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Trigonometric Function Toolkit · Tutorial 125 of 1495

Periodicity and Fundamental Periods

Learn what makes a number a period, why the basic trigonometric functions have their fundamental periods, and how input scaling changes those periods.

Beginner 9 min read

What You'll Learn

  • Define a period and distinguish it from a fundamental period.
  • Explain why sine and cosine repeat after a full turn and tangent after a half-turn.
  • Prove that the fundamental periods are two pi for sine and cosine and pi for tangent.
  • Determine how multiplying the input by a nonzero constant changes a fundamental period.
  • Handle negative and zero input multipliers correctly.
  • Check candidate periods by substitution and verify that they are fundamental.

Repeating Values and Periods

A function is periodic when its values repeat after a fixed shift in the input. Periodicity describes a precise algebraic relationship; recognizing that a function repeats is not enough to identify its smallest positive repeating shift.

For trigonometric functions, the unit circle gives a direct way to understand this repetition. Angles are measured in radians. A full turn adds \(2\pi\) to an angle and returns to the same point on the unit circle, so the sine and cosine coordinates repeat. A half-turn adds \(\pi\) and takes a point to its antipodal point. The tangent, which is the quotient of the two coordinates, is unchanged when both coordinates change sign.

Definition: A positive number \(P\) is a period of a function \(f:A\to B\) if, for every \(x\in A\), the shifted input \(x+P\) is also in \(A\) and \(f(x+P)=f(x)\). If a function has a least positive period, that number is its fundamental period.

The domain condition matters for functions such as tangent, which is not defined at every real number. A shift must preserve the domain as well as the function values. A period need not be fundamental: every positive integer multiple of a period is also a period, but may not be the smallest one.

Periods from Unit-Circle Behavior

For sine and cosine, the unit-circle coordinates return to their original values after a full revolution. For tangent, the quotient of the coordinates repeats after a half-revolution. These observations establish the following periods:

$$ \sin(x+2\pi)=\sin x,\qquad \cos(x+2\pi)=\cos x,\qquad \tan(x+\pi)=\tan x $$

The tangent equality applies whenever the tangent values are defined. Shifting by \(\pi\) preserves its domain: the excluded angles, where the horizontal coordinate is zero, are shifted to other excluded angles. The half-turn changes both unit-circle coordinates to their negatives, leaving their quotient unchanged.

Theorem: The fundamental period of \(\sin x\) is \(2\pi\), the fundamental period of \(\cos x\) is \(2\pi\), and the fundamental period of \(\tan x\) is \(\pi\). Their positive periods are, respectively, the positive integer multiples of \(2\pi\), \(2\pi\), and \(\pi\).

To show that these periods are fundamental, it is not enough to show that one shift works. We must also rule out every smaller positive period. The unit circle identifies the relevant special values: \(\sin t=0\) exactly when \(t=k\pi\); \(\cos t=1\) exactly when \(t=2k\pi\); and \(\tan t=0\) exactly when \(t=k\pi\), for integers \(k\).

1
Sine.
If \(P>0\) is a period of sine, setting \(x=0\) gives \(\sin P=\sin 0=0\). Thus \(P=k\pi\) for an integer \(k\). Since \(P>0\), \(k\) is positive. Now set \(x=\pi/2\). The period condition requires \(\sin(\pi/2+P)=\sin(\pi/2)=1\). If \(k\) were odd, \(\pi/2+k\pi\) would have sine \(-1\), so \(k\) must be even. Therefore \(P\) is a positive integer multiple of \(2\pi\). As \(2\pi\) is itself a period, it is the least positive one.
2
Cosine.
If \(P>0\) is a period of cosine, setting \(x=0\) gives \(\cos P=\cos 0=1\). The unit-circle coordinate equals \(1\) only at angles \(2k\pi\). Hence every positive period is a positive integer multiple of \(2\pi\). Since \(2\pi\) is a period, it is fundamental.
3
Tangent.
If \(P>0\) is a period of tangent, set \(x=0\). Both \(0\) and \(P\) must be in the domain, and the period condition gives \(\tan P=\tan 0=0\). Thus \(P=k\pi\) for a positive integer \(k\). Since \(\pi\) is a period, it is the least positive one.

This argument establishes more than a repeating shift: it shows that no positive period smaller than the stated fundamental period can work. It also classifies every positive period of each basic function.

What Input Scaling Does

Now consider a function whose input is multiplied by a constant \(c\), such as \(\sin(cx)\). When \(x\) increases by \(P\), the trigonometric input changes by \(cP\). To reproduce the original values, that change must be a period of the underlying trigonometric function. The sign of \(c\) determines the direction of the change, but a period is measured as a positive shift in \(x\).

Theorem: If \(c\ne 0\), the fundamental periods of \(\sin(cx)\) and \(\cos(cx)\) are \(2\pi/|c|\), and the fundamental period of \(\tan(cx)\) is \(\pi/|c|\). If \(c=0\), each expression is a constant function on its domain and has no fundamental period: every positive number is a period, so there is no least positive period.

The absolute value is essential when \(c\) is negative. A shift \(P>0\) in \(x\) changes the trigonometric input by \(cP\), which is negative if \(c<0\). The size of that change is \(|cP|=|c|P\).

Why the Scaling Rule Works

For sine or cosine, let \(g\) denote the underlying function, and suppose \(P>0\) is a period of \(f(x)=g(cx)\), where \(c\ne0\). Then for every real \(x\),

$$ g(c(x+P))=g(cx). $$

Set \(y=cx\) and \(d=cP\). Since \(c\ne0\), \(y\) ranges over all real numbers as \(x\) does. The period condition becomes \(g(y+d)=g(y)\) for every real \(y\). If \(d>0\), this says that \(d\) is a positive period of \(g\). If \(d<0\), replace \(y\) by \(y-d\) in that equality. This gives

$$ g(y)=g(y-d), \qquad\text{so}\qquad g(y+|d|)=g(y). $$

Thus in either case \(|d|=|c|P\) is a positive period of the underlying function. For sine and cosine, it must be a positive integer multiple of \(2\pi\). Therefore \(P\) must be a positive integer multiple of \(2\pi/|c|\). Conversely, choosing \(P=2\pi/|c|\) makes \(|cP|=2\pi\), so the input changes by one full turn, in either direction. This shift works and is the least positive one.

For tangent, the same input change must be a period of tangent. One can see this directly: if \(P>0\) is a period of \(\tan(cx)\), the domain includes \(x=0\) and the period condition gives \(\tan(cP)=\tan 0=0\). Therefore \(cP=k\pi\) for some nonzero integer \(k\), so \(|c|P=|k|\pi\). Conversely, when \(P=\pi/|c|\), the tangent input changes by \(\pi\) or \(-\pi\), preserving tangent values and its domain. This is the least positive such shift.

Worked Examples

Worked Example: Finding the Fundamental Period of \(\sin(3x/2)\)

Here the input multiplier is \(c=3/2\), which is positive. The fundamental period is the fundamental period of sine divided by the size of this multiplier:

$$ P=\frac{2\pi}{|3/2|} =\frac{2\pi}{3/2} =2\pi\cdot\frac{2}{3} =\frac{4\pi}{3}. $$

Check that this shift works by substituting it into the input:

$$ \sin\left(\frac{3}{2}\left(x+\frac{4\pi}{3}\right)\right) =\sin\left(\frac{3x}{2}+\frac{3}{2}\cdot\frac{4\pi}{3}\right) =\sin\left(\frac{3x}{2}+2\pi\right) =\sin\left(\frac{3x}{2}\right). $$

The classification above says that any positive period \(P\) must satisfy \((3/2)P=2k\pi\) for some positive integer \(k\), so \(P=4k\pi/3\). The value \(4\pi/3\) is therefore the least positive period. The substitution verifies the period; the classification verifies that it is fundamental.

Worked Example: Finding the Fundamental Period of \(\cos(-4x)\)

Here \(c=-4\). Because a period in \(x\) is positive even though the input decreases as \(x\) increases, use \(|c|=4\):

$$ P=\frac{2\pi}{|-4|} =\frac{2\pi}{4} =\frac{\pi}{2}. $$

Substitute this shift into the cosine input:

$$ \cos\left(-4\left(x+\frac{\pi}{2}\right)\right) =\cos\left(-4x-2\pi\right) =\cos(-4x). $$

The input changes by \(-2\pi\), one full turn in the negative direction, so the values repeat. If \(P\) is any positive period, the cosine classification requires \(|-4P|=2k\pi\), where \(k\) is a positive integer. Thus \(P=k\pi/2\), and the least positive choice is \(\pi/2\).

Worked Example: Finding the Fundamental Period of \(\tan(2x/3)\)

The input multiplier is \(c=2/3\), so the candidate fundamental period is

$$ P=\frac{\pi}{|2/3|} =\pi\cdot\frac{3}{2} =\frac{3\pi}{2}. $$

Check the function values by substituting:

$$ \tan\left(\frac{2}{3}\left(x+\frac{3\pi}{2}\right)\right) =\tan\left(\frac{2x}{3}+\pi\right) =\tan\left(\frac{2x}{3}\right). $$

The domain is preserved as well. The excluded inputs satisfy \(\frac{2x}{3}=\pi/2+k\pi\), or \(x=3\pi/4+3k\pi/2\). Adding \(3\pi/2\) sends an excluded input to the next excluded input; subtracting the same shift sends it to the preceding one. Thus an input is in the domain exactly when its shifted input is in the domain. Finally, any positive period must make the tangent input change by a positive or negative integer multiple of \(\pi\), so \((2/3)P=k\pi\) in absolute value. Its smallest positive solution is \(3\pi/2\).

A Common Scaling Mistake

A frequent error is to multiply the original period by the input multiplier. For example, sine has period \(2\pi\), so one might claim that \(\sin(3x)\) has fundamental period \(6\pi\). That shift does repeat the values, but it is not the fundamental period. The input changes three times as fast, so we must solve \(3P=2\pi\), not \(P=3(2\pi)\):

$$ P=\frac{2\pi}{3}. $$

Checking directly confirms the smaller shift:

$$ \sin\left(3\left(x+\frac{2\pi}{3}\right)\right) =\sin(3x+2\pi) =\sin(3x). $$

The general rule is to divide the underlying fundamental period by the absolute value of the input multiplier. Multiplying by a positive integer can produce a larger period, but it misses the smaller shift that makes the function fundamental.

When There Is No Fundamental Period

The scaling formula requires \(c\ne0\). If \(c=0\), then \(\sin(cx)=\sin 0=0\) and \(\cos(cx)=\cos 0=1\) for every real \(x\). Also, \(\tan(cx)=\tan 0=0\), defined for every real \(x\). Each is constant, so every positive shift preserves its values. There is no smallest positive real number among all positive shifts, and therefore no fundamental period under the definition used here.

Periodicity is useful whenever a function models a repeating pattern, but its basic algebraic meaning is important even before applications: it lets us compare shifts without relying on a graph. Keep three checks in mind: the shift in the original input must be positive, the trigonometric input change must match a known period, and the domain must be preserved where the function is not defined everywhere.

Check Your Understanding

Use unit-circle behavior and the scaling rule to answer these questions. For each proposed period, distinguish a period from the fundamental period.

  1. What is the fundamental period of \(\sin(5x)\), and what input change does that shift produce?
  2. Find and verify the fundamental period of \(\cos(-x/2)\).
  3. What are the positive periods of \(\tan x\)? Why does the tangent domain remain valid after a shift of \(\pi\)?
  4. Does \(\sin(0x)\) have a fundamental period? Explain.
  5. If \(P>0\) is a period of \(\sin(cx)\) with \(c<0\), why is the relevant input-shift size \(|c|P\) rather than \(cP\)?

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