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Sample Size and Expected Sample Size · Tutorial 236 of 499

Interpreting Expected Enrollment Relative to the Maximum

You will distinguish expected enrollment from maximum enrollment, calculate both across stopping scenarios, and understand why the full maximum must remain feasible.

Advanced 12 min read

What You'll Learn

  • Define maximum and scenario-specific expected enrollment for a MAMS design.
  • Calculate expected enrollment from stage sizes and probabilities of reaching each stage.
  • Interpret expected enrollment as a planning summary, not a guaranteed trial size.
  • Compare expected enrollment across assumed stopping scenarios while holding the design maximum fixed.
  • Identify calculation and planning errors that can make a low expectation misleading.

Why Expected Enrollment and Maximum Enrollment Answer Different Questions

A multi-arm multi-stage (MAMS) design can stop early when interim results meet a stopping rule, so its realized enrollment may be below the amount needed to complete every stage. This creates two useful but distinct quantities. Expected enrollment summarizes average enrollment under a specified scenario and design. Maximum enrollment describes the largest enrollment the design may require if the trial proceeds through all planned stages. The expectation can help compare the likely resource use of designs; the maximum indicates the enrollment capacity that may still be needed.

Expected enrollment is scenario-specific because the probabilities of stopping or continuing depend on the assumed treatment effects, variability, stopping boundaries, allocation, and other design features. It is not a promise about the number of participants a particular trial will enroll. Nor does a low expectation change the design’s stopping rules or guarantee that recruitment will end early.

Definition: For a specified MAMS design, the maximum enrollment is the total number of participants enrolled if every planned stage is reached, under the design’s planned allocation and stage sizes. The expected enrollment under scenario \(s\), written \(E_s[N]\), is the probability-weighted average of total enrollment \(N\) over the possible stopping paths when the design is evaluated under scenario \(s\). A scenario specifies the assumed outcomes or treatment effects used to determine the probabilities of those paths.

Calculating Expected Enrollment From Stage-Reach Probabilities

First consider a design with fixed total stage increments. Let \(n_k\) be the number of participants newly enrolled at stage \(k\), across all arms, and let \(R_k\) equal 1 if stage \(k\) is reached and 0 otherwise. The first stage is always reached, so \(R_1=1\). Total enrollment is the sum of the increments for stages that are reached. Since \(E_s[R_k]=P_s(R_k=1)\), taking expectations gives the stage-based calculation:

$$ N=\sum_{k=1}^{K} n_k R_k, \qquad E_s[N]=\sum_{k=1}^{K} n_k P_s(R_k=1). $$

The maximum for this fixed-increment design is \(N_{\max}=\sum_{k=1}^{K} n_k\). The stage-reach probabilities are unconditional probabilities: \(P_s(R_k=1)\) is the probability, under scenario \(s\), that the trial reaches stage \(k\), including all the decisions required to continue through earlier stages. They therefore cannot increase with stage number. In particular, \(P_s(R_1=1)=1\), and \(P_s(R_{k+1}=1)\leq P_s(R_k=1)\).

If the number enrolled at a stage depends on the path—for example, because the allocation or number of active arms changes—the fixed-increment formula needs to reflect that. In general, list the possible paths \(j\), let \(N_j\) be total enrollment on path \(j\), and let \(P_s(j)\) be its probability under scenario \(s\). Then \(E_s[N]=\sum_j P_s(j)N_j\), and the maximum is the largest \(N_j\) among paths allowed by the design. This path-based definition avoids treating a path-dependent stage size as if it were fixed.

Justification: For fixed stage increments, the indicator \(R_k\) contributes \(n_k\) participants when stage \(k\) is reached and zero otherwise. Thus \(E_s[n_kR_k]=n_kE_s[R_k]=n_kP_s(R_k=1)\). Summing these expectations gives \(E_s[N]=\sum_k n_kP_s(R_k=1)\). Because each reach probability is at most 1, \(E_s[N]\leq\sum_k n_k=N_{\max}\).

Worked Examples

Worked Example: Expected Enrollment Under One Scenario

Suppose a hypothetical three-stage MAMS design enrolls 90 participants in stage 1, 120 in stage 2, and 150 in stage 3. These are fixed total increments across all arms. Under a specified treatment-effect scenario, the probabilities of reaching stages 1, 2, and 3 are 1.00, 0.75, and 0.45, respectively. Find the expected enrollment, maximum enrollment, and expected enrollment as a percentage of the maximum.

The maximum is the sum of all three stage increments: \(N_{\max}=90+120+150=360\) participants.

The expected enrollment weights each increment by its probability of being needed: \(E_s[N]=(90)(1.00)+(120)(0.75)+(150)(0.45)=90+90+67.5=247.5\) participants.

Relative to the maximum, this is \(247.5/360=0.6875\), or \(68.75\%\). The expectation is 112.5 participants below the maximum, since \(360-247.5=112.5\). These are averages over trials evaluated under the stated scenario; they do not imply that a single trial will enroll 247.5 participants. The stage-3 reach probability is no greater than the stage-2 probability, as required for nested stages.

Worked Example: A Low Expectation Does Not Remove the Maximum

Consider a hypothetical design with fixed stage increments of 60, 90, and 120 participants. Under one scenario, the probabilities of reaching the three stages are 1.00, 0.50, and 0.20. Calculate the expected and maximum enrollment, then interpret the 20% probability of reaching the final stage.

The maximum is \(60+90+120=270\) participants. The expected enrollment is \(E_s[N]=(60)(1.00)+(90)(0.50)+(120)(0.20)=60+45+24=129\) participants. The expected-to-maximum ratio is \(129/270=0.4778\), or \(47.78\%\).

The 129-participant expectation is substantially below the 270-participant maximum, but the design still has a 0.20 probability of reaching stage 3 under this scenario. On those paths, all 270 participants may be required. Therefore, if the trial is to remain feasible whenever its rules call for stage 3, recruitment capacity must accommodate up to 270 participants, not just an average of 129. The expectation describes probability-weighted use across possible paths; it does not limit the enrollment on any particular path.

Worked Example: Comparing Two Assumed Scenarios

A hypothetical design has stage increments of 80, 100, and 120 participants, so its maximum enrollment is 300. Under scenario A, the probabilities of reaching stages 2 and 3 are 0.80 and 0.60. Under scenario B, they are 0.40 and 0.10. The first stage is reached with probability 1 in both scenarios. Compare expected enrollment.

For scenario A, \(E_A[N]=(80)(1.00)+(100)(0.80)+(120)(0.60)=80+80+72=232\) participants. This is \(232/300=77.33\%\) of the maximum.

For scenario B, \(E_B[N]=(80)(1.00)+(100)(0.40)+(120)(0.10)=80+40+12=132\) participants. This is \(132/300=44.00\%\) of the maximum.

The expected enrollment is 100 participants lower under scenario B than under scenario A, while the maximum remains 300 in both. The difference arises from the assumed probabilities of continuing, not from a change to the planned stage sizes or the all-stages enrollment. These expectations support a comparison of anticipated resource use under the two scenarios; they do not establish that one scenario’s maximum can be ignored.

Interpreting the Comparison and Checking the Calculation

The ratio \(E_s[N]/N_{\max}\) is a convenient descriptive summary of expected enrollment relative to the design cap. For example, a ratio of 0.70 means the scenario-specific expectation is 70% of the maximum. It does not mean that every trial will enroll 70% of the maximum, nor does it describe the probability of stopping at any particular stage. A single average cannot show the full distribution of possible enrollment.

For a nonnegative enrollment variable bounded above by \(N_{\max}\), \(E_s[N]\geq N_{\max}P_s(N=N_{\max})\). Consequently, \(P_s(N=N_{\max})\leq E_s[N]/N_{\max}\). This is only an upper bound on the probability of using the maximum, not a value for that probability. For instance, an expectation-to-maximum ratio of 0.48 does not tell us that there is a 48% chance of reaching the maximum.

Useful checks include confirming that the maximum matches the planned all-stages enrollment, that each stage’s reach probability is between 0 and 1, and that later-stage reach probabilities do not exceed earlier-stage probabilities. The expected enrollment should be no less than the mandatory first-stage enrollment and no greater than the maximum. If the trial must enroll all participants in stage 1, a calculated expectation below that stage’s size signals an error in the inputs or arithmetic. If expected enrollment exceeds the maximum, check for a duplicated stage, inconsistent units, or probabilities applied to the wrong increments.

The reach probabilities must also correspond to the scenario being interpreted. Changing the assumed effects or other scenario inputs can change the probabilities of continuing, and therefore the expectation, without changing the design’s maximum. If expected enrollment is estimated by simulation, the estimate also has Monte Carlo error: apparent small differences between scenarios may partly reflect simulation noise. That uncertainty in the estimate is distinct from variation in the enrollment path of an actual trial.

Why the Maximum Still Matters

The maximum is an operational requirement, not another estimate of average use. Recruitment systems, sites, funding, and follow-up arrangements may need to remain workable if the design continues through every planned stage. Planning only around a low expected enrollment can leave the trial unable to continue when an uncommon but valid path requires more participants. Early stopping is governed by the design’s rules and observed interim data; it is not guaranteed by a favorable expected-enrollment calculation.

Expected enrollment and maximum enrollment are therefore complementary, not competing, summaries. Expected enrollment is useful when comparing anticipated resource use across designs or scenarios. Maximum enrollment provides the all-stages bound for feasibility and contingency planning. If a decision specifically concerns a chance of exceeding a resource threshold, the relevant quantity is a probability or other feature of the enrollment distribution, not the expectation alone.

Common Mistakes and Limitations

  • Treating expected enrollment as a promised sample size. The expectation averages over possible paths. A particular trial follows one path and may enroll substantially fewer or more participants than the expectation.
  • Using the expectation as the recruitment cap. A low average does not rule out the all-stages path. If continuing to the final stage is possible, the maximum remains relevant to feasibility.
  • Comparing scenarios as if they were different designs. If stage sizes and stopping rules are unchanged, a lower scenario-specific expectation does not imply a lower maximum.
  • Confusing conditional and unconditional reach probabilities. The formula uses the probability of reaching a stage from the start of the trial. A conditional probability of continuing given that the previous stage was reached must be converted to an unconditional probability before weighting that stage’s enrollment.
  • Assuming the expected enrollment is the sample size used for design guarantees. The design’s operating characteristics are tied to its planned stages and stopping rules, not to replacing the design with a fixed trial of size \(E_s[N]\).

These summaries also have limits. The maximum and expectation alone do not describe the distribution of enrollment across paths, the probability of reaching each individual stage, or uncertainty in an estimated expectation. A scenario-specific expectation is only as informative as the assumptions used to calculate its path probabilities. It should not be interpreted as a guarantee that the assumed scenario is true.

Check Your Understanding

Answer each question, then compare your reasoning with the solutions below.

  1. A design has fixed stage increments of 50, 70, and 100 participants. The probabilities of reaching the stages are 1.00, 0.60, and 0.30. Find the expected and maximum enrollment.
  2. In question 1, what proportion of the maximum is the expected enrollment? Does this proportion equal the probability of reaching stage 3?
  3. Why must a trial with a 30% probability of reaching its final stage still consider that stage when planning enrollment capacity?
  4. Suppose a calculated expected enrollment is greater than the maximum. Give two checks that could identify the problem.
  5. Two scenarios use the same stage sizes, but one has a lower expected enrollment. What can be concluded about the maximum enrollment?

Solutions. (1) The maximum is \(50+70+100=220\) participants. The expectation is \((50)(1.00)+(70)(0.60)+(100)(0.30)=50+42+30=122\) participants. (2) The ratio is \(122/220=0.5545\), or \(55.45\%\). It is not the probability of reaching stage 3, which is 0.30; the ratio summarizes expected enrollment across all stages relative to the maximum. (3) On paths that reach the final stage, the additional participants may be required. The 30% probability makes that path less frequent under the scenario, not impossible, so planning only for the expectation could leave the trial unable to complete. (4) Check that stage increments have not been counted more than once and that each probability is between 0 and 1 and is attached to the correct stage. Also verify that the maximum and expectation use the same enrollment units and paths. (5) If the stage sizes and design paths are unchanged, the maximum is unchanged. The lower expectation reflects different scenario-specific reach probabilities, not a smaller all-stages requirement.

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