Why “Rare” Needs a Definition
A variant can be called rare in one data set and not rare in another. The label depends not only on the variant, but also on the frequency measure, the threshold, and the people whose genotypes were counted. In genetic studies, the basic quantity is usually the proportion of observed allele copies at a site that carry a specified allele.
That proportion is not the proportion of people who carry the allele. A person with two copies contributes two allele copies; a heterozygous person contributes one. Keeping the unit of counting clear is essential when defining frequency, identifying a singleton, or applying a threshold.
Counting Allele Copies
For \(N\) diploid individuals with complete genotype calls at a biallelic site, each person contributes two chromosome copies. If \(k\) of the \(2N\) copies carry the alternate allele, its observed frequency is \(k/(2N)\). For example, a heterozygous genotype contributes one alternate copy, while a homozygous-alternate genotype contributes two. The reference-allele frequency is \(1-p_{\mathrm{alt}}\), and the MAF is the smaller of those two frequencies.
The denominator should match the data actually used. If some individuals have no usable genotype at the site, their chromosome copies are not observed and should not be included in the denominator. More generally, if the called individuals have different ploidies, the denominator is the total number of observed chromosome copies, not automatically twice the number of individuals. This tutorial uses diploid examples unless stated otherwise.
Worked Example: Alternate Frequency and MAF
Suppose a hypothetical study has complete diploid genotypes for 500 individuals at a biallelic site. Among them, 493 are homozygous reference, 7 are heterozygous, and none are homozygous alternate. Find the alternate-allele frequency and the MAF.
There are \(2(500)=1{,}000\) observed chromosome copies. Each of the 7 heterozygotes contributes one alternate copy, so \(k=7\). Thus
The reference-allele frequency is \(1-0.007=0.993\), or 99.3%. The alternate allele is the less common allele here, so the MAF is also 0.007, or 0.7%. If instead 997 copies were reference and 3 were alternate, the alternate frequency would be 0.3% and the MAF would likewise be 0.3%. But if the alternate allele were more common than the reference allele, its frequency and the MAF would differ.
At a multiallelic site, there are more than two alleles, so the simple biallelic definition \( \min(p_{\mathrm{alt}},1-p_{\mathrm{alt}}) \) does not apply to an individual alternate allele. The frequency of each allele can be reported separately. If a study uses a summary called “minor-allele frequency” for a multiallelic site, its convention should be stated; the label alone does not specify which frequency is being summarized.
Singletons and Frequency Thresholds
A singleton is an allele observed exactly once in the sample being described. In a diploid sample, that is one alternate chromosome copy, not necessarily one heterozygous individual in every possible data structure. Under complete diploid genotype calls, a single alternate copy occurs in one heterozygote. The term is sample-relative: it describes the observed count in a specified sample, not a claim that the allele occurs only once in a wider population.
Different studies use different cutoffs, and the inequality matters. “Less than 1%” excludes a frequency exactly equal to 1%, whereas “at most 1%” includes it. A useful report identifies the frequency measure, cutoff, inequality, and sample in which frequency was calculated. Without these details, “rare” is underspecified.
Worked Example: A Singleton and a One-Percent Cutoff
In a hypothetical sequencing analysis, 600 diploid individuals have complete calls at a biallelic site. Exactly one of the 1,200 observed chromosome copies carries the alternate allele. Calculate the alternate-allele frequency and decide whether the variant meets a strict MAF threshold of less than 1%.
The count is \(k=1\), so the observed alternate-allele frequency is
The alternate allele is the minor allele, so the MAF is 0.08333%. The allele is a singleton in this sample, and \(0.08333\%<1\%\), so it meets the specified rarity rule. The conclusion is limited to this sample and this rule: it does not establish that the allele is a singleton in every sample or that it falls below 1% in every population.
From a Frequency Cutoff to an Allele-Count Rule
For a complete diploid sample of \(N\) individuals, a frequency threshold can be translated into a maximum allele count. This makes the role of sample size explicit. Let \(k\) be the count of the allele of interest and let \(t\) be a frequency cutoff. For the strict rule \(k/(2N)<t\), multiplying by the positive number \(2N\) gives \(k<2Nt\). Since \(k\) must be an integer, the largest qualifying count is \(\lceil 2Nt\rceil-1\), where \(\lceil x\rceil\) denotes the smallest integer greater than or equal to \(x\).
For an inclusive rule \(k/(2N)\leq t\), the largest qualifying count is instead \(\lfloor 2Nt\rfloor\), where \(\lfloor x\rfloor\) is the greatest integer less than or equal to \(x\). These formulas assume the denominator is \(2N\); with missing calls or variable ploidy, use the actual number of observed chromosome copies in its place.
Worked Example: Applying the Same Cutoff at Two Sample Sizes
Consider two hypothetical complete diploid samples and a strict MAF cutoff of less than 0.5%. In Sample A, \(N=200\); in Sample B, \(N=2{,}000\). Find the largest alternate-allele count that qualifies when the alternate allele is the minor allele.
For Sample A, there are \(2N=400\) chromosome copies. The cutoff count is \(400(0.005)=2\), and the strict rule requires \(k<2\). Therefore, counts 0 or 1 qualify; a count of 2 gives exactly 0.5% and does not qualify.
For Sample B, there are \(2N=4{,}000\) copies. Now \(2Nt=4{,}000(0.005)=20\), so the strict rule requires \(k<20\). Counts up to 19 qualify, whereas a count of 20 is exactly 0.5% and does not qualify. The frequency cutoff is unchanged, but the largest qualifying count is different because the sample sizes differ.
How the Sample and Study Design Affect the Label
A sample frequency describes the sampled chromosome copies. Which individuals are recruited therefore matters. A study restricted to people with a particular disease, a specific ancestry background, or membership in a selected family is not a random miniature of every population. Its allele counts and frequency may differ from those in a broader target population. A case-control study can also have a case fraction chosen by design rather than by disease prevalence; a frequency calculated by pooling cases and controls then describes that pooled study sample, not automatically the population from which the cases arose.
Sample size matters in a separate but related way. At a fixed frequency, a larger sample will generally contain more copies of the allele than a smaller sample. Thus an observed count alone does not describe rarity: one copy among 200 chromosome copies is 0.5%, while one copy among 20,000 is 0.005%. The count must be interpreted with its denominator.
Worked Example: A Case-Control Sample Is Not a Population Sample
Suppose a hypothetical case-control study includes 200 diploid cases and 200 diploid controls. At a biallelic site, there are 3 alternate copies among cases and none among controls. Calculate the frequency in each group and in the pooled study sample, then interpret the result.
Cases contribute \(2(200)=400\) chromosome copies, so their alternate frequency is \(3/400=0.0075\), or 0.75%. Controls have \(0/400=0\%\). The pooled sample has \(3\) alternate copies among \(400+400=800\) copies:
The pooled sample frequency is 0.375%, which is lower than the case-only frequency because the pooled denominator includes the control chromosomes. It is a valid description of this deliberately balanced study sample. It should not be presented as a population frequency without an appropriate sampling rationale: the one-to-one case-control ratio was a design choice, not necessarily the proportion of cases in the source population.
Name the individuals or groups whose genotype calls contribute to the frequency.
State whether the reported value is alternate-allele frequency, MAF, or another defined measure, and count the observed chromosome copies used.
Give the cutoff and whether it is strict or inclusive, then report the resulting classification in that sample.
Common Mistakes and Careful Reporting
- Confusing allele frequency with carrier proportion. Three alternate copies among 800 chromosomes give an allele frequency of \(3/800\), not a carrier proportion of \(3/800\). Carriers are people; allele frequency counts chromosome copies.
- Assuming “alternate” means “minor.” Alternate is a label relative to a reference representation. Compute the two allele frequencies before identifying the minor allele.
- Calling a singleton universally rare. A singleton is observed once in a specified sample. State that sample and avoid extending the count to unsampled populations.
- Reporting a rarity label without its rule. A statement such as “this is rare” omits the measure, threshold, inequality, and sample. Report those details so the classification can be interpreted and reproduced.
- Interpreting a study-sample frequency as a population frequency. Recruitment and case-control sampling can shape the observed sample. Describe what was measured before making a broader claim.
Check Your Understanding
Answer each question using the sample and frequency rule stated.
- In 300 diploid individuals with complete calls, 6 chromosome copies carry the alternate allele. What are the alternate-allele frequency and MAF?
- What does “singleton” mean, and why should the sample be named when using the term?
- For 1,000 complete diploid individuals, what is the largest allele count meeting a strict frequency threshold of less than 0.1%?
- Why can a pooled case-control sample frequency fail to represent the frequency in the source population?
- List the information needed to make a statement that a variant is rare interpretable.