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Pedigrees and Genetic Relatedness · Tutorial 75 of 989

How Inbreeding Changes Diagonal Genetic Covariance

Learn why an individual's additive genetic variance is multiplied by one plus its inbreeding coefficient under the standard allele-effect model.

Beginner 9 min read

What You'll Learn

  • Define the diagonal additive genetic covariance as an individual's additive genetic variance.
  • Relate the inbreeding coefficient to the probability that the individual's two alleles are identical by descent.
  • Derive the factor of one plus the inbreeding coefficient for the diagonal covariance.
  • Calculate an offspring's additive genetic variance from parental kinship and a reference variance.
  • Interpret the result and recognize the assumptions and limits of the model.

Why Inbreeding Changes a Diagonal Entry

An additive genetic covariance matrix records how additive genetic values vary together across individuals. Its diagonal entries have a direct interpretation: each is the variance of one individual's additive genetic value. Inbreeding affects that variance because it increases the chance that the two alleles an individual carries at a locus are identical by descent (IBD). Under a standard additive allele-effect model, that shared ancestry contributes covariance between the two allele effects.

The result is a simple scaling rule: if \(\sigma_A^2\) is the additive genetic variance for a noninbred reference individual, then an individual with inbreeding coefficient \(F_i\) has diagonal additive genetic covariance \((1+F_i)\sigma_A^2\). This is a model-based statement about additive genetic variance, not a claim that every component of phenotypic variance, or every real population's variance, changes by exactly that factor.

Definition: The inbreeding coefficient \(F_i\) of individual \(i\) is the probability that the individual's two homologous alleles at a randomly chosen autosomal locus are identical by descent, relative to the specified founder population. The diagonal additive genetic covariance for individual \(i\) is \(\operatorname{Cov}(g_i,g_i)=\operatorname{Var}(g_i)\), where \(g_i\) is that individual's additive genetic value.

The Allele-Effect Model

Consider one autosomal locus. Write the additive genetic value at that locus for individual \(i\) as \(g_i=a_{i1}+a_{i2}\), where \(a_{i1}\) and \(a_{i2}\) are the effects of the individual's two allele copies. Use a centered random-effect model: each allele effect has mean zero and variance \(v\); effects of alleles that are not IBD are independent; and copies that are IBD have the same effect. This model treats effects as additive, with no dominance or epistatic terms.

If the two copies are not IBD, their covariance is zero under the model. If they are IBD, their effects are the same random effect, so their covariance is \(v\). Since the probability of IBD is \(F_i\), the unconditional covariance between the two effects is \(F_i v\). The variance of their sum is therefore the sum of the two individual variances plus twice their covariance.

$$ \operatorname{Var}(g_i) =\operatorname{Var}(a_{i1})+\operatorname{Var}(a_{i2}) +2\operatorname{Cov}(a_{i1},a_{i2}) =v+v+2F_i v =2v(1+F_i). $$

For a noninbred reference individual, \(F_i=0\), so the variance at this locus is \(2v\). For multiple loci, assume the effects at different loci have no covariance and add their variances. If \(v_\ell\) is the allele-effect variance at locus \(\ell\), the noninbred reference variance is \(\sigma_A^2=\sum_\ell 2v_\ell\). Applying the same inbreeding coefficient across the autosomal loci gives the diagonal relationship below.

Theorem: Under the additive allele-effect model, with no covariance between loci, an individual's diagonal additive genetic covariance is \(\operatorname{Var}(g_i)=(1+F_i)\sigma_A^2\), where \(\sigma_A^2\) is the additive genetic variance for a noninbred reference individual under the same model. The quantity \(\sigma_A^2\) has units of trait units squared; \(F_i\) is dimensionless.

Connection to Kinship and the Relationship Matrix

The same result can be expressed using the kinship coefficient \(\phi_{ij}\), the probability that a randomly selected allele from individual \(i\) and one from individual \(j\) are IBD. For two distinct individuals, the standard additive covariance model gives \(\operatorname{Cov}(g_i,g_j)=2\phi_{ij}\sigma_A^2\). On the diagonal, selecting one allele from individual \(i\) twice requires accounting for the chance that the selections choose the same physical copy.

Two independent selections from the two allele copies of individual \(i\) choose the same physical copy with probability \(1/2\); those selections are necessarily IBD. They choose different copies with probability \(1/2\), and those copies are IBD with probability \(F_i\). Thus \(\phi_{ii}=(1+F_i)/2\). Substituting this diagonal kinship value into the additive covariance formula yields the diagonal scaling rule.

1
Express diagonal kinship.
For two allele selections from the same individual, \(\phi_{ii}=\frac12(1)+\frac12(F_i)=\frac{1+F_i}{2}\).
2
Use the additive covariance relation.
The diagonal covariance is \(2\phi_{ii}\sigma_A^2\).
3
Simplify.
\(2\phi_{ii}\sigma_A^2=2\left(\frac{1+F_i}{2}\right)\sigma_A^2=(1+F_i)\sigma_A^2\), which is also the variance derived from the allele effects.

This establishes why the diagonal entry is not simply \(\sigma_A^2\) when \(F_i>0\). The IBD copies are not two independent draws of allele effect: the same inherited effect appears twice in the additive sum. The additional covariance is \(F_i\sigma_A^2\). When \(F_i=0\), the diagonal returns to the noninbred reference value.

Worked Calculations

Worked Example: Scaling a Reference Variance

Suppose a hypothetical noninbred reference population has additive genetic variance \(320\) trait-units\(^2\). An individual's inbreeding coefficient is \(F_i=1/16\). Find the individual's diagonal additive genetic covariance and interpret it.

The model gives \(\operatorname{Var}(g_i)=(1+F_i)\sigma_A^2\). Substitute the stated values:

$$ \operatorname{Var}(g_i) =\left(1+\frac{1}{16}\right)(320) =\frac{17}{16}(320) =340\ \text{trait-units}^2. $$

The diagonal covariance is \(340\) trait-units\(^2\), which is the modeled additive genetic variance for this individual. It is \(20\) trait-units\(^2\) above the noninbred reference variance. The calculation does not say that the individual's observed phenotype is \(20\) units higher; variance is a measure of spread, not a change in the individual's trait value.

Worked Example: Using Parental Kinship

In a hypothetical pedigree, an offspring's parents are half-siblings with kinship coefficient \(\phi=1/8\). Assume the founders are unrelated and noninbred, and let the noninbred reference additive genetic variance be \(240\) trait-units\(^2\). Find the offspring's diagonal covariance.

An offspring's inbreeding coefficient equals the kinship coefficient between its parents, so \(F_i=1/8\). This uses the pedigree relationship to determine the chance that the offspring receives IBD alleles from its two parents. Apply the diagonal scaling:

$$ \operatorname{Var}(g_i) =(1+F_i)\sigma_A^2 =\left(1+\frac18\right)(240) =\frac98(240) =270\ \text{trait-units}^2. $$

Thus the modeled additive genetic variance is \(270\) trait-units\(^2\). Its standard deviation is \(\sqrt{270}=16.43\) trait units, compared with \(\sqrt{240}=15.49\) trait units for the noninbred reference. The variances, rather than the standard deviations, are multiplied by \(9/8\); the standard deviations are multiplied by \(\sqrt{9/8}\).

Worked Example: Summing Contributions Across Loci

Consider a hypothetical three-locus additive model. The allele-effect variances per copy are \(v_1=4\), \(v_2=9\), and \(v_3=1\) trait-units\(^2\). Assume effects at the three loci have no covariance, and consider an individual with \(F_i=1/4\). Calculate the noninbred reference variance and the individual's variance.

At each locus, the noninbred variance is \(2v_\ell\). Adding the three loci gives the reference variance:

$$ \sigma_A^2=2(4)+2(9)+2(1)=8+18+2=28\ \text{trait-units}^2. $$

The inbreeding multiplier is \(1+F_i=1.25\), so the total diagonal variance is:

$$ \operatorname{Var}(g_i) =1.25(28) =35\ \text{trait-units}^2. $$

This can also be checked locus by locus. The variances are \(2(4)(1.25)=10\), \(2(9)(1.25)=22.5\), and \(2(1)(1.25)=2.5\) trait-units\(^2\); their sum is \(10+22.5+2.5=35\) trait-units\(^2\). The agreement depends on using the same \(F_i\) across the loci and adding independent locus contributions.

Interpretation and Limits

A diagonal additive genetic covariance is an individual's modeled additive genetic variance. It is not a covariance between distinct relatives: those entries describe how two individuals' additive genetic values vary together. It is also not the total phenotypic variance. Environmental variation and other genetic components are outside the quantity calculated here.

The multiplier \(1+F_i\) has a clear reference point. If \(F_i=0\), the individual's two allele copies are not IBD under the specified pedigree model, and the diagonal equals \(\sigma_A^2\). If \(F_i=0.10\), the model predicts a variance \(1.10\sigma_A^2\), or 10% above that reference. Since \(F_i\) is a probability, it lies between 0 and 1; within this model, the corresponding multiplier lies between 1 and 2.

The result relies on the chosen reference population and on the allele-effect assumptions: additive effects, identical effects for IBD copies, independent effects for non-IBD copies, and no covariance across loci. The formula is not a universal adjustment that can be applied without checking the model. For example, if the analysis includes nonadditive genetic effects or uses a different variance parameterization, those components require their own covariance model.

Common Mistake

  • Wrong reasoning: “The inbreeding coefficient is \(F_i\), so the diagonal covariance is \(F_i\sigma_A^2\).” This keeps only the added IBD contribution and drops the noninbred baseline.
  • Correction: The baseline variance is \(\sigma_A^2\), and IBD contributes an additional \(F_i\sigma_A^2\). Therefore the full diagonal is \(\sigma_A^2+F_i\sigma_A^2=(1+F_i)\sigma_A^2\).
  • Another error: Treating the multiplier as a change in the individual's trait value. The multiplier changes modeled variance; it does not specify a directional change in that individual's additive genetic value.
Key takeaway: Under the standard additive allele-effect model, an individual's diagonal additive genetic covariance equals its additive genetic variance, \((1+F_i)\sigma_A^2\). The extra term arises because the two allele effects have covariance \(F_i\) times the noninbred per-copy variance, aggregated over loci.

Check Your Understanding

Use the assumptions stated in this tutorial when answering.

  1. If the reference additive genetic variance is \(500\) trait-units\(^2\) and \(F_i=0.20\), what is the individual's diagonal additive genetic covariance?
  2. Why does the probability that two allele copies are IBD create a covariance between their effects under the allele-effect model?
  3. An offspring's parents have kinship coefficient \(1/16\). Under the stated pedigree convention, what is the offspring's inbreeding coefficient?
  4. Explain why an individual's diagonal additive genetic covariance is a variance, while an off-diagonal entry describes covariance between two individuals.
  5. Which model assumptions would need reconsideration before applying the same scaling rule to a model that includes nonadditive effects?
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