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Trigonometric Function Toolkit · Tutorial 124 of 1495

Even And Odd Trigonometric Functions

Learn why cosine is even and sine and tangent are odd, and use these symmetries to simplify negative-angle evaluations.

Beginner 8 min read

What You'll Learn

  • Define even and odd functions and recognize the domain requirement for each.
  • Derive the sine and cosine symmetries from reflection across the horizontal axis of the unit circle.
  • Prove the tangent symmetry using its quotient definition and its domain.
  • Apply symmetry rules to evaluate sine, cosine, and tangent at negative angles.
  • Identify the parity of reciprocal trigonometric functions from their definitions.
  • Avoid confusing an odd function with a function that is always negative at negative inputs.

Why Negative Angles Have Useful Symmetry

A negative angle describes rotation in the direction opposite to a positive angle. On the unit circle, changing an angle \(\theta\) to \(-\theta\) reflects its point across the horizontal axis. This reflection gives a simple way to relate trigonometric values at opposite angles.

The resulting relationships are useful whenever an expression contains negative angles. Instead of evaluating each negative angle from scratch, we can use the value at the corresponding positive angle and apply the appropriate sign rule. The rule depends on the trigonometric function: cosine keeps its value, while sine and tangent change sign.

Key idea: Reflection across the horizontal axis leaves a point’s horizontal coordinate unchanged and reverses the sign of its vertical coordinate. On the unit circle, those coordinates are cosine and sine.

Even and Odd Functions

A function can be called even or odd only when its domain is symmetric about zero: whenever \(x\) is in the domain, \(-x\) must also be in the domain. The definitions compare the function’s values at those two inputs.

Definition: A function \(f\) with a domain symmetric about zero is even if \(f(-x)=f(x)\) for every \(x\) in its domain. It is odd if \(f(-x)=-f(x)\) for every \(x\) in its domain.

For an even function, opposite inputs give the same output. For an odd function, opposite inputs give outputs with opposite signs. These are exact identities, not rules that apply only when \(x\) is positive or when a particular angle lies in a certain quadrant.

Reflection on the Unit Circle

For an angle \(\theta\), the point on the unit circle has coordinates \((\cos\theta,\sin\theta)\). The angle \(-\theta\) turns through the same amount in the opposite direction. Its point is the reflection of the point for \(\theta\) across the horizontal axis.

Reflection across that axis sends any point \((x,y)\) to \((x,-y)\). Therefore the point for \(-\theta\) has horizontal coordinate \(\cos\theta\) and vertical coordinate \(-\sin\theta\). Since its coordinates are also \((\cos(-\theta),\sin(-\theta))\), matching coordinates gives both identities.

$$ (\cos(-\theta),\sin(-\theta)) = (\cos\theta,-\sin\theta). $$
Theorem: For every real angle \(\theta\), cosine is even and sine is odd: $$ \cos(-\theta)=\cos\theta \qquad\text{and}\qquad \sin(-\theta)=-\sin\theta. $$

This argument establishes the rules for every real angle at once. The horizontal coordinate is unchanged by the reflection, so cosine keeps its value. The vertical coordinate changes sign, so sine changes sign.

Tangent’s Symmetry and Domain

Tangent is defined as the quotient of sine by cosine wherever cosine is nonzero. Its domain therefore excludes angles at which \(\cos\theta=0\). To determine tangent’s symmetry, use this quotient together with the sine and cosine identities just derived.

$$ \tan(-\theta) = \frac{\sin(-\theta)}{\cos(-\theta)} = \frac{-\sin\theta}{\cos\theta} = -\tan\theta. $$

The calculation applies only when \(\tan\theta\) is defined. The domain is symmetric about zero: if \(\cos\theta=0\), then \(\cos(-\theta)=\cos\theta=0\) as well, so both angles are excluded. Thus tangent is odd on its domain.

Important condition: The identity \(\tan(-\theta)=-\tan\theta\) applies when \(\cos\theta\ne 0\), which is exactly the condition that tangent be defined at \(\theta\). It does not assign a value to tangent at an excluded angle.

Using the Symmetries to Evaluate Negative Angles

The practical method is to move the minus sign outside the angle using the relevant parity identity. Then evaluate the trigonometric function at the positive angle. The exact values at the positive special angles are established by unit-circle coordinates.

Worked Example: Evaluating Sine at a Negative Angle

Evaluate \(\sin(-\pi/6)\). Since sine is odd,

$$ \sin(-\pi/6)=-\sin(\pi/6). $$

The unit-circle value at \(\pi/6\) is \(\sin(\pi/6)=1/2\). Substituting it gives

$$ \sin(-\pi/6)=-\frac{1}{2}. $$

Check using reflection: the point at \(\pi/6\) has coordinates \((\sqrt{3}/2,1/2)\), so its reflection has coordinates \((\sqrt{3}/2,-1/2)\). The vertical coordinate is \(-1/2\), as calculated.

Worked Example: Evaluating Cosine at a Negative Angle

Evaluate \(\cos(-2\pi/3)\). Cosine is even, so

$$ \cos(-2\pi/3)=\cos(2\pi/3). $$

At \(2\pi/3\), the unit-circle coordinates are \((-1/2,\sqrt{3}/2)\), so \(\cos(2\pi/3)=-1/2\). Therefore

$$ \cos(-2\pi/3)=-\frac{1}{2}. $$

Check: reflecting \((-1/2,\sqrt{3}/2)\) across the horizontal axis gives \((-1/2,-\sqrt{3}/2)\). The horizontal coordinate remains \(-1/2\), confirming the result.

Worked Example: Evaluating Tangent at a Negative Angle

Evaluate \(\tan(-\pi/3)\). First use the oddness of tangent:

$$ \tan(-\pi/3)=-\tan(\pi/3). $$

At \(\pi/3\), the coordinates are \((1/2,\sqrt{3}/2)\). Since tangent is sine divided by cosine,

$$ \tan(\pi/3) = \frac{\sqrt{3}/2}{1/2} = \frac{\sqrt{3}}{2}\cdot 2 = \sqrt{3}. $$

It follows that

$$ \tan(-\pi/3)=-\sqrt{3}. $$

Check from the reflected point: at \(-\pi/3\), the coordinates are \((1/2,-\sqrt{3}/2)\), and the quotient is

$$ \frac{-\sqrt{3}/2}{1/2}=-\sqrt{3}, $$

which agrees with the parity calculation. The denominator is nonzero, so tangent is defined at this angle.

Parity of the Reciprocal Trigonometric Functions

The reciprocal trigonometric functions inherit their symmetry from sine and cosine. Using their definitions, a reciprocal of an even function remains even, and a reciprocal of an odd function remains odd, wherever that reciprocal is defined. The domain restrictions still matter: a reciprocal is undefined when its denominator is zero.

Function Symmetry Identity on its domain
Sine Odd \(\sin(-\theta)=-\sin\theta\)
Cosine Even \(\cos(-\theta)=\cos\theta\)
Tangent Odd \(\tan(-\theta)=-\tan\theta\)
Cosecant Odd \(\csc(-\theta)=-\csc\theta\)
Secant Even \(\sec(-\theta)=\sec\theta\)
Cotangent Odd \(\cot(-\theta)=-\cot\theta\)

For instance, where \(\sin\theta\ne 0\), the cosecant identity follows directly:

$$ \csc(-\theta) = \frac{1}{\sin(-\theta)} = \frac{1}{-\sin\theta} = -\csc\theta. $$

The other reciprocal identities follow in the same way from their definitions and the corresponding parity rules for sine, cosine, or tangent. Each identity is understood only at angles where both sides are defined.

A Common Sign Mistake

A frequent error is to assume that every trigonometric function changes sign when its input angle is negated. That confuses the odd-function rule with a rule for all functions. Cosine is even, so its value does not change sign just because the angle is negative.

Worked Example: Correcting a Cosine Sign Error

A mistaken calculation might claim

$$ \cos(-\pi/3)=-\cos(\pi/3)=-\frac{1}{2}. $$

The first equality uses the odd-function rule, which does not apply to cosine. Cosine is even, and \(\cos(\pi/3)=1/2\). The correction is

$$ \cos(-\pi/3)=\cos(\pi/3)=\frac{1}{2}. $$

Check using reflection: the point at \(\pi/3\) is \((1/2,\sqrt{3}/2)\); its reflection is \((1/2,-\sqrt{3}/2)\). The horizontal coordinate remains \(1/2\), confirming that \(\cos(-\pi/3)=1/2\), not \(-1/2\).

When These Rules Are Useful

Parity lets us simplify expressions before doing further calculations. For example, an expression involving \(\sin(-x)\) can be rewritten as \(-\sin x\), and one involving \(\cos(-x)\) can be rewritten as \(\cos x\). This can make algebraic simplification more direct and helps check whether a computed sign is plausible.

The rules also give a quick consistency check. If a calculation says that sine has the same value at \(\theta\) and \(-\theta\), it conflicts with sine’s oddness unless that value is zero. If it says cosine changes sign between those angles, it conflicts with cosine’s evenness. Always identify which function is being used, and check that the angle is in that function’s domain.

Takeaway: Reflection across the horizontal axis gives \(\cos(-\theta)=\cos\theta\) and \(\sin(-\theta)=-\sin\theta\). Taking their quotient gives \(\tan(-\theta)=-\tan\theta\) wherever tangent is defined.

Check Your Understanding

Use the parity rules, the unit-circle values, and domain conditions where needed.

  1. Is \(\cos(-\theta)=\cos\theta\) the even-function rule or the odd-function rule?
  2. Evaluate \(\sin(-\pi/4)\) using the sine symmetry.
  3. Evaluate \(\cos(-\pi/6)\) using the cosine symmetry.
  4. Why must the tangent parity identity be restricted to angles where tangent is defined?
  5. Is cosecant even or odd, and what definition gives its parity?

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