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Variance Components and Family QTLs · Tutorial 290 of 989

Multipoint IBD Probabilities in Family QTL Models

Use recombination-aware marker information to estimate uncertain IBD sharing at a QTL and convert those sharing probabilities into covariances among relatives.

Advanced 12 min read

What You'll Learn

  • Define multipoint IBD probabilities conditional on pedigree, marker data, and a genetic map
  • Convert Haldane map distances into recombination probabilities
  • Describe inheritance states and their transitions across marker intervals
  • Calculate posterior IBD sharing from informative flanking markers
  • Convert expected IBD allele sharing into QTL covariance entries
  • Distinguish a posterior mean sharing coefficient from a most likely IBD state

Why Multipoint IBD Matters

At a quantitative-trait locus (QTL), relatives may share alleles inherited from a common ancestor. That sharing can induce covariance in their trait values. Marker genotypes near the QTL help infer which alleles relatives inherited, but usually do not reveal the QTL inheritance state with certainty. Markers on both sides of a QTL can be more informative than a single marker because recombination probabilities connect inheritance states across the genetic map.

The task here is to calculate the probability distribution of IBD sharing at a QTL given pedigree and marker data, then use its expected sharing to form the QTL covariance matrix. The key is to carry uncertainty forward: a pair that has some chance of sharing zero QTL alleles and some chance of sharing two does not generally have the same covariance as a pair known to share exactly one.

Definition: Two alleles at a locus are identical by descent (IBD) if they are copies of the same ancestral allele. For a pair of relatives, let \(K_{ij}\) be the number of alleles they share IBD at a locus, with \(K_{ij}\in\{0,1,2\}\). Given pedigree information, marker data \(M\), and a genetic map, the multipoint IBD probabilities are \(P(K_{ij}=k\mid M)\), for \(k=0,1,2\). Their expected proportion of alleles shared IBD is \(\pi_{ij}=E(K_{ij}/2\mid M)\).

Inheritance States and Recombination Along a Map

An inheritance state records which parental homolog was transmitted to each relative at a locus. For two siblings in a nuclear family, a convenient state has four binary entries: the homolog inherited by each sibling from the father and the homolog inherited by each sibling from the mother. For either parent, the siblings share that parent's transmitted allele IBD when they inherited the same homolog, and do not share it when they inherited different homologs. Thus \(K_{ij}\) is the sum of the paternal and maternal sharing indicators.

Across an interval, a transmitted homolog can switch when a recombination occurs between the marker positions. Under the Haldane map, crossovers in a meiosis follow a Poisson process along map distance, with no crossover interference. If the interval has length \(d\) Morgans, the probability of an odd number of crossovers—and therefore a switch in inherited homolog—is:

$$ \theta(d)=\frac{1-e^{-2d}}{2}. $$

For distinct meioses, switches are independent under the standard transmission model. Therefore, for a pair of siblings, each of the four transmission bits has its own interval transition probability \(\theta(d)\). This is a model assumption, not a consequence of observed marker data. A different genetic map or crossover model can imply different transition probabilities.

Marker genotypes are evidence about inheritance states, rather than direct observations of them in every case. When parental phase and marker alleles are informative, a marker may identify a transmitted homolog. With uninformative genotypes, unknown phase, or possible genotyping error, the marker likelihood should reflect that uncertainty. In a multipoint calculation, the inheritance states form a hidden Markov model: transitions are determined by the map, and each marker contributes an emission likelihood for the observed genotypes given the state.

Multipoint calculation: Let \(S_j\) be the inheritance state at map position \(j\), and let \(M_j\) be the marker data there. A transition probability \(P(S_j\mid S_{j-1})\) comes from the interval recombination probabilities; an emission probability \(P(M_j\mid S_j)\) describes the marker observations under that state. Combining transitions and emissions across the marker map gives the posterior distribution of the inheritance state at the QTL. The IBD probabilities follow by grouping QTL states according to the number of alleles shared.

Worked Example: Converting Map Distance to Recombination Probability

Worked Example: Converting Map Distance to Recombination Probability

Suppose two adjacent markers are 10 cM apart, and use the Haldane map. Convert the distance to Morgans and find the probability that a particular meiosis switches inherited homologs across the interval.

Since 100 cM equals one Morgan, \(d=10/100=0.10\) Morgans. The Haldane probability is:

$$ \theta(0.10)=\frac{1-e^{-2(0.10)}}{2} =\frac{1-e^{-0.20}}{2} =\frac{1-0.8187}{2} =0.09063. $$

Thus the model assigns a 9.063% probability of a switch for this meiosis across the interval. This is not the probability that a sibling pair shares an allele IBD; that depends on the transmissions of both siblings and, for a multipoint result, on all relevant marker data.

Using Flanking Markers to Infer Sharing at a QTL

A simple bridge calculation illustrates why two flanking markers can be informative. For a specified parent and a pair of siblings, define \(D=0\) if the siblings inherited the same parental homolog and \(D=1\) if they inherited different homologs. Across an interval, \(D\) switches if exactly one of the two sibling transmissions switches. If each transmission switches with probability \(\theta\), independently, then:

$$ \eta=P(\text{\(D\) switches}) =\theta(1-\theta)+(1-\theta)\theta =2\theta(1-\theta). $$

If the marker states at both flanks establish \(D=0\), the state at a QTL between them is still uncertain. It can switch from 0 to 1 in the first interval and return to 0 in the second. The posterior probability at the QTL is obtained by considering the possible paths and conditioning on the observed right-flank state.

Worked Example: Posterior Sharing From Two Flanking Markers

Consider two siblings and a QTL midway between two informative flanking markers. Suppose the markers establish that the siblings inherited the same paternal homolog at both flanks and the same maternal homolog at both flanks. Assume the intervals on each side have recombination fraction \(\theta=0.10\), and assume independent transmissions and no genotyping error. Find the posterior IBD distribution at the QTL.

For either parent, the probability that the sibling-pair state \(D\) switches over one interval is:

$$ \eta=2(0.10)(0.90)=0.18. $$

Given \(D=0\) at the left marker, the probability of \(D=1\) at the QTL and \(D=0\) at the right marker is \(\eta(1-\eta)\). The probability of the observed same-state endpoints is the sum of the two compatible paths, \(D=0\) at the QTL or \(D=1\) at the QTL. Consequently:

$$ P(D_Q=1\mid D_L=0,D_R=0) =\frac{\eta(1-\eta)} {(1-\eta)^2+\eta^2} =\frac{(0.18)(0.82)}{(0.82)^2+(0.18)^2} =\frac{0.1476}{0.7048} =0.2094. $$

The probability of sharing the parental allele at the QTL is therefore \(1-0.2094=0.7906\). Under independent paternal and maternal transmission processes, the number \(K\) of alleles shared IBD has probabilities:

$$ \begin{aligned} P(K=2\mid M)&=(0.7906)^2=0.6250,\\ P(K=1\mid M)&=2(0.7906)(0.2094)=0.3311,\\ P(K=0\mid M)&=(0.2094)^2=0.04386. \end{aligned} $$

The probabilities sum to 1 up to rounding. The expected proportion of alleles shared IBD is:

$$ \pi_{ij} =E(K/2\mid M) =\frac{2(0.6250)+1(0.3311)}{2} =0.7906. $$

The markers make sharing more likely than not, but they do not establish the QTL state with certainty. These calculations use the stated endpoint information as exact; with uncertain marker phase or genotype error, marker likelihoods would instead contribute probabilistic evidence for the endpoint states.

From Expected IBD Sharing to a QTL Covariance Matrix

To translate sharing into covariance, use the additive QTL model. Suppose each allele has an additive effect with mean zero and variance \(\tau^2\), and effects of distinct ancestral alleles are independent. An individual's QTL value is the sum of the effects of their two alleles, so its QTL variance is \(\sigma_Q^2=2\tau^2\). Two relatives have covariance \(\tau^2\) for each allele they share IBD. Averaging over an uncertain IBD state gives the following result.

QTL covariance result: Under the additive allele-effect model, the QTL covariance between relatives \(i\) and \(j\), conditional on marker data, is \(\operatorname{Cov}_Q(i,j\mid M)=\pi_{ij}\sigma_Q^2\), where \(\pi_{ij}=E(K_{ij}/2\mid M)\). For a diagonal entry, an individual shares both of their QTL alleles with themselves, so \(\pi_{ii}=1\) and \(\operatorname{Cov}_Q(i,i)=\sigma_Q^2\).

This result follows directly from the allele-effect model. Conditional on sharing \(K_{ij}\) alleles IBD, exactly \(K_{ij}\) pairs of allele effects are the same random effect. Each contributes variance \(\tau^2\) to the covariance, while non-IBD allele effects have covariance zero. Thus the conditional covariance is \(K_{ij}\tau^2\). Taking its expectation over the marker-informed IBD distribution gives \(E(K_{ij}\mid M)\tau^2=\pi_{ij}\sigma_Q^2\).

Worked Example: Building a Three-Person QTL Covariance Matrix

Suppose a family contains one parent, \(P\), and two offspring, \(A\) and \(B\). Marker analysis gives \(\pi_{AB}=0.7906\) for the sibling pair, as in the preceding calculation. At an autosomal locus, each child inherits one allele IBD from \(P\), so the parent–child sharing proportions are \(\pi_{PA}=\pi_{PB}=0.5\). Let the additive QTL variance be \(\sigma_Q^2=4\) trait-units squared. Construct the QTL covariance matrix in the order \(P,A,B\).

The diagonal entries are \(4\), and each off-diagonal entry is the appropriate sharing proportion multiplied by \(4\):

$$ \operatorname{Cov}_Q =4 \begin{pmatrix} 1 & 0.5 & 0.5\\ 0.5 & 1 & 0.7906\\ 0.5 & 0.7906 & 1 \end{pmatrix} = \begin{pmatrix} 4 & 2 & 2\\ 2 & 4 & 3.162\\ 2 & 3.162 & 4 \end{pmatrix} \quad\text{trait-units squared}. $$

For example, the sibling covariance is \(0.7906(4)=3.162\) trait-units squared. The parent–child covariance is \(0.5(4)=2\) trait-units squared. This is the QTL component only; other modeled sources of familial covariance and individual residual variation would contribute additional covariance terms.

Practical Checks and Common Pitfalls

A multipoint calculation is sensitive to the inheritance model, marker informativeness, phase, and map. The Haldane expression is appropriate only when its crossover assumptions are being used. In applications, marker likelihoods should account for the observed genotypes and any relevant uncertainty; treating an ambiguous marker pattern as a known transmission can make posterior sharing too certain.

A common mistake is to replace uncertain sharing by the most likely IBD category. In the worked sibling example, \(K=2\) is the most probable category, but it has probability only 0.6250. Setting \(K=2\) as if it were certain would produce \(\pi_{AB}=1\), whereas the posterior expected sharing is 0.7906. The covariance uses the expectation over all IBD states, not the category with the largest probability.

Another important distinction is between constructing a covariance matrix from posterior expected sharing and integrating a phenotype likelihood over IBD states. The former is the task here: each entry uses \(\pi_{ij}\). Whether a likelihood should instead average over complete latent inheritance configurations is a separate modeling step. Finally, the entries must describe a coherent pedigree and marker model; independently chosen pairwise sharing values need not form a valid family covariance matrix.

1
Specify inheritance states.
Record which parental homolog each relative inherited at each relevant locus.
2
Apply the map transitions.
Convert interval distances to recombination probabilities under the chosen map and crossover model.
3
Condition on marker data.
Combine transition probabilities with marker likelihoods to obtain the posterior QTL inheritance-state distribution.
4
Form the QTL covariance.
Compute \(\pi_{ij}=E(K_{ij}/2\mid M)\) for each pair, then use \(\pi_{ij}\sigma_Q^2\), with diagonal sharing proportion 1.
Key takeaway: Multipoint markers and recombination probabilities yield a posterior distribution over QTL inheritance states. Under the additive QTL model, the covariance between relatives is determined by their expected proportion of alleles shared IBD—not by an assumed certain sharing category.

Check Your Understanding

Answer each question using the definitions and assumptions stated above.

  1. Under the Haldane map, what does \(\theta(d)\) represent, and what crossover assumption underlies its formula?
  2. For two siblings, explain why the probability that their same-parent sharing state switches is \(2\theta(1-\theta)\), rather than \(\theta\).
  3. If a pair has \(P(K=0\mid M)=0.2\), \(P(K=1\mid M)=0.5\), and \(P(K=2\mid M)=0.3\), calculate \(\pi_{ij}\).
  4. Why does a most probable IBD category not generally determine the QTL covariance?
  5. If \(\pi_{ij}=0.6\) and \(\sigma_Q^2=5\) trait-units squared, what is the pair's QTL covariance, and what are its units?
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