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Estimands: ATE, ATT, ATO and Estimand Shifts After Matching · Tutorial 49 of 699

When ATE, ATT, and ATC Coincide

See when ATE, ATT, and ATC must agree, and distinguish constant individual effects from the weaker condition that treated and control groups have equal average effects.

Intermediate 10 min read

What You'll Learn

  • Define ATE, ATT, and ATC using potential outcomes.
  • Derive the population-weighted relationship among the three estimands.
  • Show why a constant individual treatment effect guarantees equality.
  • Calculate the estimands when treatment effects vary across units.
  • Distinguish constant effects from equality of subgroup average effects.
  • Recognize why equality of estimands does not itself establish causal identification.

Why Compare These Three Effects?

The average treatment effect (ATE), average treatment effect on the treated (ATT), and average treatment effect on the controls (ATC) describe effects for different target groups. They need not have the same value: if treatment effects vary across units, the average effect among treated units can differ from the average effect among controls, and both can differ from the overall average. A key special case is a constant individual treatment effect, which guarantees that all three estimands agree.

The earlier material on ATE and ATT under treatment-effect heterogeneity emphasizes that group composition can matter. Here the focus is the exact condition that makes the three averages coincide, why that condition is sufficient but not necessary, and how to check the arithmetic without confusing estimands with estimates from observed data.

Definition: Let \(Y_i(1)\) and \(Y_i(0)\) be unit \(i\)'s potential outcomes under treatment and control, and define the unit's treatment effect as \(\tau_i=Y_i(1)-Y_i(0)\). Let \(D_i=1\) indicate that unit \(i\) is treated and \(D_i=0\) that the unit is a control. For a target population containing both groups, define $$ ATE=E[\tau_i], \qquad ATT=E[\tau_i\mid D_i=1], \qquad ATC=E[\tau_i\mid D_i=0]. $$ The ATE averages effects over the whole target population, the ATT averages effects over its treated members, and the ATC averages effects over its control members.

These are population estimands, not automatically quantities identified by a particular observed-data analysis. The definitions use both potential outcomes for each unit, although only one is observed for that unit. Identification from observed data requires additional design or assumptions; equality among the estimands alone does not supply them.

The Relationship Among ATE, ATT, and ATC

Write \(p=P(D_i=1)\) for the treated proportion in the target population, with \(0<p<1\). Every member of the population is either treated or a control. Partitioning the population average according to these two groups gives the following identity.

$$ \begin{aligned} ATE &=E[\tau_i]\\ &=E[\tau_i\mid D_i=1]P(D_i=1) +E[\tau_i\mid D_i=0]P(D_i=0)\\ &=p\,ATT+(1-p)\,ATC. \end{aligned} $$

This is the population version of a weighted-average identity: the overall mean effect is the treated-group mean effect weighted by the treated proportion, plus the control-group mean effect weighted by the control proportion. The weights are nonnegative and sum to one. Consequently, ATE lies between ATT and ATC, inclusive. It equals both if and only if ATT and ATC are equal, when both groups have positive population proportions.

Key result: If the individual treatment effect is constant in the target population, so that \(\tau_i=\tau\) for every unit, then \(ATE=ATT=ATC=\tau\). More generally, the three estimands coincide exactly when the treated and control groups have the same average treatment effect: \(ATT=ATC\). Constant individual effects guarantee this equality, but are not required for it.

Why Constant Effects Guarantee Equality

If \(\tau_i=\tau\) for every unit, then averaging \(\tau_i\) over any nonempty subset of the target population produces the same value. In particular, the whole population, the treated group, and the control group each have average effect \(\tau\). This establishes the result directly.

The weighted-average identity gives a second justification. Under constant effects, \(ATT=ATC=\tau\), so \(ATE=p\tau+(1-p)\tau=\tau\). Both arguments rely on the same substantive condition: no unit in the target population has a different treatment effect from any other unit. The potential outcomes themselves need not be constant across units; it is their difference that must be constant.

Worked Example: Constant Effects Across Two Groups

Consider a hypothetical target population of four units. The treatment effects shown below are calculated from each unit's two potential outcomes. Units A and B are treated; units C and D are controls.

Unit\(D_i\)\(Y_i(0)\)\(Y_i(1)\)\(\tau_i=Y_i(1)-Y_i(0)\)
A110155
B112175
C08135
D015205

Every unit has an effect of 5 outcome units. Therefore \(ATT=(5+5)/2=5\) outcome units and \(ATC=(5+5)/2=5\) outcome units. The overall average is \(ATE=(5+5+5+5)/4=20/4=5\) outcome units. Since \(p=2/4=0.5\), the identity also gives \(ATE=0.5(5)+0.5(5)=5\) outcome units.

The baseline potential outcomes differ across people, but those differences do not create treatment-effect heterogeneity here: subtracting \(Y_i(0)\) from \(Y_i(1)\) gives 5 for every unit. The equality concerns effects, not equality of outcome levels.

Heterogeneity Can Separate the Estimands

When effects vary, treated and control groups may have different average effects. If, for example, the treated group contains more units who benefit greatly, ATT may exceed ATC. The overall ATE remains the weighted average of the two subgroup means, so its location depends on both their values and the group proportions.

Worked Example: Different Average Effects by Treatment Status

Suppose a hypothetical target population has four units, two treated and two controls. Their individual effects are 8 and 6 outcome units among the treated, and 2 and 4 outcome units among the controls.

The treated-group average is \(ATT=(8+6)/2=14/2=7\) outcome units. The control-group average is \(ATC=(2+4)/2=6/2=3\) outcome units. The overall average is \(ATE=(8+6+2+4)/4=20/4=5\) outcome units.

Checking the weighted identity, \(p=2/4=0.5\), so \(p\,ATT+(1-p)\,ATC=0.5(7)+0.5(3)=3.5+1.5=5\) outcome units. Here the estimands do not coincide: \(ATT=7\), \(ATC=3\), and \(ATE=5\). The treated group has a larger mean effect than the control group, and the ATE lies between them.

Heterogeneity by itself does not force the estimands to differ. The relevant comparison is whether the average effects in the treated and control groups differ. Each group can contain units with different effects while the two group averages still match.

Worked Example: Heterogeneous Effects but Equal Estimands

In another hypothetical population, suppose the effects for the two treated units are 2 and 8 outcome units, while those for the two control units are 4 and 6 outcome units.

The effects vary across individuals, so treatment effects are not constant. Nevertheless, \(ATT=(2+8)/2=10/2=5\) outcome units, and \(ATC=(4+6)/2=10/2=5\) outcome units. With two units in each group, \(ATE=(2+8+4+6)/4=20/4=5\) outcome units. Thus \(ATE=ATT=ATC=5\) outcome units despite individual heterogeneity.

The heterogeneity within each group balances in the group averages. Equality of the three estimands is therefore weaker than constancy of individual effects. It is a statement about averages, not about every unit having the same response.

Checking the Claim and Avoiding Common Errors

When assessing whether these estimands coincide, separate two questions. First, is the individual treatment effect constant? That is a strong unit-level claim: every \(\tau_i\) must be the same. Second, are the treated-group and control-group mean effects equal? That is an average-level claim. The first implies the second, but the second does not imply the first.

In many applications, both potential outcomes are not observed for any one person, so the individual effect cannot be directly computed from the observed record. Constant effects may be a substantive modeling assumption, but equality of ATE, ATT, and ATC is not established merely by seeing similar observed outcome averages in treatment groups. Such a comparison may reflect baseline differences, confounding, or other features of the data rather than equality of causal effects.

A useful algebraic diagnostic is to check the weighted identity whenever all three estimands are reported. If \(p=0.3\), \(ATT=6\), and \(ATC=2\), for example, the implied ATE is \(0.3(6)+0.7(2)=3.2\), not 4. This check can reveal an arithmetic error, inconsistent target populations, or a mismatch in the stated group proportions. It cannot, by itself, verify that the estimands have been identified correctly.

ClaimWhat it meansWhat it does not establish
Constant individual effectsEvery unit has the same \(Y_i(1)-Y_i(0)\).That the effect has been identified from observed data.
Equal ATT and ATCThe treated and control groups have the same mean effect.That effects are constant within either group.
Equal observed outcome meansThe observed outcomes average to the same value across groups.That ATE, ATT, and ATC are equal or even that the causal effect is zero.

A common mistake is to reason, “Treatment effects are heterogeneous, so ATE, ATT, and ATC must differ.” The correction is that heterogeneity alone says effects vary across units; it does not say the treated and control groups have different average effects. Conversely, assuming a constant effect can make the three estimands equal, but it does not remove confounding or guarantee that a statistical procedure estimates their common value. Estimand equality is an algebraic and population-composition statement, whereas causal identification concerns whether the target effect can be learned from the available design and data.

The main alternative to assuming constant effects is to allow heterogeneity and define the target group explicitly. Then report the estimand appropriate to that group rather than treating the ATE, ATT, and ATC as interchangeable. These are different target-population averages in general; choosing among them is a scientific decision, not a way to make estimates agree. Equality may be a justified simplification in a particular application, but it should not be inferred from notation or from an unadjusted comparison.

Key takeaway: Constant treatment effects are sufficient for \(ATE=ATT=ATC\), but not necessary. The exact average-level condition is \(ATT=ATC\); when it holds, the weighted-average identity makes ATE equal to them as well. None of these equalities, on its own, establishes identification from observed outcomes.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions.

  1. A target population is 40% treated, with \(ATT=4\) and \(ATC=1\) outcome units. What is the ATE?
  2. If every unit's treatment effect is \(-2\) outcome units, what are ATE, ATT, and ATC?
  3. Can treatment effects vary across individuals while ATE, ATT, and ATC remain equal? State the condition that permits this.
  4. A researcher observes equal mean outcomes in the treated and control groups. Does that establish equal ATE, ATT, and ATC? Explain.

Solutions. (1) \(ATE=0.4(4)+0.6(1)=1.6+0.6=2.2\) outcome units. (2) Each estimand is \(-2\) outcome units because every group averages the same constant individual effect. (3) Yes. Heterogeneous effects can have equal means in both groups; the required average-level condition is \(ATT=ATC\). (4) No. Equality of observed outcome means is not equality of average causal effects and does not establish their identification.

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