Why Degree Comparison Comes First
Before applying partial fractions to a rational function, first check whether the numerator has degree less than the denominator. This quick comparison tells you whether the fraction is already in the form needed for a proper rational part, or whether polynomial division is needed first.
The comparison is about the degrees of the whole numerator and denominator polynomials. It does not depend on whether those polynomials are expanded or factored. Equal degrees count as improper, not proper. Common factors may change how the fraction looks, but they do not change the degree comparison that determines its classification.
Degrees and the Properness Test
The degree of a nonzero polynomial is the greatest exponent of its variable with a nonzero coefficient. For example, \(4x^3-2x+7\) has degree \(3\), while the nonzero constant polynomial \(5\) has degree \(0\). The zero polynomial is assigned degree \(-\infty\) for the purpose of the comparison below.
A rational function is written as \(P(x)/Q(x)\), where \(P\) and \(Q\) are polynomials and \(Q\) is not the zero polynomial. The degree test compares \(\deg P\) and \(\deg Q\).
The criterion is simple, but it is important to apply it to the full polynomials. A numerator containing several terms does not have degree equal to its number of terms, and the degree of a product is found by adding the degrees of its polynomial factors.
This product rule applies when \(A\) and \(B\) are nonzero polynomials. In particular, a factored numerator or denominator can often be classified without expanding it.
Worked Examples: Comparing Degrees
Worked Example: A Proper Rational Function
Classify \(\frac{3x+1}{x^3-2x+5}\). The numerator has leading term \(3x\), so its degree is \(1\). The denominator has leading term \(x^3\), so its degree is \(3\). Since \(1<3\), the rational function is proper.
As a check, the denominator's degree is greater than the numerator's degree, exactly as required by the definition of proper. No polynomial division is needed to make this rational function proper.
Worked Example: Equal Degrees Are Improper
Classify \(\frac{6x^2-3x+4}{2x^2+5x-1}\). The leading terms are \(6x^2\) and \(2x^2\), so the numerator and denominator both have degree \(2\). The degrees are equal, and therefore the rational function is improper.
The check is the defining inequality: properness would require \(2<2\), which is false. Equal degree is not a borderline case that counts as proper; it belongs to the improper case. When this function is prepared for a partial-fraction decomposition, division is needed, with a constant polynomial part.
Worked Example: Using Factors to Compare Degrees
Classify \(\frac{(x^2+1)(2x-3)}{(x+4)^2}\). The numerator is a product of a degree-\(2\) polynomial and a degree-\(1\) polynomial, so its degree is \(2+1=3\). The denominator has degree \(2\), because it is the square of a degree-\(1\) polynomial. Since \(3\geq2\), the rational function is improper.
As a check, the numerator's degree exceeds the denominator's degree by \(1\), so the numerator is not of lower degree. The factors need not be expanded to make this decision.
Why Equal Degrees Still Require Division
It can be tempting to think that a numerator and denominator of equal degree are already suitable for partial fractions because neither degree is larger. The properness definition rules this out: the numerator must have strictly lower degree.
There is also a useful way to understand the equal-degree case. The leading terms of two degree-\(n\) polynomials are both multiples of \(x^n\). A constant multiple of the denominator can match and remove the numerator's leading term. That constant is the ratio of the leading coefficients. This is why the polynomial part produced by division in the equal-degree case is a constant, rather than a polynomial of positive degree.
The degree comparison determines whether division is needed; it does not require you to carry out that division. The full quotient-and-remainder method belongs to the next stage of the procedure.
Common Factors Do Not Change the Classification
A numerator and denominator may share a nonzero polynomial factor. Canceling such a factor reduces the degree of both polynomials by the same amount. Consequently, it does not change whether the numerator degree is less than, equal to, or greater than the denominator degree.
Here is the justification. Since \(P\) and \(Q\) are divisible by \(G\), their quotients are polynomials. The degree of a product of nonzero polynomials is the sum of the degrees of its factors. From \(P=G(P/G)\), it follows that \(\deg(P/G)=\deg P-\deg G\). Likewise, \(\deg(Q/G)=\deg Q-\deg G\). Subtracting the second equality from the first gives
The sign of this difference determines the classification: a negative difference means proper, while zero or a positive difference means improper. Because cancellation leaves the difference unchanged, it cannot switch a rational function from one class to the other.
Worked Example: An Equal-Degree Fraction with a Common Factor
Consider \(\frac{(x-2)(3x+1)}{(x-2)(x+4)}\), initially defined for \(x\neq2\) and \(x\neq-4\). The numerator has degree \(1+1=2\), and the denominator also has degree \(1+1=2\). The original expression is therefore improper.
For \(x\neq2\), the common factor can be canceled algebraically, giving \(\frac{3x+1}{x+4}\). The numerator and denominator of this reduced expression both have degree \(1\), so it is also improper.
To check the cancellation at a value in the original domain, take \(x=0\). The original expression gives \(\frac{(-2)(1)}{(-2)(4)}=\frac14\), and the reduced expression gives \(\frac{1}{4}=\frac14\). The degree comparison also checks: before cancellation it is \(2\) versus \(2\), and afterward it is \(1\) versus \(1\). Both comparisons identify an improper rational function.
Cancellation does have a separate domain issue. The original expression in the example is undefined at \(x=2\), even though the reduced formula \((3x+1)/(x+4)\) has a value there. Canceling a factor gives the same values wherever the original expression is defined, but it does not automatically restore points excluded from the original domain. This distinction matters when discussing the function's domain; it does not affect the degree test.
A Reliable Decision Process
Use the following sequence whenever you encounter a rational function and need to know whether division comes first.
Write the expression as \(P(x)/Q(x)\), with \(Q\) a nonzero polynomial.
Use the highest nonzero exponent, or add degrees of factors when the polynomials are factored.
If the numerator degree is smaller, the function is proper. If it is equal or larger, the function is improper.
Canceling a factor shared by numerator and denominator lowers both degrees equally, so it preserves the comparison.
Common Mistake: Treating Equality as Proper
A frequent error is to use “less than or equal to” in the definition of a proper rational function. For example, someone might classify \(\frac{x^2+1}{4x^2-7}\) as proper because the numerator degree is not greater than the denominator degree.
The calculation \(2\leq2\) is true, but it is not the test for properness. Properness requires a strict inequality. The correct comparison is \(2<2\), which is false, so the rational function is improper. The correction is to remember that equality belongs with the improper case.
Another source of error is counting visible factors rather than adding their degrees. For example, \((x^2+1)(x-1)\) has two displayed factors, but its degree is \(2+1=3\), not \(2\). Use polynomial degrees, not the number of terms or factors, in the comparison.
Why the Test Matters
Partial-fraction methods are designed to handle proper rational terms. When the numerator degree is at least the denominator degree, the expression must first be separated into a polynomial part and a proper rational part. Recognizing this before beginning prevents an attempted decomposition from being incomplete.
The degree test is also efficient: it does not require finding roots, factoring every polynomial, or solving for partial-fraction coefficients. It is a preliminary decision based only on the highest powers. If common factors are visible, they may help reveal the reduced expression, but they cannot change the proper-or-improper outcome.
Check Your Understanding
For each question, compare the degrees carefully and state whether division is needed to make the rational function proper.
- Classify \(\frac{5x^2-1}{x^4+3x}\) and give the two degrees.
- Is \(\frac{7x^3+x}{2x^3-4}\) proper or improper? Explain the role of equal degrees.
- Find the numerator and denominator degrees of \(\frac{(x^2+2)(x+1)}{(x-3)^2}\), then classify it.
- Can canceling a nonzero common polynomial factor turn an improper rational function into a proper one? Explain using the degree difference.
- What domain restriction must be remembered when canceling a common factor that vanishes at some value of \(x\)?