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Polar Coordinates and Graphs · Tutorial 971 of 998

Multiple Traces and Repeated Curve Points

Use Cartesian point equality and parameter intervals to distinguish a radial period from a complete tracing period for rose curves and circles.

Beginner 9 min read

What You'll Learn

  • Distinguish a period of the radius function from a repeat period of the plotted curve.
  • Test whether two polar coordinate pairs represent the same Cartesian point.
  • Determine how parity affects the tracing of rose curves.
  • Identify tracing intervals for circles centered at the pole and circles through the pole.
  • Count repeated traversals while treating shared points and interval endpoints carefully.

Why a Polar Equation Can Trace a Curve More Than Once

A polar equation gives a radius for each angle, but the angle itself is also part of how the curve is traced. An interval of angles can describe every point on a curve once, or it can travel around the curve again. The period of the radius function alone does not always settle the question.

To track tracing, associate each angle \(\theta\) with its Cartesian point:

$$ \mathbf{P}(\theta) = \bigl(r(\theta)\cos\theta,\;r(\theta)\sin\theta\bigr). $$

The key question is whether two different angle values produce the same point \(\mathbf{P}(\theta)\). This requires care because polar coordinates can describe one point in more than one way.

Definition: An interval traces a curve once if a typical point on the curve is reached once as the parameter runs through the interval. It traces the curve multiple times if a typical point is reached more than once. A typical point excludes exceptional points such as the pole, a shared endpoint, or an intersection that is reached by different parts of the curve.

This convention prevents a shared point from making the phrase “traced once” misleading. For instance, several petals of a rose meet at the pole, but that does not mean each petal has been traced repeatedly.

When Do Two Polar Pairs Give the Same Point?

For a nonzero point, two polar pairs \((r_1,\theta_1)\) and \((r_2,\theta_2)\) represent the same Cartesian point precisely in either of these cases:

$$ r_2=r_1,\qquad \theta_2=\theta_1+2k\pi, $$

or

$$ r_2=-r_1,\qquad \theta_2=\theta_1+(2k+1)\pi, \qquad k\in\mathbb{Z}. $$

The first case uses the same signed radius and angles that differ by a full turn. The second uses opposite signed radii and directions that differ by a half-turn. In fact, changing both signs leaves the Cartesian coordinates unchanged:

$$ (-r)\cos(\theta+\pi)=r\cos\theta, \qquad (-r)\sin(\theta+\pi)=r\sin\theta. $$

The pole is an exception: if \(r=0\), every angle represents the same point \((0,0)\). These equivalences give a direct test for repeated curve points. Comparing only the values of \(r(\theta)\) is not enough; the angle must be considered as well.

Rose Curves: The Parity of the Petal Number Matters

Consider a rose curve \(r=a\cos(n\theta)\) or \(r=a\sin(n\theta)\), where \(a>0\) and \(n\) is a positive integer. These equations have familiar radial periods, but their Cartesian tracing behavior depends on whether \(n\) is odd or even.

For either sine or cosine, shifting the angle by \(\pi\) changes the radius according to

$$ r(\theta+\pi)=(-1)^n r(\theta). $$

If \(n\) is odd, both the radius and the direction reverse. Those two reversals cancel in Cartesian coordinates, so the same point is reached after an angle increase of \(\pi\). If \(n\) is even, the radius is unchanged by that shift while the direction reverses; a typical point is therefore not the same point.

Key takeaway: For a rose with odd \(n\), an interval of length \(\pi\) traces the curve once, and an interval of length \(2\pi\) traces it twice. For a rose with even \(n\), an interval of length \(2\pi\) traces the curve once. In both cases, the pole can be reached at multiple angles.

The claim about a full tracing interval concerns typical points. In an odd rose, for example, \(\mathbf{P}(\theta+\pi)=\mathbf{P}(\theta)\). Within an interval of length \(\pi\), two distinct angles can differ by \(\pi\) only if they are the two endpoints. Thus a typical point is not repeated inside that interval. For an even rose, an angle shift of \(\pi\) gives the opposite point for a typical nonzero radius; a full repeat occurs after \(2\pi\).

Why the Rose Tracing Rule Works

Here is the Cartesian argument for the parity rule. Write the rose point as

$$ \mathbf{P}(\theta) = \bigl(a\cos(n\theta)\cos\theta,\; a\cos(n\theta)\sin\theta\bigr). $$

For odd \(n\), \(\cos(n(\theta+\pi))=-\cos(n\theta)\), while \(\cos(\theta+\pi)=-\cos\theta\) and \(\sin(\theta+\pi)=-\sin\theta\). Consequently,

$$ \mathbf{P}(\theta+\pi) = \bigl(a\cos(n\theta)\cos\theta,\; a\cos(n\theta)\sin\theta\bigr) = \mathbf{P}(\theta). $$

So the parametrization repeats after \(\pi\). To see why the curve is not already repeated at a smaller angular difference within an interval of length \(\pi\), apply the equality test for polar pairs. Two distinct angles in that interval cannot differ by \(2\pi\), and can differ by \(\pi\) only at its endpoints. Hence a typical point occurs only once there.

For even \(n\), the shift by \(\pi\) leaves the radius unchanged. The polar direction changes by \(\pi\), so the Cartesian point becomes its opposite rather than the same point, unless the radius is zero. A shift by \(2\pi\) restores both the radius and the direction. This establishes the stated tracing intervals for typical points; zeros of the radius remain exceptional shared points.

Worked Example: An Odd Rose Traced Twice on a Full Turn

Worked Example: An Odd Rose Traced Twice on a Full Turn

Consider \(r=2\sin(3\theta)\). Determine whether the interval \([0,2\pi]\) traces the curve once or multiple times.

Here \(n=3\), which is odd. First compare the radius at angles separated by \(\pi\):

$$ r(\theta+\pi) =2\sin(3\theta+3\pi) =-2\sin(3\theta) =-r(\theta). $$

The angle has also increased by \(\pi\). Thus \((r(\theta+\pi),\theta+\pi)=(-r(\theta),\theta+\pi)\) represents the same Cartesian point as \((r(\theta),\theta)\). The curve repeats after an angular shift of \(\pi\).

For example, at \(\theta=\frac{\pi}{6}\),

$$ r\left(\frac{\pi}{6}\right) =2\sin\left(\frac{\pi}{2}\right)=2, \qquad \mathbf{P}\left(\frac{\pi}{6}\right) =(\sqrt{3},1). $$

At \(\theta=\frac{7\pi}{6}=\frac{\pi}{6}+\pi\),

$$ r\left(\frac{7\pi}{6}\right) =2\sin\left(\frac{7\pi}{2}\right)=-2, $$

and therefore

$$ \mathbf{P}\left(\frac{7\pi}{6}\right) = \left( -2\cos\frac{7\pi}{6},\; -2\sin\frac{7\pi}{6} \right) =(\sqrt{3},1). $$

The two angle values give exactly the same point. Since the repeat shift is \(\pi\), the interval \([0,2\pi]\) covers the same typical points twice. The two computed Cartesian points agree, as required.

Worked Example: An Even Rose Traced Once on a Full Turn

Worked Example: An Even Rose Traced Once on a Full Turn

Consider \(r=3\cos(2\theta)\) on \([0,2\pi]\). The radial function has period \(\pi\), since

$$ 3\cos(2(\theta+\pi)) =3\cos(2\theta+2\pi) =3\cos(2\theta). $$

But this does not mean the curve is traced twice on \([0,2\pi]\). At \(\theta=0\), the radius is \(3\), giving \(\mathbf{P}(0)=(3,0)\). At \(\theta=\pi\), the radius is also \(3\), but

$$ \mathbf{P}(\pi) = (3\cos\pi,\;3\sin\pi) =(-3,0). $$

These points are opposites, not the same point. More generally, the radius repeats after \(\pi\), while the direction reverses. A typical nonzero point is not repeated by that shift. After \(2\pi\), both radius and direction return to their original values, so the curve is traced once on \([0,2\pi]\).

For a direct repeat check, at \(\theta=\frac{\pi}{6}\) the radius is \(3\cos(\frac{\pi}{3})=\frac{3}{2}\), and the point is

$$ \mathbf{P}\left(\frac{\pi}{6}\right) = \left(\frac{3\sqrt{3}}{4},\frac{3}{4}\right). $$

At \(\theta=\frac{7\pi}{6}\), the radius is again \(\frac{3}{2}\), but the point is

$$ \mathbf{P}\left(\frac{7\pi}{6}\right) = \left(-\frac{3\sqrt{3}}{4},-\frac{3}{4}\right). $$

The points are distinct. At \(\theta=\frac{13\pi}{6}=\frac{\pi}{6}+2\pi\), the radius and direction both return, giving \((\frac{3\sqrt{3}}{4},\frac{3}{4})\) again. This confirms that the full-turn repeat is \(2\pi\), despite the shorter radial period.

Circles: Check the Cartesian Point, Not Just the Radius

For a circle centered at the pole with equation \(r=a\), where \(a>0\), the point is \((a\cos\theta,a\sin\theta)\). Its coordinates return after \(2\pi\), and a full interval of length \(2\pi\) traces the circle once. An interval of length \(4\pi\) traces it twice.

A circle through the pole can have equation \(r=2a\cos\theta\), with \(a>0\). Its Cartesian coordinates are

$$ x=2a\cos^2\theta=a(1+\cos 2\theta), \qquad y=2a\sin\theta\cos\theta=a\sin 2\theta. $$

These coordinates satisfy \((x-a)^2+y^2=a^2\), so they lie on the circle centered at \((a,0)\) with radius \(a\). They also show directly that the point repeats after an angle increase of \(\pi\): both \(\cos 2\theta\) and \(\sin 2\theta\) remain unchanged. Thus \([0,\pi]\) traces this circle once, while \([0,2\pi]\) traces it twice.

Worked Example: A Circle Through the Pole

For \(r=4\cos\theta\), determine the tracing on \([0,2\pi]\). Here \(a=2\), so the Cartesian form is

$$ x=2(1+\cos 2\theta), \qquad y=2\sin 2\theta. $$

At \(\theta=\frac{\pi}{3}\), \(r=4\cos(\frac{\pi}{3})=2\), and

$$ \mathbf{P}\left(\frac{\pi}{3}\right) = (2\cos\tfrac{\pi}{3},2\sin\tfrac{\pi}{3}) =(1,\sqrt{3}). $$

At \(\theta=\frac{4\pi}{3}=\frac{\pi}{3}+\pi\), \(r=4\cos(\frac{4\pi}{3})=-2\). Using the signed radius,

$$ \mathbf{P}\left(\frac{4\pi}{3}\right) = (-2\cos\tfrac{4\pi}{3},-2\sin\tfrac{4\pi}{3}) =(1,\sqrt{3}). $$

This point is reached twice, and the Cartesian formula repeats for every shift of \(\pi\). Therefore \([0,2\pi]\) traces the circle twice; \([0,\pi]\) traces it once, apart from the usual endpoint identification. Substitution verifies that both parameter values give the same Cartesian point.

A Common Mistake: Treating a Radial Period as a Curve Period

A tempting but incorrect argument is: “\(3\cos(2\theta)\) has period \(\pi\), so the rose is traced twice on \([0,2\pi]\).” The calculation establishing the radial period is correct, but the conclusion does not follow. The polar direction changes too.

Correction: When \(\theta\) changes, compare the full points \((r\cos\theta,r\sin\theta)\), or use the equivalent-polar-pairs test. A repeated radius at angles differing by \(\pi\) can correspond to opposite Cartesian points, as it does for an even rose.

The same caution applies in reverse: a radius may change sign while the represented point stays the same, as in an odd rose or a circle through the pole. Always test the signed radius and angle together.

A Reliable Tracing Check

For a new polar equation, use the following sequence before deciding that an interval covers the graph once or multiple times:

1
Write the point map.
Use \(\mathbf{P}(\theta)=(r(\theta)\cos\theta,r(\theta)\sin\theta)\) so both radius and direction are included.
2
Find candidate shifts.
Check shifts that repeat \(r(\theta)\), reverse its sign, or change the angle by \(\pi\) or \(2\pi\).
3
Test point equality.
Use the polar-pair equivalences or compare the Cartesian coordinates for a typical nonzero point.
4
Count the interval’s repeats.
Compare the interval length with the repeat shift, while allowing for a shared endpoint and exceptional points such as the pole.

This method matters whenever an interval is intended to describe a curve without redundant tracing. The same equation can appear to have a short period in its radius but a longer period in its Cartesian points. For roses, parity explains the difference; for circles through the pole, a half-turn in the parameter can already return to the same point. The decisive evidence is always equality of points, not a radius pattern on its own.

Check Your Understanding

For each question, focus on the actual Cartesian point or on how signed radius and angle work together.

  1. For \(r=5\sin(5\theta)\), what interval length gives one tracing of the rose, and how many times is it traced on \([0,2\pi]\)?
  2. For \(r=2\cos(4\theta)\), does the radius period of \(\frac{\pi}{2}\) mean the curve is repeated after that shift? Explain using the parity rule.
  3. Why can two polar pairs with opposite signed radii represent the same nonzero point?
  4. For \(r=6\cos\theta\), how many times does \([0,2\pi]\) trace the circle through the pole?
  5. Why should the pole be treated as an exceptional point when counting how many times a rose is traced?

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