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Gene–Gene Interaction · Tutorial 814 of 989

Statistical Epistasis Versus Biological Interaction

Learn to state what scale and model a claim of statistical epistasis refers to, and why that claim does not by itself establish a biological mechanism.

Advanced 11 min read

What You'll Learn

  • Define statistical epistasis relative to a specified additive model and phenotype scale
  • Calculate a two-locus difference-in-differences on the risk scale
  • Compare additive-risk and multiplicative-odds conclusions for the same genotype table
  • Explain how transforming a phenotype can change whether an additive model fits
  • Distinguish a statistical departure from a mechanistic claim about genes
  • Identify what must be specified before interpreting an epistasis result

Why “Interaction” Needs a Model

When two loci are associated with a phenotype, researchers may ask whether their joint pattern departs from what an additive model predicts. That question is statistical: its answer depends on how the phenotype is represented and what “additive” means in the chosen model. It is not, by itself, a claim that the two gene products physically interact or jointly cause the phenotype.

The distinction matters because the same two-locus pattern can show no departure from additivity on one scale and a departure on another. A precise report therefore names the phenotype, scale, genotype comparison, and model. Without those details, “epistasis” can sound more definitive than the analysis warrants.

Definition: Statistical epistasis is a departure from a specified model in which the effects associated with two loci combine additively on a specified scale. The term describes a statistical pattern relative to that model; it does not, on its own, identify a molecular mechanism. Biological interaction refers to a mechanistic or functional dependence between biological components, such as gene products or pathways. It requires biological interpretation and is not defined by a single statistical scale.

Two-Locus Additivity as a Statistical Statement

To make the idea concrete, consider two loci, each represented here by two states: 0 and 1. Let \(m_{ab}\) denote the expected phenotype for individuals in state \(a\) at the first locus and state \(b\) at the second, with \(a,b\in\{0,1\}\). The expectations might be cell risks, mean trait values, or another outcome summary. The meaning of \(m_{ab}\) depends on the chosen phenotype scale.

On a scale where additivity means that the change associated with the first locus is the same in both states of the second, the two-locus model has the form \(m_{ab}=\mu+\alpha a+\beta b\). The model predicts that the joint state combines the two single-locus changes without an additional cross-term. For these two binary states, its implication can be checked with one difference-in-differences contrast.

$$ \Delta = (m_{11}-m_{01})-(m_{10}-m_{00}) = m_{11}-m_{10}-m_{01}+m_{00}. $$

The first expression compares the change from locus 0 to locus 1 when the second locus is in state 1 with that change when it is in state 0. Under the additive model, both changes equal \(\alpha\), so \(\Delta=0\). A nonzero value is a departure from this particular additive model on this particular scale. It does not establish that the departure is statistically distinguishable from sampling variation; that requires uncertainty estimates and an appropriate inferential procedure.

Interpretation: A zero two-locus contrast means that the four specified cell expectations satisfy the additive restriction on the stated scale. It does not mean the loci have no effects, that they are biologically independent, or that every possible model of their joint effects is additive.

Worked Examples: The Scale Changes the Answer

Worked Example: Additivity of Risk in a Hypothetical Two-Locus Table

Suppose a hypothetical cohort has 1,000 individuals in each of four two-locus genotype-state groups. The numbers with a binary outcome are 100, 200, 300, and 400 for states \(00,10,01,11\), respectively. Assume each person contributes one outcome, and treat the cell risks as the quantities of interest. The estimated risks are the outcome counts divided by the group sizes.

The four risks are \(m_{00}=100/1000=0.10\), \(m_{10}=200/1000=0.20\), \(m_{01}=300/1000=0.30\), and \(m_{11}=400/1000=0.40\). The risk-scale interaction contrast is

$$ \widehat{\Delta}_{\mathrm{risk}} =0.40-0.20-0.30+0.10=0. $$

Equivalently, the first-locus risk difference is \(0.20-0.10=0.10\) when the second locus is in state 0, and \(0.40-0.30=0.10\) when it is in state 1. Thus these hypothetical cell risks fit additivity on the risk scale: the joint risk is 0.40, or 40%, and the additive prediction is \(0.10+0.10+0.20=0.40\), including the baseline risk once.

This arithmetic describes the table, not a causal effect of changing a person's genotype. It also does not provide a test of the population interaction: the cell risks are estimated from finite groups, and uncertainty would need to be incorporated before making an inferential claim.

Worked Example: No Odds-Scale Interaction but a Risk-Scale Departure

In a second hypothetical table, suppose the risks for states \(00,10,01,11\) are \(0.10\), \(2/11\), \(0.25\), and \(0.40\). Consider first a logistic model with no interaction term: the odds for state 10 are twice the odds for state 00, those for state 01 are three times the odds for state 00, and those for state 11 are six times the odds for state 00. The table has exactly that pattern. The baseline odds are \(0.10/(1-0.10)=1/9\); multiplying by 2 gives odds \(2/9\), corresponding to risk \((2/9)/(1+2/9)=2/11\). Multiplying by 3 gives odds \(1/3\), corresponding to risk \(1/4\); multiplying by 6 gives odds \(2/3\), corresponding to risk \(2/5=0.40\).

The odds-scale interaction ratio compares the joint odds ratio with the product of the two single-locus odds ratios. Under the stated model, it is

$$ \frac{\mathrm{odds}_{11}\mathrm{odds}_{00}} {\mathrm{odds}_{10}\mathrm{odds}_{01}} = \frac{(2/3)(1/9)}{(2/9)(1/3)} =1. $$

So the odds combine multiplicatively, with no departure from the specified no-interaction logistic model. On the risk scale, however, the contrast is

$$ \Delta_{\mathrm{risk}} =\frac{2}{5}-\frac{2}{11}-\frac{1}{4}+\frac{1}{10} =\frac{88-40-55+22}{220} =\frac{15}{220} =\frac{3}{44} \approx 0.06818. $$

The risk-scale contrast is about 6.82 percentage points, whereas the odds-scale interaction ratio is 1. These results are not contradictory: odds and risks are different scales, and a no-interaction logistic model does not generally imply additive risks. The conclusion should name the scale rather than say simply that the loci “do” or “do not” interact.

Worked Example: A Phenotype Transformation Changes Additivity

Suppose a hypothetical positive-valued biomarker has expected measurements of 1, 2, 3, and 6 units in states \(00,10,01,11\). Assume the cell expectations are the target summaries and compare additivity on the original measurement scale with additivity on the natural-log scale. No assumption about a molecular mechanism follows from these cell means.

On the original scale, the difference-in-differences is

$$ \Delta_{\mathrm{original}} =6-2-3+1=2\text{ units}. $$

Thus the joint state departs from the additive prediction on the original scale: starting at 1 unit, the separate increases are 1 unit and 2 units, so the additive prediction for state 11 is \(1+1+2=4\) units, not 6.

On the natural-log scale, the four values are \(\log(1)=0\), \(\log(2)\), \(\log(3)\), and \(\log(6)\). The contrast is

$$ \Delta_{\log} =\log(6)-\log(2)-\log(3)+\log(1) =\log\left(\frac{6\cdot1}{2\cdot3}\right) =\log(1)=0. $$

The same expected measurements are additive on the log scale and nonadditive on the original scale. On the log scale, additivity corresponds to a multiplicative pattern on the original scale: \(6=1\times2\times3\). This example illustrates why a statement about statistical epistasis is incomplete unless the phenotype scale is specified.

Statistical and Biological Interaction Are Different Claims

A statistical interaction describes how a chosen model summarizes observed or expected outcomes. Biological interaction concerns processes: for example, whether one gene product alters another product's activity, whether two pathways converge, or whether one locus changes the functional consequence of another. Such mechanisms can be investigated with molecular and experimental evidence, but a nonzero statistical contrast alone does not demonstrate them.

The distinction also works in the other direction. A biological dependence may be present while a particular statistical contrast is zero. Effects can be masked by the chosen outcome, offset by other processes, averaged over different biological contexts, or represented additively on the selected scale. A statistical result is therefore not a universal verdict about whether two loci interact in nature.

In genetic data, genotype groups are generally observed rather than assigned at random. Differences between groups can reflect ancestry, environment, selection, or other sources of structure as well as genetic associations. Consequently, statistical epistasis in an observational analysis is not automatically a causal effect of jointly changing two loci. The population, conditioning variables, genotype comparison, and assumptions behind the analysis all matter.

A Short Justification of the Additive Contrast

The contrast has a direct model-based justification. If the expected outcome follows the additive model \(m_{ab}=\mu+\alpha a+\beta b\), then the four expected values are \(m_{00}=\mu\), \(m_{10}=\mu+\alpha\), \(m_{01}=\mu+\beta\), and \(m_{11}=\mu+\alpha+\beta\). Substitution gives

$$ m_{11}-m_{10}-m_{01}+m_{00} =(\mu+\alpha+\beta)-(\mu+\alpha)-(\mu+\beta)+\mu =0. $$

Conversely, with these four cell expectations, if the contrast is zero, then \(m_{11}=m_{10}+m_{01}-m_{00}\). Setting \(\mu=m_{00}\), \(\alpha=m_{10}-m_{00}\), and \(\beta=m_{01}-m_{00}\) gives the additive model's prediction for all four cells, including \(m_{11}\). Thus, for these two binary states, the zero contrast is exactly the restriction that the four cell expectations can be represented by this additive model. This justification applies to whichever outcome scale defines \(m_{ab}\); changing that scale changes the cell expectations and can change the conclusion.

What to Specify When Reporting Epistasis

A useful report makes the statistical claim reproducible and limits its interpretation to what the analysis supports. State:

  • The outcome and scale: for example, mean biomarker concentration, risk, or log odds.
  • The genotype comparison and reference states: define which two-locus groups the contrast compares.
  • The null model: say what additivity means on that scale, rather than using “additive” without qualification.
  • The estimate and uncertainty: provide the interaction contrast or model-based effect, with its standard error or interval and the inferential method when making a population-level claim.
  • The scope of interpretation: distinguish a statistical association from a causal or mechanistic conclusion.

A frequent mistake is to reason, “The interaction test was not significant, so the two genes do not interact biologically.” The correction is that a test concerns evidence against a specified statistical restriction, given the data and analysis. A nonsignificant result does not prove that restriction true, and neither a nonsignificant nor a significant result alone settles a biological mechanism. Another mistake is to report “epistasis is present” without naming the scale. A more precise statement is that the data show evidence of departure from a specified additive model on a named outcome scale.

Key takeaway: Statistical epistasis is model-relative and scale-dependent. It can describe a two-locus pattern accurately, but biological interaction and causal joint effects require additional reasoning and evidence.

Check Your Understanding

Answer each question by naming the model or scale involved.

  1. For cell expectations \(m_{00},m_{10},m_{01},m_{11}\), write the two-locus contrast that is zero under additivity on the chosen scale.
  2. Why can a table have no interaction on the odds scale but a nonzero risk-scale interaction contrast?
  3. In the biomarker example, what does a zero contrast on the log scale say, and what does it not establish about biology?
  4. What additional information is needed before interpreting a nonzero estimated contrast as evidence of population-level statistical epistasis?
  5. Explain why a nonsignificant interaction test does not demonstrate that two gene products are biologically independent.
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