatment versions and interference are innocuous. Those are design and substantive questions. If an assumption fails, the ratio may not estimate the complier effect even when every arithmetic step is correct.

Worked Example: A Very Small First Stage

In a hypothetical randomized trial, 150 participants are assigned encouragement and 150 control. Treatment is received by 90 in the encouragement group and 86 in control. The mean outcome is 5.20 points under encouragement and 5.00 points under control.

The first stage is \(90/150-86/150=0.6000-0.5733=0.02667\). The reduced-form contrast is \(5.20-5.00=0.20\) points. The sample Wald calculation is:

$$ \widehat{\text{Wald}} =\frac{0.20\text{ points}}{0.02667} \approx 7.50\text{ points per treatment recipient}. $$

This is the arithmetic result, not a reason to conclude confidently that treatment raises the outcome by 7.50 points among compliers. The observed difference in treatment receipt is only about 2.67 percentage points, so sampling noise in that denominator can strongly affect the ratio. The IV interpretation also still requires the design assumptions. A weak observed first stage is a warning about precision and stability, not proof that the assumptions hold or fail.

How the Wald Estimate Differs From Other Comparisons

ApproachWhat is comparedWhat it answers or risks
Wald ratioOutcome contrast by assignment divided by treatment-receipt contrast by assignmentUnder the IV assumptions, estimates the treatment effect among compliers.
Intention-to-treat contrastMean outcome by randomized assignmentEstimates the effect of assignment to encouragement, not the effect of treatment receipt.
As-treated comparisonMean outcome among those who received treatment versus those who did notMay be confounded because receipt is not randomized, even if assignment is.

The Wald estimate is useful when the scientific target is the effect of receiving treatment for people whose receipt is changed by encouragement. It does not generally recover the effect for always-takers, never-takers, or the whole population. The complier group is defined by potential responses to assignment, so membership cannot usually be identified for each individual from the observed table.

Common mistake: “The offer group’s outcome is lower by 0.6 points, so treatment lowered the outcome by 0.6 points for everyone.” This confuses the randomized assignment contrast with the treatment effect and ignores that encouragement changes receipt for only some participants. The correction is to report the 0.6-point assignment contrast as the reduced form, calculate the first stage, and divide the former by the latter only when the IV assumptions are defensible. Even then, interpret the result as a complier effect, not an all-participant effect.

Key takeaway: Calculate both contrasts by randomized assignment, then form \(\widehat{\Delta}_Y/\widehat{\Delta}_D\). The ratio’s complier-effect interpretation depends on valid assignment, exclusion, monotonicity, consistency, no interference, and a nonzero first stage; the table alone cannot verify all of these.

Check Your Understanding

For each question, calculate the requested contrast before interpreting it.

  1. In a hypothetical trial, treatment receipt is 48% under encouragement and 18% under control. Mean outcome is 10 points under encouragement and 9.4 under control. Calculate the first stage, reduced form, and Wald estimate with units.
  2. A trial has 80 people assigned to an offer, of whom 56 receive treatment, and 120 assigned to control, of whom 48 receive treatment. What is the first-stage contrast?
  3. In a randomized trial, the first stage is 0.25 and the outcome contrast is \(-1.0\) point. State the Wald estimate and its assumption-dependent interpretation.
  4. Why is a comparison of mean outcomes among treatment recipients and nonrecipients not the Wald calculation, even when assignment was randomized?

Solutions. (1) The first stage is \(0.48-0.18=0.30\); the reduced form is \(10-9.4=0.60\) points; the Wald estimate is \(0.60/0.30=2.00\) points per treatment recipient, interpretable under the IV assumptions as a complier effect. (2) The receipt proportions are \(56/80=0.70\) and \(48/120=0.40\), so the first stage is \(0.30\). (3) The Wald estimate is \(-1.0/0.25=-4.00\) points per treatment recipient; under the IV assumptions, it estimates the average treatment effect among compliers. (4) Treatment receipt is not the randomized grouping variable: recipients and nonrecipients may differ in outcome-related characteristics. The Wald calculation instead uses the outcome and receipt contrasts between randomized assignment groups.

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