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Parametric Linkage Analysis · Tutorial 220 of 989

Parametric Linkage Models and the Recombination Fraction

Learn how recombination and penetrance jointly describe the relationship between a disease locus, a genetic marker, and observed family phenotypes.

Intermediate 9 min read

What You'll Learn

  • Define the disease locus, marker locus, recombination fraction, and phenotype penetrance in a two-point model.
  • Interpret recombination fractions from zero to one-half and explain the no-linkage value.
  • Distinguish a model for disease transmission from the model connecting genotype to phenotype.
  • Calculate phenotype probabilities from a specified genotype-specific penetrance model.
  • Identify the assumptions needed to interpret a parametric linkage model.

Why Model Linkage and Phenotype Together?

A family can show a pattern of affected and unaffected relatives because a disease-associated allele is inherited through generations. A genetic marker provides another inherited signal: if it lies near the disease locus, the marker allele carried by a relative can tend to travel with the disease-associated allele. Linkage analysis describes this relationship, while a phenotype model describes how often each disease-locus genotype produces the observed disease status.

These are related but distinct parts of a statistical model. The recombination fraction describes the relationship between the disease locus and marker during inheritance. Penetrance describes the relationship between disease-locus genotype and phenotype. A marker can be linked to a disease locus even if penetrance is incomplete, and a phenotype can be modeled without any marker information.

Definition: A two-point linkage model considers inheritance at two loci: a disease locus and a marker locus. Its linkage parameter is the recombination fraction \(\theta\), the probability that the alleles transmitted from a parent at the two loci are recombinant, relative to the parental arrangement of those alleles. Its phenotype component specifies the probability of an observed phenotype conditional on disease-locus genotype.

The Recombination Fraction

To define a recombinant transmission, it is necessary to know which disease-locus and marker alleles are on each of a parent's two homologous chromosomes. This arrangement is called the parental phase. A transmitted pair is recombinant when it combines alleles from different parental homologs, rather than preserving one of the parental allele pairings. Thus, whether a transmission is called recombinant depends on the parental arrangement, not just on the allele names.

In the standard two-point model, \(\theta\) is restricted to the interval from 0 to 0.5. At \(\theta=0\), transmissions preserve the parental allele pairings in the model; as \(\theta\) increases, recombinant transmissions become more frequent. At \(\theta=0.5\), the disease-locus and marker transmissions show no two-point linkage. This is the conventional null value for a test of linkage:

$$ H_0:\theta=0.5 $$

The usual linkage alternative is \(\theta<0.5\). A value above 0.5 does not represent stronger linkage in this parameterization; interchanging the phase labels leads to the corresponding value below 0.5. The value 0.5 is also not proof that the loci are physically far apart. Multiple crossovers between loci can make the observed two-point recombination fraction approach 0.5 even when the loci are on the same chromosome. The parameter describes the inheritance relationship captured by the model, not a direct measurement of physical distance.

Worked Example: Interpreting a Specified Recombination Fraction

Suppose a hypothetical two-point model specifies \(\theta=0.08\). Interpret this value for transmissions classified relative to the parent's phase.

By definition, the probability of a recombinant transmission is \(\theta\), so it is \(0.08\), or 8%. The probability of a nonrecombinant transmission is the complement:

$$ 1-\theta=1-0.08=0.92 $$

Thus, under this model, recombinant and nonrecombinant transmissions have probabilities 0.08 and 0.92, respectively. The value is below 0.5, so it represents a model with linkage rather than the no-linkage null. It does not say that 8% of relatives must be affected: \(\theta\) concerns inheritance at the two loci, not phenotype.

A useful justification for the null value is to consider the meaning of no linkage in the two-point model. When inheritance at the loci is independent, a marker allele carries no information about which disease-locus homolog was transmitted. Relative to a fixed parental phase, recombinant and nonrecombinant classifications are then equally likely. Their probabilities sum to one, so each is one-half and \(\theta=0.5\). This is why the no-linkage hypothesis is represented by that boundary value rather than by \(\theta=0\).

Phenotype Penetrance

Linkage concerns which alleles are transmitted; it does not by itself determine whether a person is affected. That connection is represented by penetrance. Let \(G_i\) denote individual \(i\)'s disease-locus genotype and let \(Y_i\) denote their recorded phenotype. For a binary phenotype, \(Y_i=1\) can denote affected and \(Y_i=0\) unaffected. The penetrance for genotype \(g\) is the conditional probability that an individual with that genotype is affected.

Definition: For a binary disease phenotype, the genotype-specific penetrance is \(f(g)=P(Y_i=1\mid G_i=g)\). The corresponding probability of an unaffected phenotype is \(P(Y_i=0\mid G_i=g)=1-f(g)\). A penetrance model specifies these probabilities for the disease-locus genotypes under consideration.

Penetrance is a probability, not a deterministic rule. A penetrance of 0.80 for genotype \(g\) means that affected status occurs with probability 0.80 among individuals with that genotype under the model; it does not mean that exactly 80% of every small group with genotype \(g\) will be affected. Different genotypes may have different penetrances. Incomplete penetrance allows an individual with a disease-associated genotype to be unaffected, while a nonzero penetrance for other genotypes allows affected individuals who do not carry that genotype.

A parametric linkage model therefore requires a phenotype specification as well as \(\theta\). A simple model might use genotype-specific penetrances, while a more detailed model could account for features such as age. The penetrance assumptions must suit the disease and the recorded phenotype. Otherwise, a mismatch between predicted and observed disease status could be incorrectly attributed to the transmission relationship between the marker and disease locus.

Worked Example: Applying Genotype-Specific Penetrance

Consider a hypothetical dominant disease model with penetrance 0.80 for genotypes \(DD\) and \(Dd\), and penetrance 0.01 for genotype \(dd\). Calculate the probabilities of affected and unaffected status for an individual with genotype \(Dd\).

For \(Dd\), the specified penetrance is \(f(Dd)=0.80\). Therefore:

$$ P(Y_i=1\mid G_i=Dd)=0.80 $$

The probability of unaffected status is the complement:

$$ P(Y_i=0\mid G_i=Dd)=1-0.80=0.20 $$

Under this hypothetical model, a \(Dd\) individual has an 80% probability of being affected and a 20% probability of being unaffected. The genotype raises the modeled probability of disease, but it does not determine the phenotype with certainty. The 0.01 penetrance for \(dd\) also means the model allows affected individuals without either copy of \(D\).

Putting the Model Components in Context

A pedigree linkage model brings together several kinds of information. Disease-locus genotypes connect inheritance to phenotype through penetrance. Marker genotypes provide evidence about inheritance at the marker locus. The parameter \(\theta\) describes how often the transmitted disease-locus and marker-locus alleles are recombinant, relative to phase. These components answer different questions, so their parameters should not be interchanged.

1
Specify the loci and phase.
Identify the disease locus and marker locus and define the parental allele arrangement used to classify transmissions as recombinant or nonrecombinant.
2
Specify the linkage parameter.
Use \(\theta\) for the recombination fraction, with \(0\leq\theta\leq0.5\); no linkage is represented by \(\theta=0.5\).
3
Specify the phenotype model.
Give the probability of affected status for each disease-locus genotype, and use its complement for unaffected status.
4
Relate the assumptions to the observations.
Interpret marker and phenotype data in light of both the inheritance parameter and the penetrance specification; neither component alone describes the full model.

In a basic model, the penetrance probabilities are understood to apply to the population and phenotype definition being analyzed. The analysis also needs a defensible treatment of phase; if phase is uncertain, it must be represented as uncertain rather than silently treated as known. A model using one \(\theta\) assumes that a common recombination fraction is appropriate for the transmissions being analyzed. If sex-specific recombination is relevant, that simplification may need revision. Accurate interpretation also depends on appropriate handling of uncertain genotypes and missing observations.

Worked Example: Separating Phenotype Probability From Linkage

Suppose a hypothetical family has three individuals whose disease-locus genotypes are treated as known: \(Dd\), \(Dd\), and \(dd\). Under the penetrance model in the previous example, their recorded phenotypes are affected, unaffected, and unaffected, respectively. Assume phenotype statuses are independent conditional on the specified genotypes. Calculate the probability of this phenotype pattern under the penetrance model.

The conditional probabilities for the three observations are \(0.80\) for an affected \(Dd\) individual, \(0.20\) for an unaffected \(Dd\) individual, and \(0.99\) for an unaffected \(dd\) individual. Under the stated conditional-independence assumption, multiply these probabilities:

$$ P(\text{pattern}\mid \text{genotypes}) =0.80\times(1-0.80)\times(1-0.01) =0.80\times0.20\times0.99 =0.1584 $$

The probability of this particular phenotype pattern conditional on these genotypes is 0.1584, or 15.84%. This calculation concerns the phenotype component only. It does not use marker genotypes and does not estimate or test \(\theta\). A linkage analysis must also account for how the disease-locus and marker-locus alleles are transmitted.

Assumptions and Interpretation

A parametric model is useful because it makes its biological assumptions explicit. Before interpreting linkage evidence, check that the disease model defines the relevant genotypes and penetrances, that the marker information and phase are handled appropriately, and that the chosen recombination parameterization fits the transmissions under study. If any of these specifications are wrong, the model's predictions can be unreliable even when the arithmetic is correct.

The no-linkage hypothesis concerns the relationship between the two loci, not whether the disease is genetic, whether a major-gene model is correct, or whether penetrance is complete. Conversely, observing that a marker allele and disease status tend to co-occur in a small family does not by itself establish linkage. The pattern must be evaluated against the inheritance and phenotype assumptions of the model.

Key takeaway: In a two-point parametric linkage model, \(\theta\) describes recombination between a disease locus and a marker, while penetrance describes phenotype probability conditional on disease-locus genotype. The no-linkage null is \(H_0:\theta=0.5\); neither \(\theta\) nor penetrance alone describes the whole family model.

Common Mistakes

  • Confusing \(\theta\) with disease risk. A recombination fraction of 0.08 is not an 8% probability of disease. It is the modeled probability of a recombinant transmission between the two loci.
  • Treating penetrance as certainty. A penetrance of 0.80 does not require every person with that genotype to be affected. It assigns an 80% conditional probability under the model.
  • Using \(\theta=0\) as the no-linkage null. Zero represents no recombinant transmissions under the model. No two-point linkage is represented by \(\theta=0.5\).
  • Interpreting \(\theta=0.5\) as proof that loci are on different chromosomes. It indicates no detectable two-point linkage under this parameterization; multiple crossovers can also produce a recombination fraction near one-half.
  • Equating marker association with causation. A marker can track inheritance near a disease locus without causing the disease. The phenotype model concerns the disease genotype, not a causal effect of the marker.

Check Your Understanding

Answer each question using the model definitions and assumptions presented here.

  1. What does \(\theta=0.12\) mean, and what is the corresponding probability of a nonrecombinant transmission?
  2. Why is \(H_0:\theta=0.5\) the conventional no-linkage hypothesis in a two-point model?
  3. If \(f(g)=0.65\), what are the modeled probabilities of affected and unaffected status for genotype \(g\)?
  4. Explain why a penetrance value is not a deterministic rule for an individual's phenotype.
  5. Does \(\theta=0.5\) prove that the disease locus and marker are on different chromosomes? Explain.
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