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Calculus-Based Model Construction · Tutorial 1475 of 1495

Resource Stocks Under Extraction And Replenishment

Build and interpret a resource stock balance using time-varying extraction and replenishment rates.

Advanced 9 min read

What You'll Learn

  • Define a resource stock and its extraction and replenishment rates with consistent units
  • Derive the stock balance from conservation of resource
  • Use the sign of the net rate to identify decline, recovery, or an instant of no change
  • Calculate stock changes from rates over a time interval
  • Recognize when a mathematical stock prediction conflicts with resource availability

Modeling a Resource Stock

A resource stock is an amount available at a particular time: for example, water in a reservoir, timber in a managed forest, or a mineral reserve. Extraction reduces the amount, while replenishment adds to it. When both processes vary over time, the stock’s change depends on their rates at each moment.

The key modeling question is not simply how much is extracted or replenished in total. It is how those flows compare at a given time. If extraction is faster than replenishment, the stock is declining at that instant. If replenishment is faster, the stock is recovering.

Define the State and Rates

Let \(S(t)\) denote the amount of resource in the stock at time \(t\). Suppose \(E(t)\) is the extraction rate and \(R(t)\) is the replenishment rate. Use compatible units: if \(S\) is measured in tonnes and \(t\) in years, both rates must be measured in tonnes per year.

Definition: The resource-stock balance is $$ \frac{dS}{dt}=R(t)-E(t). $$ Here \(R(t)\) and \(E(t)\) are gross rates, usually nonnegative. The difference \(R(t)-E(t)\) is the net rate of change of the stock.

The minus sign records the direction of extraction’s contribution: resource leaving the stock reduces \(S\). The plus sign records that replenishment adds resource. This is a conservation balance: the stock changes by the amount entering minus the amount leaving.

Rates may be functions of time, or may be specified by different formulas in different operating periods. The balance applies within each period where the rates are defined. If a rate changes abruptly at a boundary, the stock itself is still continuous under the usual model: a finite jump in a rate does not imply an instantaneous jump in the amount.

Why the Balance Formula Holds

Consider a short time interval from \(t\) to \(t+\Delta t\). The amount replenished over that interval is approximately \(R(t)\Delta t\), and the amount extracted is approximately \(E(t)\Delta t\), when the interval is sufficiently short and the rates do not change too much within it. Thus the stock change is approximately the net inflow:

$$ S(t+\Delta t)-S(t) \approx R(t)\Delta t-E(t)\Delta t. $$

Divide by \(\Delta t\), then let the interval length approach zero. The left-hand side approaches the derivative of the stock, giving the balance equation. This argument is made precise by the definition of instantaneous rate of change.

The same balance also gives a finite-interval formula. If the rates are integrable on \([a,b]\), and the stock follows the balance throughout that interval, then

$$ S(b)-S(a)=\int_a^b \bigl(R(t)-E(t)\bigr)\,dt, $$

so that

$$ S(b)=S(a)+\int_a^b R(t)\,dt-\int_a^b E(t)\,dt. $$

The integrals are the total replenishment and total extraction over the interval. This is the accumulation form of the balance, obtained from the Fundamental Theorem of Calculus when \(S\) is differentiable and its derivative is the net rate.

Interpreting the Net Rate

The sign of \(R(t)-E(t)\) gives a direct local interpretation. These statements concern the stock’s instantaneous direction of change, not necessarily its total change across a long interval.

Rate comparison at time \(t\)Net rateStock behavior at that instant
\(R(t)<E(t)\)\(\frac{dS}{dt}<0\)The stock is declining.
\(R(t)>E(t)\)\(\frac{dS}{dt}>0\)The stock is recovering.
\(R(t)=E(t)\)\(\frac{dS}{dt}=0\)The stock has zero instantaneous rate of change.

For instance, a stock can decline during one part of an interval and recover during another. Its overall change depends on the accumulated net rate across the whole interval. A positive net rate at one time does not by itself show that the stock increased over an entire month or year.

Worked Example: A Stock Declining Under Linear Rates

A reserve initially contains \(500\) tonnes. For the next \(4\) years, replenishment is \(R(t)=12+2t\) tonnes per year and extraction is \(E(t)=20+t\) tonnes per year, where \(t\) is measured in years from the start. Find the stock after \(4\) years and determine whether it is declining throughout the interval.

First form the net rate:

$$ R(t)-E(t)=(12+2t)-(20+t)=-8+t. $$

For \(0\le t\le4\), this net rate ranges from \(-8\) to \(-4\) tonnes per year, so it is negative throughout. The stock is therefore declining throughout the specified interval.

Integrate the net rate and add the initial stock:

$$ \begin{aligned} S(4) &=500+\int_0^4(-8+t)\,dt\\ &=500+\left[-8t+\frac{t^2}{2}\right]_0^4\\ &=500+\left(-32+8\right)-0\\ &=476\text{ tonnes}. \end{aligned} $$

Check by calculating the gross totals. Replenishment is \(12(4)+\int_0^4 2t\,dt=48+16=64\) tonnes. Extraction is \(20(4)+\int_0^4 t\,dt=80+8=88\) tonnes. Thus \(500+64-88=476\) tonnes, agreeing with the net-rate calculation.

Time-Varying Rates Can Give Different Directions

When rates vary, the comparison must be made at the time of interest. It is possible for a stock to decline during one period and recover during another, even if its final amount equals its initial amount. The next example shows why an endpoint comparison alone does not describe the stock’s behavior throughout the interval.

Worked Example: Decline Followed by Recovery

A stock begins at \(100\) units. Over \(0\le t\le4\) months, replenishment and extraction rates are \(R(t)=8+2t\) units per month and \(E(t)=14-t\) units per month. Find the stock at \(t=1\), \(t=3\), and \(t=4\), and interpret the rates.

The net rate is

$$ R(t)-E(t)=(8+2t)-(14-t)=-6+3t. $$

It is negative for \(0\le t<2\), zero at \(t=2\), and positive for \(2<t\le4\). Hence the stock declines during the first part of the interval and recovers during the later part. Integrating the net rate gives a stock formula valid on the stated interval:

$$ \begin{aligned} S(t) &=100+\int_0^t(-6+3u)\,du\\ &=100-6t+\frac{3}{2}t^2. \end{aligned} $$

At \(t=1\),

$$ S(1)=100-6+\frac{3}{2}=95.5\text{ units}. $$

At \(t=3\),

$$ S(3)=100-18+\frac{3}{2}(9)=100-18+13.5=95.5\text{ units}. $$

At \(t=4\),

$$ S(4)=100-24+\frac{3}{2}(16)=100-24+24=100\text{ units}. $$

Check the endpoint using gross totals. Total replenishment is \(\int_0^4(8+2t)\,dt=32+16=48\) units. Total extraction is \(\int_0^4(14-t)\,dt=56-8=48\) units. Equal totals leave the stock at its initial value, consistent with \(S(4)=100\). The equal endpoints do not mean the stock was constant: the rate comparison shows an interval of decline followed by an interval of recovery.

Piecewise Operating Periods

Resource operations often change regime. A site may have one extraction plan during a scheduled maintenance period and another after maintenance. The balance remains the same in each period, but the relevant rates must be applied to the correct time interval. Add the changes from consecutive periods to find the stock at the end.

Worked Example: Two Operating Regimes

A resource stock contains \(240\) kilograms at \(t=0\). During \(0\le t<3\) days, replenishment is \(4\) kilograms per day and extraction is \(10\) kilograms per day. During \(3\le t\le5\) days, replenishment is \(12\) kilograms per day and extraction is \(5\) kilograms per day. Find the stock at days \(3\) and \(5\), and describe the direction of change in each regime.

In the first regime, the net rate is \(4-10=-6\) kilograms per day. Over \(3\) days the stock changes by \((-6)(3)=-18\) kilograms, so

$$ S(3)=240-18=222\text{ kilograms}. $$

In the second regime, the net rate is \(12-5=7\) kilograms per day. Over the next \(2\) days the stock changes by \(7(2)=14\) kilograms, so

$$ S(5)=222+14=236\text{ kilograms}. $$

The stock declines in the first regime because extraction exceeds replenishment, then recovers in the second because replenishment exceeds extraction. Check by totals over all five days: replenishment is \(4(3)+12(2)=12+24=36\) kilograms, and extraction is \(10(3)+5(2)=30+10=40\) kilograms. Therefore \(240+36-40=236\) kilograms, as calculated. The rate may jump at day \(3\); the stock value on either side remains \(222\) kilograms in this model.

Physical Limits and Modeling Assumptions

The balance equation describes accounting, but it does not automatically enforce physical constraints. In particular, a resource stock normally cannot be negative. If a chosen extraction schedule implies that cumulative extraction exceeds the initial stock plus all replenishment, then the formula predicts an impossible negative amount.

$$ \int_0^t E(u)\,du > S(0)+\int_0^t R(u)\,du \quad\Longrightarrow\quad S(t)<0 $$

Such a result does not mean that the physical resource becomes negative. It means that at least one modeling assumption has failed: perhaps extraction cannot continue at the specified rate once the stock is depleted, replenishment was omitted or misestimated, or the model’s time horizon is too long. A realistic model must specify how extraction responds when resource availability becomes limiting. The simple balance alone does not decide that behavior.

Another common issue is confusing a gross rate with a net rate. If the stated rate is already “net replenishment after extraction,” subtracting extraction again would count it twice. Conversely, if separate gross extraction and replenishment rates are supplied, their difference is needed to determine the stock’s net change.

Modeling check: Before interpreting a stock prediction, verify that the initial amount and both rates use compatible units, that extraction and replenishment are assigned the correct signs, and that the predicted stock remains physically meaningful under the stated assumptions.

Common Mistake: Treating Extraction as a Positive Addition

Suppose the replenishment rate is \(6\) units per day and the extraction rate is \(9\) units per day. A mistaken calculation might write the net rate as \(6+9=15\), concluding that the stock is growing rapidly. This adds two gross magnitudes without regard to their directions.

The correction is to assign replenishment a positive contribution and extraction a negative contribution:

$$ \frac{dS}{dt}=6-9=-3\text{ units per day}. $$

The stock is declining at \(3\) units per day at that time. The minus sign is not a convention to remember mechanically; it follows from extraction carrying resource out of the stock.

Why the Stock Balance Matters

The balance separates two questions that are easy to confuse. The sign of the net rate describes the stock’s direction of change at a moment, while the integral of the net rate describes its total change over an interval. Both are useful: managers may need to know whether a resource is currently being depleted, while also tracking how much remains after an operating season.

The same structure applies to many settings in which an amount changes through inflows and outflows. For a resource, the physical interpretation is especially clear: conservation links the observed stock to the accumulated difference between replenishment and extraction. Good predictions therefore depend on clearly defining the stock, measuring rates in consistent units, specifying their time variation, and stating the conditions under which the extraction plan can actually be carried out.

Check Your Understanding

Use the stock-balance equation to answer the following questions.

  1. A stock has replenishment \(11\) tonnes per year and extraction \(15\) tonnes per year at a particular time. Is the stock declining or recovering, and at what rate?
  2. Why can equal total replenishment and extraction over a year coexist with periods of both decline and recovery?
  3. A stock starts at \(80\) units. Over an interval, total replenishment is \(18\) units and total extraction is \(25\) units. What is the final stock under the balance model?
  4. What does a negative stock prediction indicate about a resource-extraction model?
  5. If a reported rate is already the net rate after extraction, should gross extraction be subtracted from it again? Explain.

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