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Linearization and Differentials · Tutorial 626 of 1495

Unit Conversion And Measurement Uncertainty

Convert a measured value and its uncertainty together, accounting for scale factors and offsets in the unit conversion.

Intermediate 9 min read

What You'll Learn

  • Convert a measurement with a linear formula of the form y = ax + b.
  • Transform an absolute uncertainty by the magnitude of the conversion scale factor.
  • Explain why an offset changes the measured value but not its absolute uncertainty.
  • Check converted measurements by converting both endpoints of their uncertainty interval.
  • Distinguish absolute uncertainty from relative uncertainty when units change.

Why Convert the Uncertainty Too?

A measurement is not just a number. It also has a unit and, often, an uncertainty that describes how far the actual value could be from the reported value. If a thermometer reports \(68\pm1.8^\circ\mathrm{F}\), converting only the number \(68\) to Celsius does not give a complete converted measurement. The uncertainty must be expressed in Celsius as well.

The important distinction is between a scale factor and an offset. A scale factor changes the size of a difference between two measurements. An offset shifts all measurements by the same amount, so it changes the reported value but not the size of its uncertainty. This tutorial develops that distinction for linear unit conversions and checks it with concrete measurements.

Measurements and Linear Conversions

Suppose a measurement in one unit is reported as \(x_0\pm\Delta x\), where \(x_0\) is the reported central value and \(\Delta x\geq0\) is its absolute uncertainty in the same unit. When the uncertainty is being used as a bound, this notation means that the value lies in the interval from \(x_0-\Delta x\) to \(x_0+\Delta x\).

A linear conversion between the numerical values in two units has the form \(y=ax+b\), where \(a\) and \(b\) are constants. The corresponding converted measurement is \(y_0=ax_0+b\). The uncertainty in the converted value is \(|a|\Delta x\), not \(a\Delta x+b\). The absolute value is needed because uncertainty is nonnegative even when the conversion reverses order.

Rule for a linear unit conversion: If \(y=ax+b\), then a measurement \(x_0\pm\Delta x\) converts to \(ax_0+b\pm |a|\Delta x\). The uncertainty is multiplied by the magnitude of the scale factor; the offset is not applied to it.

The units must be carried through each calculation. If \(a\) converts the numerical value in units \(U\) to the numerical value in units \(V\), then \(a\Delta x\) is an uncertainty in \(V\). The offset \(b\) is also expressed in the numerical scale for \(V\).

Why the Offset Does Not Affect Absolute Uncertainty

The rule follows directly from comparing the converted central value with a possible value at either edge of the original uncertainty interval. The two endpoints in the original unit are \(x_0-\Delta x\) and \(x_0+\Delta x\). Under \(y=ax+b\), their converted values are \(a(x_0-\Delta x)+b\) and \(a(x_0+\Delta x)+b\). Subtracting the converted central value \(ax_0+b\) gives deviations of \(-a\Delta x\) and \(a\Delta x\). Their magnitudes are both \(|a|\Delta x\).

$$ \begin{aligned} \bigl|a(x_0+\Delta x)+b-(ax_0+b)\bigr| &=|a\Delta x|\\ &=|a|\Delta x. \end{aligned} $$

The same conclusion holds if \(a<0\): the endpoints exchange order, but their distances from the converted central value are still \(|a|\Delta x\). Thus the transformed interval has the converted central value as its midpoint and \(|a|\Delta x\) as its half-width. This is an exact result for an affine conversion, not a first-order approximation.

If \(\Delta x\) represents a standard uncertainty rather than a guaranteed bound, the same scale rule applies to the standard deviation under the affine transformation \(y=ax+b\): adding a constant shifts the distribution without changing its spread, and multiplying by \(a\) scales the spread by \(|a|\). The interpretation of the uncertainty should still be stated when it matters.

Worked Examples

Worked Example: Fahrenheit to Celsius

A temperature is measured as \(68\pm1.8^\circ\mathrm{F}\). Convert both the temperature and its absolute uncertainty to Celsius. The conversion formula is \(C=\frac{5}{9}(F-32)\).

First convert the central value. Since \(68-32=36\),

$$ C_0=\frac{5}{9}(68-32) =\frac{5}{9}(36) =20^\circ\mathrm{C}. $$

The conversion has scale factor \(a=\frac{5}{9}\) and offset \(-\frac{160}{9}\), since \(C=\frac{5}{9}F-\frac{160}{9}\). The absolute uncertainty is therefore multiplied by \(\left|\frac{5}{9}\right|\):

$$ \Delta C=\frac{5}{9}(1.8^\circ\mathrm{F}) =\frac{5}{9}\left(\frac{9}{5}^\circ\mathrm{F}\right) =1^\circ\mathrm{C}. $$

So the converted measurement is \(20\pm1^\circ\mathrm{C}\). Check by converting the endpoints. The lower Fahrenheit endpoint is \(68-1.8=66.2^\circ\mathrm{F}\), and the upper endpoint is \(68+1.8=69.8^\circ\mathrm{F}\). Their Celsius conversions are

$$ \frac{5}{9}(66.2-32) =\frac{5}{9}(34.2) =19^\circ\mathrm{C}, \qquad \frac{5}{9}(69.8-32) =\frac{5}{9}(37.8) =21^\circ\mathrm{C}. $$

The converted interval is \(19^\circ\mathrm{C}\) to \(21^\circ\mathrm{C}\), exactly one degree on either side of \(20^\circ\mathrm{C}\), confirming the uncertainty calculation.

Worked Example: Centimetres to Inches

A length is reported as \(12.0\pm0.2\) centimetres. Use the exact conversion \(1\text{ inch}=2.54\text{ centimetres}\) to express the result in inches.

To convert centimetres to inches, divide the numerical value and its uncertainty by \(2.54\). The central value is

$$ x_0=\frac{12.0\text{ cm}}{2.54\text{ cm/in}} =\frac{600}{127}\text{ in} \approx4.72441\text{ in}. $$

Here the conversion is a pure scale change, with no offset. Convert the uncertainty by the same positive scale factor:

$$ \Delta x =\frac{0.2\text{ cm}}{2.54\text{ cm/in}} =\frac{10}{127}\text{ in} \approx0.0787402\text{ in}. $$

The converted measurement is therefore \(\frac{600}{127}\pm\frac{10}{127}\) inches, or approximately \(4.72441\pm0.0787402\) inches. For an exact check, the original endpoints are \(12.0-0.2=11.8\) cm and \(12.0+0.2=12.2\) cm. They convert to

$$ \frac{11.8}{2.54}\text{ in} =\frac{590}{127}\text{ in}, \qquad \frac{12.2}{2.54}\text{ in} =\frac{610}{127}\text{ in}. $$

Since \(\frac{590}{127}=\frac{600}{127}-\frac{10}{127}\) and \(\frac{610}{127}=\frac{600}{127}+\frac{10}{127}\), these endpoints confirm the converted central value and uncertainty.

Worked Example: Kilometres per Hour to Metres per Second

A speed is measured as \(72\pm3\) kilometres per hour. Convert it to metres per second. From the unit definitions,

$$ 1\text{ km/h} =\frac{1000\text{ m}}{3600\text{ s}} =\frac{5}{18}\text{ m/s}. $$

This is again a pure scale conversion. The central speed is

$$ v_0 =72\text{ km/h}\cdot\frac{5}{18}\frac{\text{m/s}}{\text{km/h}} =20\text{ m/s}. $$

Apply the magnitude of the same factor to the uncertainty:

$$ \Delta v =3\text{ km/h}\cdot\frac{5}{18}\frac{\text{m/s}}{\text{km/h}} =\frac{5}{6}\text{ m/s}. $$

Thus the converted measurement is \(20\pm\frac{5}{6}\text{ m/s}\). Check the endpoints: \(72-3=69\) km/h and \(72+3=75\) km/h. Converting them gives

$$ 69\cdot\frac{5}{18} =\frac{115}{6} =20-\frac{5}{6}\text{ m/s}, \qquad 75\cdot\frac{5}{18} =\frac{125}{6} =20+\frac{5}{6}\text{ m/s}. $$

The endpoint check agrees exactly with the converted central value and uncertainty.

Absolute and Relative Uncertainty Are Not the Same

Absolute uncertainty is expressed in the same units as the measurement. For example, \(20\pm1^\circ\mathrm{C}\) has an absolute uncertainty of \(1^\circ\mathrm{C}\). Relative uncertainty compares the absolute uncertainty with the magnitude of the reported value; when the reported value is nonzero, it is \(\frac{\Delta x}{|x_0|}\). These two kinds of uncertainty do not always behave the same way under conversion.

Under a pure scale conversion \(y=ax\), with \(a\ne0\), both the measurement magnitude and absolute uncertainty are multiplied by \(|a|\). Their ratio is unchanged. Under an affine conversion \(y=ax+b\) with a nonzero offset, the absolute uncertainty still becomes \(|a|\Delta x\), but the converted central value is \(ax_0+b\). Consequently, the relative uncertainty can change. This is why a Celsius-to-Fahrenheit conversion preserves neither the numerical temperature nor, in general, its relative uncertainty.

Key takeaway: Offsets change the central value, not the absolute uncertainty. Scale factors change the absolute uncertainty by their magnitude. Relative uncertainty must be recalculated from the converted value and converted absolute uncertainty.

A Common Conversion Mistake

A frequent error is to apply the entire temperature formula, including its offset, to the uncertainty. For example, for Fahrenheit-to-Celsius conversion, the incorrect calculation might be written

$$ \Delta C_{\text{wrong}} =\frac{5}{9}(1.8-32) =-\frac{151}{9}^\circ\mathrm{C}. $$

This is wrong for two reasons. An uncertainty is a distance, so it cannot be negative, and subtracting \(32\) makes no sense for a distance between two temperatures. The correct conversion uses only the scale factor:

$$ \Delta C =\left|\frac{5}{9}\right|(1.8^\circ\mathrm{F}) =1^\circ\mathrm{C}. $$

The offset disappears because it is added to both the central temperature and each possible temperature. Their differences are unaffected by adding the same constant.

A Reliable Procedure

For a measurement reported with an absolute uncertainty, the following sequence keeps the conversion and its uncertainty consistent:

1
Write the conversion formula.
Identify its scale factor \(a\) and any offset \(b\), including the units involved.
2
Convert the central value.
Evaluate \(ax_0+b\), retaining the target unit.
3
Convert the absolute uncertainty.
Evaluate \(|a|\Delta x\); do not apply the offset.
4
Check the result.
Convert \(x_0-\Delta x\) and \(x_0+\Delta x\), then confirm that the resulting distances from the converted central value equal the converted uncertainty.

This procedure matters whenever converted measurements are compared, reported, or used in later calculations. A correct central value paired with an uncertainty in the wrong unit can give a misleading impression of precision. For a linear conversion, the uncertainty transformation is simple and exact, provided the conversion formula and units are handled consistently.

Check Your Understanding

For each question, identify the scale factor and decide whether the conversion has an offset before calculating.

  1. A length is \(4.0\pm0.1\) metres. Convert both the value and its absolute uncertainty to centimetres using \(1\text{ m}=100\text{ cm}\).
  2. In a conversion \(y=3x-7\), what is the converted absolute uncertainty if \(x\) has uncertainty \(0.2\)? Explain why the \(-7\) is not used.
  3. A temperature is \(50\pm2^\circ\mathrm{F}\). Using \(C=\frac{5}{9}(F-32)\), find its converted central value and absolute uncertainty in Celsius.
  4. Why can an offset change relative uncertainty even though it does not change absolute uncertainty except through the scale factor?
  5. What endpoint calculation can you use to check a converted measurement written as a central value plus or minus an uncertainty?

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