Why Combine Vectors?
A single directed quantity can describe one change in position, but many situations involve several changes acting together. A traveler may repeat one movement, then follow another, and then reverse a third. A geometric construction may combine several directed steps into one overall displacement. In each case, the calculation has two parts: scale vectors by numbers, then add the results.
An expression built this way is called a linear combination. The idea is simple, but careful component-by-component work matters: each coordinate must be scaled and added with its own signs intact.
The coefficients specify how each vector contributes. A coefficient of \(2\) means twice that vector; a coefficient of \(-1\) means its negative; and a coefficient of \(0\) means that vector contributes nothing. The result is still a vector in three-dimensional space.
Compute by Components
Write each vector as an ordered triple. If \(\mathbf{u}=(u_1,u_2,u_3)\), then multiplying by a real number \(a\) scales each component by \(a\). Vector addition adds corresponding components. Applying those operations to three vectors gives a direct calculation rule:
This rule is useful because it organizes the arithmetic by coordinate. First scale each vector, then add the first components together, the second components together, and the third components together. Do not add components from different positions in the triples.
Worked Example: Evaluate a Linear Combination
Let \(\mathbf{u}=(2,-1,3)\), \(\mathbf{v}=(-1,4,0)\), and \(\mathbf{w}=(3,2,-2)\). Evaluate \(2\mathbf{u}-\mathbf{v}+3\mathbf{w}\).
Scale the vectors by their coefficients. In particular, the coefficient of \(\mathbf{v}\) is \(-1\), so its contribution is \(-\mathbf{v}\):
Add corresponding components:
Check each coordinate directly from the component formula. The first is \(2(2)-(-1)+3(3)=4+1+9=14\). The second is \(2(-1)-4+3(2)=-2-4+6=0\). The third is \(2(3)-0+3(-2)=6+0-6=0\). The computed vector is therefore \((14,0,0)\).
Why the Component Formula Works
The component rule is not a separate trick. It follows from the definitions of scalar multiplication and vector addition. For triples, scalar multiplication acts on every coordinate, and addition combines matching coordinates. Applying those definitions in sequence gives the full formula.
From \(\mathbf{u}=(u_1,u_2,u_3)\), scalar multiplication gives \(a\mathbf{u}=(au_1,au_2,au_3)\), and likewise for the other vectors.
By componentwise vector addition, \(a\mathbf{u}+b\mathbf{v}=(au_1+bv_1,au_2+bv_2,au_3+bv_3)\).
Adding \(c\mathbf{w}=(cw_1,cw_2,cw_3)\) adds \(cw_i\) to the \(i\)th component, for \(i=1,2,3\). This yields the stated formula.
Thus the rule holds for every choice of real coefficients and three-dimensional vectors: each coordinate of the result is the same linear combination of the corresponding coordinates. The reasoning depends only on the definitions of scalar multiplication and vector addition; no assumptions about the particular values or directions of the vectors are needed.
Directed Movements as Linear Combinations
When vectors represent directed movements, coefficients describe how those movements are used. A positive integer coefficient can represent repeating a movement that many times. A negative coefficient reverses its direction as well as scaling it. A fractional coefficient represents a corresponding fraction of the directed vector. If several movements are carried out consecutively, their total displacement is the sum of their displacement vectors.
Worked Example: Combine Movements Along a Route
Suppose three directed movements are \(\mathbf{A}=(3,-2,1)\) metres, \(\mathbf{B}=(-1,4,2)\) metres, and \(\mathbf{C}=(0,1,-3)\) metres. A route uses two copies of \(\mathbf{A}\), one copy of \(\mathbf{B}\), and the reverse of \(\mathbf{C}\). The combined displacement is \(2\mathbf{A}+\mathbf{B}-\mathbf{C}\).
Scale each movement, noting that reversing \(\mathbf{C}\) changes the signs of all its components:
Add the movements coordinate by coordinate:
Check the coordinates from the original movements. The first component is \(2(3)+(-1)-0=5\) metres. The second is \(2(-2)+4-1=-1\) metre. The third is \(2(1)+2-(-3)=7\) metres. The total displacement is \((5,-1,7)\) metres.
The result summarizes the combined directed change. It does not list the individual steps of the route; it records their net effect in a single vector. This interpretation is valid because vector addition combines displacements, while scalar multiplication accounts for repetition, reversal, or scaling.
Parentheses and Signs
Linear combinations often include parentheses, especially when one vector is subtracted from another. The distributive rule applies to vectors: multiplying a sum or difference by a scalar means multiplying each term by that scalar. In particular, a negative coefficient changes the sign of every component in the vector it multiplies.
Worked Example: Expand Before Computing
Let \(\mathbf{u}=(1,-2,0)\), \(\mathbf{v}=(3,1,-1)\), and \(\mathbf{w}=(-2,0,4)\). Evaluate \(-2(\mathbf{u}-\mathbf{v})+3\mathbf{w}\).
First compute the vector difference:
Multiply this result by \(-2\), then compute the other scaled vector:
Add the two results:
Check by expanding first. Distributing \(-2\) gives \(-2\mathbf{u}+2\mathbf{v}+3\mathbf{w}\). Its three scaled vectors are \((-2,4,0)\), \((6,2,-2)\), and \((-6,0,12)\). Their sum is \((-2+6-6,\;4+2+0,\;0-2+12)=(-2,6,10)\), agreeing with the earlier result.
A Geometric Construction from Directed Steps
A geometric construction can be described by the same calculation. Imagine starting at a point and carrying out directed steps represented by \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\). If the construction uses three copies of \(\mathbf{u}\), two copies of \(\mathbf{v}\), and the reverse of \(\mathbf{w}\), the overall directed change is \(3\mathbf{u}+2\mathbf{v}-\mathbf{w}\). The vector sum combines these steps regardless of the order in which the component arithmetic is organized.
For example, take \(\mathbf{u}=(1,2,-1)\), \(\mathbf{v}=(0,-1,3)\), and \(\mathbf{w}=(2,1,1)\). Then
As a check, the first component is \(3(1)+2(0)-2=1\); the second is \(3(2)+2(-1)-1=3\); and the third is \(3(-1)+2(3)-1=2\). The combined directed step is \((1,3,2)\). This example shows how a geometric description can be translated into a precise vector expression and then evaluated.
Common Pitfall: Negating Only Part of a Vector
A frequent error is to treat a negative coefficient as if it affected only one component. For instance, if \(\mathbf{v}=(-1,4,0)\), then \(-\mathbf{v}\) is not \((1,4,0)\). The negative sign multiplies every component:
Another sign error can occur when a coefficient multiplies a difference. The incorrect calculation \(-2(\mathbf{u}-\mathbf{v})=-2\mathbf{u}-2\mathbf{v}\) fails to distribute the negative coefficient correctly. The correct expansion is
because \(-2\) multiplies both \(\mathbf{u}\) and \(-\mathbf{v}\). A reliable check is to compute the vector in parentheses first, scale its three components, and compare that result with any expanded calculation.
A Reliable Calculation Routine
For a linear combination with several terms, use a consistent order of work. Keep each vector’s components together while scaling, and only then add corresponding coordinates. If the expression contains parentheses, either evaluate them first or expand carefully; both routes should agree. Finally, verify each output component against the original coefficients and input components.
Check Your Understanding
Work through these questions by writing out the scaled vectors and showing the component arithmetic.
- If \(\mathbf{p}=(2,0,-1)\) and \(\mathbf{q}=(-1,3,2)\), what is \(2\mathbf{p}-\mathbf{q}\)?
- For \(\mathbf{a}=(1,-2,3)\), \(\mathbf{b}=(0,4,-1)\), and \(\mathbf{c}=(2,1,0)\), evaluate \(\mathbf{a}+2\mathbf{b}-3\mathbf{c}\).
- What does a coefficient of \(-1\) mean when a vector represents a directed movement?
- Expand \(3(\mathbf{u}-\mathbf{v})+2\mathbf{w}\) as a sum of scalar multiples of the individual vectors.
- What component-by-component check can you use to verify a computed linear combination?