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Variance Components and Family QTLs · Tutorial 287 of 989

Deriving QTL Covariance From Identity By Descent

Learn how additive allele effects turn expected identity-by-descent sharing into the covariance contribution of a quantitative-trait locus.

Advanced 10 min read

What You'll Learn

  • Define identity by descent and the allele-sharing count for a pair of relatives.
  • Derive the covariance contribution of an additive quantitative-trait locus from shared ancestral allele effects.
  • Relate expected IBD sharing to the proportion of alleles shared IBD and locus-specific variance.
  • Calculate QTL covariance for full siblings, parent–child pairs, and half-siblings under explicit pedigree assumptions.
  • Recognize why relationship labels alone do not determine IBD sharing when additional ancestry is present.

Why IBD Sharing Determines Locus-Specific Covariance

Relatives can resemble one another because they share genetic material, but the amount shared at a particular locus varies with their inheritance. For a quantitative-trait locus (QTL), the key link is direct: if two relatives inherit the same ancestral allele copy, that copy contributes the same allele effect to both of their trait values. The expected number of such shared copies therefore determines the covariance contribution from the locus.

This is a locus-specific statement. It does not by itself describe the entire covariance of the relatives' phenotypes, which may also reflect other genetic or environmental sources. Here the aim is to derive the covariance attributable to one additive QTL and to calculate it from IBD sharing under clearly specified pedigree assumptions.

Definition: Two allele copies are identical by descent (IBD) at a locus if they are copies of the same ancestral allele copy, passed down through inheritance. Sharing the same allele value by chance is not enough: that is identity by state, and it does not establish IBD.

An Additive Allele-Effect Model

Consider two relatives, \(i\) and \(j\), at a candidate QTL. Assume each is non-inbred at this locus, so each has two distinct ancestral allele copies. Under the additive model, the QTL value for person \(i\) is the sum of the effects of the two allele copies they carry. Let each distinct ancestral allele copy have a random effect with mean zero and variance \(\tau^2\). Effects of distinct ancestral copies are independent; descendants inherit an allele's effect unchanged. There is no mutation, dominance, or interaction between the two copies in this model.

Define \(K_{ij}\) as the number of allele copies that the two individuals share IBD, so \(K_{ij}\) is 0, 1, or 2 for a non-inbred pair. The quantity \(K_{ij}\) depends on inheritance at the locus; it is not the number of allele copies that happen to have the same measured value. For a given pedigree, it may be fixed or random across possible inheritance patterns.

Definition: Write \(G_i\) for person \(i\)'s additive QTL value, and let \(K_{ij}\) be the number of allele copies shared IBD by the pair. The locus-specific marginal variance for a non-inbred individual is \(v_Q=2\tau^2\). Define the proportion of alleles shared IBD as \(\pi_{ij}=E(K_{ij})/2\). The QTL covariance is \(\operatorname{Cov}_Q(G_i,G_j)=\tau^2 E(K_{ij})=v_Q\pi_{ij}\).

The expectation in this expression is over the inheritance pattern under the pedigree. If the pair's IBD sharing is known, \(E(K_{ij})\) is simply its observed or specified value. If sharing varies across possible transmissions, the expected count averages over those transmissions. A useful equivalent form is \(2\tau^2\pi_{ij}\): each expected shared allele copy contributes \(\tau^2\) to covariance.

Deriving the Covariance Formula

The derivation follows by conditioning on which ancestral allele copies each relative inherited. Label each distinct ancestral allele copy by \(u\), and write its effect as \(A_u\), with \(E(A_u)=0\), \(\operatorname{Var}(A_u)=\tau^2\), and independent effects for distinct copies. Let \(S_i\) and \(S_j\) be the two-copy sets carried by individuals \(i\) and \(j\). Then \(G_i=\sum_{u\in S_i}A_u\) and \(G_j=\sum_{w\in S_j}A_w\). In the product \(G_iG_j\), terms for the same ancestral copy have expectation \(\tau^2\); terms for distinct copies have expectation zero by independence and zero means. There are \(K_{ij}\) shared copies. Thus, conditional on the inheritance pattern, the covariance is \(K_{ij}\tau^2\).

$$ \begin{aligned} \operatorname{Cov}(G_i,G_j\mid S_i,S_j) &=E(G_iG_j\mid S_i,S_j)\\ &=E\left(\sum_{u\in S_i}\sum_{w\in S_j}A_uA_w\right)\\ &=\sum_{u\in S_i\cap S_j}E(A_u^2)\\ &=K_{ij}\tau^2. \end{aligned} $$

Both conditional means are zero, so the conditional expectation of each QTL value does not vary with the inheritance pattern. Averaging the conditional covariance over inheritance therefore gives the unconditional covariance. Equivalently, the law of total covariance has a zero contribution from the covariance of the conditional means:

$$ \begin{aligned} \operatorname{Cov}(G_i,G_j) &=E\{\operatorname{Cov}(G_i,G_j\mid S_i,S_j)\} +\operatorname{Cov}\{E(G_i\mid S_i,S_j),E(G_j\mid S_i,S_j)\}\\ &=E(K_{ij}\tau^2)+0\\ &=\tau^2 E(K_{ij})\\ &=v_Q\pi_{ij}, \qquad v_Q=2\tau^2,\quad \pi_{ij}=\frac{E(K_{ij})}{2}. \end{aligned} $$

For a non-inbred individual, the two allele effects are independent, so \(E(G_i)=0\) and \(\operatorname{Var}(G_i)=2\tau^2\). That establishes the \(v_Q\) used above. The interpretation is specific: a greater expected proportion of alleles shared IBD means a greater covariance contribution from this locus, with all other model assumptions held fixed.

Worked Example: Full Siblings Under Standard Pedigree Assumptions

Suppose two hypothetical full siblings inherit alleles from two parents who are both non-inbred and unrelated to each other, with no additional shared ancestry among the parental allele copies. Assume ordinary Mendelian transmission without mutation and an additive QTL with \(\tau^2=9\) trait-units squared. Find their expected IBD sharing and QTL covariance.

For each parent, the two siblings independently receive one of that parent's two allele copies. They receive the same copy from that parent with probability \(1/2\). Under the stated assumptions, the two parental contributions are independent, and there is no other route to IBD sharing. Therefore \(K_{ij}\) is the sum of two independent Bernoulli variables, each with success probability \(1/2\):

$$ P(K_{ij}=0)=\frac14,\qquad P(K_{ij}=1)=\frac12,\qquad P(K_{ij}=2)=\frac14. $$

The expected count is \(E(K_{ij})=0(1/4)+1(1/2)+2(1/4)=1\), so \(\pi_{ij}=1/2\). The locus-specific variance for either non-inbred sibling is \(v_Q=2\tau^2=18\) trait-units squared. Hence

$$ \operatorname{Cov}_Q(G_i,G_j)=\tau^2E(K_{ij})=9(1)=9\ \text{trait-units squared}, \qquad v_Q\pi_{ij}=18\left(\frac12\right)=9\ \text{trait-units squared}. $$

The two calculations agree. The sharing distribution depends on the pedigree assumptions stated here; being full siblings alone does not rule out additional shared ancestry that could change it.

Worked Example: Parent and Child With No Additional Shared Ancestry

Consider a hypothetical parent–child pair. Assume the parent is non-inbred, the other parent is unrelated to the first parent, and there is no other shared ancestry that could make the child's non-paternal allele copy IBD with either of the first parent's copies. Assume no mutation. Let \(\tau^2=5\) trait-units squared. What is the pair's QTL covariance?

The child inherits one allele copy from the specified parent, and that copy is IBD with one of the parent's two copies. By the no-additional-ancestry assumption, the child's other copy does not add another IBD match. Thus \(K_{ij}=1\) for this pair at the locus, and \(E(K_{ij})=1\). The child's and parent's QTL marginal variances are each \(v_Q=2(5)=10\) trait-units squared.

$$ \pi_{ij}=\frac{1}{2},\qquad \operatorname{Cov}_Q(G_i,G_j)=5(1)=5\ \text{trait-units squared} =10\left(\frac12\right)\ \text{trait-units squared}. $$

The result is not guaranteed just by naming the relationship “parent and child.” If the child's other parent shares ancestry with the specified parent, the child's other allele might also be IBD with a copy carried by that parent. The assumed pedigree structure is what makes \(K_{ij}=1\) here.

Worked Example: Half-Siblings With No Other Shared Ancestry

Suppose two hypothetical half-siblings have one non-inbred parent in common. Assume their other parents are unrelated to each other and to the shared parent, with no additional shared ancestry elsewhere in the pedigree. Assume Mendelian transmission without mutation and \(\tau^2=4\) trait-units squared. Find their expected sharing and QTL covariance.

Each child receives one of the shared parent's two allele copies. The transmissions are independent, so the children receive the same copy with probability \(1/2\) and different copies with probability \(1/2\). The assumptions about the other parents and the rest of the pedigree rule out additional IBD matches. Therefore \(K_{ij}=1\) with probability \(1/2\) and \(K_{ij}=0\) with probability \(1/2\). It follows that \(E(K_{ij})=1(1/2)+0(1/2)=1/2\), and \(\pi_{ij}=1/4\).

$$ v_Q=2(4)=8\ \text{trait-units squared},\qquad \operatorname{Cov}_Q(G_i,G_j)=4\left(\frac12\right)=2\ \text{trait-units squared} =8\left(\frac14\right)\ \text{trait-units squared}. $$

The calculation illustrates how expected sharing—not merely the label “half-siblings”—sets the covariance contribution. If other ancestry creates additional IBD, the distribution of \(K_{ij}\), and therefore the covariance, may differ.

Reading the Sharing Coefficient Carefully

The proportion \(\pi_{ij}\) is the expected fraction of the pair's two allele copies that are shared IBD. It is not the probability that the pair shares at least one copy. For example, in the full-sibling example, \(P(K_{ij}\geq 1)=3/4\), while \(\pi_{ij}=1/2\). These are different summaries: one is a probability of any sharing, and the other is half the expected count.

A related convention uses the kinship coefficient, the probability that one randomly selected allele copy from each relative is IBD. For non-inbred individuals, there are four equally likely cross-person allele-copy pairs, so this coefficient is \(E(K_{ij})/4\). It follows under the present model that the QTL covariance is \(4\tau^2\) times the kinship coefficient, or \(2v_Q\) times that coefficient. This is the same result in a different convention; checking which sharing quantity is being used prevents a factor-of-two error.

In a pedigree analysis, the calculation proceeds from the specified or expected IBD sharing at the candidate locus. The inheritance model and pedigree assumptions determine \(E(K_{ij})\); the additive allele-effect model then converts it to covariance by multiplying by \(\tau^2\). This relationship concerns the QTL component only, not the total phenotypic covariance.

Common Mistakes and Assumptions

  • Using a relationship label as if it fixed sharing. “Full sibling,” “half-sibling,” or “parent–child” does not by itself rule out inbreeding or additional shared ancestry. State the pedigree conditions that justify the IBD distribution being used.
  • Confusing IBD with matching allele values. Two allele copies can have the same measured value without descending from the same ancestral copy. The covariance derivation counts shared ancestral copies, not accidental value matches.
  • Mixing up \(K_{ij}\) and \(\pi_{ij}\). \(K_{ij}\) is a count from 0 to 2 for a non-inbred pair; \(\pi_{ij}=E(K_{ij})/2\) is an expected proportion. The covariance is \(\tau^2E(K_{ij})\), equivalently \(v_Q\pi_{ij}\).
  • Calling the QTL covariance the total trait covariance. The formula isolates the contribution from the specified additive locus. Other sources of covariance are not included in this derivation.
Key takeaway: Under an additive model with independent ancestral allele effects of variance \(\tau^2\), each allele copy shared IBD contributes \(\tau^2\) to the QTL covariance. For a non-inbred pair, \(\operatorname{Cov}_Q(G_i,G_j)=\tau^2E(K_{ij})=v_Q\pi_{ij}\), with \(v_Q=2\tau^2\). The pedigree assumptions are essential because they determine the expected IBD count.

Check Your Understanding

Answer each question using the allele-effect model and state any pedigree assumptions needed.

  1. For a non-inbred individual with two independent allele effects, each with variance \(\tau^2\), what is the QTL marginal variance?
  2. A pair has \(E(K_{ij})=0.8\) and \(\tau^2=3\) trait-units squared. Calculate \(\pi_{ij}\) and the QTL covariance, including units.
  3. Why is the full-sibling sharing distribution \(1/4, 1/2, 1/4\) not justified merely by saying that both siblings are non-inbred?
  4. For a parent–child pair, what additional condition prevents the child's other allele from creating another IBD match with the parent?
  5. Explain why \(P(K_{ij}\geq 1)\) and \(\pi_{ij}\) are not the same quantity.
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