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Independence and unions · Tutorial 281 of 1000

What Independent Events Mean

See how independence describes whether knowing one event occurred changes the chance of another, using coin flips and draws with and without replacement.

Beginner 9 min read

What You'll Learn

  • Explain independence as one event not changing the probability of another.
  • Compare an event’s original probability with its probability after another event is known to have occurred.
  • Show why two separate fair coin flips are independent.
  • Show why draws without replacement are often dependent.
  • Distinguish independence from mutual exclusivity and from a claim about cause and effect.

What Does Independence Mean?

When two events are independent, knowing that one occurred does not change the probability of the other. This idea is about information: learning the result of one event gives you no reason to revise the chance you assigned to the other. Coin flips provide a familiar example. After a fair coin lands heads, the next flip is still just as likely to be heads as it was before.

That is different from drawing items from a group without replacement. If you draw a red token and keep it out of the group, there are fewer red tokens left for the next draw. The first result changes the makeup of the group, so it can change the probability of a red token on the next draw.

In What Conditional Probability Means, you learned that \(P(B\mid A)\) describes the probability of \(B\) among outcomes where \(A\) occurred. That notation gives us a practical way to think about independence: compare the probability of an event before and after learning that another event occurred. If learning the first event leaves the probability of the second unchanged, the events are independent.

Definition: Events \(A\) and \(B\) are independent when the occurrence of one event does not change the probability of the other. If knowing that \(A\) occurred changes the chance of \(B\), the events are dependent.

As covered in Mutually Exclusive Versus Independent Events, independence can also be described by the product rule \(P(A\cap B)=P(A)P(B)\). We will use that established rule as a check in some examples, but the main idea here is the meaning: one event does not alter the chance of the other.

Independence is not about whether events are related in everyday language or whether they happen at the same time. It is a statement about probabilities in a particular chance process. To assess it, identify the events and ask what information the occurrence of one event provides about the chance of the other.

Compare the Chance Before and After

A helpful routine is to find the original probability of the event you care about, then find its conditional probability given the other event. The original probability uses the full chance process. The conditional probability uses the reduced group of outcomes where the condition occurred. If the two probabilities match, the condition has not changed the chance in that comparison.

Be precise about which probability is being compared. For example, \(P(B)\) is the probability of \(B\) before restricting attention to cases where \(A\) occurred. The probability \(P(B\mid A)\) is the chance of \(B\) among the outcomes where \(A\) did occur. These quantities answer related but different questions.

How to check in context: Define the two events. Find the original probability of one event, then find its probability given that the other event occurred. Explain whether the chance changed and what feature of the chance process accounts for that result.

If it is convenient, you can also check the product rule from the earlier tutorial: calculate \(P(A\cap B)\) and compare it with \(P(A)P(B)\). The product rule is a useful numerical check; the comparison of original and conditional probabilities helps explain what independence means in the situation.

Worked Example: Two Fair Coin Flips

Worked Example: Two Fair Coin Flips

A fair coin is flipped twice. Let \(A\) be the event that the first flip is heads, and let \(B\) be the event that the second flip is heads. Are \(A\) and \(B\) independent?

Identify the comparison: The original probability that the second flip is heads is \(P(B)=1/2\). To see whether the first result changes that chance, find the probability that the second flip is heads given that the first flip was heads.

Calculate: The equally likely outcomes for the two flips are HH, HT, TH, and TT. If the first flip was heads, only HH and HT remain possible. One of those two outcomes has heads on the second flip.

$$ P(B\mid A)=\frac{1}{2} $$

Thus \(P(B\mid A)=P(B)=1/2\): learning that the first flip was heads does not change the probability of heads on the second flip. The results come from separate flips, and the coin is not altered by the first result. So \(A\) and \(B\) are independent.

The product rule gives the same conclusion. Only HH has heads on both flips, so \(P(A\cap B)=1/4\). Also \(P(A)P(B)=(1/2)(1/2)=1/4\). The intersection probability agrees with the product of the individual probabilities.

Conclusion: The event that the first flip is heads and the event that the second flip is heads are independent. Both can happen together, and knowing the first result does not change the chance of the second result.

Worked Example: Drawing Without Replacement

Worked Example: Drawing Without Replacement

A bag contains 5 red tokens and 3 blue tokens. Two tokens are drawn one at a time without replacement. Let \(A\) be the event that the first token is red, and \(B\) the event that the second token is red. Are \(A\) and \(B\) independent?

Find the original probability: Before any token is drawn, 5 of the 8 tokens are red. Therefore, the chance that the second token is red, considered without knowing the first result, is \(5/8\). Each of the 8 tokens is equally likely to be in the second position.

Find the conditional probability: If the first token is red, the bag now has 4 red tokens among 7 remaining tokens. The second token is selected from those 7.

$$ P(B\mid A)=\frac{4}{7}\approx 0.5714 $$

The original probability is \(P(B)=5/8=0.625\). The conditional probability is about \(0.5714\), which is less than \(0.625\). Knowing that the first token was red lowers the chance that the second token is red. Thus, \(A\) and \(B\) are dependent.

The product rule confirms the comparison. The probability of a red token on the first draw is \(5/8\). Given a red first token, the probability of a red second token is \(4/7\), so

$$ P(A\cap B)=\frac{5}{8}\cdot\frac{4}{7} =\frac{5}{14}\approx 0.3571 $$

But the product of the two original probabilities is

$$ P(A)P(B)=\frac{5}{8}\cdot\frac{5}{8} =\frac{25}{64}\approx 0.3906 $$

These results differ, which is consistent with the events being dependent. The key feature is not simply that two draws occur. It is that the first token is kept out of the bag, changing the contents available for the second draw.

Conclusion: The events that the first and second tokens are red are dependent. In this situation, learning the first token was red changes the probability that the second token is red.

Worked Example: Drawing With Replacement

Worked Example: Drawing With Replacement

Use the same bag of 5 red and 3 blue tokens, but now return the first token to the bag and mix the tokens before the second draw. Let \(R_1\) be the event that the first token is red and \(R_2\) the event that the second token is red. Are these events independent?

Before either draw, the probability of red is \(5/8\). If the first token is red, it is returned to the bag. The bag again contains 5 red tokens and 3 blue tokens, so the chance of red on the second draw is still \(5/8\):

$$ P(R_2)=\frac{5}{8} \qquad\text{and}\qquad P(R_2\mid R_1)=\frac{5}{8} $$

Because the conditional probability matches the original probability, learning that the first token was red does not change the chance of red on the second draw. The events are independent in this model.

The product-rule check also matches. The probability of two red draws is

$$ P(R_1\cap R_2)=\frac{5}{8}\cdot\frac{5}{8} =\frac{25}{64} $$

The product of the individual probabilities is also \((5/8)(5/8)=25/64\). Returning and mixing the token restores the original group before the next draw, so the first draw does not change the second draw’s red probability.

Conclusion: The events that the first and second tokens are red are independent when the first token is replaced before the second draw. The replacement is what makes this process different from drawing without replacement.

Independence Is Not the Same as Mutual Exclusivity

In What Mutually Exclusive Events Mean, you learned that mutually exclusive events cannot occur together. Independence is different: it concerns whether knowing one event occurred changes the probability of the other. Two events can occur together and still be independent, as the two-heads coin-flip example shows.

In fact, if two events have positive probabilities and are mutually exclusive, they are dependent. If \(A\) occurs, then \(B\) cannot occur, so the probability of \(B\) given \(A\) is 0. That is different from the original positive probability of \(B\). Mutually exclusive events with positive probabilities therefore do not meet the meaning of independence.

Do not conclude that events are independent just because they are different events, occur in sequence, or sound unrelated. Nor does dependence necessarily mean that one event causes the other. The events may be connected because the chance process changes after the first event, as with drawing without replacement, or because both outcomes are influenced by some feature of the process.

Common Mistakes and AP Exam Tips

  • Assuming every sequence of trials is independent. Trials such as coin flips can be independent, but drawing items without replacement generally changes the probabilities from draw to draw. Check what happens to the process after the first result.
  • Comparing the wrong probabilities. To assess whether learning \(A\) changes the chance of \(B\), compare \(P(B)\) with \(P(B\mid A)\). State what each number describes so the comparison is clear.
  • Calling events independent because they can happen together. Overlap alone does not establish independence. Independent events may overlap, but you must still check whether one event changes the probability of the other.
  • Calling events independent because they cannot happen together. That describes mutually exclusive events. If each event has positive probability, mutual exclusivity means that occurrence of one rules out the other, so the events are dependent.
  • Giving only a yes-or-no answer. A strong response supports the conclusion with the probability comparison and a contextual explanation, such as “the first red token is not replaced, so fewer red tokens remain.”
  • Treating independence as cause and effect. Independence describes a probability relationship. It does not, by itself, tell you whether one event causes another.

On an AP response, name both events, show the relevant probabilities, and explain what the comparison means in context. For example: “The probability of a red second token is \(5/8\) before knowing the first result, but it is \(4/7\) given a red first token. Since those probabilities differ, the events are dependent; removing the first red token changes the bag’s contents.”

AP Exam Tip: Make the evidence for your conclusion visible. State the original probability, the probability given the other event, and whether learning the condition changed the chance. Then connect that change—or lack of change—to the chance process.

Key Takeaway

Independence is about whether one event changes the probability of another. Separate fair coin flips are independent because the first result does not alter the chance of the second. Draws without replacement are often dependent because the first draw changes what remains. When deciding, define the events and compare the original probability with the probability given that the other event occurred.

Key takeaway: Events are independent when knowing that one occurred does not change the probability of the other. Focus on the probabilities in the chance process, not simply on whether the events happen at different times or can occur together.

Check Your Understanding

For each situation, decide whether the named events are independent or dependent. Support your decision by explaining whether knowing one event occurred changes the probability of the other.

  1. A fair six-sided die is rolled twice. Let \(A\) mean the first roll is a 2 and \(B\) mean the second roll is a 2. Explain why the two events are independent or dependent.
  2. A box contains 4 green and 6 yellow counters. Two counters are selected without replacement. Let \(G_1\) and \(G_2\) mean the first and second counters are green. Compare the original probability of \(G_2\) with \(P(G_2\mid G_1)\).
  3. Two cards are drawn from a shuffled deck, with the first card returned and the deck reshuffled before the second draw. Let \(A\) mean the first card is a heart and \(B\) mean the second card is a heart. What feature of the process matters for independence?
  4. Explain why “the events can both occur” is not enough information to establish that they are independent.
  5. Two events are mutually exclusive and each has a positive probability. Explain why they must be dependent.