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Growth and Decay Models · Tutorial 1408 of 1495

Interpreting Remaining Fractions and Percent Decayed

Translate between fractions and percentages in an exponential decay model, then use each representation to interpret how much remains or has decayed.

Intermediate 9 min read

What You'll Learn

  • Define the remaining fraction as the amount at a given time divided by the initial amount.
  • Convert a remaining fraction into a percentage remaining or a percentage decayed.
  • Read percentage-decayed information correctly when finding an amount still present.
  • Calculate the remaining and decayed amounts from an exponential decay model.
  • Check that remaining and decayed quantities add to the initial amount.

Introduction

In a decay problem, a statement such as “40% has decayed” describes a different quantity from “40% remains.” Confusing these statements can lead to a large error in the amount calculated.

The key is to keep track of the amount still present relative to the initial amount. That ratio is the remaining fraction. From it, we can express the same information as a percentage remaining or as a percentage decayed.

The Remaining Fraction in an Exponential Model

For a continuous exponential decay model, let \(A_0\) be the initial amount and let \(k>0\) be the decay constant. Measuring time \(t\) from the initial measurement, the amount remaining is

$$ A(t)=A_0e^{-kt}. $$

Here \(A_0>0\), \(t\ge 0\), and \(k\) has units reciprocal to the time units used for \(t\). For example, if \(t\) is measured in hours, \(k\) is measured in inverse hours. The exponent \(kt\) is dimensionless.

Definition: The remaining fraction at time \(t\) is the amount remaining divided by the initial amount: $$ R(t)=\frac{A(t)}{A_0}. $$ For the exponential decay model, \(R(t)=e^{-kt}\). The percentage remaining is \(100R(t)\%\), and the percentage decayed is \(100(1-R(t))\%\).

A fraction is a ratio, so it has no units. It lies between 0 and 1 for this model: at \(t=0\), \(R(0)=1\), and for \(t>0\), \(0<R(t)<1\). The amount decayed by time \(t\) is \(A_0-A(t)\); dividing by \(A_0\) gives the fraction decayed.

How the Two Percentages Are Related

The initial amount is divided into two parts: the amount still present and the amount that has decayed. Their fractions of the initial amount must therefore add to 1. If \(D(t)\) denotes the fraction decayed, then

$$ D(t)=\frac{A_0-A(t)}{A_0} =1-\frac{A(t)}{A_0} =1-R(t). $$

Multiplying these fractions by 100 expresses them as percentages. Thus, the percentage remaining and percentage decayed add to 100%. This relationship is a consequence of how the quantities are defined; it does not depend on the exponential formula.

Theorem: At any time \(t\), the percentage decayed is 100% minus the percentage remaining. Equivalently, if \(p\) is the percentage remaining, then the remaining fraction is \(p/100\), and the fraction decayed is \(1-p/100\).

The exponential model supplies the remaining fraction \(e^{-kt}\). The percentage statements are just different ways of reporting that fraction. In particular, “\(p\)% remains” corresponds to \(R(t)=p/100\), whereas “\(q\)% has decayed” corresponds to \(R(t)=1-q/100\).

Worked Example: Finding Both Percentages and Amounts

Worked Example: Finding Both Percentages and Amounts

A sample initially contains \(1000\) milligrams of a substance. It decays with \(k=0.12\) per month. Find the amount remaining, the amount decayed, and both percentages after 6 months. Round final numerical answers to three decimal places.

First calculate the exponent:

$$ kt=(0.12\text{ month}^{-1})(6\text{ months})=0.72. $$

The remaining fraction is

$$ R(6)=e^{-0.72}\approx 0.4867522559599717. $$

The percentage remaining is \(100R(6)\%\), and the percentage decayed is \(100(1-R(6))\%\):

$$ 100R(6)\%\approx 48.67522559599717\%, \qquad 100(1-R(6))\%\approx 51.32477440400283\%. $$

The corresponding amounts are

$$ A(6)=1000e^{-0.72} \approx 486.7522559599717\text{ mg}, $$ $$ 1000-A(6) \approx 513.2477440400283\text{ mg}. $$

Rounded as requested, approximately \(486.752\) mg remains and \(513.248\) mg has decayed. The percentages round to \(48.675\%\) remaining and \(51.325\%\) decayed.

Check: the rounded amounts add to \(486.752+513.248=1000.000\) mg, and the rounded percentages add to \(48.675\%+51.325\%=100.000\%\). Both checks agree with the initial amount and the full 100%.

Converting a Percentage Decayed into an Amount

If a problem gives the percentage decayed, subtract that percentage from 100% to find the percentage remaining. Convert the resulting percentage to a fraction by dividing by 100, then multiply by the initial amount. The amount decayed can be found either by multiplying its own fraction by the initial amount or by subtracting the remaining amount from the initial amount.

Worked Example: Using a Percentage Decayed

A container initially holds \(450\) grams of a substance. After a certain time, \(28\%\) has decayed. Find the percentage remaining, the remaining fraction, and the remaining and decayed amounts.

The percentage remaining is

$$ 100\%-28\%=72\%. $$

As a fraction of the initial amount, this is

$$ \frac{72}{100}=0.72. $$

Therefore, the amount remaining is

$$ 0.72(450\text{ g})=324\text{ g}. $$

The decayed fraction is \(28/100=0.28\), so the amount decayed is

$$ 0.28(450\text{ g})=126\text{ g}. $$

Check: \(324\text{ g}+126\text{ g}=450\text{ g}\), the initial amount. Also, \(126/450=0.28\), confirming that 28% of the initial amount decayed.

Using a Percentage Remaining Directly

When the percentage remaining is given, convert it directly to a fraction by dividing by 100. Multiplying the initial amount by this fraction gives the amount remaining. Then use the complementary fraction, or subtract from the initial amount, to find the amount decayed.

Worked Example: Starting from a Percentage Remaining

A sample initially has \(250\) milligrams of material. At a specified time, \(18\%\) remains. Find the remaining fraction, the amount remaining, the percentage decayed, and the amount decayed.

Convert the percentage remaining to a fraction:

$$ R=\frac{18}{100}=0.18. $$

Multiply this fraction by the initial amount:

$$ A=0.18(250\text{ mg})=45\text{ mg}. $$

The percentage decayed is \(100\%-18\%=82\%\), corresponding to the fraction \(0.82\). Thus,

$$ \text{amount decayed}=0.82(250\text{ mg})=205\text{ mg}. $$

Check: \(45\text{ mg}+205\text{ mg}=250\text{ mg}\), and \(45/250=0.18\). The calculated amount and fraction match the stated 18% remaining.

Why the Conversion Works

The conversion follows from dividing each amount by the same initial amount. Since \(A(t)\) remains and \(A_0-A(t)\) has decayed,

$$ \frac{A(t)}{A_0}+\frac{A_0-A(t)}{A_0} = \frac{A(t)+A_0-A(t)}{A_0} = \frac{A_0}{A_0} = 1. $$

The first ratio is the remaining fraction; the second is the decayed fraction. Their sum is exactly 1, so their percentages sum to 100%. For an exponential model, substituting \(A(t)=A_0e^{-kt}\) into the first ratio gives

$$ R(t)=\frac{A_0e^{-kt}}{A_0}=e^{-kt}, $$

where the cancellation is valid because \(A_0>0\). Consequently, the decayed fraction is \(1-e^{-kt}\), and the amount decayed is \(A_0(1-e^{-kt})\). These expressions describe the same amounts as subtracting the remaining amount from the initial amount.

Common Pitfall: Treating Percent Decayed as Percent Remaining

Suppose \(28\%\) has decayed from an initial amount of \(450\) grams. A common incorrect calculation is

$$ 0.28(450\text{ g})=126\text{ g remaining}. $$

This calculation uses the correct fraction for the decayed amount, but labels it as the amount remaining. It reverses the meanings of the two percentages. The correction is to recognize that \(0.28\) is the fraction decayed, while the fraction remaining is \(1-0.28=0.72\):

$$ \text{remaining}=0.72(450\text{ g})=324\text{ g}, \qquad \text{decayed}=0.28(450\text{ g})=126\text{ g}. $$

The check \(324+126=450\) confirms the corrected interpretation. A useful habit is to write “remaining fraction” or “decayed fraction” beside a decimal before multiplying it by the initial amount.

Choosing the Right Representation

A model may provide a rate constant and time, or a problem may directly state a percentage. In either case, identify which quantity the statement describes before calculating:

  • If the model gives \(k\) and \(t\), calculate \(R(t)=e^{-kt}\).
  • If a percentage remaining is given, divide it by 100 to obtain the remaining fraction.
  • If a percentage decayed is given, subtract it from 100% to obtain the percentage remaining.
  • Multiply the remaining fraction by \(A_0\) to obtain the amount remaining.
  • Subtract the remaining amount from \(A_0\), or use the decayed fraction, to obtain the amount decayed.

Always preserve the distinction between a fraction and a percentage: \(0.28\) as a fraction corresponds to \(28\%\). Also keep the initial amount explicit in calculations. A percentage of the initial amount is not, by itself, an amount; multiplying by \(A_0\) supplies the units and the quantity.

Check Your Understanding

For each question, distinguish carefully between what remains and what has decayed.

  1. If the remaining fraction is \(0.43\), what are the percentage remaining and the percentage decayed?
  2. If \(65\%\) has decayed from an initial amount of \(200\) grams, what fraction remains and how many grams remain?
  3. For \(A(t)=A_0e^{-kt}\), write the remaining fraction and the fraction decayed in terms of \(k\) and \(t\).
  4. If \(12\%\) remains from an initial amount of \(500\) milligrams, how much remains and how much has decayed?
  5. Why must the remaining fraction and the decayed fraction add to 1?

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