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Sequences · Tutorial 196 of 1000

Limit Comparison Arguments

Use quotient limits to build eventual two-sided bounds and transfer conclusions about sequences.

Intermediate 10 min read

What You'll Learn

  • Identify when a quotient limit gives a two-sided comparison on a tail
  • Transfer boundedness and divergence to positive infinity using quotient bounds
  • Use a quotient limit to determine a finite limit from a known sequence limit
  • Distinguish positive finite ratio limits from zero or infinite ratio limits
  • Check the sign and nonzero-denominator hypotheses before comparing sequences

From a Quotient Limit to a Comparison

In the previous tutorial, fixed-multiple comparisons were used to transfer boundedness between sequences. A useful way to obtain such comparisons is to study the limit of their quotient. If two sequences are eventually positive and their quotient tends to a positive finite number, then their terms are eventually within fixed positive multiples of one another. The quotient need not equal a constant at any particular index; being sufficiently close to a positive constant is enough.

The positivity and finiteness of the quotient limit matter. They provide both an eventual upper bound and an eventual positive lower bound. These bounds can transfer more information than a one-sided comparison alone.

Definition: Suppose \((b_n)\) is nonzero for every sufficiently large \(n\). The sequences \((a_n)\) and \((b_n)\) have a positive finite ratio limit \(c\) if \(a_n/b_n\to c\), where \(0<c<\infty\). If both sequences are eventually positive, the quotient is positive wherever it is defined on their common positive tail.

A quotient defined only for sufficiently large indices is enough: convergence depends on the tail, and finite changes preserve convergence. In the comparison arguments below, we will assume the sequences are eventually positive so that multiplying or dividing inequalities does not reverse their direction.

The Two-Sided Estimate

Suppose \(a_n/b_n\to c\), with \(c>0\). Apply the definition of convergence using the tolerance \(c/2\). Eventually the quotient differs from \(c\) by less than \(c/2\), so it lies between \(c/2\) and \(3c/2\). Multiplying by the positive term \(b_n\) gives a two-sided estimate for \(a_n\).

Theorem (Two-Sided Bounds from a Positive Ratio Limit): Suppose \((a_n)\) and \((b_n)\) are eventually positive and \(a_n/b_n\to c\), where \(c>0\). Then there is an \(N\in\mathbb{N}_0\) such that, for every \(n\geq N\),

\(\dfrac{c}{2}b_n\leq a_n\leq\dfrac{3c}{2}b_n.\)

Consequently, \((a_n)\) is bounded if and only if \((b_n)\) is bounded. Also, \(a_n\to+\infty\) if and only if \(b_n\to+\infty\).

Proof. Since \(a_n/b_n\to c\), there is an index \(N_1\) such that, for every \(n\geq N_1\),

$$ \left|\frac{a_n}{b_n}-c\right|<\frac{c}{2}. $$

This inequality implies

$$ \frac{c}{2}<\frac{a_n}{b_n}<\frac{3c}{2} $$

for every \(n\geq N_1\). Choose \(N\) large enough that this estimate holds and both sequences are positive for \(n\geq N\). Multiplication by \(b_n>0\) gives the asserted two-sided bounds (with weak inequalities as well).

For boundedness, the upper bound \(a_n\leq(3c/2)b_n\) on the tail is a fixed-multiple magnitude comparison. If \((b_n)\) is bounded, the Boundedness Transfers Through an Upper Magnitude Comparison theorem from the previous tutorial shows that \((a_n)\) is bounded. The lower bound can be rearranged, since \(c/2>0\), to give \(b_n\leq(2/c)a_n\) on the tail. The same theorem shows that boundedness of \((a_n)\) implies boundedness of \((b_n)\). Thus the sequences are bounded together or unbounded together.

Now suppose \(b_n\to+\infty\). Given any real \(R\), choose a positive number \(T\) such that \((c/2)T>R\). For all sufficiently large \(n\), both \(n\geq N\) and \(b_n>T\), and hence

$$ a_n\geq\frac{c}{2}b_n>\frac{c}{2}T>R. $$

Therefore \(a_n\to+\infty\). Conversely, the upper bound gives \(b_n\geq(2/(3c))a_n\) on the tail. If \(a_n\to+\infty\), this inequality proves \(b_n\to+\infty\) by the same threshold argument, using \(2/(3c)>0\). This proves both directions. \(\square\)

The result is a limit-based method for obtaining the fixed constants required by comparison arguments. It does not say that the sequences have the same limit: a quotient tending to \(c\) says their sizes are related by a factor approaching \(c\), and their finite limits, when they exist, may therefore differ by that factor.

Worked Example: Comparing Two Quadratic Sequences

Let \(a_n=3n^2+4n+1\) and \(b_n=n^2+2\), for \(n\in\mathbb{N}_0\). Both sequences are positive. Dividing numerator and denominator of the quotient by \(n^2\) for \(n\geq1\) gives

$$ \frac{a_n}{b_n} = \frac{3+4/n+1/n^2}{1+2/n^2} \longrightarrow 3. $$

The limit is positive and finite, so the theorem supplies eventual two-sided bounds. In particular, for all sufficiently large \(n\), \(a_n\geq(3/2)b_n\). Also \(b_n\to+\infty\): given \(R\), choose \(n\) large enough that \(n^2+2>R\). The theorem now gives \(a_n\to+\infty\) as well. This conclusion follows from the quotient limit without needing to estimate \(a_n\) independently against every threshold.

The constant in the quotient limit is \(3\), not \(1\). The sequences grow at comparable rates, but the estimate predicts that \(a_n\) is eventually about three times \(b_n\), not that their terms become close.

Using the Ratio to Find a Finite Limit

A positive finite ratio limit is also useful when one of the sequences converges to a finite value. On a tail, the identity \(a_n=(a_n/b_n)b_n\) expresses one sequence as the product of the quotient and the other sequence. The Limit of a Product theorem then determines the limit of \(a_n\).

Theorem (Finite Limit from a Ratio Limit): Suppose \((b_n)\) is eventually positive, \(a_n/b_n\to c\) for some finite \(c\), and \(b_n\to L\in\mathbb{R}\). Then \(a_n\to cL\).

Proof. Choose an index \(N\) such that \(b_n>0\) for every \(n\geq N\), and define \(r_n=a_n/b_n\) on that tail. Extend \((r_n)\) to a real sequence by assigning arbitrary real values to its finitely many terms before \(N\). The extension still converges to \(c\), since finite changes preserve convergence. For every \(n\geq N\),

$$ a_n=r_nb_n. $$

By the Limit of a Product theorem, \(r_nb_n\to cL\). The sequence \((a_n)\) agrees with \((r_nb_n)\) for every \(n\geq N\), so the Finite Changes Preserve Convergence theorem implies \(a_n\to cL\). \(\square\)

The conclusion includes the case \(L=0\): then \(a_n\to0\), even if the ratio limit \(c\) is not \(1\). When \(c=1\), the theorem says that \(a_n\) and \(b_n\) have the same finite limit, provided the quotient is defined on a positive tail.

Worked Example: Transferring a Finite Limit

For \(n\in\mathbb{N}_0\), let

$$ b_n=1+\frac{1}{n+1}, \qquad a_n=\left(3+\frac{(-1)^n}{n+1}\right)b_n. $$

The factor \(3+(-1)^n/(n+1)\) is positive: since \(|(-1)^n/(n+1)|\leq1\), it is at least \(2\). Also \(b_n>0\). Thus the quotient is defined, and the defining identity gives

$$ \frac{a_n}{b_n}=3+\frac{(-1)^n}{n+1}\longrightarrow3. $$

Since \(b_n\to1\), the Finite Limit from a Ratio Limit theorem gives \(a_n\to3\cdot1=3\). The alternating term in the quotient tends to zero because its absolute value is \(1/(n+1)\), which tends to zero. The quotient limit, rather than a direct expansion of \(a_n\), makes the limit calculation immediate.

Why the Positive Finite Condition Matters

A quotient limit of zero does not give a positive lower comparison. It may still provide useful information in other settings, but it cannot be used here to conclude that the sequences share boundedness status or divergence to infinity. Likewise, a quotient that grows without bound does not produce the fixed upper and lower constants in the theorem. Always check which kind of quotient limit has actually been established before using a limit comparison.

Worked Example: A Zero Ratio Limit Does Not Preserve Boundedness

Set \(a_n=1\) and \(b_n=n+1\). Both are positive, and

$$ \frac{a_n}{b_n}=\frac{1}{n+1}\longrightarrow0. $$

The sequence \((a_n)\) is bounded, since \(|a_n|=1\) for every \(n\). The sequence \((b_n)\) is unbounded: for any \(R\geq0\), choose an integer \(n>R\), so \(b_n=n+1>R\). Thus a ratio limit of zero does not make boundedness status match. The proof of the two-sided estimate cannot be used: taking half of the proposed limit gives zero, which is not a positive lower factor and cannot be used to bound \(b_n\) by a fixed multiple of \(a_n\).

There are two further common pitfalls. First, the quotient must be defined on a tail; if \(b_n=0\) at arbitrarily large indices, the ratio \(a_n/b_n\) cannot have the stated ordinary real limit along all sufficiently large indices. Second, the comparison step uses \(b_n>0\). Without eventual positivity, multiplying a quotient inequality by \(b_n\) can reverse its direction, and quotient estimates alone do not give the displayed order bounds. For sequences that change sign, one must make an appropriate comparison of magnitudes and verify the needed hypotheses.

A Practical Limit-Comparison Routine

When a quotient appears simpler than the sequences themselves, use it to generate the constants needed for a comparison. Then match the comparison to the desired conclusion rather than treating all limit behavior as interchangeable.

1
Check the tail and signs.
Make sure the denominator is nonzero and, for the two-sided order estimate, both sequences are positive from some index onward.
2
Find the quotient limit.
Establish \(a_n/b_n\to c\). For boundedness and positive-infinity comparisons, the useful case is \(0<c<\infty\).
3
Choose a tolerance around the limit.
Using \(c/2\) gives \(c/2<a_n/b_n<3c/2\) eventually, and hence fixed lower and upper comparisons.
4
Apply only the conclusion supported.
Use the two-sided bounds for boundedness or divergence to positive infinity. If one sequence has a finite limit, use the quotient identity and the product limit law to find the other limit.

A ratio limit is a way to turn information about relative size into concrete inequalities. A positive finite limit gives comparisons in both directions; a zero limit loses the lower bound, and a limit that is not finite loses the fixed upper bound. Keeping these distinctions explicit makes limit comparisons reliable and prevents a useful estimate from being applied beyond what it proves.

Check Your Understanding

Use the quotient limit and the comparison results in this tutorial to answer the following questions.

  1. If \(a_n/b_n\to c>0\) and both sequences are eventually positive, what eventual lower and upper bounds for \(a_n\) follow by using tolerance \(c/2\)?
  2. Under the same hypotheses, why does boundedness of either sequence imply boundedness of the other?
  3. If \(a_n/b_n\to c>0\) and \(b_n\to+\infty\), which inequality proves that \(a_n\to+\infty\)?
  4. If \(a_n/b_n\to c\) and \(b_n\to L\), what is the limit of \(a_n\), and which limit law justifies the conclusion?
  5. Why does the example \(a_n=1\), \(b_n=n+1\) show that a ratio limit of zero is insufficient for equivalent boundedness conclusions?