From a Circle to an Ellipse
A circle can be parametrized using cosine and sine because \(\cos^2 t+\sin^2 t=1\). An ellipse with different horizontal and vertical semiaxis lengths has the same basic structure, but the two circular coordinates must be scaled separately. This gives a direct way to write parametrizations for ellipses in the coordinate planes and to control which part of an ellipse is traced.
The center of an ellipse determines where the curve is located. Its two positive semiaxis lengths determine how far it extends in each coordinate direction. The parameter interval then determines which points are traced and in what order.
Definition and General Forms
An axis-aligned ellipse in a coordinate plane is the curve whose equation, after shifting to its center, has the form \(u^2/a^2+v^2/b^2=1\), where \(a>0\) and \(b>0\). The positive numbers \(a\) and \(b\) are the semiaxis lengths in the respective coordinate directions. They need not be equal; if they are equal, the ellipse is a circle.
For a parametrization, the point on the curve is given by a vector-valued function \(\mathbf{r}(t)\). The following forms use \(t\) as the angle parameter. The center coordinates are added to the scaled cosine and sine components.
In each line, \(h\) and \(k\) are the center coordinates within the named plane. The first semiaxis \(a\) is along the first varying coordinate in that plane, and \(b\) is along the second varying coordinate. For example, in the \(xz\) plane, \(a\) measures the extent in the \(x\)-direction and \(b\) measures the extent in the \(z\)-direction. The fixed coordinate \(c\) determines which parallel coordinate plane contains the ellipse.
For a complete traversal, use \(0\le t\le 2\pi\). The points at \(t=0\) and \(t=2\pi\) coincide, so the endpoint is repeated. Other intervals can trace arcs; their choice also affects the direction of travel.
Why Separate Scaling Produces an Ellipse
The standard unit-circle parametrization is \(\langle \cos t,\sin t\rangle\). Its coordinates satisfy \(u^2+v^2=1\). Multiplying the first coordinate by \(a\) and the second by \(b\) changes this equation into the ellipse equation. Adding the center shifts the curve without changing its shape.
This argument shows both that every point produced by the parametrization lies on the ellipse and that the parametrization reaches every point of the ellipse over a complete cycle. It also explains why the scale factors belong to their respective coordinates: each normalized coordinate must divide by its own semiaxis length.
Worked Example: A Complete Ellipse in the \(xy\) Plane
Worked Example: A Complete Ellipse in the \(xy\) Plane
Parametrize the complete ellipse centered at \((1,-2,3)\), with semiaxis lengths \(4\) in the \(x\)-direction and \(2\) in the \(y\)-direction.
The curve lies in the plane \(z=3\). Scaling cosine by \(4\), sine by \(2\), and shifting by the center gives
To verify the trace, write its coordinates as \(x=1+4\cos t\), \(y=-2+2\sin t\), and \(z=3\). Then
Thus the parametrization lies on the required ellipse, whose equation is \((x-1)^2/16+(y+2)^2/4=1\) in \(z=3\). Sample values show how the curve is traversed:
The points are the rightmost, uppermost, leftmost, and lowermost points relative to the ellipse’s center, followed by the starting point again. The repeated endpoint confirms that the interval completes one traversal.
Choosing an Interval to Select an Arc
The parameter interval determines which angles are used. Because cosine and sine change sign in different quadrants, intervals such as \([0,\pi]\) and \([\pi,2\pi]\) select different halves for the standard ordering \(x=h+a\cos t,\ y=k+b\sin t\). On \([0,\pi]\), \(\sin t\ge 0\), so the parametrization stays on or above the center’s horizontal line. On \([\pi,2\pi]\), \(\sin t\le 0\), so it stays on or below that line.
The endpoints and direction should be checked rather than inferred from the interval name alone. Evaluate \(\mathbf{r}\) at both endpoints. To check which side of the ellipse is traced, inspect the signs of the relevant sine or cosine term throughout the interval. To check direction, compare the endpoint coordinates or use the derivatives of the component formulas.
Worked Example: The Lower Half from Largest \(y\) to Smallest \(y\)
Worked Example: The Lower Half from Largest \(y\) to Smallest \(y\)
Parametrize the lower half of the ellipse centered at \((0,2,-1)\) in the \(yz\) plane, with \(y\)-semiaxis \(2\) and \(z\)-semiaxis \(5\). The requested direction is from the point with largest \(y\)-coordinate to the point with smallest \(y\)-coordinate.
Here \(x=0\), while the varying coordinates are \(y=2+2\cos t\) and \(z=-1-5\sin t\). Choose \(0\le t\le\pi\). Then
Substitution verifies that the trace is on the ellipse:
On this interval, \(\sin t\ge 0\), so \(z=-1-5\sin t\le -1\). This is the lower half relative to the center’s \(z\)-coordinate, as required. At the endpoints,
These are respectively the largest and smallest \(y\)-coordinates on the ellipse. For \(0<t<\pi\), the derivative of the \(y\)-coordinate is \(dy/dt=-2\sin t<0\), so \(y\) decreases throughout the interior of the interval. At the midpoint,
This point is below the center, confirming the chosen half. The endpoint order and the decreasing \(y\)-coordinate confirm the requested direction.
Worked Example: A Quarter-Ellipse in the \(xz\) Plane
Worked Example: A Quarter-Ellipse in the \(xz\) Plane
Parametrize the quarter of the ellipse centered at \((-1,0,2)\) in the plane \(y=0\) for which \(x\ge -1\) and \(z\ge 2\). Let its semiaxis lengths be \(4\) in the \(x\)-direction and \(3\) in the \(z\)-direction.
Using cosine for the \(x\)-displacement and sine for the \(z\)-displacement gives
For \(0\le t\le\pi/2\), both \(\cos t\) and \(\sin t\) are nonnegative. Therefore \(x\ge -1\) and \(z\ge 2\), so the interval selects the requested quarter. The ellipse equation is verified directly:
The endpoints are
As an intermediate check, at \(t=\pi/4\) the point is
Its normalized displacements are \(\sqrt{2}/2\) and \(\sqrt{2}/2\), whose squares sum to \(1/2+1/2=1\). Thus this sample point also satisfies the ellipse equation. Increasing \(t\) moves the parametrization from the rightmost endpoint toward the uppermost endpoint of this quarter.
A Common Scaling Error
A frequent mistake is to put a semiaxis length in the denominator of the wrong squared coordinate. For example, the parametrization \(x=2\cos t,\ y=5\sin t\) has semiaxis \(2\) in the \(x\)-direction and semiaxis \(5\) in the \(y\)-direction. Its equation is \(x^2/4+y^2/25=1\), not \(x^2/25+y^2/4=1\).
The incorrect equation fails even at the parameter value \(t=0\): the parametrization gives \((x,y)=(2,0)\), and substitution into the incorrect equation gives \(2^2/25+0^2/4=4/25\ne1\). In the correct equation, the same point gives \(2^2/4+0^2/25=1\). The denominator for each coordinate must be the square of that coordinate’s semiaxis length.
Another interval error is to use \([0,\pi]\) automatically for a lower half. With \(y=k+b\sin t\), that interval gives \(y\ge k\), which is the upper half. The sign in the component formula matters: in the second worked example, the lower half is selected because \(z=-1-5\sin t\), not \(-1+5\sin t\). Checking the component formula and endpoints prevents both interval and direction errors.
Why This Construction Is Useful
Separate scaling makes an ellipse parametrization nearly as direct as a circle parametrization. It identifies the center, the two semiaxis lengths, the containing coordinate plane, and the traversal order in a single vector-valued function. The same verification works in each coordinate plane: subtract the center coordinates, divide by the corresponding semiaxis lengths, and use \(\cos^2 t+\sin^2 t=1\).
For a complete ellipse, use an interval of length \(2\pi\), such as \([0,2\pi]\). For a half or quarter, choose endpoints that delimit the desired angle range, then verify the resulting points and signs. When direction is specified, also check the endpoint order; an interval that traces the right arc can still travel in the wrong direction.
Check Your Understanding
For each question, identify the center, semiaxis directions, trace, and interval behavior as appropriate.
- Write a complete parametrization for the ellipse \((x-3)^2/9+(y+1)^2/4=1\) in the plane \(z=2\).
- For \(x=4\cos t,\ z=1+3\sin t\) in the plane \(y=0\), which half is traced on \(0\le t\le\pi\)?
- For an ellipse with \(y\)-center \(5\) and \(y\)-semiaxis \(2\), what is its largest \(y\)-coordinate?
- What are the endpoints of \(\mathbf{r}(t)=\langle 0,1+3\cos t,2+4\sin t\rangle\) on \(0\le t\le\pi/2\)?
- Explain why the equation \(x^2/a^2+y^2/b^2=1\) follows from \(x=a\cos t,\ y=b\sin t\), assuming \(a,b>0\).