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Partial Identification and Bounds · Tutorial 412 of 699

Monotone Treatment Response Bounds

Learn how monotone treatment response restricts binary potential outcomes and tightens worst-case bounds without assuming treatment is randomly assigned.

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What You'll Learn

  • State the unit-level monotone treatment response assumption for binary potential outcomes.
  • Derive bounds for each population potential-outcome mean from observed treatment and outcome rates.
  • Obtain the sharp average treatment effect bounds while respecting the dependence between the potential outcomes.
  • Compare the result with worst-case bounds that do not impose monotone response.
  • Assess what the assumption means, what observed data can and cannot diagnose, and when the bounds are informative.

What Monotone Treatment Response Adds

When an outcome is binary, the treatment effect for a unit can only be \(-1\), \(0\), or \(1\). If treatment is assumed not to lower anyone’s outcome, the value \(-1\) is ruled out for every unit. This is a strong restriction on individual potential outcomes, not a claim that treated units must have better observed outcomes than untreated units. Treatment assignment may still depend on potential outcomes, so the observed treated and untreated groups can differ for many reasons.

Let \(D\in\{0,1\}\) indicate treatment, and let \(Y(1)\) and \(Y(0)\) be a unit’s potential outcomes under treatment and no treatment. The observed outcome is \(Y=DY(1)+(1-D)Y(0)\). Define the population average treatment effect as \(E[Y(1)-Y(0)]\). The goal is to bound this quantity using the observed treatment rate and outcome rates, while allowing treatment assignment to be associated with the potential outcomes.

Definition: Monotone treatment response (MTR) for a higher-is-better outcome means \(Y(1)\geq Y(0)\) for every unit (or, in a population formulation, with probability one). For a binary outcome, the possible pairs \((Y(0),Y(1))\) are therefore \((0,0)\), \((0,1)\), and \((1,1)\); the pair \((1,0)\) is ruled out.

MTR is the added assumption. Consistency links the observed outcome to the potential outcome under the treatment actually received. No random assignment, exchangeability, or independence between \(D\) and the potential outcomes is assumed here.

Observed Quantities and Potential-Outcome Means

Suppose \(0<P(D=1)<1\), so both treatment groups are present. Write \(p=P(D=1)\), \(q_1=P(Y=1\mid D=1)\), and \(q_0=P(Y=1\mid D=0)\). The observed population masses with outcome one in the two groups are \(p q_1\) and \((1-p)q_0\). These are joint population proportions, rather than conditional outcome rates.

$$ r_1=pq_1=P(Y=1,D=1), \qquad r_0=(1-p)q_0=P(Y=1,D=0). $$

Let \(\mu_1=E[Y(1)]\) and \(\mu_0=E[Y(0)]\). Among treated units, \(Y(1)\) is observed. Under MTR, any treated unit whose observed \(Y(1)=0\) must also have \(Y(0)=0\). Thus the unobserved mass of \(Y(0)=1\) among treated units can range from zero to \(r_1\). Among untreated units, \(Y(0)\) is observed. MTR requires \(Y(1)=1\) whenever \(Y(0)=1\), while units with \(Y(0)=0\) may have either value of \(Y(1)\). These restrictions give the following marginal bounds.

$$ (1-p)q_0 \leq \mu_0 \leq (1-p)q_0+pq_1, $$
$$ pq_1+(1-p)q_0 \leq \mu_1 \leq pq_1+(1-p). $$

These intervals restrict each potential-outcome mean separately. To bound their difference, it is important to respect which unobserved outcomes belong to which treatment group; subtracting arbitrary endpoints of the two marginal intervals need not give sharp bounds.

Deriving the Sharp Average Treatment Effect Bounds

Let \(x\) be the population mass of treated units whose \(Y(0)=1\). MTR and the observed treated outcomes imply \(0\leq x\leq r_1\). Let \(z\) be the mass of untreated units whose \(Y(1)=1\) and \(Y(0)=0\). The untreated group has mass \(1-p\), of which \(r_0\) has \(Y(0)=1\). Therefore \(0\leq z\leq (1-p)-r_0\). The potential-outcome means can be written as \(\mu_0=r_0+x\) and \(\mu_1=r_1+r_0+z\), so their difference is \(r_1+z-x\).

$$ E[Y(1)-Y(0)] = (r_1+r_0+z)-(r_0+x) = r_1+z-x. $$

The smallest value occurs at \(z=0\) and \(x=r_1\), giving zero. The largest occurs at \(z=(1-p)-r_0\) and \(x=0\), giving \(r_1+(1-p)-r_0\). Substituting the observed rates yields the result.

Theorem: Under consistency, binary outcomes, and MTR, with \(0<p<1\), the sharp bounds on the population average treatment effect are
$$ 0\leq E[Y(1)-Y(0)]\leq pq_1+(1-p)(1-q_0). $$
“Sharp” means that both endpoints, and values between them, can be attained by potential-outcome assignments consistent with the observed data and the assumptions. The interval does not generally identify one treatment-effect value.

To see why the endpoints are attainable, set \(x=r_1\) and \(z=0\) for the lower endpoint: treated units have \(Y(0)=Y(1)\), and untreated units also have \(Y(1)=Y(0)\). This construction reproduces the observed outcomes and gives zero effect for every unit. For the upper endpoint, set \(x=0\), and set \(Y(1)=1\) for every untreated unit with \(Y(0)=0\). This assigns the largest allowed effect to each group while matching the observed outcomes. The choices are feasible because MTR is imposed within each unit and does not restrict treatment assignment.

Worked Example: Computing the MTR Bounds

Suppose, hypothetically, \(p=0.40\), \(q_1=0.75\), and \(q_0=0.30\). Assume binary outcomes, consistency, and MTR. No assumption about how treatment was assigned is made. First calculate the observed joint masses: \(r_1=0.40(0.75)=0.30\) and \(r_0=0.60(0.30)=0.18\).

For the untreated potential-outcome mean, the bounds are \(\mu_0\in[r_0,r_0+r_1]=[0.18,0.48]\). For the treated potential-outcome mean, they are \(\mu_1\in[r_1+r_0,r_1+(1-p)]=[0.48,0.90]\). These are population proportions on the zero-to-one outcome scale.

The sharp effect bounds are \[ 0\leq E[Y(1)-Y(0)]\leq 0.40(0.75)+0.60(1-0.30) =0.30+0.42=0.72. \] Thus the data and MTR restrict the average effect to between 0 and 0.72, or between 0 and 72 percentage points on this binary outcome scale. The separate marginal endpoints do not imply a 0.90−0.18 effect: those endpoints cannot be combined as if they were independent choices. The joint derivation above gives the sharp upper bound, 0.72.

Comparison With Worst-Case Bounds

Without MTR, consistency alone gives \(\mu_1\in[r_1,r_1+(1-p)]\) and \(\mu_0\in[r_0,r_0+p]\). Taking the least favorable combinations gives the usual worst-case effect bounds:

$$ r_1-r_0-p \leq E[Y(1)-Y(0)] \leq r_1+(1-p)-r_0. $$

Under MTR, the upper endpoint is unchanged, but the lower endpoint becomes zero. The upper endpoint already corresponds to an MTR-compatible construction: treated units can have \(Y(0)=0\), while untreated units with \(Y(0)=0\) can have \(Y(1)=1\). The new restriction rules out negative unit effects and hence removes negative values from the worst-case interval. In contrast, assuming exchangeability or random assignment can identify the average effect from observed group means, but those assumptions address treatment assignment and are not being made here.

Worked Example: Observed Outcomes Can Favor the Untreated

Consider hypothetical data with \(p=0.50\), \(q_1=0.40\), and \(q_0=0.60\). The treated group’s observed outcome rate is lower, but that fact alone does not contradict MTR: treated and untreated units may differ in their potential outcomes before treatment.

Here \(r_1=0.50(0.40)=0.20\) and \(r_0=0.50(0.60)=0.30\). The MTR marginal bounds are \(\mu_0\in[0.30,0.50]\) and \(\mu_1\in[0.50,0.70]\). The sharp effect bounds are \[ 0\leq E[Y(1)-Y(0)]\leq 0.20+0.50(1-0.60)=0.20+0.20=0.40. \] For comparison, the worst-case lower endpoint without MTR is \(0.20-0.30-0.50=-0.60\), while its upper endpoint is \(0.20+0.50-0.30=0.40\). MTR rules out the negative part of that interval, but it does not make the observed group rates a causal comparison.

Worked Example: An Observed Rate Can Make the Upper Bound Small

Suppose, hypothetically, \(p=0.30\), \(q_1=0\), and \(q_0=0.80\). Then \(r_1=0\) and \(r_0=0.70(0.80)=0.56\). Because no treated unit has observed \(Y(1)=1\), MTR forces \(Y(0)=0\) for all treated units as well. Consequently, \(\mu_0\in[0.56,0.56]\).

For \(Y(1)\), the untreated units with \(Y(0)=1\) must remain at one, while the untreated units with \(Y(0)=0\) may or may not improve. Thus \(\mu_1\in[0.56,0.70]\). The effect bounds are \[ 0\leq E[Y(1)-Y(0)]\leq 0.30(0)+0.70(1-0.80)=0.14. \] The narrow upper limit follows from the small share of untreated units who could improve under treatment. It does not establish that treatment has a positive effect; zero remains compatible with the data.

Diagnostics, Interpretation, and Limitations

MTR is a substantive, unit-level assumption. For an outcome such as survival, it says treatment cannot cause any individual who would otherwise survive to die. For a higher-is-better test result, it says no individual’s result can be lowered by treatment. Whether such a claim is credible depends on the treatment, outcome, time horizon, and population. If the outcome is coded so that larger values are worse, the inequality must be reversed or the outcome recoded before applying the formulas.

The assumption concerns both potential outcomes for the same unit, but only one is observed. Therefore, the observed data generally cannot verify MTR. A treated unit’s observed outcome of zero does not reveal that unit’s untreated outcome; an untreated unit’s observed outcome of one does not reveal the treated outcome. Observed rates with \(q_1<q_0\) do not by themselves refute MTR, as the preceding example illustrates. Diagnostics should instead examine whether the treatment mechanism and outcome definition make individual-level non-harm plausible, and whether the claim is credible in relevant subgroups. A plausible average benefit is not enough to establish that no individual can be harmed.

The bounds are population statements. If \(p\), \(q_1\), and \(q_0\) are estimated from a sample, substituting sample proportions gives estimated endpoints, not exact population bounds. Sampling uncertainty requires separate inference for the endpoints or the identified set. In addition, if treatment or outcome definitions are inconsistent, the link between observed and potential outcomes may fail. If \(p=0\) or \(p=1\), one of the conditional rates \(q_0,q_1\) is unavailable; the formulas should then be expressed using observed joint masses and the unobserved group’s outcomes will generally leave wider bounds.

A common mistake is to read MTR as saying that observed treated outcomes must be at least as good as observed untreated outcomes. That comparison mixes different units and does not follow from \(Y(1)\geq Y(0)\) unit by unit. The correction is to apply the restriction only to each unit’s pair of potential outcomes, use consistency for the outcome actually observed, and leave treatment assignment unrestricted. This distinction is why MTR can tighten bounds without turning an observed association into a causal effect.

Key takeaway: For a binary outcome, MTR removes the possibility of negative individual effects and gives the sharp average-effect interval \([0,\ pq_1+(1-p)(1-q_0)]\). Its validity depends on a strong no-harm claim for every unit, not merely on the observed treated and untreated rates.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions.

  1. In one sentence, state the restriction MTR imposes on binary potential outcomes. Which potential-outcome pair does it rule out?
  2. Suppose \(p=0.25\), \(q_1=0.80\), and \(q_0=0.40\). Find \(r_1\), \(r_0\), and the sharp MTR bounds on the average treatment effect.
  3. Why does \(q_1<q_0\) not, by itself, contradict MTR?
  4. For \(p=0.60\), \(q_1=0.50\), and \(q_0=0.50\), calculate the no-MTR worst-case lower bound and the MTR lower bound. What does the change represent?

Solutions. (1) MTR requires \(Y(1)\geq Y(0)\) for every unit, ruling out \((Y(0),Y(1))=(1,0)\). (2) \(r_1=0.25(0.80)=0.20\), \(r_0=0.75(0.40)=0.30\), and the effect interval is \([0,\ 0.20+0.75(0.60)]=[0,0.65]\). (3) The two observed rates describe different groups; treatment assignment may select units with different potential outcomes, so their ordering does not determine the within-unit ordering. (4) The worst-case lower bound is \(r_1-r_0-p=0.30-0.20-0.60=-0.50\). Under MTR it is zero. The assumption excludes negative individual effects; it does not show that the average effect is strictly positive.

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