Why the Significance Level Matters
A hypothesis test turns sample data into a decision: reject the null hypothesis or do not reject it. But a decision rule can sometimes reject \(H_0\) even when \(H_0\) is true. This possibility matters because a test is not judged only by what it decides in one sample; its rule can also be evaluated across repeated samples under specified conditions.
The significance level, written \(\alpha\), describes how often a testing procedure is allowed to make one particular error: rejecting a true null hypothesis. It is chosen as part of the procedure, before the data are used to decide whether to reject. The interpretation depends on holding that procedure fixed, including its sampling plan, statistical model, and rejection rule.
The phrase long-run probability is essential. Imagine repeating the same study many times under the same null condition and applying the same test rule each time. The fraction of those repetitions that reject a true \(H_0\) estimates the Type I error probability. The significance level controls that repeated-use behavior; it does not tell us the probability that a particular rejection is wrong after observing the data.
Decisions and Errors
Whether an error has occurred depends on two things: the test's decision and whether the null hypothesis is in fact true. A test cannot determine the truth directly; the outcomes in the table describe the possibilities that would be known only in principle.
| Truth about \(H_0\) | Decision: reject \(H_0\) | Decision: do not reject \(H_0\) |
|---|---|---|
| \(H_0\) is true | Type I error | Correct non-rejection |
| \(H_0\) is false | Correct rejection | Type II error |
This tutorial focuses on the first error. “Do not reject \(H_0\)” is a description of the decision, not proof that the null is true. Likewise, a rejection is not automatically a Type I error: it is a Type I error only in the situation where the null hypothesis really is true.
Significance Level as a Probability of the Rejection Rule
A test's rejection rule identifies which possible data outcomes lead to rejection. Under \(H_0\), the statistical model assigns probabilities to those outcomes. The Type I error probability is the probability that the data fall in the rejection region when the null condition holds.
For example, if a test rejects for large values of a statistic \(T\), then its Type I error probability at a specified null value is \(P(T\text{ is in the rejection region}\mid H_0\text{ is true})\). If \(H_0\) permits several parameter values, that probability may differ across them. A level-\(\alpha\) test keeps the probability at or below \(\alpha\) throughout the null parameter space. In some tests the maximum equals \(\alpha\); in others it is smaller.
Worked Example: A One-Sided Z Test at the Five Percent Level
Suppose a hypothetical process produces measurements with known population standard deviation \(\sigma=12\) units. A random sample of \(n=36\) independent measurements is taken. Assume the measurements follow a normal model and test \(H_0:\mu=100\) against \(H_a:\mu>100\). The fixed rule is to reject \(H_0\) when the one-sided Z statistic exceeds the 5% upper-tail critical value.
The assumptions for this calculation are that the observations are independent, the population standard deviation is known, and the normal model applies. Under \(H_0\), the sample mean has mean 100 and standard error \(12/\sqrt{36}=2\) units. Thus the test statistic under the null is standard normal:
The standard normal upper-tail critical value for a 5% test is approximately 1.645. Therefore, the procedure rejects when
If \(H_0\) is true, then \(\bar{x}\) has a normal distribution centered at 100 units with standard deviation 2 units. Consequently, the probability of rejecting a true null is
The procedure therefore has a 5% Type I error probability under the stated null model. In repeated samples from a process with mean 100 units, about 5% would be expected to cross this rejection threshold, subject to the model assumptions. This does not mean there is a 5% probability that \(H_0\) is true for any particular sample.
One-Sided and Two-Sided Rejection Regions
The alternative hypothesis determines where the rejection region lies. A one-sided test puts the rejection region in one tail; a two-sided test places it in both tails. The significance level is the total probability assigned to the rejection region when the null model holds. For a symmetric two-sided test, that probability is split between the two tails.
Worked Example: A Two-Sided Z Test at the One Percent Level
Consider a hypothetical measurement process with known \(\sigma=10\) units. A random sample of \(n=25\) independent observations is taken. Assume the population is normal. Test \(H_0:\mu=50\) against \(H_a:\mu\ne50\), using the fixed rule to reject for a two-sided Z statistic beyond the 1% critical values.
Under the null, the standard error is \(10/\sqrt{25}=2\) units. The assumptions of independent sampling, known standard deviation, and a normal population make the null distribution of the standardized sample mean standard normal. For a two-sided test with \(\alpha=0.01\), each tail has probability \(0.005\), and the critical values are approximately \(-2.576\) and \(2.576\). The rejection rule is
In terms of the sample mean, this is
When the null is true, the probability of falling into either rejection tail is
Thus, under the stated model, the rule has a 1% Type I error probability. It would be incorrect to count 1% in each tail: that would make the total probability of rejecting a true null approximately 2%.
Why a Test's Actual Error Rate Can Be Below Alpha
The outcomes of some tests are discrete: the statistic can take only separated values. In that case, it may be impossible to choose a rejection region whose null probability is exactly \(\alpha\). A standard level-\(\alpha\) procedure can instead use a rejection region whose probability is less than \(\alpha\). The difference between the stated level and the actual probability is not a contradiction; the level is an upper bound.
Worked Example: A Discrete Binomial Test
Suppose a hypothetical experiment consists of 10 independent trials, each with success probability \(p\). Test \(H_0:p=0.5\) against \(H_a:p>0.5\). Let \(X\) be the number of successes, so under the null \(X\sim\operatorname{Binomial}(10,0.5)\). The assumptions are a fixed 10 trials, independent outcomes, and the same success probability on each trial. Consider an upper-tail rule that rejects for sufficiently large \(X\), with a target significance level of 0.05.
If the rule rejects when \(X\ge 9\), its Type I error probability is
If the rule instead rejected for \(X\ge8\), the probability would be
The latter rule exceeds 0.05, while the former stays below it. With this upper-tail form, rejecting for \(X\ge9\) is the most inclusive of these two rules that controls the Type I error at 0.05. Its actual error probability is approximately 0.0107, not exactly 0.05. The gaps between possible values of \(X\) prevent this rule from using precisely the full 5% probability.
A Short Justification: Why the Tail Probability Is the Error Rate
The link between a rejection threshold and Type I error follows directly from the definition of the error and the probability model. Let \(R\) denote the event that the fixed rule rejects \(H_0\). When the null is true, a Type I error occurs exactly when \(R\) occurs. Therefore, at a particular null parameter value \(\theta\),
For a level-\(\alpha\) procedure, the design requirement is \(P(R\mid\theta)\le\alpha\) for every \(\theta\) allowed by the null. If the null is simple, it specifies one parameter value, so there is one probability to evaluate. If the null is composite, there can be several such probabilities; controlling their maximum ensures the bound holds throughout \(H_0\). This explains both why the rejection rule must be fixed and why the null model is needed: changing the rule or the model changes the probability of \(R\).
What Alpha Does—and Does Not—Say
The significance level describes a property of a testing procedure under a true null hypothesis. It is not a measure of the size or importance of an observed effect, and it is not a guarantee that a particular conclusion is correct. A 5% level means the procedure is designed so that its long-run Type I error rate is no greater than 5% under the null conditions.
A p-value answers a different question: assuming \(H_0\) and the model, it measures how unusual results at least as incompatible with \(H_0\) as the observed result would be. Comparing a p-value with a chosen \(\alpha\) determines whether the observed result falls in the test's rejection region when the test is built using that rule. Neither quantity is the probability that \(H_0\) is true. In particular, an \(\alpha\) of 0.05 does not mean that a rejection has a 5% chance of being a Type I error.
Common Mistakes
- Wrong: “Alpha is the probability that the null hypothesis is true.” Correction: Alpha is a probability of a rejection decision under the condition that the null is true; it does not assign a probability to the truth of the null.
- Wrong: “A 5% significance level means that 5% of this study's rejection is likely to be wrong.” Correction: The 5% describes long-run behavior over repetitions under the null, not the probability that a particular rejection is erroneous.
- Wrong: “A test at level 0.05 must have an actual Type I error probability of exactly 0.05.” Correction: The probability must be no greater than 0.05; discreteness or conservative procedures can make it smaller.
- Wrong: “A rejection is always a Type I error.” Correction: It is a Type I error only when \(H_0\) is actually true.
- Wrong: “A two-sided 5% test has 5% in each tail.” Correction: For a symmetric test, each tail contains 2.5%, so the total rejection probability under the null is 5%.
Check Your Understanding
Answer each question by referring to the decision rule and the null model.
- In your own words, define a Type I error. Which two facts must both hold for it to occur?
- A procedure has significance level 0.02. State what this means in repeated samples when the null hypothesis is true.
- Why can a discrete test designed at level 0.05 have an actual Type I error probability of 0.03?
- For a symmetric two-sided test with \(\alpha=0.10\), how is the null rejection probability divided between the tails?
- Explain why alpha is not the probability that a particular rejected null hypothesis is true.