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Relatedness and Kinship Estimation · Tutorial 161 of 989

Pedigree Kinship Coefficients As Benchmarks

Use pedigree relationships to calculate expected kinship coefficients, distinguish them from twice-as-large relatedness values, and identify the assumptions behind familiar benchmarks.

Intermediate 10 min read

What You'll Learn

  • Define a pedigree kinship coefficient as an identity-by-descent probability for alleles sampled from two individuals.
  • Distinguish kinship coefficients from the relatedness scale, which is twice as large.
  • State the assumptions behind the conventional unrelated, parent–offspring, and full-sibling benchmarks.
  • Calculate benchmarks for half siblings, grandparent–grandchild pairs, avuncular pairs, and cousins.
  • Recognize how parental inbreeding or relatedness changes familiar pedigree expectations.
  • Separate expected pedigree values from estimates based on observed genetic data.

Why Pedigree Benchmarks Matter

A pair of relatives can share alleles because they inherited copies from a common ancestor. Pedigree kinship coefficients provide reference expectations for that sharing under a specified family tree. These values are useful benchmarks, but they are not direct measurements of the alleles observed in a particular pair, and they depend on the pedigree assumptions.

A frequent source of confusion is that two relatedness scales are used in practice. The kinship coefficient is the probability that one allele sampled from each of two people is identical by descent. A commonly used relatedness scale is twice that coefficient. Thus, parent–offspring kinship is conventionally \(1/4\), whereas their relatedness on the doubled scale is \(1/2\). Keeping the scale explicit prevents an apparently simple benchmark from being reported incorrectly.

Definition: For two individuals \(i\) and \(j\), the pedigree kinship coefficient \(\phi_{ij}\) is the probability that a randomly chosen allele copy from \(i\) and a randomly chosen allele copy from \(j\), at the same autosomal locus, are identical by descent (IBD). IBD means the copies descend from the same ancestral allele copy. Define the relatedness scale here as \(r_{ij}=2\phi_{ij}\). These are pedigree expectations under the stated pedigree model, not necessarily the sharing observed at every locus.

The probability concerns a pair of sampled allele copies, one from each person. It is not the probability that the two people have identical genotypes, nor does it mean that a fixed proportion of their entire genomes must match exactly. In the conventional outbred pedigree examples below, \(r_{ij}\) is interpreted as the expected fraction of alleles in one individual that are IBD with alleles in the other.

Assumptions Behind the Familiar Values

Unless a case says otherwise, use the following conventional assumptions: the pedigree is autosomal; the relevant founders are unrelated to one another and non-inbred; there are no unrecorded ancestral connections; and inheritance is Mendelian. A non-inbred individual has two homologous allele copies that are not themselves IBD by pedigree. For an individual \(i\), write \(F_i\) for the probability that the individual's two homologous copies are IBD, the inbreeding coefficient. For distinct unrelated founders, \(\phi_{ij}=0\); each founder can be non-inbred while also having zero kinship with another founder.

The standard benchmark table follows under these assumptions. “First cousins” means cousins whose parents are siblings, with no additional pedigree connections.

RelationshipKinship coefficient \(\phi\)Doubled relatedness \(r=2\phi\)
Unrelated pair00
Parent–offspring1/41/2
Full siblings1/41/2
Half siblings1/81/4
Grandparent–grandchild1/81/4
Avuncular pair (aunt/uncle and niece/nephew)1/81/4
First cousins1/161/8

For two individuals who are themselves the same person, the kinship coefficient is \(\phi_{ii}=(1+F_i)/2\), not the unrelated-pair value. This diagonal case is distinct from the pairwise benchmarks in the table.

Deriving Parent–Offspring Kinship

The parent–offspring benchmark illustrates both the definition and the role of assumptions. Let \(P\) be a parent and \(C\) the child. Sample one allele copy from \(P\) and one from \(C\). Assume the child’s other parent is unrelated to \(P\), so an allele inherited from that other parent contributes no IBD probability with the sampled allele from \(P\).

The child’s sampled allele comes from \(P\) with probability \(1/2\). Conditional on that event, it is a uniformly transmitted copy from \(P\). The sampled allele from \(P\) is the same homologous copy with probability \(1/2\), giving IBD with certainty. It is the other homolog with probability \(1/2\), and those two homologs are IBD with probability \(F_P\). Therefore:

$$ \phi_{PC} = \frac{1}{2}\left[\frac{1}{2}(1)+\frac{1}{2}F_P\right] +\frac{1}{2}(0) = \frac{1+F_P}{4}. $$

If \(P\) is non-inbred, \(F_P=0\), so \(\phi_{PC}=1/4\) and \(r_{PC}=1/2\). If the parent is inbred, the conventional \(1/4\) value does not apply: the probability rises with \(F_P\). If the child’s other parent is related to \(P\), there can also be IBD when the child’s allele came from that other parent, so the unrelated-other-parent assumption matters as well.

Worked Example: Parent–Offspring With a Non-Inbred Parent

Suppose a hypothetical pedigree has a non-inbred parent \(P\) and child \(C\). Assume the child’s other parent is unrelated to \(P\), and there are no other ancestral connections between the relevant lineages. Find both scales.

Here \(F_P=0\). Substituting into the derived expression gives:

$$ \phi_{PC}=\frac{1+F_P}{4} =\frac{1+0}{4} =0.25. $$

The doubled relatedness is \(r_{PC}=2\phi_{PC}=2(0.25)=0.50\). Thus the expected kinship coefficient is 0.25 and the relatedness value on the doubled scale is 0.50. These are expectations under this pedigree, not claims that every genomic region has exactly that sharing.

Sibling and More Distant-Relative Benchmarks

For full siblings, each child inherits one allele copy from each parent. To see the kinship benchmark, sample one allele from each sibling. There is probability \(1/4\) that both sampled alleles are maternal; conditional on this, the two transmissions are IBD with probability \(1/2\) when the mother is non-inbred. The paternal–paternal case contributes another \(1/4 \times 1/2\). Under unrelated, non-inbred parents, the two cross-parent cases contribute zero. The total is \(1/8+1/8=1/4\), so \(r=1/2\).

This calculation also shows why “full siblings share one-half” needs a scale attached: it is their conventional doubled relatedness, while their kinship coefficient is \(1/4\). Half siblings share only one parent. With unrelated, non-inbred founders, the probability that both sampled alleles came from that shared parent is \(1/4\), and the two transmitted copies are IBD with probability \(1/2\). The result is \(\phi=1/8\), or \(r=1/4\).

For more distant relationships, a useful rule for a simple pedigree with unrelated, non-inbred founders is to add the contribution from each common ancestor. If the paths from the two individuals to a particular common ancestor contain \(n_1\) and \(n_2\) parent–offspring links, that ancestor contributes \(2^{-(n_1+n_2+1)}\) to kinship. This rule applies when the pedigree paths are distinct and there are no additional shared ancestors or loops; otherwise, contributions and pedigree structure must be handled with care.

Pedigree rule: In a simple outbred pedigree, a common ancestor reached by paths of lengths \(n_1\) and \(n_2\) contributes \(2^{-(n_1+n_2+1)}\) to \(\phi\). Add contributions over the common ancestors, then obtain the doubled relatedness as \(r=2\phi\).

A grandparent and grandchild have one common ancestor with path lengths 0 and 2 if the grandparent is counted as the common ancestor, giving \(2^{-3}=1/8\). An aunt or uncle and a niece or nephew have two common grandparents; each contributes \(1/16\), for a total kinship of \(1/8\). First cousins have two common grandparents, each reached by paths of length 2 from both cousins. Each contributes \(2^{-5}=1/32\), so their total is \(1/16\).

Worked Example: First Cousins

Consider a hypothetical pair of first cousins whose parents are full siblings. Assume the four grandparents are unrelated, non-inbred founders and that there are no other connections in the pedigree. The cousins have two common grandparents.

For each common grandparent, the path length to each cousin is 2. The contribution from one grandparent is:

$$ 2^{-(2+2+1)}=2^{-5}=\frac{1}{32}=0.03125. $$

Adding the two independent common-ancestor contributions gives:

$$ \phi_{\text{cousins}}=\frac{1}{32}+\frac{1}{32} =\frac{1}{16}=0.0625, \qquad r_{\text{cousins}}=2\left(\frac{1}{16}\right) =\frac{1}{8}=0.125. $$

The pair’s expected kinship is 0.0625; on the doubled scale, the expected relatedness is 0.125. Counting only one grandparent would incorrectly halve both answers.

Worked Example: Half Siblings With an Inbred Shared Parent

Suppose a hypothetical pair of half siblings share a parent \(S\) with \(F_S=0.20\). Assume their other parents are unrelated to \(S\), to each other, and to the relevant pedigree founders, with no additional ancestral connections.

Both sampled alleles must come from \(S\), an event with probability \(1/4\). Conditional on that event, the two transmitted copies are IBD if they are the same homolog (probability \(1/2\)), or if they are different homologs that are IBD (probability \(F_S\), also weighted by \(1/2\)). Thus:

$$ \phi =\frac{1}{4}\left[\frac{1}{2}(1)+\frac{1}{2}(0.20)\right] =\frac{1}{4}(0.60) =0.15. $$

Therefore \(r=2(0.15)=0.30\). The usual half-sibling benchmark, \(\phi=1/8=0.125\) and \(r=1/4=0.25\), assumes the shared parent is non-inbred. The larger values here arise from the specified inbreeding of \(S\), not from a different definition of kinship.

When Benchmarks Change and Why They Matter

Pedigree values are reference expectations, not universal constants that apply regardless of family structure. The parent–offspring derivation shows explicitly that a parent’s inbreeding can change the coefficient. Likewise, if the parents of full siblings are related or inbred, their kinship need not equal the simple \(1/4\) benchmark. Additional shared ancestors can raise the coefficient for any pair. A pedigree should therefore be checked for inbreeding and extra connections before a conventional value is used as an expectation.

These benchmarks help describe the scale of a relationship and provide a conceptual reference when considering relatedness estimates. They do not determine a particular pair’s observed sharing at each locus: inheritance is random, and realized sharing can differ from its pedigree expectation. Later analyses may estimate relatedness from genotype data, but the pedigree coefficients themselves are defined by inheritance probabilities, not by a calculation from observed genotype codes.

Common mistake: “Parent–offspring kinship is \(1/2\), because a child inherits half of its genome from each parent.” This uses the doubled relatedness scale while labeling it kinship. The correction is to state the scale: under the standard non-inbred, unrelated-parent assumptions, \(\phi=1/4\) and \(r=2\phi=1/2\). A second related pitfall is to apply \(1/4\) to every parent–offspring pair without checking parental inbreeding or the relationship between the parents.

Key takeaway: State the scale and the pedigree assumptions together. Under the standard unrelated-founder, non-inbred assumptions, parent–offspring and full-sibling pairs have \(\phi=1/4\), half siblings and grandparent–grandchild pairs have \(\phi=1/8\), and first cousins have \(\phi=1/16\). The corresponding doubled relatedness values are \(2\phi\).

Check Your Understanding

Use the definitions and assumptions in this tutorial to answer the following.

  1. Under the standard assumptions, what are the kinship coefficient and doubled relatedness for a pair of full siblings?
  2. A parent has \(F_P=0.40\), and the child’s other parent is unrelated to that parent. Calculate their kinship coefficient and doubled relatedness.
  3. Why does a first-cousin calculation include two common-ancestor contributions rather than one?
  4. Under the conventional assumptions, compare the kinship coefficient of half siblings with that of grandparent and grandchild.
  5. Explain why a pedigree benchmark is an expected value rather than a guarantee about sharing at every genomic locus.
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