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Accumulation from Sums · Tutorial 899 of 1495

Signed Changes and Direction

Learn to assign signs by direction and combine interval changes into a signed accumulated total.

Beginner 8 min read

What You'll Learn

  • Choose and state a positive direction for a motion or flow model.
  • Interpret positive, negative, and zero interval changes.
  • Add signed contributions while keeping their units consistent.
  • Check a signed accumulation by tracking the quantity from its initial value.
  • Recognize and correct the error of subtracting an already negative contribution.

Direction Determines the Sign

When a quantity changes over several intervals, its changes may point in different directions. A number alone does not tell us which way a change points. We first choose a reference direction and use it consistently: changes in that direction are positive, and changes in the opposite direction are negative.

This convention lets a single addition represent changes that point both ways. For example, a vehicle that moves forward and then backward has a positive contribution for the forward motion and a negative contribution for the backward motion, if forward was chosen as positive. The signs are part of the information, not decoration.

Definition: A signed interval change is the change in a tracked quantity over one interval, recorded as positive if it points in the chosen positive direction, negative if it points in the opposite direction, and zero if there is no change in that quantity. A signed accumulated total is the sum of the signed interval changes over the intervals being considered.

The chosen positive direction is a convention. It can be “east,” “up,” or “into a tank,” for instance. What matters is that the convention is stated and applied consistently. Reversing the convention reverses every sign, including the sign of the accumulated total.

Adding Signed Contributions

Suppose a quantity has signed changes \(c_1,c_2,\ldots,c_n\) on successive intervals. The signed accumulated total is found by adding those values as they are written. A negative contribution is already negative; it is added using its sign. The total has the same units as the interval changes.

$$ \text{signed accumulated total} = c_1+c_2+\cdots+c_n $$

For instance, if the interval changes are \(+5\) metres, \(-2\) metres, and \(+1\) metre, the signed accumulated total is \(5+(-2)+1=4\) metres. The result is a directed change: it is positive in the chosen direction.

Keep three details clear as you calculate:

  • Direction: know which way has been assigned the positive sign.
  • Sign: record each interval change with the sign that follows from its direction.
  • Units: add quantities measured in compatible units, and carry those units through the calculation.

Why Signed Changes Add

The reason for keeping direction in the signs can be seen by tracking the quantity’s value from one interval to the next. Let its values at successive endpoints be \(x_0,x_1,\ldots,x_n\). The signed change on interval \(i\) is the later value minus the earlier value, \(x_i-x_{i-1}\). Adding these changes gives the overall directed change between the first and last values.

Result: If \(x_i\) is the value of a quantity at the end of interval \(i\), then the signed changes over consecutive intervals add to the final value minus the initial value.
1
Write each interval change.
The changes are \(x_1-x_0,\ x_2-x_1,\ldots,x_n-x_{n-1}\).
2
Add them in order.
Each intermediate endpoint appears once as an ending value and once as a starting value.
3
Cancel matching intermediate values.
The remaining terms are the final value \(x_n\) and the negative of the initial value \(-x_0\).

In full, this cancellation is:

$$ (x_1-x_0)+(x_2-x_1)+\cdots+(x_n-x_{n-1}) = x_n-x_0. $$

Every intermediate value cancels with the same value carrying the opposite sign. This explains why signed changes must be added with their signs intact: a change in the reverse direction moves the tracked value back in the opposite direction.

Worked Example: Motion Along a Straight Path

Worked Example: Motion Along a Straight Path

A cyclist’s signed position changes over three successive intervals are \(+3\) kilometres, \(+4\) kilometres, and \(-2\) kilometres. Take the forward direction as positive. Find the signed accumulated change, and check it by tracking the position from an initial position of \(10\) kilometres.

Step 1: Add the signed interval changes.

$$ (+3\text{ km})+(+4\text{ km})+(-2\text{ km}) $$

First, \(3+4=7\). Then, \(7+(-2)=5\). Thus the signed accumulated change is \(+5\) kilometres.

Step 2: Check by updating the position after each interval.

$$ 10\text{ km}+3\text{ km}=13\text{ km} $$
$$ 13\text{ km}+4\text{ km}=17\text{ km} $$
$$ 17\text{ km}+(-2\text{ km})=15\text{ km} $$

The cyclist ends at \(15\) kilometres, which is \(15-10=5\) kilometres in the positive direction from the starting position. This agrees with the signed accumulated change, \(+5\) kilometres.

Worked Example: Flow Into and Out of a Tank

Worked Example: Flow Into and Out of a Tank

For a tank, take flow into the tank as positive and flow out as negative. Over four intervals, the recorded changes in the amount of liquid are \(+12\) litres, \(-5\) litres, \(+8\) litres, and \(-3\) litres. Find the signed accumulated change. Check it if the tank initially contains \(40\) litres.

Step 1: Add the signed contributions, keeping the litre units.

$$ (+12\text{ L})+(-5\text{ L})+(+8\text{ L})+(-3\text{ L}) $$

In sequence, \(12+(-5)=7\), \(7+8=15\), and \(15+(-3)=12\). Therefore the signed accumulated change is \(+12\) litres.

Step 2: Check by updating the amount in the tank.

$$ 40\text{ L}+12\text{ L}=52\text{ L} $$
$$ 52\text{ L}+(-5\text{ L})=47\text{ L} $$
$$ 47\text{ L}+8\text{ L}=55\text{ L} $$
$$ 55\text{ L}+(-3\text{ L})=52\text{ L} $$

The final amount is \(52\) litres. Compared with the initial \(40\) litres, this is an increase of \(52-40=12\) litres, matching the signed accumulated change.

Worked Example: Reversing the Direction Convention

Worked Example: Reversing the Direction Convention

An elevator has signed position changes of \(+6\) metres, \(-9\) metres, and \(+4\) metres when upward is positive. Find the signed accumulated change. Then express the same motion using downward as positive and check that the two descriptions agree.

Step 1: Add the changes with upward positive.

$$ (+6\text{ m})+(-9\text{ m})+(+4\text{ m}) $$

First, \(6+(-9)=-3\). Then, \(-3+4=1\). The signed accumulated change is \(+1\) metre in the upward-positive convention.

Step 2: Reverse the convention. Each sign changes: \(+6\) metres becomes \(-6\) metres, \(-9\) metres becomes \(+9\) metres, and \(+4\) metres becomes \(-4\) metres. Therefore:

$$ (-6\text{ m})+(+9\text{ m})+(-4\text{ m}) $$

Calculating in order, \(-6+9=3\), and \(3+(-4)=-1\). The result is \(-1\) metre when downward is positive. This describes the same final position: one metre upward from the starting position is one metre in the negative direction under the downward-positive convention.

A Common Sign Mistake

A frequent error is to subtract a negative contribution a second time. Suppose the recorded changes are \(+8\) metres, \(-3\) metres, and \(+2\) metres, with the positive direction already specified. A mistaken calculation might be:

$$ 8-(-3)+2=13\text{ m}. $$

This is wrong because \(-3\) metres already records a change in the negative direction. Subtracting that negative value reverses its sign and treats the contribution as positive. The correct calculation adds each signed value:

$$ 8+(-3)+2=5+2=7\text{ m}. $$

A useful check is to ask whether each contribution’s sign matches the chosen direction before doing the arithmetic. Once a change has been recorded with its sign, add it as written.

Using the Convention Reliably

Signed accumulation is useful whenever a quantity can change in two opposite directions. In motion, the directions might be forward and backward or up and down. In a flow model, they might be into a container and out of it. A consistent sign convention lets these interval contributions be combined without losing their directional meaning.

Before adding, state the positive direction and confirm that every contribution refers to the same tracked quantity and uses compatible units. Then add the signed values in order and, when endpoint values are available, check that the result agrees with the final value minus the initial value. That check can reveal a missed negative sign, an inconsistent convention, or an arithmetic error.

Check Your Understanding

For each question, keep the chosen positive direction explicit and retain the signs of the interval changes.

  1. A cart has successive signed changes of \(+7\) metres, \(-4\) metres, and \(-2\) metres. What is its signed accumulated change?
  2. For a container, inward flow is positive. The interval changes are \(-6\) litres, \(+10\) litres, and \(-1\) litre. What is the signed accumulated change?
  3. A runner’s signed changes are \(+5\) kilometres and \(-3\) kilometres, with the forward direction positive. If the runner starts at position \(2\) kilometres, what is the final position, and how does it check the accumulated change?
  4. If a model’s positive direction is reversed, what happens to the sign of each contribution and to the sign of the accumulated total?
  5. Explain why \(+9\) metres followed by \(-4\) metres is added as \(9+(-4)\), rather than \(9-(-4)\).

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