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Comparison With Fixed Randomization · Tutorial 70 of 501

Fixed Allocation As The Benchmark

Learn to specify a fixed-allocation benchmark and identify the trial conditions that must remain comparable when allocation is response-adaptive.

Intermediate 10 min read

What You'll Learn

  • Define fixed allocation and distinguish fixed probabilities from guaranteed arm counts.
  • Calculate expected arm counts and their variability under fixed-probability assignment.
  • Specify sample size, outcomes, estimand, and analysis for a comparison.
  • Identify design differences that prevent a fair comparison.
  • Recognize how outcome-dependent assignment differs from fixed randomization.

Why a Fixed-Allocation Benchmark Is Needed

Response-adaptive randomization changes assignment probabilities as trial responses accumulate. To understand what that change contributes, it helps to compare the adaptive design with a clearly specified design whose allocation rule does not use those responses. The fixed-allocation design is a benchmark: it provides a reference for describing how the trial would be organized under a pre-specified allocation plan.

The benchmark is not automatically an equal-allocation design, nor does naming one settle every question about which trial features are comparable. Allocation is only one part of a trial. A meaningful comparison must also specify such features as the planned sample size, outcome definition and measurement, estimand, and analysis. If these differ, a resulting contrast cannot be attributed solely to the allocation rule.

Definition: A fixed-allocation design uses an allocation plan specified before responses are observed. In a fixed-probability version, each eligible participant is assigned to treatment \(j\) with a pre-specified probability \(\pi_j\), where \(\pi_j\) does not depend on accumulated trial outcomes and \(\sum_{j=1}^{K}\pi_j=1\). A fixed-allocation plan can also guarantee target arm counts, for example through a pre-specified randomized schedule. “Fixed” means the allocation plan is not adapted to observed responses; it does not necessarily mean that every realized arm count is fixed.

For a two-treatment fixed-probability design, an allocation ratio of 1:1 means that each participant has probability \(1/2\) of assignment to either treatment. A ratio of 2:1 could instead mean probabilities \(2/3\) and \(1/3\). Neither ratio requires exact realized counts when assignments are made independently with those probabilities. By contrast, a randomized schedule designed to fill exactly 60 places in one arm and 30 in another guarantees those totals, while keeping the schedule independent of responses.

For comparison, let \(A_i\) denote the treatment assigned to participant \(i\), and let \(\mathcal H_{i-1}\) denote the assignment and response history available before that assignment. A response-adaptive design allows the probability of the next assignment to depend on the observed history, such as \(P(A_i=j\mid\mathcal H_{i-1})\). A fixed-probability design instead uses \(P(A_i=j\mid\mathcal H_{i-1})=\pi_j\) at each assignment. Other fixed schedules can depend on pre-specified design features, such as a participant’s stratum, but not on trial responses.

What Must Be Held Constant

A comparison intended to isolate the role of allocation should describe both designs using the same trial framework. The following features are central.

  • Sample size and stopping plan. Specify the same planned number of participants and the same rules for ending enrollment or follow-up. If one design stops earlier because it uses a different rule, then allocation is not the only design difference.
  • Outcome and measurement. Define the same outcome, time point, measurement procedure, and handling of missing or unavailable measurements. “Response” must refer to the same event or quantity in both designs.
  • Estimand. State the treatment effect the trial is intended to estimate, including the treatment contrast, outcome summary, and relevant population. For example, the target might be the difference in 30-day response probabilities between two treatments in the eligible trial population.
  • Analysis. Use the same planned statistical model or estimator, covariate strategy, and inferential procedure. The analysis must be appropriate for the stated estimand and design. If the analysis differs, a difference in reported results may reflect that choice as well as allocation.

Holding these features constant does not mean the two designs produce identical data. Different allocation rules can produce different arm counts and different participants assigned to each treatment. Those are possible consequences of the allocation rule itself. The point is to prevent unrelated changes—such as switching from a 30-day outcome to a 90-day outcome—from being mistaken for allocation effects.

The comparison also relies on a coherent common trial setting: the same eligibility criteria, treatments, enrollment process, follow-up procedures, and outcome ascertainment should apply. The assumed treatment-outcome relationship should be the same when describing the two designs. Otherwise, the designs are being compared under different scenarios rather than under a common set of trial conditions.

Worked Example: Expected Counts Under Fixed Probabilities

Consider a hypothetical two-treatment trial planning to enroll \(n=90\) participants. The fixed-probability plan assigns each participant to treatment A with probability \(\pi_A=2/3\) and to treatment B with probability \(\pi_B=1/3\), independently of observed responses. What counts should the benchmark expect, and how much can the count in A vary?

Let \(I_i=1\) if participant \(i\) is assigned to A and \(I_i=0\) otherwise. The number assigned to A is \(N_A=\sum_{i=1}^{90} I_i\). Each indicator has \(P(I_i=1)=2/3\), so its expected value is \(2/3\). Therefore:

$$ E(N_A)=\sum_{i=1}^{90}E(I_i)=90\left(\frac{2}{3}\right)=60. $$

The expected count in B is \(90-60=30\), equivalently \(90(1/3)=30\). Under independent fixed-probability assignment, \(N_A\) has a binomial distribution with \(n=90\) and success probability \(2/3\). Its variance and standard deviation are:

$$ \operatorname{Var}(N_A)=90\left(\frac{2}{3}\right)\left(\frac{1}{3}\right)=20, \qquad SD(N_A)=\sqrt{20}=4.472. $$

Thus, 60 and 30 are expected counts, not guaranteed counts. A particular trial could have a different split. If the plan instead required exactly 60 assignments to A and 30 to B, those totals would be guaranteed by the schedule. Both plans are fixed with respect to outcomes, but they have different count properties.

Matching the Outcome, Estimand, and Analysis

An estimand makes the target of the comparison explicit. For example, with a binary outcome \(Y\) measured at a specified time, one possible two-treatment estimand is the difference in response probabilities, \(p_A-p_B\). It is not interchangeable with a difference in mean outcomes or an odds ratio. The endpoint, time point, population, and treatment contrast all matter to its interpretation.

A planned analysis is the procedure for estimating or testing that target. A benchmark comparison should name it rather than merely saying “analyze the results.” The estimator and model need to correspond to the estimand. Identical analyses cannot make different estimands equivalent; conversely, a common estimand does not by itself ensure that two analyses are comparable if the planned procedures differ.

Worked Example: Keeping a Binary Outcome and Its Analysis Aligned

In a hypothetical trial, 100 participants are assigned equally by a fixed-probability plan to treatments A and B. The outcome is whether each participant has a specified clinical response by day 30. Suppose 18 of 50 participants assigned to A respond, and 24 of 50 assigned to B respond. The stated estimand is the difference in 30-day response probabilities, \(p_A-p_B\), and the planned estimator is the difference in sample proportions.

The observed response proportions are \(\hat p_A=18/50=0.36\) and \(\hat p_B=24/50=0.48\). The estimated difference is:

$$ \hat p_A-\hat p_B = \frac{18}{50}-\frac{24}{50} = 0.36-0.48 = -0.12. $$

The estimate is \(-0.12\), or \(-12\) percentage points: in this hypothetical sample, the observed 30-day response proportion is 12 percentage points lower in A than in B. This calculation estimates the stated risk-difference estimand. It does not establish that assignment to A caused a lower response, and it does not by itself quantify uncertainty.

For a comparison with an adaptive design, retain the same 30-day response definition, the same target population and risk-difference estimand, and the same planned estimator and inferential procedure. The adaptive design need not realize 50 participants per arm; its allocation may lead to other counts. But changing the endpoint or replacing the risk difference with a different effect measure would change more than allocation.

A Short Justification for the Fixed-Probability Count

The expected-count calculation above follows directly from indicator variables. For each participant, \(I_i\) is one for assignment to A and zero otherwise. Under independent assignment with the same probability \(\pi_A\), \(E(I_i)=\pi_A\), and the variance of a zero-one variable is \(\pi_A(1-\pi_A)\). Summing the indicators gives the total count. Independence makes the covariances between distinct indicators zero, yielding:

$$ E(N_A)=n\pi_A, \qquad \operatorname{Var}(N_A)=n\pi_A(1-\pi_A). $$

This result assumes a fixed number \(n\) of assignments and independent assignment indicators with a common probability \(\pi_A\). It does not apply unchanged to every fixed schedule. In particular, if a schedule guarantees an exact number of assignments, the count has no assignment variation. The distinction matters when describing the benchmark: an allocation ratio alone does not tell the reader whether arm totals are merely expected or are constrained by design.

Worked Example: Auditing a Three-Treatment Benchmark

Suppose a hypothetical study compares a control treatment with treatments A and B. It plans \(n=200\) participants, with fixed assignment probabilities \(\pi_C=0.50\), \(\pi_A=0.30\), and \(\pi_B=0.20\). The common outcome is change from baseline to week 12 in a continuous measure. The estimand is the mean change in A minus the mean change in control, and the planned analysis is an analysis of covariance using baseline value as a covariate.

The expected assignment counts are:

$$ E(N_C)=200(0.50)=100,\qquad E(N_A)=200(0.30)=60,\qquad E(N_B)=200(0.20)=40. $$

The probabilities sum to one, \(0.50+0.30+0.20=1.00\), and the expected counts sum to the planned sample size, \(100+60+40=200\). These are expected counts under independent fixed-probability assignment; they are not guaranteed totals. A response-adaptive design could be compared with this benchmark while retaining the 200-participant plan, week-12 outcome, A-versus-control mean-change estimand, and planned analysis. If the adaptive rule uses observed outcomes to change later assignment probabilities, the allocation mechanism differs while those specified trial features remain the same.

This specification is also an audit: it reveals what a proposed comparison means. If instead the adaptive trial used a different follow-up time, an A-versus-control risk difference, or a different planned model, it would not be a comparison that changed allocation alone.

Diagnostics, Alternatives, and Limitations

Before interpreting a design comparison, check that the benchmark is operationally clear. Ask whether the allocation probabilities are stated for every treatment, whether the plan is based on probabilities or guaranteed counts, and whether the stopping rule and planned sample size are explicit. Then verify that the endpoint, time point, estimand, and analysis match across designs. If any item is ambiguous, the comparison may not have a unique interpretation.

The main alternative to a fixed allocation plan is response-adaptive allocation: future assignments can depend on observed outcomes. A fixed benchmark is often easier to describe because its allocation probabilities are set in advance. An adaptive rule may be more complicated to specify because the probability for a new participant can depend on the history of the trial. Neither label alone determines which design is preferable. Their aims and consequences depend on the full design and the evaluation criterion.

A fixed allocation need not be equal. Unequal fixed probabilities may be selected in advance for practical or scientific reasons. Likewise, a fixed exact-count schedule and independent fixed-probability assignments are not identical mechanisms, even if they share the same target ratio. The benchmark should name which one is intended rather than treating “fixed randomization” as a single universal procedure.

Finally, holding trial features constant makes a comparison interpretable; it does not guarantee that every assumption is satisfied or that all sources of variation disappear. A change in who enrolls, how outcomes are observed, or how missing outcomes are handled can complicate interpretation even when the written protocol appears similar. A careful comparison states its common trial conditions and reports design differences explicitly.

Common Mistake

Wrong reasoning: “The fixed design has a 2:1 allocation ratio, so with 90 participants it must assign exactly 60 to one treatment and 30 to the other.” This confuses target probabilities with guaranteed counts.

Correction: If each assignment is made independently with probabilities \(2/3\) and \(1/3\), the expected counts are 60 and 30, but realized counts can differ. Exact totals require a schedule that enforces them. State which mechanism defines the benchmark.

Key takeaway: A fixed-allocation benchmark is an outcome-independent reference design, not necessarily an equal-allocation design or an exact-count design. To isolate allocation in a comparison, specify and hold constant the sample-size and stopping plan, outcome, estimand, and analysis.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions below.

  1. A 1:1 fixed-probability design plans to enroll 80 participants. What are the expected counts in the two arms, and are those counts guaranteed?
  2. A study compares an adaptive design with a fixed benchmark but changes the endpoint from response by day 30 to response by day 90. Can a difference be attributed to allocation alone? Why?
  3. For a three-treatment design, the fixed probabilities are 0.4, 0.4, and 0.3. What should be checked before calculating expected arm counts?
  4. Give one difference between independent fixed-probability assignment and a fixed schedule that guarantees exact arm totals.

Solutions. (1) Each arm has expected count \(80(1/2)=40\). Under independent assignment, the realized counts are not guaranteed to be 40 and 40. (2) No. The endpoint and follow-up time differ, so the comparison changes outcome definition as well as allocation. (3) Check that probabilities sum to one: \(0.4+0.4+0.3=1.1\), not 1. The proposed probabilities do not define a valid allocation distribution and must be corrected before computing expected counts. (4) Independent fixed-probability assignment gives expected counts but allows the realized totals to vary; an exact-count schedule constrains the totals to the specified numbers.

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