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Scientific Notation and Powers of Ten

Use powers of ten to write, calculate with, and compare quantities across a wide range of scales.

Beginner 9 min read

What You'll Learn

  • Identify the coefficient and exponent in normalized scientific notation
  • Convert large and small decimal quantities into scientific notation
  • Multiply and divide quantities written with powers of ten
  • Normalize a result when its coefficient is outside the required range
  • Compare scales without assuming adjacent exponents mean a tenfold ratio

Why Use Scientific Notation?

Some quantities are inconvenient to write with ordinary decimal notation. The distance from Earth to the Sun is about \(150{,}000{,}000\) kilometres, while the width of a red blood cell is about \(0.000008\) metres. Scientific notation writes each using a short coefficient and a power of ten.

The exponent records the general scale of the quantity, while the coefficient gives its position within that scale. This makes scientific notation useful not only for shortening long strings of zeros, but also for calculating and comparing quantities that differ greatly in size.

Definition: A nonzero real number is in normalized scientific notation if it is written as \(a\times 10^n\), where \(n\) is an integer and the coefficient \(a\) satisfies \(1\leq |a|<10\). For a positive number, this means \(1\leq a<10\). Zero is written as \(0\); it has no normalized scientific-notation representation with a nonzero coefficient.

The exponent \(n\) may be positive, zero, or negative. For example, \(4.2\times10^5\) is a large number, \(4.2\times10^0=4.2\), and \(4.2\times10^{-5}\) is a small positive number. A negative exponent does not make the value negative: the sign of the number comes from its coefficient.

Converting a Decimal to Scientific Notation

To convert a nonzero decimal, move its decimal point until exactly one nonzero digit is to its left. The number of places moved determines the power of ten. If the original number is at least \(10\), moving the decimal point left gives a positive exponent. If its absolute value is less than \(1\), moving the decimal point right gives a negative exponent.

This procedure follows from the fact that moving a decimal point one place left divides the written coefficient by \(10\), so the product is preserved by multiplying by \(10\). Moving it one place right multiplies the coefficient by \(10\), so the product is preserved by dividing by \(10\). Repeating these changes gives the required power.

Worked Example: Converting a Large Number

Write \(72{,}500{,}000\) in normalized scientific notation.

Move the decimal point seven places left to obtain \(7.25\). Since the decimal moved left, pair this coefficient with \(10^7\):

$$ 72{,}500{,}000=7.25\times10^7. $$

The coefficient satisfies \(1\leq 7.25<10\), so the representation is normalized. Check by expanding the power: \(10^7=10{,}000{,}000\), and \(7.25\times10{,}000{,}000=72{,}500{,}000\), as required.

Worked Example: Converting a Small Number

Write \(0.00000408\) in normalized scientific notation.

Move the decimal point six places right to obtain \(4.08\). Because the decimal moved right, the exponent is negative:

$$ 0.00000408=4.08\times10^{-6}. $$

The coefficient is between \(1\) and \(10\). To check, \(10^{-6}=0.000001\), and \(4.08\times0.000001=0.00000408\). This also confirms that the exponent is \(-6\), not \(-5\) or \(-7\).

For a negative number, first write its magnitude in normalized form and then retain the negative sign. For instance, \(-0.0036=-3.6\times10^{-3}\). The coefficient has absolute value \(3.6\), which meets the normalization condition.

Why the Normalized Form Is Unique

For each nonzero positive number, there is exactly one normalized coefficient and integer exponent. The decimal-point procedure gives a representation, and the normalization condition rules out competing choices.

To see why, suppose a positive number had two normalized representations \(a\times10^m=b\times10^n\), with \(1\leq a<10\) and \(1\leq b<10\). If \(m<n\), then \(n\geq m+1\), so \(b\times10^n\geq10\times10^m\). But \(a\times10^m<10\times10^m\). The two representations could not be equal. The case \(n<m\) gives the same contradiction with the roles exchanged. Thus \(m=n\), and dividing the equality by \(10^m\) gives \(a=b\). For a negative number, apply the same argument to its positive magnitude and attach the negative sign.

Result: Every nonzero real number has exactly one normalized scientific-notation representation \(a\times10^n\), where \(n\) is an integer and \(1\leq |a|<10\).

Calculating with Powers of Ten

The exponent laws give efficient rules for multiplying and dividing scientific-notation expressions. For nonzero coefficients \(a\) and \(b\), and integers \(m\) and \(n\), the relevant laws are

$$ (a\times10^m)(b\times10^n)=(ab)\times10^{m+n}, \qquad \frac{a\times10^m}{b\times10^n} = \frac{a}{b}\times10^{m-n}. $$

In multiplication, multiply the coefficients and add the exponents. In division, divide the coefficients and subtract the denominator exponent from the numerator exponent. A resulting coefficient may fall outside the normalized range, so check it and adjust if needed.

Worked Example: Multiplying and Normalizing

Calculate \((3.2\times10^{-5})(4.5\times10^8)\) and express the result in normalized scientific notation.

Multiply the coefficients: \(3.2\times4.5=14.4\). Add the exponents: \(-5+8=3\). Therefore, the product is \(14.4\times10^3\). This is equal to \(1.44\times10^4\), because moving the coefficient’s decimal point one place left divides it by \(10\), so the exponent must increase by one:

$$ (3.2\times10^{-5})(4.5\times10^8) =14.4\times10^3 =1.44\times10^4. $$

The normalized coefficient \(1.44\) is in the required range. Check the value directly: \(3.2\times10^{-5}=0.000032\) and \(4.5\times10^8=450{,}000{,}000\). Their product is \(14{,}400\), which is also \(1.44\times10^4\).

Worked Example: Dividing and Normalizing

Calculate \(\dfrac{8.4\times10^6}{2.1\times10^2}\) in normalized scientific notation.

Divide the coefficients: \(8.4\div2.1=4\). Subtract the exponents: \(6-2=4\). Thus

$$ \frac{8.4\times10^6}{2.1\times10^2} = 4\times10^4. $$

The coefficient \(4\) is already normalized. To check, \(8.4\times10^6=8{,}400{,}000\) and \(2.1\times10^2=210\). Since \(210\times40{,}000=8{,}400{,}000\), the quotient is \(40{,}000=4\times10^4\).

Addition and subtraction work differently: the exponents cannot simply be added or subtracted. First express both numbers using the same power of ten, then add or subtract their coefficients.

Worked Example: Adding Different Scales

Calculate \(3.6\times10^5+2.4\times10^4\) and write the answer in normalized scientific notation.

Rewrite the second term with a factor of \(10^5\). Since \(2.4\times10^4=0.24\times10^5\), we can add the coefficients:

$$ 3.6\times10^5+2.4\times10^4 = 3.6\times10^5+0.24\times10^5 = (3.6+0.24)\times10^5 = 3.84\times10^5. $$

The coefficient is normalized. Check in decimal form: \(360{,}000+24{,}000=384{,}000\), and \(3.84\times10^5=384{,}000\).

Interpreting the Scale

The exponent gives a useful first indication of scale, but the coefficient matters when comparing values. If two positive normalized numbers have the same exponent, the one with the larger coefficient is larger. If their exponents differ by more than one, the larger exponent does guarantee the larger number. If the exponents differ by exactly one, the larger exponent still means the number is larger, but it does not guarantee a tenfold difference.

In fact, let \(a\times10^n\) and \(b\times10^{n+1}\) be positive normalized numbers, where \(1\leq a<10\) and \(1\leq b<10\). Their ratio, larger-exponent number divided by smaller-exponent number, is

$$ \frac{b\times10^{n+1}}{a\times10^n} = 10\frac{b}{a}. $$

Because \(b\geq1\) and \(a<10\), this ratio is greater than \(1\). Because \(b<10\) and \(a\geq1\), it is less than \(100\). Thus the larger-exponent number is greater, but the ratio can be less than \(10\), equal to \(10\), or greater than \(10\).

For example, \(\frac{1\times10^6}{9\times10^5}=\frac{10}{9}\), which is greater than \(1\) but less than \(10\). The exponents differ by one, yet the larger number is not ten times as large. This is why scale comparisons should use both coefficient and exponent.

Common Pitfall: Ignoring the Coefficient or the Sign of the Shift

A frequent error is to assume that a one-unit increase in exponent always makes a normalized positive number ten times as large. As the ratio calculation shows, that is not generally true: coefficients can offset much of the change in exponent.

Another common error is to use the wrong sign when converting a small decimal. For example, writing \(0.00042=4.2\times10^5\) is incorrect: the right-hand side is \(420{,}000\), not a small number. The decimal point moves five places right to make \(4.2\), so the correct power is negative:

$$ 0.00042=4.2\times10^{-4}. $$

Indeed, \(10^{-4}=0.0001\), and \(4.2\times0.0001=0.00042\). Always check both the direction of the decimal shift and the value obtained by expanding the power of ten.

Why Scientific Notation Matters

Scientific notation makes quantities easier to read, compare, and calculate. A value such as \(6.02\times10^{23}\) can be handled through its coefficient and exponent without writing all its zeros. The notation also communicates scale: \(10^{-6}\) represents one millionth, while \(10^6\) represents one million.

For measured quantities, the coefficient can also convey the precision of the reported value. The form \(3.2\times10^5\) and the form \(3.200\times10^5\) have the same numerical value, but the latter may indicate a more precise measurement when significant digits are being used. Scientific notation alone does not establish measurement precision; it is important to distinguish the written number from what is known about the measurement.

Key takeaway: Normalize a nonzero value as \(a\times10^n\) with \(1\leq |a|<10\). Use exponent laws for multiplication and division, align powers of ten before addition or subtraction, and check the coefficient as well as the exponent when interpreting scale.

Check Your Understanding

Try each question by writing out the intermediate steps and checking the final value.

  1. Write \(0.000091\) in normalized scientific notation.
  2. Write \(508{,}000{,}000\) in normalized scientific notation.
  3. Calculate \((2.5\times10^3)(4\times10^{-6})\) in normalized scientific notation.
  4. Calculate \(\dfrac{6.3\times10^{-4}}{2.1\times10^2}\) in normalized scientific notation.
  5. Which is larger, \(8\times10^7\) or \(2\times10^8\), and what is their ratio?

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